Title: Ch. 25
1Ch. 25
- Electric Current and DC Circuits
2Chapter Overview
- Definition of Current
- Ohms Law
- Resistance Conduction in Metals
- Kirchhoffs Laws
- Analysis of DC Circuits
- RC Circuits
3Current
- Up to this point we have been concerned with
charges that dont move Static - When charges do move, then an electric current
flows - Current, usually denoted by the letter i is that
rate at which charge moves. In other words how
much charges flows past a point per time
4Current
- i current
- q charge
- t time
- SI Units ampere
- Symbol A
- Fundamental Unit (More on this later)
5The ampere is a fundamental unit, so the coulomb
is a derived unit. Express the coulomb in terms
of fundamental units
- A/s
- As
- s/A
- None of he above
1 2 3 4 5
6Batteries are often rated in amphours. What type
of quantity does an amphour represent?
- Current
- charge
- Electric Potential
- Capacitance
- None of the above
1 2 3 4 5
7Ex. How many coulombs of charge are stored in 60
Ahr battery?
8Solution
- i?q/?t
- ?qi?t
- ?q60 A x 1 hr
- 60A x 1 hr x 3600 s/1 hr 216000 C
9Ex. 10000 protons fIow through a detector every
.05 s. What is the current flowing through the
detector?
10Soln.
- Current i?q/?t
- i10000x1.602x10-19 C/.05 s
- i 3.2 x 10-14 A
Protons
Detector
11Microscopic View of Current
- At the microscopic level, current is made by
individual charges moving at a speed vd in the
material - A charge will travel the distance x in a time
given by t x/vd
x
vd
q
12Microscopic view of current
- The total amount of charge that flows through
the gray shaded volume in time ?t is ?Q nqV
where n is the number of charges per volume, V is
the volume of the gray shaded area, and q is the
charge of an individual charge - V xA vd?tA
- So ?Q nqvdA?t
13Drift Velocity
- I ?Q/?t nqAvd
- vd is the drift velocity. It represents the
average speed of charges in conductor - Ex. A copper wire has a radius of .50 mm. It
carries a current of .25 A. What is the drift
velocity of the electrons in the wire. Assume 1
free electron per atom. (?cu 8.93 g /cm3)
14There will be Avagadros number of charges in 1
mole of copper. the molar mass of copper is 63.5
g. The volume of 1 mole of copper is V 63.5
g/8.93 g/cm3 7.31 cm3 7.31 x 10-6 m3
15n NA / Vmol 6.022 x 1023/7.31 x 10-6 m3
8.24 x 1028 electrons /m3 vd i/nqA .25
A/(8.24 x 1028/m3 x 1.602 x 10-19 As x 3.14 x(5 x
10-4 m)2) 2.4 x 10-5 m/s
16Ohms Law
- What factors determine how much current will flow
in a circuit (BRST)
17Ohms Law
- Potential Difference and the material properties
determine current that flows in a circuit
18Ohms Law
- Current is proportional to potential difference
- Resistance limits the amount of current that
flows - Experimental Relationship found by Georg Simon
Ohm - Not always true e.g. diodes, transistors,
19Resistance
- Units ohm denoted by O
- What is the ohm in terms of V and A
- What is the ohm in terms of fundamental units
20Units
21Resistivity
- What factors determine the resistance of a piece
of metal? (BRST)
22Resistivity
- Length L
- Cross sectional Area A
- resistivity ? material property (see table in
text p. 792)
23Two different metals with different resistivities
have the same length. Which metal will have the
higher resistance?
- The metal with the greater ?
- The metal with the smaller ?
- The resistances will be the same
- Cannot be determined
1 2 3 4 5
24Temperature Dependence of Resistance
- If you measure the resistance of a light bulb
cold and then measure it when it is glowing, do
you get the same resistance? (BRST)
25Temperature Dependence of Resistance
- Resistance increases with increasing temperature
for metals - It decreases with increasing temperature for
semiconductors - For conductors
- R R20(1 a(T- 20 C))
- a is the Temperature coefficient of resistance
(see p. 792)
26Ex. Find the temperature of the filament of a
light bulb (assume W) by measuring the resistance
when cold and glowing.
27Power
- When we apply a potential difference across a
resistor, it gets hot - What determines the power given off by a resistor?
28Power
- Work q?V
- Power Work/time
- P q?V/t but q/t i
- P i?V
29Power
- Combine the expression for electric power P
i?V with Ohms law ?V iR - P i?V i2R (?V )2/R
30Ex. A 100 W bulb is designed to emit 100 W when
connected to a 120 V circuit. a) Draw a sketch
and a schematic. b) What is the resistance of
the bulb and the current drawn when connected to
a 120 V outlet? c) Assuming the resistance
doesnt change, what would be the power output if
the bulb was connected to a 240 V circuit?
31The electric bill
- Power is a rate it tells you how much energy
per time is being used
32The electric company bills you in units of kwhr.
What is a kwhr? (TPS)
- It is a unit of power
- It is a unit of energy
- It is a unit of current
- It is a unit of potential difference
- Not enough information given
1 2 3 4 5
33The electric company bills you in units of kwhr.
What is a kwhr? (TPS)
- It is a unit of power
- It is a unit of energy
- It is a unit of current
- It is a unit of potential difference
- Not enough information given
1 2 3 4 5
34EX. How many joules are in a kWhr?
35For the circuit shown below how does the current
flowing through A compare to that flowing through
B
- It is the same
- It is greater at A
- It is greater at B
- It cannot be determined
3.0 O
B
A
V
6.0 O
1 2 3 4 5
36You connect two identical resistors in series
across a 6.0 V battery. How does the current in
the circuit compare to that when a single
resistor is connected across the battery
- There is no difference
- The current is twice as large
- The current is ½ as large
- Cannot be determined
1 2 3 4 5
37Resistors in Series
- When we add resistors is series, the current
decreases since the resistance increases - We define an equivalent resistance as a single
resistor which produces the same current when
attached to the same potential as the combination
of resistors
38Series equivalent
39Equivalent Series Resistance
- We want i to be the same
- V iReq
- V1 iR1, V2 iR2, V3 iR3
- V V1 V2 V3 iR1 iR2 iR3
- iR1 iR2 iR3 i(R1 R2 R3) iReq
- So Req R1 R2 R3
40Equivalent Series Resistance
- How would this result change if there were four
resistors in series? - In general as more resistors are added in series,
the resistance increases so the current decreases
41Ex. a) Find the equivalent resistance for the
following circuit. b) Find the current In the
circuit c) Find the potential drop across each
resistor d) Find the power dissipated by each
resistor. e) Find the power Supplied by the power
supply.
42You connect two identical resistors in parallel
across a 6.0 V battery. How does the current
supplied by the battery compare to that when a
single resistor is connected across the battery?
- There is no difference
- The current is twice as large
- The current is ½ as large
- Cannot be determined
1 2 3 4 5
43Resistors in Parallel
- When we add resistors is parallel, the current
increases - The effective resistance must then decrease
- How can that be? (BRST)
44Resistors in Parallel
- There are more branches for current to follow in
a parallel circuit, so current can be larger
45Resistors in Parallel
- What is the same for the three resistors shown?
(GR)
46Resistors in Parallel
- The potential difference across each resistor is
the same - Define i1 V/R1, i2 V/R2, i3 V/R3
- How do the currents combine?
47Parallel Equivalent Resistance
- We define the equivalent resistance as a single
resistor that will draw the same current from the
power supply
48Parallel Equivalent resistance
- The currents add. Why?
- i i1 i2 i3 V/R1 V/R2 V/R3 V/Req
49a) Find the equivalent resistance. b) Find the
current flowing through each resistor. c) Find
the current supplied by the power supply
50Find the equivalent resistance for the following
network
51Kirchhoffs laws
- The rules for series and parallel resistances are
examples of Kirchhoffs Laws - Voltage Law - Sum of the potential differences
around a closed loop is 0 - Current Law- the sum of currents at a node is 0
52Voltage Law
- A loop is a closed path in a circuit
53Current law
- A node is a point in a circuit where several
wires join
54For the circuit shown below a) choose currents
for each branch of the circuit. b) For the
choice of currents youve made, label the higher
potential side of each resistor with a and the
lower potent side with a c) Use Kirchoff s
laws to write a closed system of equations for
the currents. d) Solve for the currents. e)
Find the potential difference across each
resistor. f) Find the power dissipated by each
resistor. g) Find the power supplied by each
power supply
55(No Transcript)
56RC Circuits
- A resistor in series with a capacitor makes an RC
circuit - RC circuits have many applications e.g. camera
flashes
57RC Circuits - Charging
- Use Kirchhoffs Voltage Law to analyze the
circuit shown below
R
V
C
58RC Circuits
- V VR VC 0
- V iR Q/C 0
- But i dQ/dt
- V - R dQ/dt 1/C Q 0
59RC Circuits
- Kirchhoffs Voltage Law gives a differential
equation for the charge - dQ/dt V/R - Q/RC
- Assuming the capacitor is initially discharged
the solution (Youll work it out in lab) - Q CV(1 e-t/(RC))
60Charging a Capacitor
When t RC 5 s, Vc .63 6V 3.78 V
61Current in a Charging RC Circuit
- i dq/dt V/R e-t/RC
- The current exponentially decays with the same
time constant
62Discharging a Capacitor
- Assume that the capacitor is initially charged
with Q0 CV0 - What will happen when the switch is closed
R
C
63Discharging a Capacitor
- -R dq/dt q/C 0
- dq/dt -q/(RC)
- A solution is q CV0 e-t/(RC)
- Solution is exponential decay
- RC is the time constant
64Ex. a) What fraction of the original charge
remains when t RC? b) At what time is charge
reduced to a fraction f of the initial amount?
65Current in a Discharging RC Circuit
- i dq/dt -V/R e-t/RC
- The current exponentially decays with the same
time constant - It flows in the opposite direction