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Stoichiometry Chapter 10

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Title: Stoichiometry Chapter 10


1
Stoichiometry Chapter 10
  • Mole Relationships
  • Types of Stoichiometry Problems
  • Mass Relationships in Chemical Reactions
  • Limiting Reactants
  • Theoretical, Actual and Percent Yields

2
Stoichiometry
  • Stoichiometry
  • The study of quantitative relationships between
    substances undergoing chemical changes.
  • Law of Conservation of Matter
  • In chemical reactions, the quantity of matter
    does not change.
  • The total mass of the products must equal that of
    the reactants.

3
Mass Relationshipsin Chemical Reactions
  • Stoichiometry - The calculation of quantities of
    reactants and products in a chemical reaction.

H2 O2 ? H2O
2 H2 O2 ? 2 H2O
4
Mole calculations
  • The balanced equation shows the mole ratio
    between reactants and products.
  • 2C2H6 7O2 4CO2 6H2O
  • For each chemical, you can determine the
  • moles of each reactant consumed
  • moles of each product made
  • There are many types of stoichiometry problems.
  • All involve mole-mole relationships.

5
Mole-Mole Relationships
  • From Example Exercise 10.3
  • Carbon monoxide is produced in a blast furnace by
    passing oxygen gas over hot coal (elemental
    carbon).
  • How many moles of oxygen react with 2.50 moles of
    carbon?

6
Mole-Mole Relationships
  • Self-Test Exercise
  • Iron is produced from iron ore by passing carbon
    monoxide gas through molten iron(III) oxide.
  • How many moles of carbon monoxide react with 2.50
    moles of iron(III) oxide?
  • How many moles of iron would be produced?

7
Mass Calculations
  • We dont directly weigh out molar quantities.
  • Rememberwe dont have a mole-o-meter in the lab
  • We can use measured masses like kilograms, grams
    or milligrams.
  • The molar masses and the chemical equations allow
    us to use either mass or molar quantities.

8
Mass-Mass
  • Suppose we have a problem like Example Exercise
    10.3 or even the Self-Test Exercise
  • If we were told the mass of one of the
    substances, would we be able to determine the
    number of moles?
  • Sure!
  • We would then proceed as we did in the previous
    examples.
  • Once we obtained the moles of the substance asked
    about in the problem, could we express that
    quantity in grams?
  • Sure!
  • We have now talked through a mass-mass
    stoichiometry problem
  • Lets try one

9
Mass Calculations
  • How many grams of hydrogen will be produced if
    10.0 grams of calcium is added to an excess of
    hydrochloric acid?
  • 2HCl Ca ______gt CaCl2 H2
  • Note
  • We produce one H2 for each calcium.
  • There is an excess of HCl so we have all we need.

10
Mass Calculations
  • 2HCl Ca ____gt CaCl2 H2
  • First - Determine the number of moles of
    calcium available for the reaction.

11
Mass Calculations
  • 2HCl Ca _____gt CaCl2 H2
  • According to the chemical equation, we get one
    mole of H2 for each mole of Ca.
  • So we will make 0.25 moles of H2.
  • grams H2 produced moles x molar mass H2
  • 0.25 mol x 2.016 g/mol
  • 0.504 grams

12
Mass Calculations
  • OK, so how many grams of CaCl2 were made?
  • 2HCl Ca _____gt CaCl2 H2
  • We would also make 0.25 moles of CaCl2.
  • g CaCl2 0.25 mol x FM CaCl2
  • 0.25 mol x 110.98 g / mol CaCl2
  • 27.75 g CaCl2

13
Putting It All Together
  • 2 HCl Ca ? CaCl2 H2
  • How many grams of H2 can be produced from 10.0
    grams of calcium and excess hydrochloric acid?
  • How many grams of CaCl2 can be produced from 10.0
    grams of calcium and excess hydrochloric acid?

14
Another Mass-Mass Example
  • Solid iron(III) oxide reacts with aluminum metal.
  • Suppose we have 15.0 grams of iron(III) oxide.
    How much aluminum, in grams, do we need to react
    with it?

15
Mass-Mass Example (cont)
  • Using the quantities from the previous
    examplehow many grams of each product could we
    obtain?

16
Limiting reactant
  • Limiting reactant - the material that is in the
    shortest supply based on a balanced chemical
    equation.

17
Limiting reactant animation
18
Limiting Reactants
  • We deal with limiting reactants every day.
  • Have you ever been cooking and run out of some
    ingredient you need?
  • You have enough of all the ingredients except
    one.
  • What happens to your cooking??
  • It has to stop!

19
Limiting Reactant Example
  • Youre making PBJ sandwiches.
  • For each sandwich you need 2 tbsp. peanut butter,
    1 tbsp. jelly, and two slices of bread.
  • You have 22 slices of bread, 15 tbsp. jelly, and
    18 tbsp. peanut butter
  • How many sandwiches can you make?

20
Example
  • For the following reaction, which is limiting if
    you have 5.0 g of hydrogen and 10. g oxygen?
  • Balanced Chemical Reaction
  • 2H2 O2 ________gt 2H2O
  • You need 2 moles of H2 for each mole of O2.
  • Moles of H2 5.0 g 2.5 mol
  • Moles of O2 10.g 0.31 mol

21
Example (cont)
  • 2 H2 (g) O2 (g) ? 2 H2O (g)
  • You have 0.25 mol H2 and 0.31 mol O2
  • How many moles of water can you make from each?
  • O2 is the limiting reactant, because you can only
    make 0.62 mol H2O.
  • It doesnt matter that you have enough H2 to make
    2.5 mol H2O, you will run out of O2 once youve
    made 0.62 mol H2O.
  • Same concept as in our practical exampleIt
    doesnt matter how much bread and jelly we have,
    there is only enough peanut butter to make nine
    sandwiches.

22
Example (cont)
  • Lets add another wrinkle
  • Suppose the question asks how many GRAMS of water
    we can make.
  • We just take the moles we already calculated and
    convert to grams.

23
Putting it all together
Graphically 2 H2 (g) O2 (g) ? 2
H2O (g)
Grams O2
Grams H2O Moles O2
Moles H2O
Molar mass of O2
Molar mass of H2O
Mole ratio from balanced equation
12
24
The Reactant in Excess
  • We produced 11.3 grams of water.
  • We consumed all 10.0 grams of oxygen in the
    process.
  • We did not use all 5.00 grams of hydrogen.
  • How much of the hydrogen did we use?
  • How much hydrogen did we have left over?

25
The Reactant in Excess
  • How much hydrogen does it take to produce 11.3
    grams of water, based upon the balanced equation
    below?
  • 2 H2 O2 ? 2 H2O
  • We used 1.27 grams of hydrogen, but we had 5.00
    grams.
  • Therefore, we had 3.73 grams of hydrogen in
    excess.

26
Theoretical, actual and percent yields
  • Theoretical yield
  • The amount of product that should be formed
    according to the chemical reaction.
  • Actual yield
  • The amount of product actually formed.
  • Percent yield
  • Ratio of actual to theoretical yield, as a .

27
Yield
  • Less product is almost always produced than
    expected.
  • Possible reasons
  • A reactant may be impure.
  • Some product is lost mechanically since the
    product must be handled to be measured.
  • The reactants may undergo unexpected reactions -
    side reactions.
  • No reaction truly has a 100 yield.

28
Percent yield
  • The amount of product actually formed divided by
    the amount of product calculated to be formed,
    times 100.
  • yield
    x 100
  • In order to determine yield, you must be able
    to recover and measure all of the product in a
    pure form.

29
Yield example
  • Example. The final step in the production of
    aspirin is the reaction of salicylic acid with
    acetic anhydride.
  • 48.6 g of aspirin is produced when 50.0 g of
    salicylic acid and an excess of acetic anhydride
    are reacted. What is the yield?

30
Structural Formulae
C A T A L Y S T
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