STUDY GROUPS- MEET NEXT WEEK - PowerPoint PPT Presentation

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STUDY GROUPS- MEET NEXT WEEK

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Examples Empirical vs. Molecular Formulas Formaldehyde Empirical= CH2O Molar mass of empirical formula= 30.03g/mol Actual ... Determining Formulas from ... – PowerPoint PPT presentation

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Title: STUDY GROUPS- MEET NEXT WEEK


1
Announcements
  • STUDY GROUPS- MEET NEXT WEEK
  • HEADS-UP EXAM 1 FRIDAY, SEPTEMBER 18TH

2
How many C atoms are in a 0.96-carat diamond
ring? (1 carat 0.2g)
  1. 9.63 x 1021
  2. 1.38 x 1024
  3. 4.81 x 1022
  4. 3.47 x 1025

3
Compounds and Moles
  • 1 mole of a compound contains 6.022 x 1023
    molecules or units
  • Molar mass sum of atomic molar masses
  • H2O
  • CO2
  • Fe(NO3)3

4
Examples to try(answers posted on web site under
lecture notes)
  • Consider UF6
  • What is the molar mass?
  • How many grams in 0.5 mol?
  • How many molecules in 0.5 mol?
  • How many U atoms in 0.5 mol of UF6?
  • How many F atoms in 0.5 mol UF6?

5
Molecular vs. Nonmolecular compound terms
  • 1 mol CO2 contains 6.022 x 1023 molecules
  • 1 mol NaCl contains 6.022 x 1023 formula units

6
Percent Composition
  • The fraction of mass due to an element

7
Determining Formulas from Composition
  • The ratio of atoms in the formula is the same as
    the ratio of moles of those elements.
  • If you determine the ratio of moles, you know the
    formula.
  • However, the formula determined is the empirical
    formula.

8
Which of the following has the highest
composition of copper, Cu? (dont calculate)
  1. CuSO4
  2. Cu2SO4
  3. CuCO3
  4. Cu2CO3

9
Examples
  • 8.65g of iron combines with 3.72g of oxygen. What
    is the empirical formula of this compound?
  • Formaldehyde contains 40.0 C, 6.7 H, and 53.3
    O. What is the empirical formula?

10
Empirical vs. Molecular Formulas
  • Formaldehyde
  • Empirical CH2O
  • Molar mass of empirical formula 30.03g/mol
  • Actual Molar mass 30.03g/mol
  • Molecular CH2O
  • Fructose
  • Empirical CH2O
  • Molar mass of empirical formula 30.03g/mol
  • Actual Molar mass 180.16g/mol
  • Divide actual molar mass by empirical formula
    mass to get multiplier
  • 180.16/30.036
  • Molecular C6H12O6

11
Example
  • A hydrocarbon has 82.65C and 17.34H. The molar
    mass is 58.12 g/mol. What are the empirical and
    molecular formulas?
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