Title: MRAM (Magnetic random access memory)
1MRAM (Magnetic random access memory)
2Outline
- Motivation introduction to MRAM.
- Switching of small magnetic structures a highly
nonlinear problem with large mesoscopic
fluctuations. - Current theoretical approaches.
- Problems write reliability issues.
3An array of magnetic elements
4Schematic MRAM
5Write Two perpendicular wires generate magnetic
felds Hx and Hy
- Bit is set only if both Hx and Hy are present.
- For other bits addressed by only one line, either
Hx or Hy is zero. These bits will not be turned
on.
6Coherent rotation Picture
- The switching boundaries are given by the line
AC, for example, a field at X within the triangle
ABC can write the bit. - If Hx0 or Hy0, the bit will not be turned on.
B
A
X
Hy
C
Hx
7Read Tunnelling magneto resistance between
ferromagnets
- Miyazaki et al, Moodera et al.
- room temperature magneto resiatance is about 30
- Fixed the magnetization on one side, the
resistance is different between the AP and P
configurations - large resistance 100 ohm for 10(-4) cm2, may
save power
8Switching of magnetization of small structures
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13Understanding the basic physics different
approaches
14Semi-analytic approaches
- Solition solutions
- Conformal Mapping
15Edge domain Simulation vs Analytic approximation.
- ?tan-1 sinh(?v(y-y0))/(- v
sinh(?(x-x0))), - yy/l, xx/l the magnetic length lJ/2K0.5
?1/1v20.5 v is a parameter.
16Closure domain Simulation vs analytic
approximation
- ?tan-1A tn(? x', ?f) cn(v 1kg20.5y', k1g)/
dn(v 1kg20.5 y', k1g), - kg2A2?2(1-A2)/?2(1-A2)2-1,
- k1g2A2?2(1-A2)/(?2(1-A2)-1),
- ?f2A2?2(1-A2)2/?2(1-A2)
- v2?2(1-A2)2-1/1-A2.
- The parameters A and ? can be determined by
requiring that the component of S normal to the
surface boundary be zero
17Conformal mapping
18From circle to square Spins parallel to
boundaries
19Navier Stokes equation (Yau)
20Numerical methods
- Numerical studies can be carried out by either
solving the Landau-Gilbert equation numerically
or by Monte Carlo simulation.
21Landau-Gilbert equation
- (1?2)dmi/d?hieff?mi?(mi?(mi?hieff))
- i is a spin label,
- hieffHieff/Ms is the total reduced effective
field from all source - miMi/Ms, Ms is the saturation magnetization
- ? is a damping constant.
- ?t???Ms is the reduced time with ? the
gyromagnetic ratio. - The total reduced effective field for each spin
is composed of the exchange, demagnetization and
anisotropy field Hieffhiexhidemghiani .
22Approximate results
- EEexchEdipEanis.
- Between neighboring spins EdipltltEexch.
- The effect of Edip is to make the spins lie in
the plane and parallel to the boundaries. - Subject to these boundary conditions, we only
need to optimize the sum of the exchange and the
anisotropy energies.
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24Reliability problem of switching of magnetic
random access memory (MRAM)
25Fluctuation of the switching field
26Two perpendicular wires generate magnetic felds
Hx and Hy
- Bit is set only if both Hx and Hy are present.
- For other bits addressed by only one line, either
Hx or Hy is zero. These bits will not be turned
on.
27Coherent rotation Picture
- The switching boundaries are given by the line
AC, for example, a field at X within the triangle
ABC can write the bit. - If Hx0 or Hy0, the bit will not be turned on.
B
A
X
Hy
C
Hx
28Experimental hysteresis curve
- J. Shi and S. Tehrani, APL 77, 1692 (2000).
- For large Hy, the hysteresis curve still exhibits
nonzero magnetization at Hcx (Hy0).
29Edge pinned domain proposed
30Hysteresis curves from computer simulations can
also exhibit similar behaviour
- For nonzero Hy switching can be a two step
process. The bit is completely switched only for
a sufficiently large Hx.
O
E
S
31- For finite Hy, curves with large Hsx are usually
associated with an intermediate state.
32Bit selectivity problem Very small (green)
writable area
- Different curves are for different bits with
different randomness. - Cannot write a bit with 100 per cent confidence.
33Another way recently proposed by the Motorola
group Spin flop switching
- Two layers antiferromagnetically coupled.
34- Memory in the green area.
- Read is with TMR with the magnet in the grey
area, the same as before. - Write is with two perpendicular wires (bottom
figure) but time dependent.
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36Simple picture from the coherent rotation model
- M1, M2 are the magnetizations of the two
bilayers. - The external magnetic fields are applied at -135
degree, then 180 degree then 135 degree.
37Switching boundaries
- Paper presented at the MMM meeting, 2003 by the
Motorola group.
38This solves the bit selectivity but the field
required is too big
39Stronger field, -135 Note the edge-pinned domain
for the top layer
H
40Very similar to the edge pinned domain for the
monlayer case.
41- Switching scenario involves edge pinned domain,
similar to the monolayer case and very different
from the coherent rotation picture.
42Coercive field dependence on interlayer exchange
- For the top curve, a whole line of bits is
written. - For real systems, there are fluctuations in the
switching field, indicated by the colour lines.
If these overlap, then bits can be accidentally
written.
43Bit selectivity vs interlayer coupling Magnitude
of the switching field
44Temperature dependence
- Hc (bilayer) gtgtHc (single layer). Hc (bilayer)
exhibits a stronger temperature dependence than
the monolayer case, different from the prediction
of the coherent rotation picture. - Usually requires large current.
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46Simple Physics in micromagnetics
- Alignment of neighboring spins is determined by
the exchange, since it is much bigger than the
other energies such as the dipolar interaction
and the intrinsic anisotropy.
47Energy between spins
- H0.5 ?ijxyz,RR Vij(R-R)Si(R)Sj(R) ,
- VVdVeVa
- The dipolar energy Vdij(R)g?i?j (1/R)
- The exchange energy Ve-J? (RRd)?ij d denotes
the nearest neighbors - Va is the crystalline anisotropy energy. It can
be uniaxial or four-fold symmetric, with the easy
or hard axis aligned along specific directions.
48Optimizing the energy
- Eexch-A? dr (? S)2.
- Eani-K ? dr Sz2.
- Let S lie in the xz plane at an angle ?.
- Eexch-AS2? dr (? ?)2.
- ? (EexchEani)/? ? AS2?2 ?-K sin ?0.
- ?2?x2-?iy2.
- This is the imaginary time sine Gordon equation
and can be exactly solved.
49Dipolar interaction
- The dipolar interaction Edipo?i,j
MiaMjb?a,b/R3-3Rij,aRij,b/Rij5 - Edipo?i,j MiaMjb?ia?jb(1/Ri-Rj).
- Edipos r M( R) r M(R)/R-R
- If the magnetic charge qM-r M is small Edipo
is small. The spins are parallel to the edges so
that qM is small.
50Two dimension
- A spin is characterized by two angles ? and ?. In
2D, they usually lie in the plane in order to
minimize the dipolar interaction. Thus it can be
characterized by a single variable ?. - The configurations are then obtained as solutions
of the imaginary time Sine-Gordon equation
r2?(K/J) sin?0 with the parallel edge
boundary condition.