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SECONDORDER CIRCUITS

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Title: SECONDORDER CIRCUITS


1
SECOND-ORDER CIRCUITS
THE BASIC CIRCUIT EQUATION
Single Loop Use KVL
Single Node-pair Use KCL
Differentiating
2
LEARNING BY DOING
3
THE RESPONSE EQUATION
IF THE FORCING FUNCTION IS A CONSTANT
4
COEFFICIENT OF SECOND DERIVATIVE MUST BE ONE
DAMPING RATIO, NATURAL FREQUENCY
5
ANALYSIS OF THE HOMOGENEOUS EQUATION
Iff s is solution of the characteristic equation
6
DETERMINE THE GENERAL FORM OF THE SOLUTION
LEARNING EXTENSIONS
Divide by coefficient of second derivative
Roots are real and equal
Roots are complex conjugate
7
Form of the solution
LEARNING EXTENSIONS
Classify the responses for the given values of C
HOMOGENEOUS EQUATION
C0.5 underdamped C1.0 critically
damped C2.0 overdamped
8
THE NETWORK RESPONSE
DETERMINING THE CONSTANTS
9
LEARNING EXAMPLE
STEP 1 MODEL
ANALYZE CIRCUIT AT t0
STEP 2
STEP 3 ROOTS
STEP 4 FORM OF SOLUTION
STEP 5 FIND CONSTANTS
10
USING MATLAB TO VISUALIZE THE RESPONSE
script6p7.m plots the response in Example
6.7 v(t)2exp(-2t)2exp(-0.5t)
tgt0 tlinspace(0,20,1000) v2exp(-2t)2exp(-0.
5t) plot(t,v,'mo'), grid, xlabel('time(sec)'),
ylabel('V(Volts)') title('RESPONSE OF OVERDAMPED
PARALLEL RLC CIRCUIT')
11
LEARNING EXAMPLE
NO SWITCHING OR DISCONTINUITY AT t0. USE t0
OR t0
model
Form
12
USING MATLAB TO VISUALIZE THE RESPONSE
script6p8.m displays the function
i(t)exp(-3t)(4cos(4t)-2sin(4t)) and the
function vc(t)exp(-3t)(-4cos(4t)22sin(4t))
use a simle algorithm to estimate display
time tau1/3 tend10tau tlinspace(0,tend,350)
itexp(-3t).(4cos(4t)-2sin(4t)) vcexp(-3
t).(-4cos(4t)22sin(4t)) plot(t,it,'ro',t,vc
,'bd'),grid,xlabel('Time(s)'),ylabel('Voltage/Curr
ent') title('CURRENT AND CAPACITOR
VOLTAGE') legend('CURRENT(A)','CAPACITOR
VOLTAGE(V)')
13
LEARNING EXAMPLE
NO SWITCHING OR DISCONTINUITY AT t0. USE t0 OR
t0
14
USING MATLAB TO VISUALIZE RESPONSE
script6p9.m displays the function
v(t)exp(-3t)(16t) tau1/3 tendceil(10tau) t
linspace(0,tend,400) vtexp(-3t).(16t) plot(
t,vt,'rx'),grid, xlabel('Time(s)'),
ylabel('Voltage(V)') title('CAPACITOR VOLTAGE')
15
LEARNING EXTENSION
To find initial conditions use steady
state analysis for tlt0
And analyze circuit at t0
Once the switch opens the circuit is RLC series
16
To find initial conditions we use steady state
analysis for tlt0
LEARNING EXTENSION
And analyze circuit at t0
For tgt0 the circuit is RLC series
17
LEARNING EXTENSION
Analysis at t0
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