Cyclooctatetraene - PowerPoint PPT Presentation

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Cyclooctatetraene

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Cyclooctatetraene Cyclooctatetraene has four double bonds, reacting with Br2, KMnO4, and HCl as if it were four alkenes. Does NOT have delocalized double bonds. – PowerPoint PPT presentation

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Title: Cyclooctatetraene


1
Cyclooctatetraene
Cyclooctatetraene has four double bonds,
reacting with Br2, KMnO4, and HCl as if it were
four alkenes. Does NOT have delocalized double
bonds.
This is not a planarmolecule with
continuousoverlap of p orbitals.
Tub-shaped
2
15.6 Aromatic Ions
  • The 4n 2 rule applies to ions as well as
    neutral species
  • Both the cyclopentadienyl anion and the
    cycloheptatrienyl cation are aromatic
  • The key feature of both is that they contain 6 ?
    electrons in a continuous cyclic array of p
    orbitals

3
Cycloheptatriene
  • Cycloheptatriene has 3 conjugated double bonds
    joined by a CH2. Removal of H- leaves the
    cation.
  • The ring of the cation has a continuous array of
    seven p orbitals containing 6 pi electrons and is
    therefore aromatic


remove H-
4
Aromaticity of the Cyclopentadienyl Anion
  • 1,3-Cyclopentadiene contains conjugated double
    bonds joined by a CH2 that blocks delocalization
  • Removal of H at the CH2 produces a cyclic
    6-electron system, which is stable
  • Removal of H- or H generate nonaromatic 4 and 5
    electron systems
  • Relatively acidic (pKa 16) because the anion is
    stable

5
15.8 Why 4n 2?
  • When electrons fill the various molecular
    orbitals, it takes two electrons (one pair) to
    fill the lowest-lying orbital and four electrons
    (two pairs) to fill each of n succeeding energy
    level
  • This is a total of 4n 2 electrons(note that
    the number of p orbitals is not important)

6
15.8 Why 4n 2?
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