Title: Water Part 2.
1Chapter 2 Water Part 2.
- Ionization of water and pH.
- Strong acids and bases.
- Weak acids and bases.
- The Henderson-Hasselbach Eqn
- Titration curves and buffers.
- 6. pH problems.
21. Ionization of water.
H OH-
3H OH- 10-14 At neutrality, H
OH- 10-7 M
Taking logs of both sides log H -14 log
OH-
Define pH - log H and pOH -log OH-
Then -pH -14 pOH or pH 14 - pOH
4(No Transcript)
5(No Transcript)
62. Strong acids and bases dissociate completely
in water.
HCl ? H Cl-
What is the pH of a 10-4 M solution of HCl? H
10-4 M pH -log H log 10-4 4
NaOH ? Na OH- What is the pH of a 10-5M
solution of NaOH? OH- 10-5 M pOH 5 but
pH 14- pOH Therefore, pH 8
7- Weak acids do not dissociate completely.
- Acetic acid (H Ac) H Ac ?? H Ac-
- Ammonia (NH3) NH3 H ?? NH4
Acid hydrogen ion donor Base hydrogen ion
acceptor Conjugate acids and bases. You cant
have one without the other.
84. The Henderson-Hasselbach Equation
HA ?? H A- H A- KA
HA
or H KA A-
HA
Define pK - log KA Therefore, pH pK
log A-
HA
Base
Acid
Consequences A- HA pH pK A-
10HA pH pK 1 A- 0.1HA
pH pK - 1
95. Titration curves and buffers. The smallest
change in pH occurs when the pH pK.
Buffering region
Taken from Campbell Farrell 5th. Ed.
10(No Transcript)
11What is the conjugate base in each case?
12Phosphate buffers.
13(No Transcript)
146. .pH problems.
- What is the pH of a 0.1 M solution of H Ac? pK
4.7 -
KA H Ac- x2 . Where x
H Ac- H Ac (0.1M-x)
and H Ac 0.1 M-x
H
Assume that xltlt0.1 M. Then KA 10-4.7 x2
0.1 M
X2 10-4.7 10-1 10-5.7
Log x -2.85 pH 2.85
15- How many ml of 0.1N HCl must be added to 100ml
- of 0.1M Tris base to make a buffer of pH 8.3?
- Tris HCl ?? Tris Cl-
- To solve this problem, you need the
Henderson-Hasselbach - Equation and a conservation equation. Also,
pay attention - to units.
- pH pK log Tris or 8.3 8.0
Tris - Tris
Tris - Tris 0.3
- Tris
16Conservation Eqns Triso Tris Tris
and Tris HCl Let HCl x Tris
Then, Tris 0.1 M -x
Tris 0.3 0.1M x or 1.3x 0.1 M
and x 0.077M Tris x
How many equivalents of HCl correspond to
0.077M? Eq (eq.) conc (eq./liter) x liters
0.0077 eq. How many ml of 5N HCl is needed to
get 0.0077 eq.? x (l) 0.0077eq
0.00154 l. 1l 5 eq.
17Useful information, 1 mole/l 1 mmole/ml
1umole/ul.
18- When you do problems,
- Give the equation.
- Substitute in the equation.
- Use units.
- Give the answer with units.
- Correct answers without the set up will receive
zero credit. - Wrong answers with the correct set up will get
partial credit.