Title: Chemical Formulas and Compounds
1Chapter 7
- Chemical Formulas and Compounds
- Date Started March 25, 2009
KCl
CaS
FeO
CuBr
2Chemical formula and compounds
- Chemical formula show the types of atoms and
their ratios to each other in a chemical
compound. - The subscripts show numerically the ratio of each
atom in the compound and are always whole
numbers. - When the ratios of the compounds are simple whole
number ratios, the formula is called an empirical
formula. - When polyatomic ions are in a chemical formula
sometimes parentheses are needed within the
formula.
C8H18 8 carbon atoms 18 hydrogen atoms
Al2(SO4)3 2 aluminum ions 3 sulfate ions
3Monatomic Ions
- Ions formed from a single atom are called
monatomic ions. - Some main groups elements do not form ions,
rather they share their valence electrons.
Carbon and silicon are examples of these types. - Elements in group 14 can easily lose their
s-orbital electrons, but do not readily give
up their p-orbital electrons. - Elements in the d-block tend to lose their
electrons and have charges of 1, 2, 3, and 4.
They are called polyvalent ions. - For this reason, ion for the d-block elements
must be looked up to find their common ion
charges. - The term oxidation number is sometimes used to
refer to the apparent charge of an ion. (Very
common with elements in groups 3-12)
4Naming Monatomic ions
- Negative monatomic ions change the endings of
their name to ide. - Positive ions are simply named by their element
name, however when a atom has more than one
positive charge state(polyvalent), roman numerals
are used to indicate the charge. - Page 221, Table 7-1, has some of the common
monatomic ions and their charges.
K1 potassium ion Al3
Aluminum ion Fe2 iron(II) ion Fe3
iron(III) ion
F-1 fluoride ion S-2 sulfide ion N-3
nitride ion
5Common Ions and their Oxidation Numbers
6Binary ionic compounds
- Binary compounds are compounds composed of two
different elements. - The net (overall) charge in a binary compound
must be equal to zero. This means all of the
positive charges equals the negative charges. - Subscripts are used to balance ions with
different ionic charges. - The cation is always written first followed by
the anion. - In naming binary compounds, the use of the
monatomic ion names are the basis for naming the
compound.
MgBr2 magnesium bromide
K2S potassium sulfide
FeO iron(II) oxide Fe2O3 iron(III)
oxide
7Balancing binary compounds
- Write the symbols for the ions with the cation
first. - Cross over charges to give the subscripts.
- Make sure that subscripts are simple whole number
ratios. If they are not, reduce them by dividing
by their largest common factor. - Never indicate the cross over charge in the
subscript.
- magnesium and chlorine
- Mg2 Cl-1
- Cross over Mg2Cl-1
1 2 - Remove superscripts MgCl2
- The name of the compound is magnesium chloride.
8Stock system of nomenclature
- When ions have more than one possible positive
charge, in writing the name of the compound,
roman numerals are used to show the charge. - If there is only one possible positive charge for
a cation, roman numerals are NEVER used. - Iron(II) is an ion with an iron atom having a
charge of Fe2. - Iron(III) is an ion with an iron atom having a
charge of Fe3.
FeCl2 Iron(II) chloride
FeCl3 Iron(III) chloride
MgBr2 magnesium bromide
BaS Barium sulfide
9Common ions and their names
is
10Ternary ionic compounds
- Ternary ionic compounds have three elements in
the makeup of the compound. One of the members
in the ionic compound is a polyatomic ion. - The overall or net charge must be zero in the
ternary ionic compound if it is not then
subscripts and parentheses must be used to
balance the charge. - Polyatomic ions with oxygen in their composition
are called oxyanions and always are negatively
charged. - In naming ternary ionic compounds the ion names
are used as in the case for binary ionic
compounds. - When oxyanions combine with polyvalent cations,
the stock system must be used in the name.
11Examples of ternary ionic compounds
- Sodium ion and carbonate ion
- Na1 CO3-2
- Cross over charges Na12 CO3-21
- Na2CO3
- The name of the compound is sodium carbonate.
Iron(II) ion and sulfate ion Fe2
SO4-2 Cross over charges Fe22
SO4-22 Reduce ratios by dividing subscripts by 2.
FeSO4 The name of the compound is iron(II)
sulfate.
12Name the following compounds
- LiBr
- Lithium bromide
- Sn(NO3)4
- Tin(IV) nitrate
- FeCl2
- Iron(II) chloride
- CaS
- Calcium sulfide
- Pb(OH)2
- Lead(II) hydroxide
- Fe2(CO3)3
- Iron(III) carbonate
13Write the formula for the following
- Vanadium(V) sulfide
- V2S5
- Magnesium sulfate
- MgSO4
- Cobalt(II) bromide
- CoBr2
- Aluminum chloride
- AlCl3
- Copper(II) iodide
- CuI2
- Strontium nitrite
- Sr(NO2)2
14Acids and Bases
- Acids are ionic or polar covalent compounds that
are dissolved in water and have hydrogen as their
cation. - The symbol (aq), refers to the term aqueous which
means dissolved in water. - Acids dissolves/corrodes metals and react with
bases to form salts. - Acids have a sour taste and are in the pH range
of 1-6. - There are two types of acids, binary acids and
ternary acids.
15pH Scale and Water
- Is defined as
- pH - log H1
- H2O H1 OH1-
16Binary Acids
- Binary acids have hydrogen and a monatomic anion.
- When naming acids the prefix hydro- is placed
on the element name and the ending is changed to
-ic. - HF (aq) hydrofluoric acid
- H2S (aq) hydrosulfuric acid
- When binary acids react with bases they often
form binary salts.
17Ternary Acids
- Ternary acids have hydrogen and a polyatomic
(oxyanion) anion and are dissolved in water. - When naming ternary acids, the prefix hydro- is
NEVER used in the name. - The polyatomic anion determines the ending for
the acid. - If the polyatomic ion ends in ite, the ending is
changed to ous. - If the polyatomic ion ends in ate, the ending is
changed to ic.
18Examples of Ternary Acids
- H2SO4(aq) sulfuric acid
- HNO2 (aq) nitrous acid
- HNO3 (aq) nitric acid
- H2SO3(aq) sulfurous acid
19Bases or Alkali
- Bases are ionic or polar covalent compounds that
are dissolved in water and have the hydroxide ion
as their anion. - The symbol (aq), refers to the term aqueous which
means dissolved in water. - Bases dissolves/corrodes organic materials and
react with acids to form salts. - Bases have a bitter taste and are in the pH range
of 8-14. - Most bases are ternary compounds.
20Bases or Alkali
- Bases are very easy to name since they used the
hydroxide ion in their structures. - In all bases the word hydroxide is ALWAYS the
last word in the compounds name. - They are ternary or quaternary compounds
- NaOH(aq) Sodium hydroxide
- Fe(OH)3(aq) Iron(III) hydroxide
- Cu(OH)2(aq) Copper(II) hydroxide
21Review pH scale
- 0-6.9..acid
- 7....neutral
- 7.1-14base/alkali
22Naming molecular compounds with nonmetals in
their structure.
- Often prefixes are used in binary molecular
compounds that have two nonmetals in their
structures. - Compounds such as carbon, nitrogen, sulfur, and
phosphorus that bond with oxygen often use
prefixes in naming the compound. - The stock system can also be used in naming these
compounds. - The key concept is that these are covalently
bonded nonmetals.
23Prefix Names
- Number Prefix
- 1 mono-
- 2 di-
- 3 tri-
- 4 tetra-
- 5 penta-
- 6 hexa-
- 7 hepta-
- 8 octa-
- 9 nona-
- 10 deca-
24Prefixes in naming Binary Compounds of Nitrogen
and Oxygen
Formula Name
Oxidation
- N2O dinitrogen monoxide (I)
- NO nitrogen monoxide (II)
- NO2 nitrogen dioxide (IV)
- N2O3 dinitrogen trioxide (III)
- N2O4 dinitrogen tetroxide (IV)
- N2O5 dinitrogen pentoxide (V)
25Prefixes in naming other binary and ternary
compounds
- NaF6 sodium hexafluoride
- P2O5 diphosphorus pentoxide
- CBr4 carbon tetrabromide
- Fe2O3 di-iron trioxide
- SnO2 tin dioxide
- Fe3(PO4)2 tri-iron diphosphate
- Cu(OH)2 copper dihydroxide
26Latin names
- Fe3 ferric
- Fe2 ferrous
- Sn2 stannous
- Sn4 stannic
- Cu2 cupric
- Cu1 cuprous
- Pb4 plumbic
- Pb2 plumbous
- Hg22 mercurous
- Hg2 mercuric
- Au1 aurrous
- Au3 aurric
Co2 cobaltous Ni2 nickelous Mn2 manganous Cr
3 chromic Sb3 stibbous Sb5 stibbic
27Naming Compounds with Latin names
- Fe2O3 ferric oxide
- SnO2 stannic oxide
- SnCl2 stannous chloride
- Fe3(PO4)2 ferrous phosphate
- Cu(OH)2 cupric hydroxide
- PbCl4 plumbic chloride
- PbCO3 plumbous carbonate
- Hg2O mercurous oxide
- HgSO4 mercuric sulfate
28Common Chemical Names
29Molar Mass of Compounds
- Molar mass is the number of grams needed in one
mole of a compound. - One mole is 6.022 x 1023 molecules.
- In a compound, all atoms in the compound are used
to determine the molar mass of the compound. - The subscripts are used in determining the molar
mass.
30Finding the Molar Mass of a Compound
- Determine the total number of atoms for each
element in the compound. - Look up the atomic mass of the elements in the
compound. - Multiply the atomic mass of each element times
the subscript of the element in the compound. - Add all of the masses for each element in the
compound to find the total.
31Example Problem 1
- What is the molar mass of FeO?
- Fe 55.8 g/mol O 16.0 g/mol
- How many atoms do you have of each element?
- Add the molar masses.55.8 g/mol16.0 g/mol71.8
g/mol of FeO- Molar mass of this compound
32Molar mass example problem
- Find the molar mass of Fe2O3
- Determine the total number of atoms for each
element in the compound. - 2 Fe atoms 3 O atoms
- Look up the atomic mass of the elements in the
compound. - Fe 55.8 g/mol O 16 g/mol
- Multiply the atomic mass of each element times
the subscript of the element in the compound. - For Fe 55.8 g/atom 2 atoms 111.6 grams
- For O 16.0 g/atom 3 atoms 48.0 grams
- Add all of the masses for each element in the
compound to find the total. - From Fe 111.6 grams
- From O 48.0 grams Molar mass of
Fe2O3 159.6 grams/mol
33Percent Composition Problems
- Percent Composition of Fe2O3
- Find the molar mass of Fe2O3
- Determine the percentage of each element
- Use the total gram amount of each element
- Divide by the molar mass of the compound
- Multiply times 100 to obtain percentage.
- a. Molar Mass Determination of Fe2O3
- 2- Fe atoms 3- O atoms
- Look up the atomic mass of the elements in
the compound. - Fe 55.8 g/mol O 16 g/mol
- Multiply the atomic mass of each element times
the subscript of the element in the compound. - For Fe 55.8 g/atom 2 atoms 111.6
grams - For O 16.0 g/atom 3 atoms 48.0
grams - Add all of the masses for each element in the
compound to find the total. - From Fe 111.6 grams
- From O 48.0 gramsMolar mass of
Fe2O3 159.6 grams/mol - Percentages of Composition
- Iron (Fe) 111.6 g 100
159.6 g
69.9
34Rationale for Empirical Formula
- Percent composition can be used to determine the
simple whole number ratio of a chemical compound. - An assumption is made that a 100 g sample was the
basis of the composition. - The mole amount of each element is determined
from the composition data. - A ratio of moles and proportion is used to
determined the simple whole number ratio. - The formula is then written using the data
calculated.
35Empirical Formula Problem
- Steps
- Given the following percentages of composition
- 32.38 Na
- 22.65 S
- 44.99 O
- Assume element percentages are grams out of a
total of 100 g sample. - 32.38 Na 32.38 g Na
- 22.65 S 22.65 g S
- 44.99 O 44.99 g O
- Determine the moles of each element present
- moles of Na 32.38 g Na x 1 mol
Na 1.408 mol Na
22.99
g Na - moles of S 22.65 g S x 1 mol S
0.7063 mol S
32.07 g S - moles of O 44.99 g O x 1 mol O
2.812 mol O -
16.00 g O
36Empirical Formula Problem
- Steps (cont)
- Determine the Smallest whole-number ratio of
atoms - 1.408 mol Na x moles Na
1.993 moles Na 0.7063 mol S 1
mol S 1 mol S
- 2.812 mol O x moles O 3.981 moles
O 0.7063 mol S 1 mol S
1 mol S - Round numbers to whole numbers and write formula
Na2
S
O4
Metals are always written first. Most
electronegative nonmetal is written last.
37Empirical Formula Problem
- Problem 19
- Given the following percentages of composition
- 24.6 K
- 34.8 Mn
- 40.6 O
- Assume element percentages are grams out of a
total of 100 g sample. - 24.6 K 24.6 g K
- 34.8 Mn 34.8 g Mn
- 40.6 O 40.6 g O
- Determine the moles of each element present
- moles of K 24.6 g K x
1 mol K 0.629 mol K
39.1 g K
- moles of Mn 34.8 g Mn x 1 mol Mn
0.633 mol Mn
54.9 g Mn - moles of O 40.6 g O x 1 mol O
2.538 mol O
16.00 g O
38Empirical Formula Problem
- Steps (cont)
- Determine the Smallest whole-number ratio of
atoms - 0.633 mol Mn x moles Mn
1.006 moles Mn 0.629 mol K 1
mol K 1 mol K -
- 2.538 mol O x moles O 4.035
moles O 0.629 mol K 1 mol K
1 mol K - Round numbers to whole numbers and write formula
K
Mn
O4
Potassium permanganate
39More Practice
40Answers for Homework-1
41Answers for Homework-2
42Stock system naming of compounds of Nitrogen and
Oxygen
- N2O nitrogen(I) oxide
- NO nitrogen(II) oxide
- NO2 nitrogen(IV) oxide
- N2O3 nitrogen(III) oxide
- N2O4 nitrogen(IV) tetroxide (needed)
- N2O5 nitrogen(V) oxide
43Answers for Homework-3
44More Practice
- Name the following compounds using the three ways
covered in class - Fe3(PO4)2
- iron(II) phosphate
- iron diphosphate
- ferrous phosphate
- Cu2SO4
- copper(I) sulfate
- copper monosulfate
- cuprous sulfate
45More Practice 2
- Name the following compounds using the three ways
covered in class - Ca(MnO4)2
- calcium permanganate
- Mg(NO3)2
- magnesium nitrate
- Pb(NO2)2
- lead(II) nitrite or lead dinitrite or
- plumbous nitrite
46More Practice 3
- Write the chemical formula for the compounds
given below - strontium bromide
- iron(II) carbonate
- lead(IV) sulfide
- barium oxide
47More Practice 4
- Write the chemical formula for the compounds
given below - silicon monoxide
- iron tri-iodide
- lead(II) sulfite
- sodium phosphide