Title: Series Parallel Circuits
1Benchmark Companies Inc PO Box 473768 Aurora CO
80047
2Introduction to Combination Circuits
- Advantages of Series Circuits
- A series circuit may be used to connect small
voltages to obtain high voltages. - High voltages may be reduced by connecting
resistances in series. - Series circuits provide a means for reducing and
controlling the current by connecting resistances
in series. - Series circuits are used where different voltage
drops and a constant current are needed.
3Disadvantage of Series Circuits
- Since the current is constant in a series circuit
we are forced to use only those devices which
require the same current. - If any part of a series circuit should burn out
it would cause an open circuit and put the entire
circuit out of operation. - Series circuits are used where different voltage
drops and a constant current are needed.
4Advantages of Parallel Circuits
- If a break should occur in any branch of a
parallel circuit, it would not affect the other
branch circuits. - Any device may be operated independently of any
other device. - In a parallel circuit, more branches (devices)
may be added at any time.
- Disadvantages of Parallel Circuits
- As more devices are added more current is drawn
till eventually the fuse blows. - Parallel circuits are used where a constant
voltage and a large current are required.
5Combination Circuits
- If we combine series circuits with parallel
circuits, we produce a combination circuit. - A combination circuit makes it possible to obtain
the different voltages of a series circuit and
the different currents of a parallel circuit. - Simple combination circuits are of two types.
- 1. A parallel-series circuit in which one or
more groups of resistances in series are
connected in parallel. - 2. A series-parallel circuit in which one or
more groups of resistances in parallel are
connected in series.
6- General Method for Solving Combination Circuits
1. A group of resistances is a simple combination
of two or more resistances which are arranged in
either simple series or simple parallel circuits.
Identify these groups. 2. Every group must be
removed from the circuit as a unit and replaced
by a single resistor which offers the identical
resistance. This equivalent resistance is the
total resistance of the group.
Continued
7General Method for Solving Combination Circuits
- 3. Redraw the circuit, using the equivalent
resistance in place of each group. - 4. Solve the resulting simple circuit for all
missing values. - 5. Go back to the original circuit to find the
voltage, current, and resistance for each
resistance in the circuit.
8Solving Parallel-Series Circuits
Example
Two groups of resistors are Group A (that has
10-, and 50 ? resistors connected in series) and
Group B (that has two 30 ? resistors connected in
series). Find all the missing values connected in
parallel across a 120 V source of voltage,
current, and resistance.
Continued
9Solution
- 1. Identify groups A and B as series circuits.
- 2. Find the equivalent resistance of each group.
- 3. Since the resistors of groups A and B are in
series. - RA R1 R2
- RA 10 50 60 ? Ans.
- RB R3 R4
- RB 30 30 60 ? Ans.
-
Continued
10Solution
- 4. Redraw the circuit, using these 60 ? resistors
in place of the series groups. - 5. Solve the new parallel circuit.
- Find the voltage for each group.
- VT VA VB 120 V Ans.
- Find the current in each group
VA IA x RA 120 IA x 60 IA 120/60 2
A Ans.
VB IB x RB 120 IB x 60 IB 120/60 2 A
Ans.
Continued
11Find the total current IT. IT IA
IB IT 2 2 4 A Ans.
Find the total resistance RT. VT IT x
RT 120 4 x RT RT 120/4 30 ? Ans.
- 6. Go back to the original circuit to find the
voltage and current for each resistor. Find the
current in each resistor. - IA I1 I2 2 A Ans.
- IB I3 I4 2 A Ans.
Continued
12Find the voltage drop across each resistor.
- V2 I2 x R2
- V2 2 x 50
- V2 100 V
V1 I1 x R1 V1 2 x 10 V1 20 V
V4 I4 x R4 V4 2 x 30 V4 60 V
V3 I3 x R3 V3 2 x 30 V3 60 V
13Solving Series-Parallel Circuits
Example
- A resistor R1 10 ? is in series with two
parallel resistors R2 40 ? and R3 60 ?. The
three resistors are connected across a voltage
source of 34 V. Find all the values of voltage,
current, and resistance.
Continued
14Solution
1. Find the resistance of the parallel group A
(R2 and R3).
2. Since R2 and R3 are in parallel, RA (R2 x
R3) ? (R2 R3) RA (40 x 60) ? (40 60) 24
? Ans.
3. Redraw the circuit using this 24 ? resistor RA
in place of the parallel combination.
- 4. Solve the new series circuit. Find the total
resistance RT. - RT R1 R4 RT 10 24 34 ? Ans.
Continued
15Find the total current IT. VT IT x RT
34 IT x 34 IT 34/34 1 A Ans.
Find the current in each part of the series
circuit. IT I1 IA 1 A Ans.
- Find the voltage in each part of the series
circuit.
VA IA x RA VA 1 x 24 24 V Ans.
V1 I1 x R1 V1 1 x 10 10 V Ans.
Continued
165. Go back to the parallel group A to find V, I,
and R for each resistance in the group. Since VA
represents the total voltage of the parallel
group A. VA V2 V3 24 V
- Find the current in each resistor of group A.
V2 I2 x R2 24 I2 x 40 I2 24/40 0.6 A
V3 I3 x R3 24 I3 x 60 I3 24/60 0.4 A
6. Check IT I2 I3
IT 0.6 0.4
1 1
17