Title: NETWORKS 2: ECE 09'202'01
1 CHAPTER 10
- NETWORKS 2 ECE 09.202.01
- 25 October 2006 Lecture 2
- ROWAN UNIVERSITY
- College of Engineering
- Dr Peter Mark Jansson, PP PE
- DEPARTMENT OF ELECTRICAL COMPUTER ENGINEERING
- Autumn Semester 2006 Quarter Two
2Review Chapter 10 key concepts
- Todays learning objectives
- terminology for sinusoidal sources
- Phase angles in progress
- analyzing sinusoidal sources (10.2)
- steady-state response of an RL circuit to a
sinusoidal forcing function (10.3) - complex exponential forcing function
- the phasor concept (10.5)
3Figure 10.3-4 Right Triangle for A and B -
Trigonometry is helpful here
sin ? B/C, cos ? A/C, tan ? sin/cos B/A
4Phase angle (?)
- if a current and voltage waveform are out of
phase with each other this difference is referred
to as a phase angle (leading or lagging). - It (?) can be expressed as a difference in
degrees or radians - It can also be observed in the functions that
represent these waveforms as a time difference
5i(t) has the non-zero Phase angle and it is
leading the voltage why?
Write answer as LC1
6representing signals by equations
- typical problem encountered by ECEs
- solution is straightforward
- 1. measure the amplitude (A)
- 2. determine the period (T), calculate frequency
? 2?f - 3. Pick a time (t) and measure v (or i), observe
ascending or descending and finally, calculate
phase angle ?
When v(t) is ascending at time t1
When v(t) is descending at time t1
7sample problem analytic representation of
sinusoidal voltage waveforms v1(t) and v2(t) of
the form v(t)Acos(?t?)
2A30V, T0.2 sec Determine Vm and ?
8continuing sample problem
- 2A 30V, A Vmax 15V
- ? 2?/T 2?/0.2 10?
- At circled point v1(t) is going up (ascending
with time) and values are - v1(t) 10.6066V
- t 0.15 sec
- So
9continuing sample problem
If you calculated this on your calculator you
should find that ?-5.4977873 radians is the
answer (remember 2? radians 6.28 radians). This
equates to how many degrees? -315o 45o
Write the final analytic equation for v1(t) in
this form as LC2
10do the same for v2(t)
At circled point v2(t) is going down (descending
with time) and values are v2(t) 10.6066V t
0.15 sec
Write the final analytic equation for v2(t) in
this form as LC3
11some practice problems
- a voltage is v6cos(4t30o)
- (a) find the period of oscillation
- (b) find phase relation to associated current i
8cos(4t-70o) - (a) T2?/? since ?4 T2?/4 ?/2
- (b) (i.e., voltage leads/lags the current by x
degrees) write answer as LC4
12more practice
- a voltage is v3cos4t4sin4t
- (a) find the voltage in the form below
- REMEMBER
?tan-1(B/A) when Agt0 and ? 180o tan-1(B/A)
when Alt0 Write your answer as LC5
13steady-state response of circuit to sinusoidal
forcing function
When vs(t) Vm cos ?t, the complete response
looks like this i(t) in if Ke-t/? Imax
cos (?t ?)
14Over time the transient term dies out
- the steady-state response that is left is
i(t) Imax cos (?t ?) - applying our Net 1 knowledge about KVL in this
loop we find - Vmax cos ?t L(di/dt) Ri
- substituting i(t) above into this we find after
many calculations
15Example
If vs(t)10 cos 3t V and L1H, R4? what is
i(t)? Provide your answer as LC6
16 NOTE
- HW Problem 10.3-1, p. 474 is identical to this
problem we just solved (only the L, R, Z and ?
are different) so finish it today while it is
fresh in your memory
17Net II and complex math
- net I relied heavily on Algebra, some trig and
1st order differential equations - net II requires complex math as well as 1st and
2nd order differential equations - lets review some..
18Complex numbers
19Complex numbers
20Rectangular, Exponential and Polar Notation
- In the Complex Plane where x is the real part of
the complex number and y is the imaginary portion
of the complex number we can express the complex
number c in three very distinct ways (or
notations) - Rectangular c a jb
- Exponential c rej?
- Polar c r??
21Lets express c in all forms
- If c 4 j3
- What is it in exponential form?
- What is r?
- r (a2 b2)1/2
- r (42 32)1/2 (16 9)1/2 5
- What is ??
- ? tan-1(b/a) when agt0
- ? tan-1(3/4) 36.9o
- Write c rej?as LC7
- Write c in polar form as LC8
22Operations with complex numbers
- on board
- REMEMBER
- Easiest to subtract and add complex numbers in
rectangular form - Easiest to multiply and divide these numbers when
in polar form
23More useful relationships.
24practice notation examples
Find a and b if Provide your answer as
LC9 Find A and ? if Provide your answer as
LC10
25If you forget complex s
- See Appendix B in the back of the text, pp.
833-836
26How can we apply this?
- GUARANTEED to make solutions of net II problems
easier - Well, first a bit of tougher learning then a
greater simplification that will make our lives
enormously easier.
27Complex exponential forcing function
- the process
- 1. write the excitation (the forcing function) as
a cosine waveform with a phase angle - 2. introduce complex excitation (Eulers
identity) - e j? cos ? j sin ? (where ? ?t ?)
- 3. use the complex excitation and circuit
differential equation along with assumed response
- 4. determine the constant A Be-j? so that
desired response is achieved - xe Ae j(?t ?) Be j(?t ? - ?)
28steady-state response of circuit to complex
exponential forcing function
An EXAMPLE assume R 2?, L 1H, and vs 10
sin 3t V
step 1) write source as cosine waveform with
phase angle sovs 10 sin 3t V 10 cos
(3t90o), step 2) introduce complex excitation,
so ve 10 e j(3t-90o)
29continuing our solution
- step 3) introduce complex excitation into
circuits diff. equation - ve L(die/dt) Rie
- obtaining
- 10 e j(3t-90o) die/dt 2Rie
- assuming our response is of the form ie Ae
j(3t-90o) - step 4) substitute, take the derivative and find
the constant - j3Ae j(3t-90o) 2Ae j(3t-90o) 10 e j(3t-90o)
30hw problem 10.4-6
- Find the steady state response if vs(t) cos 2t
V
31hw problem 10.4-6
Replace the real excitation by a complex
exponential excitation to get
Let
so
32hw problem 10.4-6
Substituting
33hw problem 10.4-6
Finally
34Steinmetz observed this process
- and it led to the phasor concept
- the phasor concept may be used when the circuit
is linear, the steady-state response is sought
and all independent sources are sinusoids of the
same frequency - a transform is a change in the mathematical
description of a physical variable to facilitate
computation - a phasor is a transformed version of a sinusoidal
voltage or current waveform and consists of the
magnitude and phase angle information of the
sinusoid
35remember
36Transforming from the Time Domain ?
to the Frequency Domain
- Write time domain function, y(t) as a cosine
waveform with phase angle - Express cosine waveform as complex quantity using
Eulers identity - Drop the real part notation
- Suppress the ej?t while noting ? for future use
37example
- i 5 sin(100t120o)
- Lets convert to the frequency domain
- I Im??
Provide your answer as LC11
38LC 12
- i 4 cos(20t - 80o)
- Lets convert to the frequency domain
- I Im??
39Transforming from the Frequency Domain ?
to the Time Domain
- Write the phasor in exponential form
- Reinsert the factor ej?t
- Reinsert the real part operator Re
- Use Eulers identity to obtain the time function
40example
- V 24?125o
- Lets convert to the time domain
- v(t) Vm cos(?t ?)
41LC 5
- V 10?-140o
- Lets convert to the frequency domain
- I Im??
42Why use Phasors?
- The phasor method uses the transformation from
the time domain to the frequency domain to more
easily obtain the sinusoidal steady-state
solution of the differential equation
RC circuit example
RL circuit example
43RL example solution on board
vs(t) Vm cos 100t V , R 200?, L 2H
44RC example solution below
i(t) 10 cos 100t A, R1?, C 0.01F
45hw problem 10.6-1
- v(t) 15 cos 4t V, R6?, L2H
- find v(t) for inductor, steady-state
v(t) -
46Phasor representation
- transformation from time domain to the frequency
domain - converts solution of a differential equation to
an algebraic one - we must now learn the phasor relations on R,L
C elements
47Resistors
- V RI
- if V 10?0o, (v10 cos 30 t) and R 5
- what does I ?
- I V/R v/R2 cos 30 t
48R time domain vs. frequency domain
49LC 6
- current in a resistor is
- i 2 cos 100t A
- Find the steady-state voltage across the resistor
if its resistance is 10?
50Inductors
- V j?LI
- In a purely inductive circuit the voltage leads
the current by exactly 90o (or current lags by
90o) - if V 10?50o, and L2,?100 rads/s
- what does I ?
- I V/ j?L V/ j200 10?50o/200?90o
- I 0.05 ?-40o
51L time domain vs. frequency domain
52LC 7
- current in an inductor is
- i 2 cos 100t A
- Find the steady-state voltage across the inductor
if its inductance is 10 mH
REMEMBER voltage leads the current by exactly
90o
53Capacitors
- V (1/j?C)I
- In a purely capacitive circuit the current leads
the voltage by exactly 90o (or voltage lags by
90o) - if V 10?50o, and L2,?100 rads/s
- what does I ?
- I V/ j?L V/ j200 10?50o/200?90o
- I 0.05 ?-40o
54C time domain vs. frequency domain
55LC 8
- current in a capacitor is
- i 2 cos 100t A
- Find the steady-state voltage across the
capacitor if its capacitance is 1 mF
REMEMBER current leads the voltage by exactly
90o
56Why use Phasors?
- Lets compare algebra to diff-eqs
- Example 10.7-1
57Table 10.7-1 Time Domain and Frequency Domain
Relationships.
58Impedance (Z) and Reactance (X)
Z V/I
59Impedance (Z) and Reactance (X)
- Z (impedance) of an element is the ratio of the
phasor voltage V to the phasor current I
60KCL/KVL in the time frequency domains
61Current and voltage division
- current divider and voltage divider rules hold
for phasor currents and voltages - we substitute Impedance (Z) for Resistance (R)
in the frequency domain
62Node voltage, mesh current, supernodes, Thevenin
and Norton all work in the frequency domain
- all that work in Net 1 will really begin to pay
off
63Phasor diagrams