Title: IB Topic 9: Oxidation and Reduction 9'1 Introduction to oxidation and reduction
1IB Topic 9 Oxidation and Reduction9.1
Introduction to oxidation and reduction
- 9.1.1 Define oxidation and reduction in terms of
electron loss and gain. - 9.1.2 Deduce the oxidation number of an element
in a compound. - 9.1.3 State the names of compounds using
oxidation numbers. - 9.1.4 Deduce whether an element undergoes
oxidation or reduction in reactions using
oxidation numbers.
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29.1.1 Define oxidation and reduction in terms of
electron loss and gain.
- Many important chemical reactions involve a
transfer of electrons - Mg(s) 2H(aq)? Mg2(aq) H2(g)
- In this reaction, the Mg will _________________
electrons to become Mg 2 - In this reaction, the 2H will _________________
electrons to become H2
2
39.1.1 Define oxidation and reduction in terms of
electron loss and gain.
- Oxidation a loss of electrons
- Reduction a gain of electrons
- LEO goes GER
- Mg(s) 2H(aq)? Mg2(aq) H2(g)
- Which substance is being oxidized?
- _________
- Which substance is being reduced?
- _________
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4You cant have one without the other!
- Reduction (gaining electrons) cant happen
without an oxidation to provide the electrons. - You cant have 2 oxidations or 2 reductions in
the same equation. Reduction has to occur at the
cost of oxidation
LEO the lion says GER!
ose
lectrons
xidation
ain
lectrons
eduction
GER!
59.1.2 Deduce the oxidation number of an element
in a compound.
- All elements in a compound (even covalent
compounds) can be assigned oxidation numbers. It
is a convenient form of bookkeeping and will
assist in balancing complex equations. - Rules for assigning oxidation numbers (o.n)
- For any atom in its elemental form, the o.n. is
0. - Mg, S, H2, Cl2, P4 all are 0
- For any monatomic ion, the o.n. equals the charge
on the ion. - Mg2 is 2 Cl- is -1
- The o.n. of oxygen is usually -2 (except
peroxides, -1) - The o.n. of hydrogen is 1 when bonded to a
nonmetal and -1 when bonded to a metal. - The o.n of F- is -1. The o.n. of the other
halogens is -1 except when combined with oxygen. - The sum of the o.n. of all atoms in a neutral
compound is zero. - The sum of the o.n. in a polyatomic ion equals
the charge on the ion. -
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69.1.2 Deduce the oxidation number of an element
in a compound.
- Determine the oxidation number (state) of each
element in the following compounds. - H2S H is 1 (rule 4) S is -2 (rule 2)
- S8 S is 0 (rule 1)
- SCl2 Cl is -1 (rule 5) S is 2 (rule 6)
- Na2SO3 Na is 1 (rule 2) O is -2 (rule 3)
- S is 4 (rule 6)
- SO42- O is -2 (rule 3) S is 6 (rule 7)
- H2O2 H is 1 (rule 4) O is -1 (rule 3-peroxide)
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79.1.2 Deduce the oxidation number of an element
in a compound.
- Determine the oxidation number (state) of each
element in the following compounds. - P2O5 P is _____ O is _____
- NaH Na is _____ H is _____
- Cr2O7-2 Cr is_____ O is _____
- SnBr4 Sn is_____ Br is_____
- HClO4 H is _____ Cl is _____ O is _____
- NO2- N is _____ O is _____
- N2 N is _____
- Ca(NO3)2 Ca is _____ N is _____ O is _____
- BaO2 Ba is _____ O is _____
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89.1.3 State the names of compounds using
oxidation numbers.
- Many metals can have more than one oxidation
number. - Exceptions are alkali metals (all 1), alkaline
earth metals (all 2), zinc (2), aluminum (3)
silver (1). - These are identified using Roman numerals to
denote the charge. - Iron(II) is Fe2 (ferrous) Iron(III) is Fe3
(ferric) - Copper(I) is Cu1 Copper(II) is Cu2
- Name the following compounds using oxidation
numbers. - SnCl4 _________________________________
- Cr(NO3)3 _________________________________
- KOH _________________________________
- PbSO4 _________________________________
- CuBr _________________________________
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99.1.3 State the names of compounds using
oxidation numbers.
- Binary covalent compounds can also be named using
Roman numerals but most use prefixes. - CO Carbon (II) oxide or carbon monoxide
- CO2 Carbon (IV) oxide or carbon dioxide
- PCl3 Phosphorus (III) chloride or phosphorus
trichloride - Name the following compounds using oxidation
numbers. What are their common names? - SO3 _________________________________________
- PCl5 _________________________________________
- N2O _________________________________________
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109.1.4 Deduce whether an element undergoes
oxidation or reduction in reactions using
oxidation numbers.
- Deduce what is being oxidized and what is being
reduced in - Mg(s) 2HCl(aq) ? MgCl2(aq) H2(g)
- Assign oxidation numbers to both reactants and
products - Mg 2HCl ? MgCl2 H2
- Mg0 H1 Cl-1 ? Mg2 Cl-1 H0
- Which species increased in o.n.? That is the one
being oxidized (losing electrons) - Mg is going from 0 to 2 so is oxidized
- Which species decreased in o.n.? That is the one
being reduced (gaining electrons) - H is going from 1 to 0 so is reduced
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119.1.4 Deduce whether an element undergoes
oxidation or reduction in reactions using
oxidation numbers.
- Deduce what is being oxidized and what is being
reduced in - Cu(s) 2AgNO3(aq) ? Cu(NO3)2(aq) 2Ag(s)
- Assign oxidation numbers to both reactants and
products - Cu 2AgNO3 ? Cu(NO3)2 2Ag
- Cu0 Ag1 N5 O-2 ? Cu2 N5 O2 Ag0
- Which species increased in o.n.? That is the one
being oxidized (losing electrons) - Cu is going from 0 to 2 so is oxidized
- Which species decreased in o.n.? That is the one
being reduced (gaining electrons) - Ag is going from 1 to 0 so is reduced
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129.1.4 Deduce whether an element undergoes
oxidation or reduction in reactions using
oxidation numbers.
- Deduce what is being oxidized and what is being
reduced in - I2O5(s) 5CO(g) ? I2(s) 5CO2(g)
- Assign oxidation numbers to both reactants and
products - I2O5(s) 5CO(g) ? I2(s) 5CO2(g)
- I__ O__ C__ O__? I__ C__ O__
- Which species increased in o.n.? That is the one
being oxidized (losing electrons) - Which species decreased in o.n.? That is the one
being reduced (gaining electrons)
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139.1.4 Deduce whether an element undergoes
oxidation or reduction in reactions using
oxidation numbers.
- Deduce what is being oxidized and what is being
reduced in - 2Hg2(aq) N2H4(aq) ? 2Hg(l) ? N2(g)
4H(aq) - Deduce what is being oxidized and what is being
reduced in - Cl2(g) H2O(l) ? HCl(aq) HClO(aq)
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14IB Topic 9 Oxidation and Reduction9.2 Redox
equations
- 9.2.1 Deduce simple oxidation and reduction
half-equations given the species involved in a
redox reaction. - 9.2.2 Deduce redox equations using
half-reactions. - 9.2.3 Define the terms oxidizing agent and
reducing agent. - 9.2.4 Identify the oxidizing and reducing agents
in redox equations.
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159.2.1 Deduce simple oxidation and reduction
half-equations given the species involved in a
redox reaction.
- Consider the reaction when copper metal is placed
in a solution of silver ions. - Half-reactions
- Copper metal loses 2 electrons Cu ? Cu2
2e- - Silver ion gains 1 electron Ag e- ? Ag
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169.2.1 Deduce simple oxidation and reduction
half-equations given the species involved in a
redox reaction.
- The of e- ____ has to equal the of e-
_________ - The silver half-reaction has to be multiplied by
2 - Cu ? Cu2 2e-
- 2Ag 2e- ? 2Ag
- Overall
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179.2.1 Deduce simple oxidation and reduction
half-equations given the species involved in a
redox reaction.
- Consider the reaction when iodide ions are added
to chlorine water. - Which is more reactive, chlorine or
iodine?__________ - Since they are nonmetals will the more reactive
species gain or lose electrons? _________
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189.2.1 Deduce simple oxidation and reduction
half-equations given the species involved in a
redox reaction.
- Consider the reaction when iodide ions are added
to chlorine water. - Half-reactions
- 2I- ? I2 2e-
- Cl2 2e- ? 2Cl-
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199.2.1 Deduce simple oxidation and reduction
half-equations given the species involved in a
redox reaction.
- Since electrons lost electrons gained, the
overall reaction is
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209.2.2 Deduce redox equations using half-reactions.
- Balancing more complex red-ox reactions using
half-reactions - Write the unbalanced equation in ionic form.
- Write separate half-reactions for the oxidation
and reduction processes, adding the appropriate
electrons. - Balance the half-reactions. You may add H2O and
H to balance oxygen and hydrogen as needed. - Multiply each half-reaction by an appropriate
number to make the number of electrons equal in
both. - Add the half-reactions to show an overall
equation. - Add the spectator ions and balance the equation.
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219.2.2 Deduce redox equations using half-reactions.
- S(s) HNO3(aq) ? SO2(g) NO(g) H2O(l)
- Write the unbalanced equation in ionic form.
- Write separate half-reactions for the oxidation
and reduction processes, adding the appropriate
electrons.
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229.2.2 Deduce redox equations using half-reactions.
- S(s) HNO3(aq) ? SO2(g) NO(g) H2O(l)
- 3) Balance the half-reactions. You may add H2O
and H to balance oxygen and hydrogen as needed. - 4) Multiply each half-reaction by an appropriate
number to make the number of electrons equal in
both.
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239.2.2 Deduce redox equations using half-reactions.
- S(s) HNO3(aq) ? SO2(g) NO(g) H2O(l)
- 5) Add the half-reactions to show an overall
equation. - 6) Add the spectator ions and balance the
equation.
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249.2.2 Deduce redox equations using half-reactions.
- Cr2O72-(aq) Cl-(aq) H(aq) ? Cr3(aq)
Cl2(g) H2O(l) - Write the unbalanced equation in ionic form.
- Write separate half-reactions for the oxidation
and reduction processes, adding the appropriate
electrons. - Balance the half-reactions. You may add H2O and
H to balance oxygen and hydrogen as needed. - Multiply each half-reaction by an appropriate
number to make the number of electrons equal in
both. - Add the half-reactions to show an overall
equation. - 6) Add the spectator ions and balance the
equation.
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259.2.2 Deduce redox equations using half-reactions.
- Cu(s) NO3-(aq) H(aq)? Cu2(aq) NO2(g)
H2O(l) - Write the unbalanced equation in ionic form.
- Write separate half-reactions for the oxidation
and reduction processes, adding the appropriate
electrons. - Balance the half-reactions. You may add H2O and
H to balance oxygen and hydrogen as needed. - Multiply each half-reaction by an appropriate
number to make the number of electrons equal in
both. - Add the half-reactions to show an overall
equation. - 6) Add the spectator ions and balance the
equation.
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269.2.3 Define the terms oxidizing agent and
reducing agent.
- Oxidizing Agent (oxidant)
- Substances that are able to oxidize other
substances - They are themselves reduced
- Substances that readily gain electrons
- Reducing Agent (reductant)
- Substances that are able to reduce other
substances - They are themselves oxidized
- Substances that readily lose electrons
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279.2.4 Identify the oxidizing and reducing agents
in redox equations.
- Consider the following reactions
- 1) S(s) HNO3(aq) ? SO2(g) NO(g) H2O(l)
- 2) Cr2O72-(aq) Cl-(aq) H(aq) ? Cr3(aq)
Cl2(g) H2O(l) - 3) Cu(s) NO3-(aq) H(aq)? Cu2(aq) NO2(g)
H2O(l) - For each reaction, state the oxidizing agent and
the reducing agent
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289.2.4 Identify the oxidizing and reducing agents
in redox equations.
- Consider the following reaction
- Cd(s) NiO2(s) H2O(l) ? Cd2(aq) Ni2(aq)
OH-(aq) - 1. What is the oxidizing agent?
- 2. What is the reducing agent?
- 3. Balance the equation
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29IB Topic 9 Oxidation and Reduction9.3 Reactivity
- 9.3.1 Deduce a reactivity series based on the
chemical behavior of a group of oxidizing and
reducing agents. - 9.3.2 Deduce the feasibility of a redox reaction
from a given reactivity series.
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309.3.1 Deduce a reactivity series based on the
chemical behavior of a group of oxidizing and
reducing agents.
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319.3.1 Deduce a reactivity series based on the
chemical behavior of a group of oxidizing and
reducing agents.
- Activity Series of Metals
- Metals at the top of the chart are easily
oxidized. - Metals at the top of the chart are most reactive.
- Metals above hydrogen react with acids.
- Metals will react with ions of metals below them.
- Metals at the top of the chart are good reducing
agents. - Ions of metals at the bottom of the chart are
good oxidizing agents. - Copper does react with nitric acid but the
nitrogen in HNO3 is reduced, not the H as in
other acid-base reactions. Balance the following
and identify the o.a. r.a. -
- Cu HNO3 ? Cu(NO3)2 NO2 H2O
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329.3.1 Deduce a reactivity series based on the
chemical behavior of a group of oxidizing and
reducing agents.
- Activity Series of Halogens
- F2 2e- ? 2F- Decreasing
- Cl2 2e- ? 2Cl- Reactivity
- Br2 2e- ? 2Br-
- I2 2e- ? 2I-
- Halogens at the top of the chart are easily
reduced. - Halogens at the top of the chart are most
reactive. - Halogens will react with ions of halogens below
them. - Halogens at the top of the chart are good
oxidizing agents.
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339.3.2 Deduce the feasibility of a redox reaction
from a given reactivity series.
- Will an aqueous solution of iron(II) chloride
oxidize magnesium metal? If so, write the redox
equation. - Because Mg is above Fe2 in the activity series,
we predict the reaction will occur - Mg(s) Fe2(aq) ? Mg2(aq) Fe(s)
- Will bromine water, Br2(aq) displace Cl- in a
solution of NaCl? If so, write the redox
reaction. - The reaction will not occur since Cl is above Br
in the activity series.
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349.3.2 Deduce the feasibility of a redox reaction
from a given reactivity series.
- Which of the following metals will be oxidized by
Pb(NO3)2 Zn, Cu, Fe? Write any redox reaction
that occurs. - Predict whether a reaction occurs when the
following reagents are mixed Cl2(aq) and KI(aq)
Br2(aq) and LiCl(aq). Write any redox reaction
that occurs. - Write balanced chemical equations for the
following reactions. If no reaction occurs,
simply write NR - Zinc metal is added to a solution of silver
nitrate - Iron metal is added to a solution of aluminum
sulfate - Hydrochloric acid is added to cobalt metal
- Hydrogen gas is bubbled through a solution of
iron(II) chloride - Fluorine gas is bubbled through a solution of
sodium iodide - Balance the following redox reaction. Identify
the oxid red agents - Zn H NO3- ? Zn2 N2O H2O
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35IB Topic 9 Oxidation and Reduction9.4 Voltaic
cells
- 9.4.1 Explain how a redox reaction is used to
produce electricity in a voltaic cell. - 9.4.2 State that oxidation occurs at the negative
electrode (anode) and reduction occurs at the
positive electrode (cathode).
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369.4.1 Explain how a redox reaction is used to
produce electricity in a voltaic cell.
- A strip of zinc is placed in a copper solution.
- Write the oxidation reaction
- Write the reduction reaction
- Write the overall reaction
- Describe two observable changes
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379.4.1 Explain how a redox reaction is used to
produce electricity in a voltaic cell.
- This reaction can be used to perform electrical
work by using a voltaic (galvanic) cell. - The transfer of electrons takes place through an
external pathway. - Metal strips are placed in solutions of their
ions. The metal strips are connected by a wire
for flow of electrons. - The solutions are connected by a salt bridge or
separated by a porous glass barrier. This
maintains electrical neutrality. - Electrons flow from the anode to the cathode.
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389.4.2 State that oxidation occurs at the negative
electrode (anode) and reduction occurs at the
positive electrode (cathode).
- At the Zn electrode (anode)
- Oxidation occurs
- Negative electrode
- Electrons are produced and flow through the
external circuit toward the cathode - Zn2 ions produced and migrate away from the
electrode - Negative ions (anions) from the salt bridge
migrate into the solution to balance the increase
in positive charges.
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399.4.2 State that oxidation occurs at the negative
electrode (anode) and reduction occurs at the
positive electrode (cathode).
- At the Cu electrode (cathode)
- Reduction occurs
- Positive electrode
- Electrons come from the anode and move into the
electrode - Cu2 ions migrate to the electrode and gain
electrons producing Cu - Positive ions (cations) from the salt bridge
migrate into the solution to balance the decrease
in positive charges.
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409.4.2 State that oxidation occurs at the negative
electrode (anode) and reduction occurs at the
positive electrode (cathode).
- A voltaic cell similar to that shown in slide 38
is constructed. One electrode compartment
consists of a cadmium strip placed in a solution
of Cd(NO3)2 and the other has a nickel strip
placed in a solution of NiSO4. Cadmium is a more
reactive metal than nickel. - Write the half-reactions that occur in the two
electrode compartments. Write the overall
reaction. - Which electrode is the anode and which is the
cathode? - Indicate the signs of the electrodes.
- Which way do electrons flow?
- In which directions do the cations and anions
migrate through the solution?
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419.4.2 State that oxidation occurs at the negative
electrode (anode) and reduction occurs at the
positive electrode (cathode).
- A voltaic cell similar to that shown in slide 38
is constructed. One electrode compartment
consists of a silver strip placed in a solution
of AgNO3 and the other has a nickel strip placed
in a solution of NiSO4. Nickel is a more reactive
metal than silver. - Write the half-reactions that occur in the two
electrode compartments. Write the overall
reaction. - Which electrode is the anode and which is the
cathode? - Indicate the signs of the electrodes.
- Which way do electrons flow?
- In which directions do the cations and anions
migrate through the solution?
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42IB Topic 9 Oxidation and Reduction9.5
Electrolytic cells
- 9.5.1 Describe, using a diagram, the essential
components of an electrolytic cell. - 9.5.2 State that oxidation occurs at the positive
electrode (anode) and reduction occurs at the
negative electrode (cathode). - 9.5.3 Describe how current is conducted in an
electrolytic cell. - 9.5.4 Deduce the products of the electrolysis of
a molten salt.
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439.5.1 Describe, using a diagram, the essential
components of an electrolytic cell.
- In an electrolytic cell, electricity is supplied
from an external source and is used to make a
non-spontaneous reaction take place. - The substance that conducts electricity in the
cell is an electrolyte (substance containing
ions). - Electrolytes do not conduct when solid because
ions are not free to move and they have no
delocalized electrons. - Electrolytes do conduct when molten or dissolved
in water because the ions are free to move toward
opposite charged electrodes
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449.5.1 Describe, using a diagram, the essential
components of an electrolytic cell.
- The electrolyte conducts electricity by the
movement of ions within it. - Chemical reactions occur at each electrode so
that the electrolyte is decomposed in the
process. - 2NaCl(l) ? 2Na(l) Cl2(g)
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459.5.2 State that oxidation occurs at the positive
electrode (anode) and reduction occurs at the
negative electrode (cathode).
- Oxidation occurs at the positive electrode
(anode) because negative ions (anions) are
attracted to it, - 2Cl-(l) ? Cl2(g) 2e-
- Reduction occurs at the negative electrode
(cathode) because positive ions (cations) are
attracted to it. - Na e- ? Na(l)
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469.5.3 Describe how current is conducted in an
electrolytic cell.
- The electrochemical cell is a voltaic cell
producing electricity from a chemical reaction.
The anode produces electrons. - Electrons flow from the anode of the voltaic cell
to the cathode of the electrolytic cell. - Positive ions flow toward the cathode and gain
electrons (become reduced). - Negative ions flow toward the anode and lose
electrons (become oxidized). - Electrons flow from the anode of the electrolytic
cell to the cathode of the voltaic cell
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479.5.4 Deduce the products of the electrolysis of
a molten salt.
- Sketch a cell for the electrolysis of molten
MgBr2. - Indicate the directions in which ions and
electrons move. - Label the anode and cathode, indicating the
charge and the type of reaction occurring. - Give the electrode reactions.
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