Title: BALANCES ON REACTIVE PROCESSES
1CHAPTER 9 BALANCES ON REACTIVE PROCESSES
2- Consider the familiar reaction in which water is
formed - from hydrogen and oxygen
- On the molecular level, the reaction might be
depicted - as follows
H2
?
O2
Each time this reaction takes place, three
chemical bonds are broken (two between hydrogen
atoms and one between oxygen atoms).
3?
- Four bonds are formed among the atoms of the two
- water molecules.
- As it happens, more energy is released when the
water - molecule bonds form than it takes to break the
hydrogen - and oxygen molecules bonds.
- For the reactor temperature to remain constant,
the net - energy released must be transferred away from
the - reactor, otherwise it can raise the reactor
temperature - by several thousand degrees.
4- In any reaction between stable molecules, energy
is - required to break the reactant chemical bonds
and - energy is released when the product bonds form.
- Exothermic reactions if the first process
absorbs less - energy than the second process releases the
product - molecules at a given T and P have lower internal
ener- - gies (and hence lower enthalpies) than the
reactant - molecules at the same T and P.
- For an exothermic reaction, the net energy
released - the heat of reaction must be transferred from
the - reactor as heat or work, or else the system
temperature - increases.
5- Endothermic reactions if less energy is
released when - the product bonds form than it took to break the
reactant - bonds.
- For an endothermic reaction, energy must be added
to - the reactor as heat or work to keep the
temperature from - decreasing.
- An energy balance on a reactor tells the process
engineer - how much heating or cooling the reactor requires
in order - to operate at the desired conditions.
6- In this chapter we show how enthalpy changes that
- accompany chemical reactions are determined from
tabu- - lated physical properties of the reactants and
products and - how calculated enthalpies of reaction are
incorporated in - energy balances on reactive processes.
79.1 HEATS OF REACTION
- Consider the reaction between solid calcium
carbide and - liquid water to form solid calcium hydroxide and
gaseous - acetylene
The expression stoichiometric quantities of
reactants means molar amounts of the reactants
numerically equal to their stoichiometric
coefficients.
8- The heat of reaction (or enthalpy of reaction),
- , is the enthalpy change for a
process in - which stoichiometric quantities of reactants at
T and - P react completely in a single reaction to form
- products at the same T and P.
- For example, the heat of calcium carbide
reaction - at 25? and 1atm is
9- These two equations signify that if 1 mol of
solid CaC2 - reacts completely with 2 mol of liquid H2O to
form 1 mol - of Ca(OH)2 and 1 mol of C2H2, and the initial
and final - temperatures are both 25oC and the initial and
final - pressures are both at 1 atm, then
- If the reaction is run under conditions such that
the - energy balance reduces to Q?H, then 125.4kJ of
heat - must be transferred from the reactor in the
course of the - reaction.
10- The units of often cause confusion.
For example, - if the heat of a reaction is reported to be -50
kJ/mol, you - might ask per mol of what? This difficulty is
avoided if - you recall that the given applies
to stoichiometric - quantities of each species. For example,
means that the enthalpy change for the given
reaction is
11If you knew, say, that 150 mol of C/s was
generated in the given reaction at 100oC and 1
atm, you could calculate the associated enthalpy
change as
12- More generally, if ??A is the stoichiometric
coefficient of - a reactant or reaction product A (positive if A
is a product, - negative if it is a reactant) and nA,r moles of
A are con- - sumed or generated at TT0 and PP0, then the
asso- - ciated enthalpy change is
- In Chapter 4, we defined the extent of reaction,
??, as a - measure of how far a reaction has proceeded.
This - quantity is
13- From the preceding two equations, it follows that
if a - reaction takes place at a temperature T0 and
pressure - P0 and the extent of reaction is ?, the
associated - enthalpy change is
14- Following are several important terms and
observations - related to heats of reaction.
- If is negative the reaction is
exothermic at T - and P, and if is positive the
reaction is endo- - thermic at T and P.
- 2. At low and moderate pressure is
nearly inde- - pendent of pressure.
- 3. The value of depends on how the
stoichiome- - tric equation is written. For example
154. The value of depends on the
states of aggre- gation (gas, liquid, or
solid) of the reactants and products. For
example, The only difference between the
reactions is that the water formed is a
liquid in the first one and a vapor in the
second. 5. The standard heat of reaction
is the heat of reaction when both the
reactants and products are at a specified
reference T and P, usually 25? and 1atm.
16Example 9.1-1 Calculation of Heats of Reaction
- The standard heat of reaction of the combustion
of - n-butane vapor is
Calculate the rate of enthalpy change,
(kJ/s), if 2400 mol/s of CO2 is produced in this
reaction and the reactants and products are all
at 25?.
Soln
172. What is the standard heat of the reaction
Calculate if 2400 mol/s of CO2 is produced
in this reaction and the reactants and products
are all at 25?.
Soln
Since doubling the stoichiometric coefficients of
a reaction must double the heat of reaction,
The enthalpy change associated with the product
of 2400 mol/s of CO2 at 25oC cannot depend on
how the stoichiometric equation is written, and
so must be the value calculated in part(1).
18Let us do the calculation and prove it.
193.The heats of vaporization of n-butane and water
at 25oC are 19.2 kJ/mol and 44.0 kJ/mol,
respectively. What is the standard heat of
reaction
Calculate if 2400 mol/s of CO2 is produced
in this reaction and the reactants and products
are all at 25oC.
Soln Compare the two reactions
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23- If a reaction takes place in a closed reactor at
constant - volume, the heat released or absorbed is
determined by - the change in internal energy between the
reactants and - products.
- The internal energy of reaction, , is
the difference - Uproducts Ureactants if stoichiometric
quantities of reactants - react completely at temperature T.
- Suppose a reaction occurs, and??i is the
stoichiometric - coefficient of the ith gaseous reactant or
product. If ideal - gas behavior can be assumed and specific volumes
of - liquid and solid reactants and products are
negligible - compared with those of the gases.
24- The internal energy of reaction is related to the
heat of - reaction by
- For example, for the reaction
the internal energy of reaction is
- If there are no gaseous reactants or products,
then to - a good approximation
25Example 9.1-2 Evaluation of
The standard heat of reaction
is . Calculate
for this reaction.
Soln From the stoichiometric equation
269.2 MEASUREMENT AND CALCULATION OF HEATS OF
REACTION HESSS LAW
- A heat of reaction may be measured in a
calorimeter - a closed reactor immersed in a fluid contained
in a - well-insulated vessel.
- The rise or fall of the fluid temperature can be
measured - and used to determine the energy released or
absorbed - by the reaction, and the values of may
then be cal- - culated from that energy and known reactant and
product - heat capacities.
27For example, you wish to determine for the
reaction
You can carry out the reactions
1.
2.
and determine their heats of reaction
experimentally. You may then construct a
process path for the reaction
3.
28Reaction(3)
25oC
25oC
Reaction(1)
Reverse of reaction(2)
25oC
29- This result could have been obtained more
concisely by - treating the stoichiometric equations for
reactions 1 and - 2 as algebraic equations. If the equation for
reaction 2 is - subtracted from that for reaction 1, the result
is
?
30Hesss law
If the stoichiometric equation for reaction 1 can
be obtained by algebraic operations
(multipliation by constants, addition, and
subtraction) on stoichiometric equations for
reactions 2, 3, , then the heat of reaction
can be obtained by performing the same
operations on the heats of reactions ,
,.
31Example 9.2-1 Hesss Law
The standard heats of the following combustion
reactions have been determined experimentally
Use Hesss law and the given heats of reaction to
deter- mine the standard heat of the reaction
Soln Since (4) 2??(2) 3?(3) - (1)
329.3 FORMATION REACTIONS AND HEATS OF FORMATION
- A formation reaction of a compound is the
reaction in - which the compound is formed from its elemental
- constituents as they normally occur in nature
(e.g. O2 - rather than O).
- The enthalpy change associated with the formation
of - 1 mole of the compound at a reference
temperature - and pressure (usually 25oC and 1 atm) is the
standard - heat of formation of the compound, .
33- Standard heats of formation for many compounds
are - listed in Table B.1 of this text and on Perrys
Cemical - Engineers Handbook. For example, for
crystalline - ammonium nitrate is given in Table B.1 as
-365.14kJ/mol, - signifying
- Similarly, for liquid benzene
or
- The standard heat of formation of an elemental
species - (e.g. O2) is zero.
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35- It may be shown using Hesss law that if ?i is
the - stoichiometric coefficient of the ith species
participating - in a reaction ( for products, - for reactants)
and - is the standard heat of formation of this
species, then - the standard heat of the reaction is
The standard heats of formation of all elemental
species should be set equal to zero in this
formula.
36(0)
(1)
(2)
(3)
(4)
37Example 9.3-1 Determination of Heat of Reaction
from Heats of Formation
Determine the standard heat of reaction for the
com- bustion of liquid n-pentane, assuming
H2O(l) is a combustion product.
Soln
? Heats of formation from Table B.1
389.4 HEATS OF COMBUSTION
- The standard heat of combustion of a substance,
, - is the heat of combustion of that substance with
oxygen - to yield specified products e.g., CO2(g) and
H2O(l), with - both reactants and products at 25oC and 1 atm
(the - arbitrary but conventional reference state).
- Table B.1 lists standard heats of combustion for
a - number of substances. The given values are based
on - the following assumptions (a) all carbon in the
fuel forms - CO2(g), (b) all hydrogen forms H2O(l), (c) all
sulfur forms - SO2(g), and (d) all nitrogen forms N2(g).
39- The standard heat of combustion of liquid
ethanol, for - example, is given in Table B.1 as
- which signifies
- Additional heats of combustion are given on
Perrys - Chemical Engineers Handbook.
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41- Standard heats of reactions that involve only
combustible - substances and combustion products can be
calculated - from tabulated standard heats of combustion, in
another - application of Hesss law.
- A hypothetical reaction path may be constructed
in which - (a) all combustible reactants are burned with O2
at 25oC - and (b) CO2 and H2O combine to form the reaction
pro- - ducts plus O2. Step (b) involves the reverse of
the com- - bustion reactions of the reaction products.
- Since both steps involve only combustion
reactions, the - total enthalpy change which equals the desired
heat of - reaction can be determined entirely from heats
of com- - bustion.
42- If any of the reactants or products are
themselves com- - bustion products CO2, H2O(l), SO2,, their
terms - in the above equation should be set equal to 0.
- Note that this formula is similar to that used to
determine - from heats of formation, except that
in this case - the negative of the sum is taken. The validity
of this for- - mula is illustrated in the next example.
43(0)
(1)
(2)
(3)
44Example 9.4-1 Calculation of a Heat of Reaction
from Heats of Combustion
Calculate the standard heat of reaction for the
dehy- dration of ethane
Soln From Table B.1,
??
45- One of the principal applications of
is to determine heats of formation for
combustible substances whose formation reactions
do not occur naturally. For example, the
formation reaction of pentane
cannot be carried out in a laboratory, but
carbon, hydro- gen, and pentane can all be
burned and their standard heats of combustion
determined experimentally. The heat of formation
of pentane may then be calculated from
469.5 ENERGY BALANCES ON REACTIVE PROCESSES
9.5a General Procedures
- To perform energy balance calculations on a
reactive - system, proceed much as you did for nonreactive
- systems
- Draw and label a flowchart
- Use material balances and phase equilibrium rela-
- tionships such as Raoults law to determine
as many - stream amounts or flow rates as possible
47(c) Choose reference states for specific enthalpy
(or internal energy) calculations and
prepare and fill in inlet-outlet enthalpy
(or internal energy) table and (d) Calculate
(or or ), substitute
the calculated value in the appropriate form
of the energy balance equation, and complete
the required calculation.
48- Two methods are commonly used to choose reference
- states for enthalpy calculations and to
calculate specific - enthalpies and .
- We outlet the two approaches below, using a
propane - combustion process to illustrate them.
- For simplicity, the material balance calculations
- for the illustrative process have been performed
and - the results incorporated into the flowchart.
4925oC
100 mol O2(g)/s 2256 mol N2(g)/s
100 mol C3H8(g)/s
Furnace
300 mol CO2(g)/s 400 mol H2O(g)/s
600 mol O2(g)/s 2256 mol N2(g)/s
300oC
1000oC
50Heat of Reaction Method. This method is
generally preferable when there is a single
reaction for which is known.
- Complete the material balance calculations on the
- reactor to the greatest extent possible.
- 2. Choose reference states for specific enthalpy
- calculations. The best choices are generally
reactant - and product species at 25oC and 1 atm in the
states - for which the heat of reaction is known
C3H8(g), O2(g), - CO2(g), and H2O(l) in the example process,
and non- - reacting species at any convenient
temperature, such - as the reactor inlet or outlet temperature or
the - reference condition used for the species in an
available - enthalpy table N2(g) at 25oC and 1 atm, the
reference - state for Table B.8
513. For a single reaction in a continuous process,
calculate the extent of reaction, . When
writing the equation, choose as species A any
reactant or product for which the feed and
the product flow rates are known.
In the example, we may choose any reactant or
product since we know all inlet and outlet
species flow rates and calculate the rate of
consumption or generation of A as
. If A is propane
524. Prepare the inlet-outlet enthalpy table,
inserting known molar amounts ( ) or flow
rates ( ) for all inlet and outlet
stream components. If any of the components is
at its reference state, insert 0 for the
corresponding .
ReferencesC3H8(g), O2(g), N2(g), CO2(g), H2O(l)
at 25oC and 1 atm
535. Calculate each unknown stream component
enthalpy, , as for the species
going from its reference state to the
process state, and insert the enthalpies in
the table. In the example, from Table B.8
We proceed in the same manner to calculate
546. Calculate for the reactor. Use one of
the following formulas
A derivation of these equations is outlined
following the presentation of the heat of
formation method. Substi- tution of the
previously calculated values into the above
equation yields
7. Substitute the calculated value of in
the energy balance and complete the required
calculations.
55Heat of Formation Method. This method is
generally preferable for multiple reactions and
single reactions for which is not
readily available.
- Complete the material balance calculations on the
- reactor to the greatest extent possible.
- 2. Choose reference states for enthalpy
calculations. - (This is the step that distinguishes the
preceding - method from this one.) The choices should be
the - elemental species that constitute the
reactants and - products in the states in which the elements
are found - at 25oC and 1 atm in the states C(s), H2(g),
etc. and - nonreacting species at any convenient
temperature. - In the example, the reference states would be
C(s), - H2(g), and O2(g) at 25oC ( the elemental
species - constituting the reactants and products), and
N2(g) at - 25oC the reference temperature for Table B.8
563. Prepare the inlet-outlet enthalpy table,
inserting known molar amounts ( ) or flow
rates ( ) for all inlet and outlet
stream components. For the example process,
the table would appear as follows
References C(s), H2(g), O2(g), N2(g) at 25oC
and 1 atm
574. Calculate each unknown specific enthalpy. For
a reac- tant or product, start with the
elemental species at 25oC and 1 atm (the
references) and form 1 mol of the pro- cess
species at 25oC and 1 atm (
from Table B.1). Then bring the species from
25oC and 1 atm to its process state,
calculate using the appropriate heat
capacities from Table B.2, specific enthalpies
from Table B.8 or B.9, and latent heats from
Table B.1. The specific enthalpy that goes
in the inlet-outlet table is the sum of the
enthalpy changes for each step in the process
path.
58- In the example, we would first calculate the
specific - enthalpy of the entering propane as
follows
- This is the enthalpy of propane at 25oC (the
process - state) relative to C(s) and H2(g) at 25oC (the
reference - state).
- If the propane had entered at a temperature T0
other - than 25oC, a term of the form
would be - added to the heat of formation of propane.
59- Next, we calculate the specific enthalpy of O2 at
300oC - (the process state) relative to O2 at 25oC (the
reference - state) as (from Table
B.8). There is no - heat of formation term, since O2 is an elemental
species. - We proceed in the same manner to calculate
- ,
, - , and
. - To calculate and , we form the
corresponding - species CO2(g) and H2O(v) at 25oC from their
elements - ( ), then heat them from 25oC to
1000oC - ( from Table B.8), and add
the formation - and heating terms.
605. Calculate for the reactor. For both
single and mul- tiple reactions, the formula is
- Note that heat of reaction terms are not required
if the - elements are chosen as references.
- The heats of reaction are implicitly included
when the - heats of formation of the reactants (included in
the - terms) are subtracted from those of the products
( in - the terms) in the expression for .
Therefore
616. Substitute the calculated value of in
the energy balance equation and complete the
required calculations.
The process paths that correspond to the heat of
reaction and heat of formation methods are shown
below.
Reactants Tin
Products Tout
Products 25oC
Reactants 25oC
(a) Process path for heat of reaction method
62Reactants Tin
Products Tout
Reactants 25oC
Products 25oC
(a) Process path for heat of reaction method
63Reactants Tin
Products Tout
Elements 25oC
(b) Process path for heat of formation method
64Example 9.5-1 Energy Balance About an Ammonia
Oxidizer
The standard heat of reaction for the oxidation
of ammonia is given below
One hundred mol NH3/s and 200 mol O2/s at 25oC
are fed into a reactor in which the ammonia is
completely consumed. The product gas emerges at
300oC. Cal- culate the rate at which heat must
be transferred to or from the reactor, assuming
operation at approximately 1 atm.
65Soln
Basis Given Feed Rates
Since only one reaction takes place and
is known, we will use the heat of reaction
method for the energy balance, choosing as
references the reactant and product species in
the states for which the heat of re- action is
given.
66The enthalpy table appears as follows
References NH3(g), O2(g) ), NO(g) , H2O(v)at
25oC and 1 atm
67Calculate Unknown Enthalpies
Calculate and
Since 100 mol NH3/s is consumed in the process
68From table
69Energy Balance
For this open system,
Thus, 19,700kW of heat must be transferred from
the reactor to maintain the product temperature
at 300oC. If less heat were transferred, more of
the heat of reac- tion would go into the
reaction mixture and the outlet temperature
would increase.
709.5b Processes with Unknown Outlet Conditions
Adiabatic Reactors
- In the reactive systems we have looked at so far,
the inlet - and outlet conditions were specified and the
required heat - input could be determined from an energy
balance. - In another important class of problems, the input
condi- - tions, heat input, and product composition are
specified, - and the outlet temperature is to be calculated.
To solve - such problems, you must evaluate the enthalpies
of the - products relative to the chosen reference states
in terms - of the unknown final temperature, and then
substitute the - resulting expressions into the energy balance (
) - to calculate Tout.
719.5c Thermochemistry of Solutions
The enthalpy change associated with the formation
of a solution from the solute elements and the
solvent at 25oC is called the standard heat of
formation of the solution. If a solution
contains n moles of solvent per mole of solute,
then
where is the heat of solution at 25oC
(Section 8.5). From the definitions of
and , the dimensions of the heat of
formation of the solution are (energy)/(mole of
solute).
72The standard heat of a reaction involving
solutions may be calculated from heats of
formation of the solutions. For example, for the
reaction
the standard heat of reaction is
73The last equation signifies that if a solution
containing 2 mol of HNO3 in 50 mol of H2O(r25)
is neutralized at 25oC with 1 mol of Ca(OH)2
dissolved in enough water so that the addition
of more water would not cause a measurable
enthalpy change (r?), the enthalpy change is
-114.2 kJ.
74If a standard heat of formation is tabulated for
a solution involved in a reaction, the tabulated
value may be sub- stituted directly into the
expression for , otherwise,
must first be calculated by adding the standard
heat of formation of the pure solute to the
standard heat of solution.
759.4 FUEL AND COMBUSTION
- The use of heat generated by a combustion
reaction to - produce steam, which drives turbines to produce
electri- - city, may be the single most important
commercial appli- - cation of chemical reactions.
- The analysis of fuels and combustion reactions
and - reactors has always been an important activity
for che- - mical engineers. In this section, we review the
properties - of the fuels most often used for power
generation and - outline techniques for energy balances on
combustion - reactors.
769.6a Fuels and Their Properties
Fuels burned in power-plant furnaces may be
solids, liquids, or gases. Some of the more
common fuels are Solid fuels Principally coal
(a mixture of carbon, water, noncombustible
ash, hydrocarbons, and sulfur), coke( primarily
carbon the solid residue left after coal or
petroleum is heated, driving off volatile
substances and decomposing hydrocarbons), and
to a small extent wood and solid waste
(garbage).
77Liquid fuels Principally hydrocarbons obtained
by distilling crude oil (petroleum) also coal
tars and shale oil. There is also a strong
worldwide interest in the use of alcohols
obtained by fermenting grains. Gaseous fuels
Principally natural gas (80 to 95 methane,
the balance ethane, propane, and small
quantities of other gases) also light
hydrocarbons obtained from petroleum or coal
treatment, acetylene, and hydrogen (the latter
two are relatively expensive to produce).
78- The heating value of a combustible material is
the - negative of the standard heat of combustion.
The - higher heating value (or total heating value or
- gross heating value) is with H2O(l)
as a - combustion product, and the lower heating value
( - or net heating value) is the value based on
H2O(v) - as a product. Since is always negative,
the - heating value is positive.
- To calculate a lower heating value of a fuel from
a - higher heating value or vice versa, you must
determine - the moles of water produced when one mole of
the - fuel is burned. If this quantity is designated
n, then
79The heat of vaporization of water at 25oC is
If a fuel contains a mixture of combustible
substances, its heating value (lower or higher)
is
where (HV)i is the heating value of the ith
combustible substance. If the heating values are
expressed in units of (energy)/(mass), then the
xis are the mass fractions of the fuel
components, while if the dimensions of the
heating values are (energy)/(mole) then the xis
are mole fractions.
80- Higher heating values for common solid, liquid,
and - gaseous fuels are tabulated in Section 27 of
Perrys - Chemical Engineers Handbook. Representative
values - are given in Table 9.6-1. From the standpoint of
heating - value per unit mass, hydrogen is clearly the
best fuel - however, it does not occur naturally in
appreciable - quantities and the current cost of producing it
makes it - less economical than the other fuels in Table
9.6-1.
81Table 9.6-1 Typical Heating Values of Common Fuels
Higher Heating Value
Fuel
kJ/g Btu/lbm
Wood 17
7700 Soft coal
23 10000 Hard coal
35 15000 Fuel
oil, gasoline 44
19000 Natural gas
54 23000 Hydrogen
143 61000
829.6b Adiabatic Flame Temperature
- When a fuel is burned, a considerable amount of
- energy is released. Some of this energy is
transferred - as heat through the reactor wall, and the
remainder - raises the temperature of the reaction products
the - less heat transferred, the higher the product
- temperature.
- The highest achievable temperature is reached if
the - reactor is adiabatic and all of the energy
released by - the combustion goes to raise the temperature of
the - combustion products. This temperature is called
the - adiabatic flame temperature, Tad.
83- The calculation of an adiabatic flame temperature
follows - the general procedure outlined in Section 9.5b.
- Unknown stream flow rates are first determined by
ma- - terial balances.
- Reference conditions are chosen, specific
enthalpies of - feed components are calculated, and specific
enthalpies - of product components are expressed in terms of
the - product temperature, Tad.
- Finally, for the process is evaluated
and substi- - tuted into the energy balance equation,
- which is solved for Tad.
84- Suppose (mol/s) of a fuel species with heat
of com- - bustion is burned completely with pure
oxygen or - air in a continuous adiabatic reactor. If the
reference - states of the molecular feed and product species
are - those used to determine , the enthalpy
change - from inlet to outlet is determined from
Since the reactor is adiabatic, in the
energy balance. If shaft work and kinetic and
potential energy changes
are negligible compared to each of the first two
terms in the expression for , the
85 energy balance simplifies to
which in turn leads to
Once again, the reference states for
determination of the specific enthalpies in
this equation must be those used to determine
the value of .
869.6c Flammability and Ignition
- In this section and the one that follows, we
discuss qua- - litatively that happens during the rapid
chemical reaction - between a fuel and oxygen. Along the way, we
provide - answers to the following questions
- What is a flame? Why are some flames blue and
some - yellow?
- 2. If you light a match in a mixture of methane
and air that - contains 10 CH4 by volume, the mixture will
burn ex- - plosively, but if the mixture contains 20
CH4 nothing - will happen. Why?
87- 3. What is an explosion? What is the loud noise
you hear - when something explodes?
- 4. Hydrogen and oxygen react explosively to form
water, - yet if you mix these two gases in a flask,
nothing - happens. Why not?
- We have so far in this text only considered the
initial and - final conditions in a chemical reactor, and not
how long - it may have taken to get from one to the other.
- When you study chemical reactor kinetics, you
will learn - that the rate of a reaction depends strongly on
the reac- - tion temperature for many reactions, a
temperature rise - of only 10oC is enough to double the rate.
88- Suppose a mixture of methane and air containing
- 10 mole CH4 is heated by a central heat source
(e.g., - an electrical coil) at atmospheric pressure,
beginning at - room temperature. Although methane reacts with
oxygen
- the reaction proceeds at an immeasurably low
rate at - room temperature, and to an observer nothing
would - seem to be happening in the reactor.
- As the temperature increases, the rate of the
oxidation - reaction also increases, and measurable amounts
of - CO2 and H2O appear.
89- However, if the heat source is turned off, the
reactor - temperature drops again the rate at which heat
is - generated by the reaction alone is not enough to
com- - pensate for the rate at which heat is lost from
the - reaction zone.
- However, if the temperature at any point in the
reactor - reaches about 640oC or higher, the rate of heat
gener- - ation by the reaction exceeds the rate of heat
loss from - the reaction zone. The gas adjacent to this zone
is then - heated above 640oC, causing the zone of rapid
reaction - to spread.
- The temperature of the gas rapidly rises by
several - hundred or even a thousand degrees in a fraction
of a - second
90- Even if the heating source is turned off, the
rate of heat - generation by the now rapidly occurring reaction
is - enough to maintain the system at its high
temperature - until the reactants are exhausted.
- Combustion is defined as a rapid,
high-temperature - oxidation reaction. What happens in the reactor
just - described after the reaction rate accelerates
dramatically - is combustion, whereas the initial slow
oxidation reaction - between methane and oxygen to form CO2 and H2O
and - other reactions between these species, such as
the for- - mation reaction of formaldehyde
- are not classified as combustion reactions.
91- The rapid increase in the rate of an oxidation
reaction - when the reaction mixture exceeds a certain
temperature - is called ignition the temperature at which
this pheno- - menon occurs is called the ignition temperature,
and - the time between the instant when the mixture
reaches - the ignition temperature and the moment of
ignition is the - ignition lag.
- The value of the ignition temperature depends on
a - number of things for a given fuel, including the
fuel-to-air, - the total pressure in the reactor, and even the
reactor - geometry.
-
- For any given fuel, there is a lower limit to
this quantity - called the autoignition temperature.
92- The ignition temperature and lag are shown here
on a - representative plot of the temperature of a fuel
mixture - that is being heated.
93- Representative values of this quantity for
stoichiometric - fuel air mixtures at 1 atm are 400oC for H2,
540oC for - CH4, and 515oC for C2H6. Ignition lags are
typically 0.1 - 10 s in duration and decrease with increasing
temper- - ature above the autoignition temperature.
- The highest attainable temperature in a
combustion re- - action the adiabatic flame temperature
depends on - the fuel-to-air ratio, and this upper
temperature limit is a - maximum when the fuel and oxygen are present in
stoi- - chiometric proportion.
- If the mixture is either rich (fuel in excess) or
lean (O2 - in excess), the adiabatic flame temperature
decreases.
94- There exist two values of the mole percent of
fuel in a - reaction mixture the lower or lean
flammability limit - and the upper or rich flammability limit for
which the - adiabatic flame temperature equals the ignition
temper- - ature of the mixture.
- A fuel-air mixture whose composition falls
outside - these limits is incapable of igniting or
exploding, even if - exposed to a spark or flame.
- The composition range between the two
flammability - limits is called the explosive range of the
mixture.
95- For example, the stoichiometric percentage of
- methane in a methane-air mixture is 9.5 mole.
- Experimentally, it is found that the lower
flammability - limit of CH4-air mixtures at 1 atm is
approximately 5 - CH4 and the upper flammability limit is
approximately - 15 CH4.
- Thus, a CH4-air mixture containing between 5 CH4
- and 15 CH4 must be considered a fire or
explosion - hazard, while a mixture containing 3 CH4 may be
- considered safe, and a mixture containing 18
CH4 - may also be considered safe as long as it is not
- brought into contact with additional oxygen.
96- Flammability limits of a number of hydrogenair
mixtures - are listed in tables on pp. 26-53 and 26-54 of
Perrys - Chemical Engineerings Handbook. The given
values - apply to an initial temperature of roughly 25oC
and a - pressure of 1 atm.
- If a liquid (or a volatile solid) is exposed to
air, the vapor - given off could form a combustible mixture with
the air - adjacent to it, and a spark or match lit in the
vicinity of - the liquid could cause the mixture to ignite or
explode. - If flash point of a liquid is the temperature at
which the - liquid gives off enough vapor to form an
ignitable mixture - with the air above the liquid surface.
97- The flash point of gasoline, for example, is
roughly - 42oC, and that of ethanol is 13oC, so that these
liquids - constitute fire hazards at room temperature,
while the - flash points of fuel oils vary from 38oC to
55oC, making - the hazards associated with these materials
consi- - derably less.
989.6d Flames and Detonations
- Suppose a combustible gas-air mixture is
contained in - an open-ended tube, and a match or another
ignition - sources is applied to one end of the tube. The
gas mix- - ture at this end is heated and eventually
ignites. - The intense heat generated by the combustion
reaction - raises the chemical species formed during the
reaction - to high energy states.
- When these species return to lower energy states,
- some of the energy they lose is given off in the
form of - light. The result is a visible flame
accompanying the - combustion.
99- Initially the flame is located at the end of the
tube that - was ignited. However, the heat of combustion
quickly - raises the adjacent unburned gas to its ignition
point, - causing the flame to travel toward the other
end of - the tube.
- The flame front moves in the direction of the
unburned - gases at a velocity called the flame velocity,
which - typically has a value of 0.3 to 1 m/s.
- The exact value of the flame velocity depends on
a - number of things, including the type of fuel,
fuel-to-air - ratio, initial temperature and pressure of the
unburned - gases, and the geometry of the combustion
chamber.
100At some point, the tube appears as follows.
101- Suppose now that instead of being stationary in
the - tube, the combustion mixture is fed continuously
into - the bottom (as in a Bunsen burner), and the top
is - ignited. If the velocity with which the gases
leave the - tube equals the velocity with which the flame
would - travel down in a stationary gas, a stationary
flame - is achieved at the top.
-
- The wall of the tube lowers the flame velocity,
so that - the flame burns at the end but does not
penetrate into - the tube.
102Flame
103- If the gas flow rate is increased, the flame size
and rate - of heat generation both increase, since a larger
quantity - of gas is being burned.
- However, once the flow rate reaches a critical
value, the - flame can no longer travel back as fast as the
combus- - tion region is transported away from the burner.
The - gases in the combustion region become
increasingly - diluted with air, until the region finally falls
outside the - flammability limits and the fire is literally
blown out. - On the other hand, if the gas flow rate to the
burner tube - is decreased, the gas velocity in the tube may
become - lower than the flame propagation velocity in the
tube. - The result is flashblack.
104- Flashback means the flame travels back through
the - tube toward the fuel source. Flashback is
extremely - dangerous, and any flow system involving
combustible - gases must be designed to guarantee that flow
rate - stays above the flame propagation velocity.
- When combustion of a well-mixed fuel-air mixture
- occurs, the fuel rapidly reacts with oxygen to
form a - number of unstable intermediate species (such as
oxy- - gen and hydrogen atoms, and OH and H2O
radicals), - which then proceed through a complicated chain
me- - chanism to form CO2 and H2O.
105- Some of these species undergo transitions that
cause - them to emit radiation whose wavelength falls
within - the blue region of the visible spectrum. The
result is that - the flame appears blue.
- On the other hand, when the fuel and air are not
well - mixed (such as when a pure hydrocarbon gas is
burned - as it emerges from a stack and mixes with
atmospheric - air), the combustion proceeds relatively slowly,
and some - of the hydrocarbon fuel decomposes to form
elementary - carbon and hydrogen before oxidation takes
place. - The heat of reaction is sufficient to raise the
temperature - to a point where the carbon particles glow
incandescently. - A yellow flame is the result.
106- Finally, suppose ignition of a gas takes place in
a con- - fined or partially confined space.
- The large temperature rise in the combustion
region - causes a rapid buildup of pressure in this
region. - If the combustion is fast enough and the heat of
reac- - tion is high enough, a detonation may result,
wherein - a sharply defined high-pressure front, or shock
wave, - travels through the gas at a velocity well in
excess of - the flame propagation velocity in the gas. The
shock - wave rapidly compresses and ignites the gas as
it - passes through, giving the appearance of an
instan- - taneous combustion.
107- Even after the combustion reaction that gave rise
to - the detonation has consumed all the available
fuel, - the shock wave can persist for large distances,
- carrying with it considerable energy.
- The energy of even a small shock wave is
sufficient - to vibrate the eardrums of anyone near the site
of - the detonation, producing the bang that always
- accompanies an explosion. The energy of a large
- shock wave may be sufficient to demolish a city.