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CHE 333 Class 14

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do not account for the decrease in cross. sectional area that occurs in ... be plastically deformed and. will have a permanent shape. change. On loading again, ... – PowerPoint PPT presentation

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Title: CHE 333 Class 14


1
CHE 333 Class 14
  • True Stress True Strain
  • Crystalline Processes During Deformation.

2
Typical Data - Metals
3
Polymer Stress V Strain
4
Typical Data-Polymers
Iron Modulus is 282 Gpa on same scale
5
Typical Data - Ceramics
Iron 41 Al 11
6
True Stress and Strain
  • Engineering stress and strain calculations
  • do not account for the decrease in cross
  • sectional area that occurs in the plastic
    region.
  • True stress and strain do take into acccount
  • the cross sectional area changes and so
  • change the shape of stress strain data in
  • the plastic deformation region.
  • st F / Ai
  • st True stress
  • F Force
  • Ai instantaneous cross section.
  • et ln li/lo
  • et true strain
  • li instantaneous length
  • lo original length
  • Assumes constant volume.

7
Work or Strain Hardening
  • From the true stress strain data, one important
    feature is the difference to the
  • engineering stress strain data. A UTS before
    failure is absent for the true stress strain
  • case. It can be said that the material requires
    an increase in stress to continually
  • increase the strain. This is called Work
    Hardening for metals. Analysis shows that
  • if a metal is work hardened that the stress
    required to cause more plastic deformation
  • is increased. If the material is loaded
  • to point 1, then unloaded it will
  • be plastically deformed and
  • will have a permanent shape
  • change. On loading again,
  • the yield stress will no longer
  • be point 2, but point 1, which
  • effectively increases the
  • service load before
  • plastic deformation.

1
Load unload load path
2
8
True Stress Strain Relations
9
Upper and Lower Yield Stress
  • Steels show a stress strain curve around the
  • yield point which exhibit a decrease in stress
  • as strain increases, followed by a yield
  • point elongation before the usual plastic
  • deformation occurs. The 0.2 yield stress
  • construction is used in this case.

10
Deformation Mechanisms
  • Elastic deformation.
  • Metals stretching of bonds between
  • the atoms.
  • Polymer same
  • Ceramics same.
  • As bond strength increases, so does the
  • elastic modulus, proportional to the slope
  • of the Force distance curve at 0 force.
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