Title: Chapter 15 Chemical Equilibrium
1Chapter 15Chemical Equilibrium
2For the gas-phase reaction A B the
forward reaction rate is 3.0 ? 10?4 s?1 and the
reverse reaction rate is 1.5 ? 10?2 s?1. What is
the value of the equilibrium constant, Keq?
3Correct Answer
4 5Correct Answer
This is definitely a heterogeneous equilibrium
because the reactants and products exist in two
different phases, the solid and gaseous states.
6Which of the following is the correct Keq for the
equilibrium equation below? 2 Ag(s) Zn2(aq)
2 Ag(aq) Zn(s)
7Correct Answer
2AgZn
- Keq ___________
- Keq ___________
- Keq ___________
2AgZn2
Zn2
- 4. Keq _________
- 5. Keq _________
2Ag
Ag2Zn
Zn2
Ag2Zn2
Ag2
Ag2
Zn2
8Correct Answer (cont.)
Remember the equilibrium constant expression is
given in terms of concentrations of products
(raised to the exponent of their coefficients)
divided by concentrations of reactants (raised to
the exponent of their coefficients). Pure
solids, liquids, and solvents are not included in
the expression.
9For the following hypothetical reaction 2 Y(aq)
3 Z(aq) A(aq) Calculate Keq given the
following equilibrium concentrations A 0.50
M, Y 0.10 M, Z 1.0 M
10Correct Answer
0.50
K
eq
3
2
1.0
0.10
11For the following hypothetical reaction 2 X(g)
Y(g) A(g) Keq 250. At a point during
the reaction, the concentrations are A 1.0 M,
X 0.50 M, and Y 0.10 M. How will the
reaction proceed to achieve equilibrium?
- From left to right (toward products)
- From right to left (toward reactants)
- Already at equilibrium
12Correct Answer
- From left to right (toward products)
- From right to left (toward reactants)
- Already at equilibrium
1.0
K
c
2
0.10
0.50
Because Kc lt Keq, the reaction will shift from
reactants toward products to achieve equilibrium.
13For the following hypothetical reaction Y(g)
Z(g) 2 A(g) Keq 4.0 ? 10?2. Given that,
what is the value of Keq for the reaction 4 A(g)
2 Y(g) 2 Z(g)
14Correct Answer
The second equation is twice the first and
reversed. Thus, Keq of the second equation is
related to the first as shown below
15The following reaction is at equilibrium N2(g)
3 H2(g) 2 NH3(g) If we remove NH3(g), in what
direction will the reaction move to reestablish
equilibrium?
- From left to right (toward products)
- From right to left (toward reactants)
- No change in equilibrium
16Correct Answer
- From left to right (toward products)
- From right to left (toward reactants)
- No change in equilibrium
If NH3 is decreased, to return to equilibrium,
more NH3 must be produced from the reactants.
Thus, the reaction shifts from the reactants to
the products.
17The following reaction is at equilibrium N2(g)
3 H2(g) 2 NH3(g) If we increase the volume
while holding the temperature constant, in what
direction will the reaction move to reestablish
equilibrium?
- From left to right (toward products)
- From right to left (toward reactants)
- No change in equilibrium
18Correct Answer
- From left to right (toward products)
- From right to left (toward reactants)
- No change in equilibrium
Increasing the volume causes a shift in the
equilibrium in the direction that produces more
gas molecules, in this case on the reactants side.
19The following reaction is at equilibrium N2(g)
O2(g) 2 NO(g) If we increase the pressure,
in what direction will the reaction move to
reestablish equilibrium?
- From left to right (toward products)
- From right to left (toward reactants)
- No change in equilibrium
20Correct Answer
- From left to right (toward products)
- From right to left (toward reactants)
- No change in equilibrium
The number of gas molecules on both sides of the
equation are equal thus, changing the pressure
will not change the equilibrium position.
21The following reaction is at equilibrium N2(g)
O2(g) 2 NO(g) DH 180.8 kJ. In what
direction will the reaction move to reestablish
equilibrium if the temperature is decreased?
- From left to right (toward products)
- From right to left (toward reactants)
- No change in equilibrium
22Correct Answer
- From left to right (toward products)
- From right to left (toward reactants)
- No change in equilibrium
As the temperature is lowered, equilibrium will
shift to the side of the equation that produces
heat. Thus, for an endothermic reaction, the
equilibrium shifts from right to left toward the
reactants.