Title: ACIDBASE SPECIATION CALCULATIONS
1ACID-BASE SPECIATION CALCULATIONS
2MONOPROTIC ACIDS
- What are the pH and concentrations of all species
in a 0.1 mol L-1 HF solution? - 1) Write out important species H, OH-, HF0, F-.
- 2) Write out all independent reactions and their
equilibrium constants - HF0 ? H F-
- H2O(l) ? H OH-
3- 3) Write out mass-balance expressions
- 0.1 mol L-1 ?F F- HF0
- 4) Write out the charge-balance expression
- H F- OH-
- 5) Make reasonable assumptions
- HF is an acid, so H gtgt OH- the
charge-balance becomes - H ? F- X
- and the mass-balance becomes
- HF0 0.1 - X
4- 6) Solve quadratic equation
a -1 b -10-3.2 -6.31x10-4 c 10-4.2
6.31x10-5
X1 -0.00825 X2 0.00765 H F-
7.65x10-3 mol L-1 pH -log H 2.12 HF0
0.1 - 0.00765 0.0924 mol L-1
5- 7) Check assumption 1.318x10-12 ltlt 7.65x10-3, so
OH- ltlt H. - What if we assumed HF0 gtgt F-, i.e., HF0 ?
0.1? This might be valid because HF is a weak
acid. - 10-3.2 X2/0.1
- X2 10-4.2
- X 10-2.1 0.00794
- H F- 7.94x10-3 mol L-1 pH 2.10
- HF0 0.1 - 0.00794 0.092 mol L-1
- The above answer is only 8 different from 0.1.
It seems in any case where KA lt 10-3.2, the above
assumption should be good!
6POLYPROTIC ACID
- What is the pH and concentration of all species
in a 0.1 mol L-1 solution of H3PO4? - 1) Species H, OH-, H3PO40, H2PO4-, HPO42-,
PO43- - 2) Mass action expressions
- H3PO40 ? H2PO4- H
- H2PO4- ? HPO42- H
- HPO42- ? PO43- H
7- H2O(l) ? H OH-
- 3) Mass-balance
- 0.1 mol L-1 H3PO40 H2PO4- HPO42-
PO43- - 4) Charge-balance
- H H2PO4- 2HPO42- 3PO43- OH-
- 5) Assumptions
- a) Because H3PO40 is an acid H gtgt OH-
- b) Because H2PO4- and HPO42- are very weak acids
and H3PO40 is only moderately weak - H3PO40 gt H2PO4- gtgt HPO42- gtgt PO43-
- so, 0.1 H3PO40 H2PO4-
- and H H2PO4- X.
8X1 0.0245 X2 -0.0324 H H2PO4-
0.0245 mol L-1 pH 1.61 H3PO40 0.1 - 0.0245
0.0755 mol L-1
So HPO42- 10-7.0 mol L-1
9- PO43- 10-17.79 1.62x10-18 mol L-1
- OH- 10-14/10-1.61 10-12.39 4.07x10-13 mol
L-1
10THE pH OF NORMAL RAINWATER
- The pH of normal, unpolluted rainwater is
controlled by carbonic acid equilibrium - CO2(g) ? CO2(aq) ? H2CO30
- What is the pH of rainwater in equilibrium with
atmospheric CO2 (PCO2 10-3.5 atm)? - 1) Species CO2(g), H2CO30, HCO3-, CO32-, H,
OH-. - 2) Mass action
- CO2(g) H2O(l) ? H2CO30
11- H2CO30? HCO3- H
- HCO3- ? CO32- H
- H2O(l) ? H OH-
- 3) Instead of a mass-balance we have PCO2
10-3.5 atm - 4) Charge balance
- H HCO3- 2CO32- OH-
- 5) Assumptions
- a) H2CO30 is an acid so H gtgt OH-
- b) HCO3- is a weak acid so HCO3- gtgt CO32-
- Therefore, H HCO3- X
12H2CO30 (10-1.5)(10-3.5) 10-5 mol L-1
X2 (10-6.3)(10-5.0) 10-11.3 X H
HCO3- 10-5.65 2.24x10-6 mol L-1 pH
5.65 So the pH of pure, normal rainwater is
acidic! Check assumption OH- 10-14/10-5.65
4.47x10-9 so H gtgt OH-
13pH OF RAIN ACIDIFIED WITH SO2
- The concentration of SO2 in the atmosphere is
usually less than that of CO2, but SO2 is more
soluble in water and forms a stronger acid. - What is the pH of a rain droplet in equilibrium
with an atmosphere with PSO2 5x10-9 atm? - We proceed as in previous example, but we assume
that the effect of CO2 can be neglected because
SO2 produces a stronger acid. - 1) Species SO2(g), H2SO30, HSO3-, SO32-, H, OH-
14- 2) Mass action
- SO2(g) H2O(l) ? H2SO30
- H2SO30 ? HSO3- H
- HSO3- ? SO32- H
- H2O(l) ? H OH-
- 3) Instead of mass-balance PSO2 5x10-9 atm
- 4) Charge-balance H HSO3- 2SO32-
OH-
15- 5) Assumptions
- a) Because H2SO30 is an acid H gtgt OH-
- b) HSO3- is a weak acid so HSO3- gtgt SO32-
- Therefore, H HSO3- X
- H2SO30 KHPSO2 2.0 x 5x10-9 10-8 mol L-1
- K1 2x10-2 X2/10-8
- X2 2x10-10
- X H HSO3- 1.414x10-5 mol L-1 pH
4.85 - OH- 10-14/10-4.85 7.07x10-10 mol L-1
- Note that only a very small amount of SO2 in the
atmosphere can result in significant
acidification of rain!
16EFFECT OF OXIDATION OF SO2
- What would the pH of a droplet of rain be if all
the SO2 in the atmosphere were oxidized to H2SO4? - Assume that 1 m3 of atmosphere contains 0.001 dm3
of liquid water and the temperature is 15C. - Because H2SO4 is a strong acid, we can assume
that it is totally dissociated. Thus, we can
solve this problem simply by calculating the
concentration of SO2 in moles L-1. - If PSO2 5x10-9 atm, then 1 m3 of atmosphere
contains 5x10-9 m3 of SO2. To convert to moles,
we must know how much volume a mole of gas
occupies at 15 C and 1 atm.
17USE IDEAL GAS LAW
- PV nRT
- P 1 atm n 1 mol R 0. 0820575 atm L
moles-1 K-1 T 288.15 K - V
- (1 mol)(0.0820575 atm L moles-1 K-1)(288.15 K)/1
atm - 23.65 L 23.65x103 cm3 (1 m/100 cm)3 0.02365
m3 - Thus, 1 m3 of air would contain 5x10-9/0.0237
2.11x10-7 moles of SO2. If all this SO2 is
oxidized and removed into a droplet of H2O of
volume 0.001 dm3, this would result in 2.11x10-4
mol L-1 of H2SO4. This yields 4.22x10-4 mol L-1
H or pH 3.37.
18URBAN ATMOSPHERE
- Primary pollutant a pollutant compound directly
released to the atmosphere (e.g., smoke, CO, CO2,
etc.). - Secondary pollutant a pollutant compound formed
as a product of chemical reactions in the
atmosphere.
19LONDON SMOGPRIMARY POLLUTION
- Urban air pollution was primarily the product of
combustion of fuels. - The rapid development of pollution coincided with
the transition to fossil fuel burning. - Normal, complete fuel combustion is described by
- 4CH 5O2(g) ? 4CO2(g) 2H2O(g)
- Neither CO2 nor H2O are particularly toxic.
However, during incomplete combustion we get CO - 4CH 3O2(g) ? 4CO(g) 2H2O(g)
20LONDON SMOG(CONTINUED)
- And also smoke particles
- 4CH O2(g) ? 4C(s) 2H2O(g)
- At low temperatures, we might also get PAHs
(polycyclic aromatic hydrocarbons) such as
benzo(?)pyrene, which are carcinogenic.
21LONDON SMOG(CONTINUED)
- Fuel contaminants may also be a problem
- 4FeS2(s) 11O2(g) ? 8SO2(g) 2Fe2O3(s)
- Sulfur is highest in coals and fuel oils.
- Smoke and SO2 are primary pollutants.
- SMOG combination of smoke and fog (water
droplets). - SO2(g) H2O(l) ? H HSO3-
- 2HSO3- O2(aq) ? 2H 2SO42-
- Fog droplets containing H2SO4 caused respiratory
diseases.
22LOS ANGELES SMOGSECONDARY POLLUTION
- Use of greater volatility liquid fuels in motor
vehicles caused a new type of air pollution. - The major pollutants are not themselves emitted
by motor vehicles, but are formed by reactions
involving primary pollutants. - Photochemical smog smog whose formation is
catalyzed by sunlight. - Fuel is burned in air, not pure O2, which has
important consequences.
23LOS ANGELES SMOG (CONTINUED)
- O(g) N2(g) ? NO(g) N(g)
- N(g) O2(g) ? NO(g) O(g)
- N2(g) O2(g) ? 2NO(g)
- Next, NO is oxidized in smog to give NO2(g) (see
Box 3.6 in Andrews for details). NO2 is a
brownish gas that absorbs light. - NO2(g) h? ? NO(g) O(g)
- O(g) O2(g) ? O3(g)
- Thus, ozone (a respiratory irritant) is produced
as a secondary pollutant.
24VOLATILE ORGANIC COMPOUNDS (VOCs)
- VOCs may also be released from fuel combustion.
- VOCs cause two problems
- They aid in NO2 production.
- CH4(g) 2O2(g) 2NO(g) h? ? H2O HCHO(g)
2NO2(g) - They lead to formation of aldehydes (eye
irritants and carcinogens) - PAN peroxyacetylnitrate - important eye irritant
in photochemical smog.
25LEADED VS. UNDLEADED GASOLINE
- Leaded gasoline contained tetraethyl lead -
Pb(C2H5)4 which resulted in Pb pollution of air,
soils and waters. - Some unleaded gasoline contains benzene, which is
a carcinogen and contributor to photochemical
SMOG. - Some gasoline contains MTBE (methyl tertiary
butyl ether) which was added to improve air
quality as a fuel oxygenate, but now has
contaminated water supplies where gasoline has
leaked or spilled.
26EFFECTS OF AIR POLLUTION
- H2SO4 formed in smog can be an important agent of
corrosion - H2SO4(aq) CaCO3(s) H2O(l) ? CO2(g)
CaSO42H2O(s) - Gypsum causes two problems
- 1) It dissolves in rain.
- 2) Increased volume leads to mechanical stress.
- Ozone attacks rubber, plastics, pigments and dyes.
27REMOVAL PROCESSES
- Wet deposition removal of soluble components in
rain or snow. - Oxidation is an important acid-forming process.
- Organic compounds ? carboxylic acids (acetic,
formic) - Sulfur compounds ? H2SO4
- Organosulfur compounds ? MSA (methanesulfonic
acid or CH3SO3H - Nitrogen compounds ? HNO3
- Rain is usually acidic due to presence of
dissolved CO2 (pH 5.6). These acids can lower
pH further. - Dry deposition Direct removal of gaseous or
particulate pollutants onto surface of the Earth.