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Isoplethal Analysis of a Ternary Phase Diagram

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Title: Isoplethal Analysis of a Ternary Phase Diagram


1
Isoplethal Analysis of a Ternary Phase Diagram
  • Presented By
  • Adam Chamberlain

2
Definitions
  • Primary Crystallization Field
  • Gives the first solid that forms upon cooling
  • Compatibility Triangle
  • Gives the final solid mixture of the composition
  • Crystallization Path
  • The path that is followed upon cooling a liquid.
    The path that is traced gives the composition of
    the liquid while cooling the solid composition
    is determined using tie lines from the liquid
    path.

3
Isoplethal Analysis
4
Finding the composition
C
  • Method of Parallel lines

Alkemade lines
B
Ltotal length
Given a composition X A, Y B, ZC
Boundary lines
E2
A
E1
C ZC x L
  • Draw a line parallel to AB

C
A
B
AXA x L
AB
composition
  • Draw a line parallel to AC

5
The 3 questions
C
  • What is the primary crystallization field?
  • The field is AB
  • What is the compatibility triangle?

E2
E1
  • C-AB-B
  • What is the invariant point?
  • To find the invariant point, locate the point
    within the diagram that has each of the
    components of the compatibility triangle in
    equilibrium, in this case E2

A
B
AB
Alkemade lines
Boundary lines
6
Crystallization Path
C
  • Draw a line connecting the composition to the
    composition of the crystallization field
  • Continue the line until it hits a boundary line

E2
E1
  • Follow the boundary line until the invariant
    point is reached

A
B
AB
final liquid composition
7
Analysis at T1
  • Above T1 only liquid is present

C
  • The composition of the liquid is found using
    parallel lines
  • Below T1 an infinitesimal amount of AB
    crystallizes.

E2
  • Percent solid and liquid is given by the tie line

E1
T1
  • Percent A and B in AB is given by the tie line ab

y
A
B
a
AB
b
Temp Prop Phase
Composition Analysis

A
B C
T1() 100 L
(L)Parallel Lines 100A
100B 100C
T2() y/yL 100L (L)
same 100A
100B 100C e
0S (S) 100AB
0100A 0100B

Aa/ab Bb/ab
8
Analysis at T2
C
  • Above T2 there is solid AB and liquid.
  • Percent solid and liquid is given by the tie line
    xy

E2
  • The liquid composition is found using parallel
    lines method at T2

E1
T2
x
y
  • Below T2 infinitesimal amount of B crystallizes

A
B
a
AB
b
Temp Prop Phases
Composition
Analysis

A B
C
T2 () Ly y/xyL
(L)parallel lines LA
LB LC
Sx x/xyS
(S)100AB SABA
SABB
Aa/ab Bb/ab
T2(-) same same
(L)same LA
LB LC
(S)
100AB 0B SABA SABBSB

9
Analysis above TE
C
  • Above TE solid AB, B, and liquid are present
  • Percent solid and liquid are given by the tie
    line xy

E2
  • Liquid composition is given using parallel lines
    method

E1
x
  • Percent AB and B are given by the tie line ab and
    b

y
A
B
AB
b
ab
Temp Prop Phases
Composition
Analysis A B
C
TE() Ly y/xyL
(L)parallel lines LA
LA LC Lx
x/xyS (S) a/abAB
SABA SABB

b/abB
SB
10
Analysis below TE
C
  • Below TE only solid is present

AB
  • The composition is given by using the parallel
    lines method at the initial composition with
    respect to its compatibility triangle

E2
E1
B
C
A
B
AB
Temp Prop Phases
Composition
Analysis

A B
C
TE 100 S
parallel lines
100ABA 100ABB 100C


100A
11
Analysis of the KF-NaF-MgF2 System
  • Identify boundary lines
  • Identify the Alkemade lines
  • Identify the compatibility triangles

NaFMgF2- MgF2- KFMgF2
NaFMgF2- NaF- KFMgF2
Alkemade lines
NaF- KFMgF2- 2KFMgF2
Boundary lines
NaF- 2KFMgF2-KF
12
Locating the composition
  • 17NaF-23MgF2-60KF

KF
NaF 100 x .17 17
MgF2 100 x .23 23
MgF2
NaF
Triangle sides are 100 mm
13
The 3 questions
  • What is the primary crystallization field?

E
KFMgF2
  • What is the compatibility triangle?

NaF-2KFMgF2-KF
  • What is the invariant point?

E
14
Crystallization Path
  • Draw a line connecting the composition to the
    composition of the primary crystallization field
  • Continue the line until it hits the boundary line
  • KFMgF2 is resorbed to form all 2KFMgF2 at 750
  • The line is then extended to the boundary of NaF
    and 2KFMgF2
  • The boundary line is then followed until the
    eutectic reaction is reached

Crystallization Path
15
Analysis at 850
  • Above 850 only liquid is present
  • The composition is given by the initial
    composition
  • Below 850 an infinitesimal amount of KFMgF2
    crystallizes
  • Percent solid and liquid are given by the tie
    line y

y
Temp Prop Phases
Composition
Analysis
MgF2 KF NaF
850 () 100L
(L) 17NaF 23MgF2 60KF 17
23 60

850(-) y23 100L (L)
same 17 23
60 e
0S (S)100 KFMgF250KF 50MgF2
010050 010050
16
Analysis at 780
  • Above 780 there is liquid and solid KFMgF2
    present
  • Percent solid and liquid are given by the tie
    line xy
  • Liquid composition is found using parallel lines
    at 780

x
  • Below 780 KFMgF2 is being resorbed to form
    2KFMgF2

y
Temp Prop Phases
Composition
Analysis MgF2
KF NaF
780() y 23 82 L
(L) 22 NaF 16 MgF2 62 KF
13 51
18 x 5 18 S
(S) 100 KFMgF2
9
9
780() same same
(L) same
13 51
18 same
same (S) 100 KFMgF2
0 2KFMgF2 9
9
17
Analysis at 750
  • At 750 resorption is complete and the solid is
    100 2KFMgF2
  • The liquid composition is found using parallel
    lines

x
y
Temp Prop Phases
Composition
Analysis
MgF2
KF NaF
750 y 15 56 L
(L)32NaF 12 MgF2 53KF
7 30
18 Resorption x 12 44 S
(S)100 2KFMgF2 67KF 33MgF2 15
30 complete

18
Analysis at 700
  • Since all KFMgF2 is resorbed the path proceeds
    through the 2KFMgF2 crystallization field
  • Above 700 liquid and solid 2KFMgF2 are present
  • Percent liquid and solid are given by the tie
    line xy

x
y
  • Below 700 infinitesimal amount NaF crystallizes

Temp Prop Phases
Composition
Analysis
MgF2 KF NaF
700() y 15 45 L
(L) 39NaF 10 MgF2 51 KF 5
23 17
x 18 55 S (S)
100 2KFMgF2
18 37
700(-) same same
(L) same
5 23
17
(S) 100 2KFMgF2
0 NaF 18
37 0
19
Analysis above 685
  • Above 650 solid NaF, 2KFMgF2, and liquid are
    present

2KFMgF2
  • Percent solid and liquid are given by the tie
    line xy

x
  • The solid composition is found by using the
    NaF-2KFMgF2 Alkemade line as a tie line

y
NaF
Temp Prop Phases
Composition
Analysis MgF2
KF NaF
685() y 6 27 L
(L) 34NaF 6 MgF2 60 KF 2
16
9 x 16 73 S
(S) 13 NaF 21
43 9
87 2KFMgF2
20
Analysis Below 650
  • Below 650 the eutectic reaction takes place

2KFMgF2
  • 100 solid is present
  • The composition is found using parallel lines
    through the original composition with respect to
    the compatibility triangle

KF
NaF
Temp Prop Phases
Composition
Analysis MgF2
KF NaF
650(-) 100 S
(S) 20 NaF
21 16
20

16 KF
43

64 2KFMgF2
21
Summary
  • First identify the important features of the
    phase diagram Alkemade and boundary lines,
    invariant points, etc.
  • Locate the composition on the diagram
  • Determine the crystallization path
  • Finally, perform the analysis
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