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Third Law of Thermodynamics

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Title: Third Law of Thermodynamics


1
Third Law of Thermodynamics
  • If increasing temperature increases entropy, then
    the opposite should be true also.
  • Is it possible to decrease the temperature to the
    point that the entropy is zero?
  • At what T does S 0?
  • If entropy is zero, what does that mean?

2
Third Law of Thermodynamics
  • 3rd Law of Thermodynamics
  • Entropy of a perfect crystalline substance at 0 K
    is zero
  • No entropy highest order possible
  • Purpose of 3rd Law
  • Allows S to be measured for substances
  • S 0 at 0 K
  • S? standard molar entropy
  • The entropy of the pure substance is our zero
    (reference point)

3
What is a Perfect Crystal?
Perfect crystal at 0 K
Crystal deforms at T gt 0 K
4
Third Law of Thermodynamics
  • The entropy of a pure crystalline substance at
    absolute zero is 0.

5
Third Law of Thermodynamics
  • The entropy of a pure crystalline substance at
    absolute zero is 0. This allows us to calculate
    an absolute entropy.

6
Measuring Heat and Enthalpies
Constant-Volume Calorimetry
qsys qwater qbomb qrxn
qsys 0
qrxn - (qwater qbomb)
qwater msDT
qbomb CbombDT
Reaction at Constant V
DH qrxn
No heat enters or leaves!
Why only approximately the enthalpy?
7
Constant-Pressure Calorimetry
qsys qwater qcal qrxn
qsys 0
qrxn - (qwater qcal)
qwater msDt
qcal CcalDt
Reaction at Constant P
DH qrxn
No heat enters or leaves!
6.5
8
Thermochemistry
The study of heat transfer due to chemical
reactions and phase changes
qreaction qcalorimeter 0
qreaction - qcalorimeter - Ccalorimeter DT
For 18 gm C(gr) or equivalently nC 18/121.5
moles DHc 1.5(-393.5) kJ
9
Energy is a State Function if and only if DUa
DUb
  • Assume the contrary and take DUa gt DUb .
  • Go forward on a (gaining Ua) and backward along b
    (lossing -DUb)
  • During each cycle there is a net gain in energy
    (DUa - DUb ) gt 0, available to do work and no
    change in the system.
  • We could repeat this and gain energy from doing
    nothing.
  • Nothing is Free so its not possible.
  • Not possible, therefore, DUa DUb. Energy is
    conserved.
  • Energy is a state function
  • So is Enthalpy (same arguments apply), (Entropy,
    etc)

10
Thermochemistry Hesss Law
DHa DHb Hf - Hi
DH1 DH2 HCD - HAB HEF - HCD DH3
If 2 (or more reactions) are added (or
subtracted) to get a new reaction, then adding
(or subtracting) enthalpy changes for the two
reactions gives enthalpy change for the new
reaction. Hesss law takes advantage of the fact
that Enthalpy is a state function.
11
Examples of Hesss Law
When carbon burns it creates mainly carbon
dioxide and water. What is the enthalpy of
combining Carbon with Oxygen to make Carbon
Monoxide?
DH3 DH1 DH2 -393.5 kJ/mol DH1 -283.0 kJ/mol
DH1 283.0 kJ/mol -393.5 kJ/mol -110.5
kJ/mol
12
Another Example of Hesss Law
13
Latent Heat in Phase Changes
H2O(liq) H2O(gas)
DHvap 40.66 kJ/mol
Phase changes are accompanied by latent heat. Can
add heat but temp doesnt rise until all one
phase.
14
What happens to diamonds in a house fire?
15
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16
Enthalpy of Formation (defining a zero point)
DHo standard enthalpy change for reaction
when reactants and products are in their
standard states
Standard state of compound X is the most stable
form of X at P1 atm and T298.15 K.
DHof standard enthalpy of formation of a
compound.
DHof DH of reaction in which pure elements in
standard states combine to form products in std
states.
17
Examples of Enthalpy of Formation
18
Standard heats of reaction from DHof
DH298o c DHfo(C) dDHfo(D) - a DHfo(A) -
bDHfo(B)
19
Examples using Heats of Formation
DH298o 3 DHfo(H2O) 2 DHfo(CO2) - DHfo(C2H2OH)
20
Bond Enthalpies
In reactions bonds are broken and bonds are
formed, eg C--H
Define average bond strengths C-C
DHC-C 348 kJ
CC DHCC 615 kJ

C-H DHC-C 413 kJ
21
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22
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23
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24
Practical uses surroundings system
25
Condition of Spontaneity
Make this equation nicer
26
Third Law of ThemodynamicsNernst Heat Theorem
  • In any thermodynamic process involving only pure
    phases in their equilibrium states, the entropy
    change

The entropy of any element in equil state is
defined to approach 0 as T approaches 0K. This is
the reference state (sea level) for Entropy.
?S---gt0 as T---gt 0K for chem reaction where pure
elements ---gt pure compounds.
Entropy of any pure substance (element or
compound) in its equil state ---gt0 as T--gt0
27
Measuring Heat and Enthalpies
Hot metal (373K) put in cool water (283K). What
is Tf?
Heat absorbed by water
Hot Metal
28
Mechanical Equivalence of Heat
1 calorie 4.184 Joules
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