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Using Computational Chemistry to Study a Reaction Pathway

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Determine the energies of the reactants, intermediates, ... Vary dihedral angles. Lining Up the Reactants* HF / 6-31 G(d) R = 3 Angstroms. E = -648.6805142 H ... – PowerPoint PPT presentation

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Title: Using Computational Chemistry to Study a Reaction Pathway


1
Using Computational Chemistry to Study a Reaction
Pathway
  • Jessica L. Case
  • Super Chem II
  • April 30, 2002

2
Goals of the Project
  • Utilize Gaussian 98 and WebMO for various
    computational calculations
  • Geometry Optimizations
  • Frequency Calculations
  • Transition State Determination
  • IRC Calculations to find Intermediate Structures
  • Determine the energies of the reactants,
    intermediates, transition state, and product
  • Use these methods to determine a reaction pathway
  • Draw a calculated reaction coordinate diagram

3
Reaction Under Study
  • Why this reaction?
  • Studied it last summer as a possible monomer unit
    to form ladder polymers

4
Geometry Optimization2-methoxyfuran
Method Basis Set Energy (H) Energy (kcal/mol)
AM1 3-21G -0.055206032 -34.64230929
AM1 6-31G(d) -0.055206032 -34.64230929
AM1 6-311G(d,p) -0.055206032 -34.64230929
HF 3-21G -340.6059668 -2.13734105
HF 6-31G(d) -342.5083676 -2.14927105
HF 6-311G(d,p) -342.5987805 -2.14984105
B3LYP 3-21G -342.6481147 -2.15015105
B3LYP 6-31G(d) -344.5377379 -2.14945105
5
Geometry Optimizationcyclobutylbenzyne
Method Basis Set Energy (H) Energy (kcal/mol)
AM1 3-21G 0.273878653 171.8614568
AM1 6-31G(d) 0.273878653 171.8614568
AM1 6-311G(d,p) 0.273878653 171.8614568
HF 3-21G -304.5375532 -1.91100105
HF 6-31G(d) -306.2532483 -1.92177105
HF 6-311G(d,p) -306.3209326 -1.92219105
B3LYP 3-21G -306.5968457 -1.92393105
B3LYP 6-31G(d) -308.2918719 -1.93456105
6
Geometry Optimizationproduct
Method Basis Set Energy (H) Energy (kcal/mol)
AM1 3-21G 0.171341699 107.5185441
AM1 6-31G(d) 0.171341699 107.5185441
AM1 6-311G(d,p) 0.171341699 107.5185441
HF 3-21G -645.1633345 -4.04846105
HF 6-31G(d) -648.7899777 -4.07122105
B3LYP 3-21G -649.2513117 -4.07412105
B3LYP 6-31G(d) -652.8390400 -4.09663105
7
Frequency Calculations
Molecule Method Basis Set ZPE (H)
2-MF HF 3-21G 0.108346
2-MF HF 6-31G(d) 0.108148
2-MF B3LYP 6-31G(d) 0.101644
CBB HF 3-21G 0.116369
CBB HF 6-31G(d) 0.115783
CBB B3LYP 6-31G(d) 0.109457
Product HF 3-21G 0.230598
Product HF 6-31G(d) 0.230935
Product B3LYP 6-31G(d) 0.215880
8
Locating the Transition State
  • First, combine the numbering of the atoms in the
    two reactant structures
  • Second, combine the Z-matrices of the two
    geometry optimized reactants
  • Third, determine the approximate approach of the
    two molecules will take to react together to form
    the product
  • Vary distance between reactants
  • Vary intermolecular angles
  • Vary dihedral angles

9
Lining Up the ReactantsHF / 6-31G(d)
  • R 3 Angstroms
  • E -648.6805142 H
  • R 10 Angstroms
  • E -648.7616681 H
  • R 20 Angstroms
  • E -648.7615803 H
  • R 80 Angstroms
  • E -648.7615669 H
  • 2-methoxyfuran
  • E -342.5083676 H
  • cyclobutylbenzyne
  • E -306.2532483 H
  • sum of reactants
  • E -648.7616159 H

10
Determining the Transition State Structure
  • Use the combined Z-matrix of the two reactants
    and the Z-matrix of the product as input
  • The STQN method locates a transition structure
    with the QST2 keyword
  • Utilizes the input structures to determine a
    structure of maximum energy in between the
    reactants and products structures

11
The Transition State
  • Two different inputs yielded very similar
    structures
  • E1 -648.752134712 H -4.07098452053105
    kcal/mol
  • E2 -648.752134717 H -4.07098452056105
    kcal/mol
  • The transition state occurred at R 2.999
    Angstroms
  • Frequency calculations yielded a zero point
    energy of 0.229644 H and one negative vibrational
    mode, which is expected for a transition state
    structure

12
Locating the Intermediates
  • IRC Calculations
  • Takes the calculated structure and force field
    from the optimized transition state and
    determines intermediate structures along the
    reaction path
  • Varied the number of steps away from the
    transition state
  • 2 steps E -648.7522613 H
  • 10 steps E -648.7555564 H
  • 40 steps E -648.7571191 H

13
The Intermediate Structures
14
Reaction Coordinate Diagram
15
And with that, my academic career at Hope College
is complete!!!
Booyah!
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