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Classical I.e. not Quantum Waves

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Another calculation, with the kink, is instructive: There is an unbalanced force on the kink. ... Wave Equation on String, generalize our analysis of kink: ... – PowerPoint PPT presentation

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Title: Classical I.e. not Quantum Waves


1
  • Classical (I.e. not Quantum) Waves

2
  • Find speed of wave on a string, which is flexible
    and not displaced much
  • method of Tait
  • the force downward, radial with respect to the
    curve at the top of the bump, is equal to the
    component of the tension on each side

3
  • The mass of a segment of a string with mass per
    unit length ? is
  • The idea of this calculation is to equate the
    radial force with the centripetal force
  • solving for v

4
  • Another calculation, with the kink, is
    instructive

5
  • There is an unbalanced force on the kink. The
    right hand end has no y component force, the left
    end has a force
  • the impulse equals change in momentum
  • and now we use the small angle approximation that
    sin x tan x, so

6
  • Reflections at the end
  • open end pulse reflected with no change in sign
  • fixed end pulse reflected inverted
  • momentum conservation can be used to conclude
    this behavior

7
  • Reflections at the end
  • open end pulse reflected with no change in sign
  • fixed end pulse reflected inverted
  • momentum conservation can be used to conclude
    this behavior

8
  • Traveling Waves-start with Harmonic Waves,
    exciting with a simple harmonic motion of
    frequency f, wavelength ? v/f
  • We have seen that the travelling wave travels
    with speed v, so in full generality the wave
    function is (NON-DISPERSIVE)
  • and the harmonic wave excited by SHM is
  • Note k is called wave number and has nothing to
    do the the k in Hookes law used in the previous
    slide on SHM!!
  • It is useful to write the wave function in some
    other ways

9
  • Sometimes we want the choice of the origin of x
    and t to be arbitrary, so we have to throw in an
    initial phase ?
  • We like to define another 2? killer ?2?f
  • The key here is the traveling wave form, which
    comes from the wave equation, which we will soon
    derive for the string

10
  • Review of Simple Harmonic Motion

11
  • SHM formula application to wave
  • Energy transported by wave--any bit of the string
    is performing SHM, with amplitude A
  • and in a time dt the oscillation moves along by a
    distance dxvdt, to the power passing by in one
    second is

12
  • String fixed at 0 and L Standing Waves
  • the end points have to stay at zero y0
  • at the point x0, this follows from the form sin
    kx. At the other end, it implies a relation
    between k and L, sin kL 0

13
  • Some trig what if we have two traveling waves
    going in opposite directions
  • and with identity
  • sin(ab)sin a cos b cos a sin b
  • and we see that this is the wave function for the
    standing waves

14
  • What if we add (traveling) waves with different
    wave lengths?
  • So we get a difference frequency or beat
    frequency -this can be written as a oscillation
    with frequency f1f2 and variable amplitude
  • amplitude

15
  • Wave Equation on String, generalize our analysis
    of kink
  • the mass of this bit of string is ? ds? dx, and
    Fma ?

16
  • Or, canceling the dx
  • We have noted that this has any solution of the
    form
  • that is, traveling, non-dispersive waves, which
    lead to standing wave on the finite string.

17
  • Solutions of the Wave Equation 1. Traveling
    Wave solutions

18
  • 2. The Normal Modes of the string with fixed
    ends
  • A successful separation of variables! The
    equation has to be true for all x and t, can only
    be so if each is equal to the same constant, call
    it -?2

19
  • This is the familiar SHO equation, with solutions
  • but the cos kx does not fit the fixed ends,
    y(0)y(L)0, so knn?/L, so?nn ?v/L
  • The wave equation is linear, so sums of solutions
    are also solutions. The shape at time zero can
    be what we please, so we need both sin and cos in
    t, and then the general solutions are

20
Special Problem, preparation for Test, Due
Monday 18 October, questions answered 13,15 Oct.
  • Power Spectrum of String-
  • A string is 4 meters long, fixed at both ends.
    It weighs 80 grams in total, and carries a
    tension of 100 Newtons.
  • The middle half is lifted from the equilibrium
    position by 5mm, like this
  • What is the power in the vibrations in the first
    ten active modes, or harmonics?
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