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Bottle Rocket Calculations

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Select air pressure and water volume. Select air pressure i.e. 40 psi ... Drag force D = 1- Dc = 1 0.15 = 0.85. Final range Rf = R x D = 82.3 m x 0.85 = 69.96 m ... – PowerPoint PPT presentation

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Title: Bottle Rocket Calculations


1
Bottle Rocket Calculations
  • Example using 40 psi and 700 ml of water

2
Select air pressure and water volume
  • Select air pressure i.e. 40 psi
  • Select water volume i.e. 700 ml
  • Find mass of water
  • Mass density x volume
  • Vol 700 ml 700 cm3 or 0.000700 m3
  • ? density of water 998 kg/m3 which is a
    constant
  • Mass 998 kg/m3 x 0.0007 m3 0.6986 kg

3
Calculate average water mass flow rate
  • Average mass flow rate, ?, of water out of
    nozzle ? A X cd X v(2??P)
  • Find A of nozzle in m2 A pr2
  • For diameter of 21 cm .021 m
  • Radius d/2 .021 m / 2 0.0105 m
  • A p (0.0105)2 0.0003462 m2
  • Cd is given at 0.98

4
(water mass flow rate cont.)
  • Find average pressure acting on the water
  • ?P (Pi Pf) / 2 or (Pi (1Vi/Vf)) / 2, since
    PiVi PfVf, so Pf (PiVi)/Vf
  • Pi 40 psi
  • Vi of air 2 Liter 0.7 L 1.3 L
  • Vf 2 L
  • Pf 40 (1.3) / 2 26
  • ?P (40 26) / 2 33psi
  • Convert psi to N/m2
  • 14.7 psi 101,353.56 N/m2, so 33 psi
  • 101,353.56 x 33 / 14.7 227528.4 N/m2
  • Note N kg m/s2

5
(water mass flow rate cont.)
  • Back to calculating average mass flow rate, ?, of
    water out of nozzle ? A x cd x v(2??P)
  • ? A x cd x v(2??P)
  • ? 0.0003462 m2 x 0.98 x (v2 x 998 kg/m3 x
    227528.4 N/m2) 7.2302 kg/s

6
Water Exit Velocity Thrust
  • Water exit velocity V ? / ?A 7.2302 kg/s /
    (998 kg/m3)(.0003462 m2) 20.926 m/s
  • Rocket thrust ft ? x V 7.2302 kg/s x 20.926
    m/s 151.3 kg m/s2 or 151.3 N

7
Net Force on Rocket
  • Net force f ft fd (mave x g)
  • F 151.3 kg m/s2 0 ((0.3 0.7 kg)/2) x
    (9.8 m/s2) 146.4 kg m/s2 or 146.4 N
  • Note
  • Mave mass of empty rocket mass of water
    selected
  • Mass of rocket was weighted at 300 g, or 0.3 kg
  • Water selected was 0.7 kg
  • fd is the drag coefficient and is very low in
    this case

8
Rocket Acceleration
  • The rocket acceleration is a result of the net
    force acting on the mass
  • f mave x a, so a f/ mave
  • A (146.4 N) / ((0.3 0.7 kg)/2)
    292.8 m/s2

9
Range
  • To find the range you need to find the amount of
    time it takes for the water to exit and the
    velocity of the rocket
  • The time to expel the water is the mass of the
    water divide by the mass flow rate t m
    H2O/ ? 0.7 kg / 7.2302 kg/s 0.097 s

10
(Range cont.)
  • Velocity of the bottle Vrocket is a x t
  • (292.8 m/s2) x (0.097 s) 28.4 m/s
  • So the range R is V2rocket x sin 2? / g
  • ? is the launch angle which is 45 in this case.
  • R (28.4 m/s)2 x sin 2(45) / 9.8 m/s2 82.3 m

11
Final Range
  • Final range is affected by drag factor
  • Drag factor, Dc, for bottle shape is low, i.e.
    0.15
  • Drag force D 1- Dc 1 0.15 0.85
  • Final range Rf R x D 82.3 m x 0.85 69.96 m
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