Atomic Arrangements

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Materials TechnologyDr. Amr Shehata Fayed

• Chapter 3
• Atomic Arrangements

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Objectives

• To learn classification of materials based on
  atomic arrangements
• To describe the arrangements in crystalline
  solids based on lattice, basis, and crystal
  structure

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Short-Range Order versus Long-Range Order

• Short-range order - The regular and predictable
  arrangement of the atoms over a short distance -
  usually one or two atoms spacing.
• Long-range order - A regular repetitive
  arrangement of atoms in a solid which extends
  over a very large distance.

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Figure 3.1 Levels of atomic arrangements in
materials (a) Inert monoatomic gases have no
regular ordering of atoms (b,c) Some materials,
including water vapor, nitrogen gas, amorphous
silicon and silicate glass have short-range
order. (d) Metals, alloys, many ceramics and some
polymers have regular ordering of atoms/ions that
extends through the material.
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Figure 3.2 Basic Si-0 tetrahedron in silicate
glass.
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Figure 3.3 Tetrahedral arrangement of C-H bonds
in polyethylene.
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Figure 3.4 (a) Photograph of a silicon single
crystal. (b) Micrograph of a polycrystalline
stainless steel showing grains and grain
boundaries.
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Types of Solids

• Crystalline material atoms self-organize in a
  periodic array
• Single crystal atoms are in a repeating or
  periodic array over the entire extent of the
  material.
• Polycrystalline material comprised of many small
  crystals or grains. The grains have different
  crystallographic orientation. There exist atomic
  mismatch within the regions where grains meet.
  These regions are called grain boundaries.

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Types of Solids

• Amorphous lacks a systematic atomic arrangement.
  Or Materials, including glasses, that have no
  long-range order, or crystal structure.
• In amorphous solids, there is no long-range
  order. But amorphous does not mean random, in
  many cases there is some form of short-range
  order.

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Crystal Structure

• To discuss crystalline structures it is useful to
  consider atoms as being hard spheres with
  well-defined radii. In this hard-sphere model,
  the shortest distance between two like atoms is
  one diameter.
• We can also consider crystalline structure as a
  lattice of points at atom/sphere centers.

• Lattice - A collection of points that divide
  space into smaller equally sized segments

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Crystal Structure

• The unit cell is the smallest structural unit or
  building block that can describe the crystal
  structure. Repetition of the unit cell generates
  the entire crystal.
• Atomic radius (R)- The apparent radius of an
  atom, typically calculated from the dimensions of
  the unit cell, using close-packed directions
  (depends upon coordination number).
• Packing factor - The fraction of space in a unit
  cell occupied by atoms.

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Metallic Crystal Structure

• Metals are usually polycrystalline although
  formation of amorphous metals is possible by
  rapid cooling.
• The atomic bonding in metals is non-directional.
  Therefore, there is no restriction on numbers or
  positions of nearest neighbor atoms. Thereafter,
  large number of nearest neighbors and dense
  atomic packing.
• The most common types of unit cells are the faced
  centered cubic (FCC), the body-centered cubic
  (BCC) and the hexagonal close-packed (HCP).

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Figure 3.11 The fourteen types of Bravais
lattices grouped in seven crystal systems. The
actual unit cell for a hexagonal system is shown
in Figures 3.12 and 3.16.
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Figure 3.12 Definition of the lattice parameters
and their use in cubic, orthorhombic, and
hexagonal crystal systems.
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Figure 3.13 (a) Illustration showing sharing of
face and corner atoms. (b) The models for simple
cubic (SC), body centered cubic (BCC), and
face-centered cubic (FCC) unit cells, assuming
only one atom per lattice point.
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Face Centered Cubic (FCC) Crystal Structure (I)

• Atoms are located at each of the corners and on
  the centers of all the faces of cubic unit cell.
• Ex. Al, Cu, Fe, Zn, Ag, etc

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Face Centered Cubic (FCC) Crystal Structure (II)

• The hard spheres or ion cores touch one another
  across a face diagonal, the cube edge length, a
  4R/v2.
• The coordination number, CN the number of
  closest neighbors to which an atom is bonded
  number of touching atoms, CN 12.
• Number of atoms per unit cell, n 4. (For an
  atom that is shared with m adjacent unit cells,
  we only count a fraction of the atom, 1/m).
• In FCC unit cell we have
• 6 face atoms shared by two cells 6 x 1/2 3
• 8 corner atoms shared by eight cells 8 x 1/8 1

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Face Centered Cubic (FCC) Crystal Structure (III)

• Corner and face atoms in the unit cell are
  equivalent
• FCC crystal has APF of 0.74, the maximum packing
  for a system equal-sized spheres. FCC is a
  close-packed structure.
• FCC can be represented by a stack of close-packed
  planes (planes with highest density of atoms).

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Body Centered Cubic (BCC) Crystal Structure (I)

• Atoms are located at each of the corners and at
  the center of the cubic unit cell.
• Ex. Cr, a-Fe, Mo

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Body Centered Cubic (BCC) Crystal Structure (II)

• The hard spheres or ion cores touch one another
  cube diagonal, the cube edge length, a 4R/v3.
• The coordination number, CN 8
• Number of atoms per unit cell, n 2.
• In BCC unit cell we have
• Center atom (1) shared by no other cells 1 x 1
  1
• 8 corner atoms shared by eight cells 8 x 1/8 1
• Corner and center atoms in the unit cell are
  equivalent
• BCC crystal has APF of 0.68

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Example 3.1
Determining the Number of Lattice Points in Cubic
Crystal Systems
Determine the number of lattice points per cell
in the cubic crystal systems. If there is only
one atom located at each lattice point, calculate
the number of atoms per unit cell. Example 3.1
SOLUTION In the SC unit cell lattice point /
unit cell (8 corners)1/8 1 In BCC unit
cells lattice point / unit cell
(8 corners)1/8 (1
center)(1) 2 In FCC unit cells lattice point /
unit cell
(8 corners)1/8 (6 faces)(1/2) 4 The number
of atoms per unit cell would be 1, 2, and 4, for
the simple cubic, body-centered cubic, and
face-centered cubic, unit cells, respectively.
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Example 3.2
Determining the Relationship between Atomic
Radius and Lattice Parameters
Determine the relationship between the atomic
radius and the lattice parameter in SC, BCC, and
FCC structures when one atom is located at each
lattice point.
Figure 3.14 The relationships between the atomic
radius and the Lattice parameter in cubic systems
(for Example 3.2).
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Example 3.2 SOLUTION Referring to Figure 3.14,
we find that atoms touch along the edge of the
cube in SC structures.
In BCC structures, atoms touch along the body
diagonal. There are two atomic radii from the
center atom and one atomic radius from each of
the corner atoms on the body diagonal, so
In FCC structures, atoms touch along the face
diagonal of the cube. There are four atomic radii
along this lengthtwo radii from the
face-centered atom and one radius from each
corner, so
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Figure 3.15 Illustration of coordinations in (a)
SC and (b) BCC unit cells. Six atoms touch each
atom in SC, while the eight atoms touch each atom
in the BCC unit cell.
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Example 3.3
Calculating the Packing Factor
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Example 3.4
Determining the Density of BCC Iron
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Hexagonal Closed Packed (HCP) Crystal Structure
(I)

• HCP is one more common structure of metallic
  crystals.
• Six atoms form regular hexagon, surrounding one
  atom in center. Another plane is situated halfway
  up unit cell (c-axis), with 3 additional atoms
  situated at interstices of hexagonal
  (close-packed) planes.
• Cd, Mg, Zn, Ti have this crystal structure

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Hexagonal Closed Packed (HCP) Crystal Structure
(II)

• Unit cell has two lattice parameters a and C.
  Ideal ratio C/a 1.633.
• The hard spheres touch one another along the base
  edge, the cube edge length, a 2R.
• The coordination number, CN 12
• Number of atoms per unit cell, n 6.
• 3 mid-plane atoms shared by no other cells 3 x 1
  3
• 12 hexagonal corner atoms shared by 6 cells 12 x
  1/6 2
• 2 top/bottom plane center atoms shared by 2
  cells 2 x 1/2 1
• All atoms in the unit cell are equivalent.
• BCC crystal has APF of 0.74

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Hexagonal Closed Packed (HCP) Crystal Structure
(II)

• HCP is one more common structure of metallic
  crystals.
• Six atoms form regular hexagon, surrounding one
  atom in center. Another plane is situated halfway
  up unit cell (c-axis), with 3 additional atoms
  situated at interstices of hexagonal
  (close-packed) planes.
• Cd, Mg, Zn, Ti have this crystal structure

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Figure 3.16 The hexagonal close-packed (HCP)
structure (left) and its unit cell.
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Allotropic or Polymorphic Transformations (I)

• Some materials may exist in more than one crystal
  structure, this is called polymorphism. If the
  material is an elemental solid, it is called
  allotropy.
• Allotropy - The characteristic of an element
  being able to exist in more than one crystal
  structure, depending on temperature and pressure.
• Polymorphism - Compounds exhibiting more than one
  type of crystal structure.

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Allotropic or Polymorphic Transformations (II)

• An example of allotropy is carbon, which can
  exist as diamond, graphite, and amorphous carbon.

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Example 3.5
Calculating Volume Changes in Polymorphs of
Zirconia
Calculate the percent volume change as zirconia
transforms from a tetragonal to monoclinic
structure. The lattice constants for the
monoclinic unit cells are a 5.156, b 5.191,
and c 5.304 Å, respectively. The angle ß for
the monoclinic unit cell is 98.9. The lattice
constants for the tetragonal unit cell are a
5.094 and c 5.304 Å, respectively. Does the
zirconia expand or contract during this
transformation? What is the implication of this
transformation on the mechanical properties of
zirconia ceramics?
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Example 3.5 SOLUTION The volume of a tetragonal
unit cell is given by V
a2c (5.094)2 (5.304) 134.33 Å3. The volume
of a monoclinic unit cell is given by
V abc sin ß (5.156) (5.191)
(5.304) sin(98.9) 140.25 Å3. Thus, there is an
expansion of the unit cell as ZrO2 transforms
from a tetragonal to monoclinic form. The
percent change in volume (final volume
initial volume)/(initial volume) 100 (140.25
- 134.33 Å3)/140.25 Å3 100 4.21. Most
ceramics are very brittle and cannot withstand
more than a 0.1 change in volume. The conclusion
here is that ZrO2 ceramics cannot be used in
their monoclinic form since, when zirconia does
transform to the tetragonal form, it will most
likely fracture. Therefore, ZrO2 is often
stabilized in a cubic form using different
additives such as CaO, MgO, and Y2O3.
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Example 3.6
Designing a Sensor to
Measure Volume Change
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The 1-cm3 cube of iron contracts to 1 - 0.0134
0.9866 cm3 after transforming therefore, to
assure 1 accuracy, the instrument must detect a
change of ?V (0.01)(0.0134) 0.000134 cm3
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Points, Directions, and Planes in the Unit Cell

• Miller indices - A shorthand notation to describe
  certain crystallographic directions and planes in
  a material. Denoted by brackets. A negative
  number is represented by a bar over the number.
• Directions of a form - Crystallographic
  directions that all have the same
  characteristics, although their sense is
  different. Denoted by h i brackets.
• Repeat distance - The distance from one lattice
  point to the adjacent lattice point along a
  direction.
• Linear density - The number of lattice points per
  unit length along a direction.
• Packing fraction - The fraction of a direction
  (linear-packing fraction) or a plane
  (planar-packing factor) that is actually covered
  by atoms or ions.

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Figure 3.18 Coordinates of selected points in the
unit cell. The number refers to the distance from
the origin in terms of lattice parameters.
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Example 3.7
Determining Miller Indices of Directions
Determine the Miller indices of directions A, B,
and C in Figure 3.19.
Figure 3.19 Crystallographic directions and
coordinates (for Example 3.7).
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Example 3.7 SOLUTION Direction A 1. Two points
are 1, 0, 0, and 0, 0, 0 2. 1, 0, 0, -0, 0, 0
1, 0, 0 3. No fractions to clear or integers to
reduce 4. 100 Direction B 1. Two points are 1,
1, 1 and 0, 0, 0 2. 1, 1, 1, -0, 0, 0 1, 1,
1 3. No fractions to clear or integers to
reduce 4. 111 Direction C 1. Two points are 0,
0, 1 and 1/2, 1, 0 2. 0, 0, 1 -1/2, 1, 0 -1/2,
-1, 1 3. 2(-1/2, -1, 1) -1, -2, 2
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Figure 3.20 Equivalency of crystallographic
directions of a form in cubic systems.
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Figure 3.21 Determining the repeat distance,
linear density, and packing fraction for 110
direction in FCC copper.
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Example 3.8
Determining Miller Indices of Planes
Determine the Miller indices of planes A, B, and
C in Figure 3.22.
Figure 3.22 Crystallographic planes and
intercepts (for Example 3.8)
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Example 3.9
Calculating the Planar Density and Packing
Fraction
Calculate the planar density and planar packing
fraction for the (010) and (020) planes in simple
cubic polonium, which has a lattice parameter of
0.334 nm.
Figure 3.23 The planer densities of the (010)
and (020) planes in SC unit cells are not
identical (for Example 3.9).
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Example 3.9 SOLUTION The total atoms on each
face is one. The planar density is
The planar packing fraction is given by
However, no atoms are centered on the (020)
planes. Therefore, the planar density and the
planar packing fraction are both zero. The (010)
and (020) planes are not equivalent!
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Example 3.10
Drawing Direction and Plane
Figure 3.24 Construction of a (a) direction and
(b) plane within a unit cell (for Example 3.10)
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Figure 3.25 Miller-Bravais indices are obtained
for crystallographic planes in HCP unit cells by
using a four-axis coordinate system. The planes
labeled A and B and the direction labeled C and D
are those discussed in Example 3.11.
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Example 3.11
Determining the Miller-Bravais Indices for Planes
and Directions
Determine the Miller-Bravais indices for planes A
and B and directions C and D in Figure 3.25.
Figure 3.25 Miller-Bravais indices are obtained
for crystallographic planes in HCP unit cells by
using a four-axis coordinate system. The planes
labeled A and B and the direction labeled C and D
are those discussed in Example 3.11.
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Figure 3.27 The ABABAB stacking sequence of
close-packed planes produces the HCP structure.
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Figure 3.28 The ABCABCABC stacking sequence of
close-packed planes produces the FCC structure.
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Interstitial Sites

• Interstitial sites - Locations between the
  normal atoms or ions in a crystal into which
  another - usually different - atom or ion is
  placed. Typically, the size of this interstitial
  location is smaller than the atom or ion that is
  to be introduced.
• Cubic site - An interstitial position that has a
  coordination number of eight. An atom or ion in
  the cubic site touches eight other atoms or ions.
• Octahedral site - An interstitial position that
  has a coordination number of six. An atom or ion
  in the octahedral site touches six other atoms or
  ions.
• Tetrahedral site - An interstitial position that
  has a coordination number of four. An atom or ion
  in the tetrahedral site touches four other atoms
  or ions.

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Figure 3.29 The location of the interstitial
sites in cubic unit cells. Only representative
sites are shown.
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Example 3.12
Calculating Octahedral Sites
plus the center position, 1/2, 1/2, 1/2.
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Example 3.12 SOLUTION (Continued) Each of the
sites on the edge of the unit cell is shared
between four unit cells, so only 1/4 of each site
belongs uniquely to each unit cell. Therefore,
the number of sites belonging uniquely to each
cell is (12 edges) (1/4 per cell) 1 center
location 4 octahedral sites
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Example 3.13
Design of a Radiation-Absorbing Wall
We wish to produce a radiation-absorbing wall
composed of 10,000 lead balls, each 3 cm in
diameter, in a face-centered cubic arrangement.
We decide that improved absorption will occur if
we fill interstitial sites between the 3-cm balls
with smaller balls. Design the size of the
smaller lead balls and determine how many are
needed.
Figure 3.30 Calculation of an octahedral
interstitial site (for Example 3.13).
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Diffraction Techniques for Crystal Structure
Analysis

• Diffraction - The constructive interference, or
  reinforcement, of a beam of x-rays or electrons
  interacting with a material. The diffracted beam
  provides useful information concerning the
  structure of the material.
• Braggs law - The relationship describing the
  angle at which a beam of x-rays of a particular
  wavelength diffracts from crystallographic planes
  of a given interplanar spacing.
• In a diffractometer a moving x-ray detector
  records the 2y angles at which the beam is
  diffracted, giving a characteristic diffraction
  pattern

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Figure 3.43 (a) Destructive and (b) reinforcing
interactions between x-rays and the crystalline
material. Reinforcement occurs at angles that
satisfy Braggs law.
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Figure 3.44 Photograph of a XRD diffractometer.
(Courtesy of HM Analytical Services.)
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Figure 3.45 (a) Diagram of a diffractometer,
showing powder sample, incident and diffracted
beams. (b) The diffraction pattern obtained from
a sample of gold powder.
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Example 3.20
Examining X-ray Diffraction
The results of a x-ray diffraction experiment
using x-rays with ? 0.7107 Å (a radiation
obtained from molybdenum (Mo) target) show that
diffracted peaks occur at the following 2? angles
Determine the crystal structure, the indices of
the plane producing each peak, and the lattice
parameter of the material.
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Example 3.20 SOLUTION We can first determine the
sin2 ? value for each peak, then divide through
by the lowest denominator, 0.0308.
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Figure 3.46 Photograph of a transmission electron
microscope (TEM) used for analysis of the
microstructure of materials. (Courtesy of JEOL
USA, Inc.)
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Figure 3.47 A TEM micrograph of an aluminum alloy
(Al-7055) sample. The diffraction pattern at the
right shows large bright spots that represent
diffraction from the main aluminum matrix grains.
The smaller spots originate from the nano-scale
crystals of another compound that is present in
the aluminum alloy.
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Figure 3.48 Directions in a cubic unit cell for
Problem 3.51
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Figure 3.49 Directions in a cubic unit cell for
Problem 3.52.
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Figure 3.50 Planes in a cubic unit cell for
Problem 3.53.
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Figure 3.51 Planes in a cubic unit cell for
Problem 3.54.
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Figure 3.52 Directions in a hexagonal lattice
for Problem 3.55.
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Figure 3.53 Directions in a hexagonal lattice
for Problem 3.56.
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Figure 3.54 Planes in a hexagonal lattice for
Problem 3.57.
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Figure 3.55 Planes in a hexagonal lattice for
Problem 3.58.
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Figure 3.56 XRD pattern for Problem 3.107.
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Figure 3.57 XRD pattern for Problem 3.108.