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Kinetics Revision

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x = order of reaction with respect to A. k = rate coefficient ( or ' ... have simple rate laws which follow stoichiometry. A products unimolecular Rate = k [A] ... – PowerPoint PPT presentation

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Title: Kinetics Revision


1
Kinetics Revision
  • for aA bB ? cC ,
  • Rate k Ax By
  • x order of reaction with respect to A
  • k rate coefficient ( or rate constant)

2
Elementary Reactions
  • Occur in a single collision
  • have simple rate laws which follow stoichiometry
  • A ? products unimolecular Rate k A
  • Cl2 ? Cl Cl
  • A A ? products bimolecular Rate kAA
  • Cl Cl ? Cl2
  • A B ? products bimolecular Rate kAB
  • Cl H2 ? HCl Cl

3
Example
  • For reaction A 3B ? product,
  • initial A / M initial B / M
    initial rate R / M s1 1 0.10
    1.0 5.0 2 0.14 1.0 10.0 3
    0.14 0.5 5.0
  • Answer
  • sets 2 3 A constant, halving B halves rate
  • hence R µ B1 first order in B
  • sets 1 and 2 B constant, look at order with
    respect to A
  • For B constant, R µ Ax

4
Hence second order with respect to A 2nd order in
A, 1st order in B, 3rd order overall
overall order sum of individual orders
  • Find rate coefficient k where R k A2 B
  • from set 1 5.0 M s1 k ? (0.10 M)2 ? 1.0 M
  • hence k 5.0 ? 102 M2 s1
  • Units found from rate law.

5
Rate LawsDependence On Time
  • Reaction obeying 1st-order rate law A ? products

(negative sign because A disappears its
concentration is decreasing)
  • Solve this differential equation by integrating
    both sides

6
First Order lnA vs time
  • Plot of lnA as function of time
  • lnA -kt lnA0

7
Half Life
Integrated rate law
  • Half Life is independent of initial concentration
  • Solutions also exist for second-order reactions...

8
Half life for a First Order Reaction
A0
9
Reaction Mechanism andRate-determining Step
  • Mechanisms can be complex, but sometimes all
    steps are fast except onethen slow step
    rate-determining step

10
Example
  • H2(g) 2ICl(g) ? I2(g) 2HCl(g)
  • Suggested mechanism
  • (1) H2 ICl ? HI HCl slow Rate(1)
    k1H2ICl
  • (2) HI ICl ? I2 HCl fast Rate(2)
    k2HIICl

H2 2ICl ? I2 2HCl net reaction
(1) is slow rate determining step ?
Overall rate k1H2ICl Experimental rate
kH2ICl, supports mechanism HI is an
intermediate, it doesnt appear in the overall
reaction
11
  • Often no simple solution to rate equations,
    solved coupled differential equations
    numerically.Example
  • oscillating reaction iodate, malonic acid
    (CH2(CO2H)2), H2O2
  • ozone layer destruction by CFCs
    (chlorofluorocarbons) simplified mechanism is
  • CCl2F2 ? CClF2 Cl
  • Cl O3 ? ClO O2
  • ClO NO2 ? ClONO2
  • ClONO2 HCl ? HNO3 Cl2
  • Cl2 ? 2Cl

hn
hn
12
Example
  • Fast reversible reaction followed by a slow step
  • (1) 2NO(g) ? N2O2 (g) fast equilibrium, K
  • (2) N2O2 (g) N2O2(g) ? 2NO slow (rate
    coefficient k)

2NO(g) O2 (g) ? 2NO2 (g) net reaction
Rate rate of slow step k N2O2O2
So rate k N2O2 O2 k K NO2 O2 hence
rate constant ? NO2 O2 consistent with
observed rate law
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