Common%20Ion%20Effect - PowerPoint PPT Presentation

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Common%20Ion%20Effect

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Common Ion Effect Sometimes the equilibrium solutions have 2 ions in common For ... Weak acid & a conjugate base OR Weak base & a conjugate acid The concentrations ... – PowerPoint PPT presentation

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Title: Common%20Ion%20Effect


1
Common Ion Effect
  • Buffers

2
Common Ion Effect
  • Sometimes the equilibrium solutions have 2 ions
    in common
  • For example if I mixed HF NaF
  • The main reaction is HF ? H F-

3
Common Ion Effect
  • Which way will the reaction shift if NaF is
    added?
  • What effect will this have on pH?

4
Example
  • What is the pH of a 0.10M solution of HC2H3O2 (Ka
    1.8 x10-5)

5
Example
HC2H3O2 ? H C2H3O2 - Ka
1.8 x 10-5
I
C
E

6
Example
  • A mixture contains 0.10M HC2H3O2 (Ka 1.8 x10-5)
    0.10 M NaC2H3O2. Calculate the pH.

7
Example
HC2H3O2 ? H C2H3O2 - Ka
1.8 x 10-5
I
C
E

8
What are buffers?
  • Buffers resist changes in pH
  • They must have 2 parts
  • Weak acid a conjugate base OR
  • Weak base a conjugate acid
  • The concentrations of the 2 MUST be with in a
    factor of 10!!!

9
Buffers
NaC2H3O2 HC2H3O2 Buffer?
0.10M 0.10M
0.10M 1.0M
0.01M 1.0M
10
Example
  • What is the pH of a solution containing 50. mL of
    0.50M NaC2H3O2 25 mL of 0.25M HC2H3O2. (Ka
    1.8 x10-5).

11
Example
HC2H3O2 ? H C2H3O2 - Ka
1.8 x 10-5
I
C
E

12
Henderson Hasselbach Equation
  • Really easy equation to use ONLY with buffer
    solutions!!!
  • pH pKa log B/A

13
The last example using HH
  • pH pKa log B/A

14
Example (ICE TABLE)
  • What is the pH of a solution containing 25 mL of
    0.150MHClO 32mL of 0.45M KClO. Ka 3.5x10-8

15
Example (ICE TABLE)
HClO? H ClO -
Ka 3.5x10-8
I
C
E

16
Example (HH)
  • pH pKa log B/A

17
Example (ICE TABLE)
  • What is the pH of a solution containing 25 mL of
    0.50M CH3NH3NO3 is mixed with 75 mL of 0.30 M
    CH3NH2 (Kb CH3NH2 4.38 x10-4)

18
Example (ICE TABLE)
CH3NH2 H2O ? CH3NH3 OH - Ka
4.38x10-4
I
C
E

19
Example
  • Calculate the mass of NaF that must be added to
    1000.0 ml of 0.50M HF to form a solution with a
    pH of 4.00. Ka 7.2x10-4

20
Example (ICE TABLE)
HF ? H F -
Ka 7.2x10-4
I
C
E
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