Title: SECONDORDER CIRCUITS
1SECOND-ORDER CIRCUITS
THE BASIC CIRCUIT EQUATION
Single Loop Use KVL
Single Node-pair Use KCL
Differentiating
2LEARNING BY DOING
3THE RESPONSE EQUATION
IF THE FORCING FUNCTION IS A CONSTANT
4COEFFICIENT OF SECOND DERIVATIVE MUST BE ONE
DAMPING RATIO, NATURAL FREQUENCY
5ANALYSIS OF THE HOMOGENEOUS EQUATION
Iff s is solution of the characteristic equation
6DETERMINE THE GENERAL FORM OF THE SOLUTION
LEARNING EXTENSIONS
Divide by coefficient of second derivative
Roots are real and equal
Roots are complex conjugate
7Form of the solution
LEARNING EXTENSIONS
Classify the responses for the given values of C
HOMOGENEOUS EQUATION
C0.5 underdamped C1.0 critically
damped C2.0 overdamped
8THE NETWORK RESPONSE
DETERMINING THE CONSTANTS
9LEARNING EXAMPLE
STEP 1 MODEL
ANALYZE CIRCUIT AT t0
STEP 2
STEP 3 ROOTS
STEP 4 FORM OF SOLUTION
STEP 5 FIND CONSTANTS
10USING MATLAB TO VISUALIZE THE RESPONSE
script6p7.m plots the response in Example
6.7 v(t)2exp(-2t)2exp(-0.5t)
tgt0 tlinspace(0,20,1000) v2exp(-2t)2exp(-0.
5t) plot(t,v,'mo'), grid, xlabel('time(sec)'),
ylabel('V(Volts)') title('RESPONSE OF OVERDAMPED
PARALLEL RLC CIRCUIT')
11LEARNING EXAMPLE
NO SWITCHING OR DISCONTINUITY AT t0. USE t0
OR t0
model
Form
12USING MATLAB TO VISUALIZE THE RESPONSE
script6p8.m displays the function
i(t)exp(-3t)(4cos(4t)-2sin(4t)) and the
function vc(t)exp(-3t)(-4cos(4t)22sin(4t))
use a simle algorithm to estimate display
time tau1/3 tend10tau tlinspace(0,tend,350)
itexp(-3t).(4cos(4t)-2sin(4t)) vcexp(-3
t).(-4cos(4t)22sin(4t)) plot(t,it,'ro',t,vc
,'bd'),grid,xlabel('Time(s)'),ylabel('Voltage/Curr
ent') title('CURRENT AND CAPACITOR
VOLTAGE') legend('CURRENT(A)','CAPACITOR
VOLTAGE(V)')
13LEARNING EXAMPLE
NO SWITCHING OR DISCONTINUITY AT t0. USE t0 OR
t0
14USING MATLAB TO VISUALIZE RESPONSE
script6p9.m displays the function
v(t)exp(-3t)(16t) tau1/3 tendceil(10tau) t
linspace(0,tend,400) vtexp(-3t).(16t) plot(
t,vt,'rx'),grid, xlabel('Time(s)'),
ylabel('Voltage(V)') title('CAPACITOR VOLTAGE')
15LEARNING EXTENSION
To find initial conditions use steady
state analysis for tlt0
And analyze circuit at t0
Once the switch opens the circuit is RLC series
16To find initial conditions we use steady state
analysis for tlt0
LEARNING EXTENSION
And analyze circuit at t0
For tgt0 the circuit is RLC series
17LEARNING EXTENSION
Analysis at t0