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Algebraic and Transcendental Numbers

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Title: Algebraic and Transcendental Numbers


1
Algebraic and Transcendental Numbers
  • Dr. Dan Biebighauser

2
Outline
  • Countable and Uncountable Sets

3
Outline
  • Countable and Uncountable Sets
  • Algebraic Numbers

4
Outline
  • Countable and Uncountable Sets
  • Algebraic Numbers
  • Existence of Transcendental Numbers

5
Outline
  • Countable and Uncountable Sets
  • Algebraic Numbers
  • Existence of Transcendental Numbers
  • Examples of Transcendental Numbers

6
Outline
  • Countable and Uncountable Sets
  • Algebraic Numbers
  • Existence of Transcendental Numbers
  • Examples of Transcendental Numbers
  • Constructible Numbers

7
Number Systems
  • N natural numbers 1, 2, 3,

8
Number Systems
  • N natural numbers 1, 2, 3,
  • Z integers , -2, -1, 0, 1, 2,

9
Number Systems
  • N natural numbers 1, 2, 3,
  • Z integers , -2, -1, 0, 1, 2,
  • Q rational numbers

10
Number Systems
  • N natural numbers 1, 2, 3,
  • Z integers , -2, -1, 0, 1, 2,
  • Q rational numbers
  • R real numbers

11
Number Systems
  • N natural numbers 1, 2, 3,
  • Z integers , -2, -1, 0, 1, 2,
  • Q rational numbers
  • R real numbers
  • C complex numbers

12
Countable Sets
  • A set is countable if there is a one-to-one
    correspondence between the set and N, the natural
    numbers

13
Countable Sets
  • A set is countable if there is a one-to-one
    correspondence between the set and N, the natural
    numbers

14
Countable Sets
  • N, Z, and Q are all countable

15
Countable Sets
  • N, Z, and Q are all countable

16
Uncountable Sets
  • R is uncountable

17
Uncountable Sets
  • R is uncountable
  • Therefore C is also uncountable

18
Uncountable Sets
  • R is uncountable
  • Therefore C is also uncountable
  • Uncountable sets are bigger

19
Algebraic Numbers
  • A complex number is algebraic if it is the
    solution to a polynomial equation
  • where the ais are integers.

20
Algebraic Number Examples
  • 51 is algebraic x 51 0

21
Algebraic Number Examples
  • 51 is algebraic x 51 0
  • 3/5 is algebraic 5x 3 0

22
Algebraic Number Examples
  • 51 is algebraic x 51 0
  • 3/5 is algebraic 5x 3 0
  • Every rational number is algebraic
  • Let a/b be any element of Q. Then a/b is a
    solution to bx a 0.

23
Algebraic Number Examples
  • is algebraic x2 2 0

24
Algebraic Number Examples
  • is algebraic x2 2 0
  • is algebraic x3 5 0

25
Algebraic Number Examples
  • is algebraic x2 2 0
  • is algebraic x3 5 0
  • is algebraic x2 x 1 0

26
Algebraic Number Examples
  • is algebraic x2 1 0

27
Algebraic Numbers
  • Any number built up from the integers with a
    finite number of additions, subtractions,
    multiplications, divisions, and nth roots is an
    algebraic number

28
Algebraic Numbers
  • Any number built up from the integers with a
    finite number of additions, subtractions,
    multiplications, divisions, and nth roots is an
    algebraic number
  • But not all algebraic numbers can be built this
    way, because not every polynomial equation is
    solvable by radicals

29
Solvability by Radicals
  • A polynomial equation is solvable by radicals if
    its roots can be obtained by applying a finite
    number of additions, subtractions,
    multiplications, divisions, and nth roots to the
    integers

30
Solvability by Radicals
  • Every Degree 1 polynomial is solvable

31
Solvability by Radicals
  • Every Degree 1 polynomial is solvable

32
Solvability by Radicals
  • Every Degree 2 polynomial is solvable

33
Solvability by Radicals
  • Every Degree 2 polynomial is solvable

34
Solvability by Radicals
  • Every Degree 2 polynomial is solvable
  • (Known by ancient Egyptians/Babylonians)

35
Solvability by Radicals
  • Every Degree 3 and Degree 4 polynomial is solvable

36
Solvability by Radicals
  • Every Degree 3 and Degree 4 polynomial is
    solvable
  • del Ferro Tartaglia
    Cardano Ferrari
  • (Italy, 1500s)

37
Solvability by Radicals
  • Every Degree 3 and Degree 4 polynomial is
    solvable
  • Cubic Formula
  • Quartic Formula

38
Solvability by Radicals
  • For every Degree 5 or higher, there are
    polynomials that are not solvable

39
Solvability by Radicals
  • For every Degree 5 or higher, there are
    polynomials that are not solvable
  • Ruffini (Italian)
    Abel (Norwegian)
  • (1800s)

40
Solvability by Radicals
  • For every Degree 5 or higher, there are
    polynomials that are not solvable
  • is not solvable by radicals

41
Solvability by Radicals
  • For every Degree 5 or higher, there are
    polynomials that are not solvable
  • is not solvable by radicals
  • The roots of this equation are algebraic

42
Solvability by Radicals
  • For every Degree 5 or higher, there are
    polynomials that are not solvable
  • is solvable by
    radicals

43
Algebraic Numbers
  • The algebraic numbers form a field, denoted by A

44
Algebraic Numbers
  • The algebraic numbers form a field, denoted by A
  • In fact, A is the algebraic closure of Q

45
Question
  • Are there any complex numbers that are not
    algebraic?

46
Question
  • Are there any complex numbers that are not
    algebraic?
  • A complex number is transcendental if it is not
    algebraic

47
Question
  • Are there any complex numbers that are not
    algebraic?
  • A complex number is transcendental if it is not
    algebraic
  • Terminology from Leibniz

48
Question
  • Are there any complex numbers that are not
    algebraic?
  • A complex number is transcendental if it is not
    algebraic
  • Terminology from Leibniz
  • Euler was one of the first to
  • conjecture the existence of
  • transcendental numbers

49
Existence of Transcendental Numbers
  • In 1844, the French mathematician Liouville
    proved that some complex numbers are
    transcendental

50
Existence of Transcendental Numbers
  • In 1844, the French mathematician Liouville
    proved that some complex numbers are
    transcendental

51
Existence of Transcendental Numbers
  • His proof was not constructive, but in 1851,
    Liouville became the first to find an example of
    a transcendental number

52
Existence of Transcendental Numbers
  • His proof was not constructive, but in 1851,
    Liouville became the first to find an example of
    a transcendental number

53
Existence of Transcendental Numbers
  • Although only a few special examples were known
    in 1874, Cantor proved that there are
    infinitely-many more transcendental numbers than
    algebraic numbers

54
Existence of Transcendental Numbers
  • Although only a few special examples were known
    in 1874, Cantor proved that there are
    infinitely-many more transcendental numbers than
    algebraic numbers

55
Existence of Transcendental Numbers
  • Theorem (Cantor, 1874) A, the set of algebraic
    numbers, is countable.

56
Existence of Transcendental Numbers
  • Theorem (Cantor, 1874) A, the set of algebraic
    numbers, is countable.
  • Corollary The set of transcendental numbers must
    be uncountable. Thus there are infinitely-many
    more transcendental numbers.

57
Existence of Transcendental Numbers
  • Proof Let a be an algebraic number, a solution of

58
Existence of Transcendental Numbers
  • Proof Let a be an algebraic number, a solution
    of
  • We may choose n of the smallest possible degree
    and assume that the coefficients are relatively
    prime

59
Existence of Transcendental Numbers
  • Proof Let a be an algebraic number, a solution
    of
  • We may choose n of the smallest possible degree
    and assume that the coefficients are relatively
    prime
  • Then the height of a is the sum

60
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.

61
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.
  • Let a have height k. Let n be the degree of the
    polynomial for a in the definition of as height.

62
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.
  • Let a have height k. Let n be the degree of the
    polynomial for a in the definition of as height.
  • Then n cannot be bigger than k, by definition.

63
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.
  • Also,
  • implies that there are only finitely-many choices
    for the coefficients of the polynomial.

64
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.
  • So there are only finitely-many choices for the
    coefficients of each polynomial of degree n
    leading to a height of k.

65
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.
  • So there are only finitely-many choices for the
    coefficients of each polynomial of degree n
    leading to a height of k.
  • Thus there are finitely-many polynomials of
    degree n that lead to a height of k.

66
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.
  • This is true for every n less than or equal to k,
    so there are finitely-many polynomials that have
    roots with height k.

67
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.
  • This means there are finitely-many such roots to
    these polynomials, i.e., there are finitely-many
    algebraic numbers of height k.

68
Existence of Transcendental Numbers
  • Claim Let k be a positive integer. Then the
    number of algebraic numbers that have height k is
    finite.
  • This means there are finitely-many such roots to
    these polynomials, i.e., there are finitely-many
    algebraic numbers of height k.
  • This proves the claim.

69
Existence of Transcendental Numbers
  • Back to the theorem We want to show that A is
    countable.

70
Existence of Transcendental Numbers
  • Back to the theorem We want to show that A is
    countable.
  • For each height, put the algebraic numbers of
    that height in some order

71
Existence of Transcendental Numbers
  • Back to the theorem We want to show that A is
    countable.
  • For each height, put the algebraic numbers of
    that height in some order
  • Then put these lists together, starting with
    height 1, then height 2, etc., to put all of the
    algebraic numbers in order

72
Existence of Transcendental Numbers
  • Back to the theorem We want to show that A is
    countable.
  • For each height, put the algebraic numbers of
    that height in some order
  • Then put these lists together, starting with
    height 1, then height 2, etc., to put all of the
    algebraic numbers in order
  • The fact that this is possible proves that A is
    countable.

73
Existence of Transcendental Numbers
  • Since A is countable but C is uncountable, there
    are infinitely-many more transcendental numbers
    than there are algebraic numbers

74
Existence of Transcendental Numbers
  • Since A is countable but C is uncountable, there
    are infinitely-many more transcendental numbers
    than there are algebraic numbers
  • The algebraic numbers are spotted over the plane
    like stars against a black sky the dense
    blackness is the firmament of the
    transcendentals.
  • E.T. Bell, math historian

75
Examples of Transcendental Numbers
  • In 1873, the French mathematician Charles Hermite
    proved that e is transcendental.

76
Examples of Transcendental Numbers
  • In 1873, the French mathematician Charles Hermite
    proved that e is transcendental.

77
Examples of Transcendental Numbers
  • In 1873, the French mathematician Charles Hermite
    proved that e is transcendental.
  • This is the first number proved to be
    transcendental that was not constructed for such
    a purpose

78
Examples of Transcendental Numbers
  • In 1882, the German mathematician Ferdinand von
    Lindemann proved that
  • is transcendental

79
Examples of Transcendental Numbers
  • In 1882, the German mathematician Ferdinand von
    Lindemann proved that
  • is transcendental

80
Examples of Transcendental Numbers
  • Still very few known examples of transcendental
    numbers

81
Examples of Transcendental Numbers
  • Still very few known examples of transcendental
    numbers

82
Examples of Transcendental Numbers
  • Still very few known examples of transcendental
    numbers

83
Examples of Transcendental Numbers
  • Still very few known examples of transcendental
    numbers

84
Examples of Transcendental Numbers
  • Open questions

85
Constructible Numbers
  • Using an unmarked straightedge and a collapsible
    compass, given a segment of length 1, what other
    lengths can we construct?

86
Constructible Numbers
  • For example, is constructible

87
Constructible Numbers
  • For example, is constructible

88
Constructible Numbers
  • The constructible numbers are the real numbers
    that can be built up from the integers with a
    finite number of additions, subtractions,
    multiplications, divisions, and the taking of
    square roots

89
Constructible Numbers
  • Thus the set of constructible numbers, denoted by
    K, is a subset of A.

90
Constructible Numbers
  • Thus the set of constructible numbers, denoted by
    K, is a subset of A.
  • K is also a field

91
Constructible Numbers
92
Constructible Numbers
  • Most real numbers are not constructible

93
Constructible Numbers
  • In particular, the ancient question of squaring
    the circle is impossible

94
The End!
  • References on Handout
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