Title: DNA Testing
1DNA Testing
Bell Ranch New Mexico
2(No Transcript)
3(No Transcript)
4(No Transcript)
5Lecture 15
Breeding Values
6Genotype Frequency Phenotype Genetic
Value B1B1 p2 P11 V11 B1B2
2pq P12 V12 B2B2 q2 P22 V22
7Genotype Frequency Phenotype Genetic
Value B1B1 p2 P11 V11 B1B2
2pq P12 V12 B2B2 q2 P22 V22 Pij mgt
Vij
8Genotype Frequency Phenotype Genetic
Value B1B1 p2 P11 V11 B1B2
2pq P12 V12 B2B2 q2 P22 V22 Pij mgt
Vij mgt (P11 P22) / 2
9Genotype Frequency Phenotype Genetic
Value B1B1 p2 P11 V11 B1B2
2pq P12 V12 B2B2 q2 P22 V22 Pij mgt
Vij mgt (P11 P22) / 2 ? mgt (p - q) V11
2pq V12 (if equil)
10Genotype Frequency Phenotype Genetic
Value B1B1 p2 P11 V11 B1B2
2pq P12 V12 B2B2 q2 P22 V22 Pij mgt
Vij mgt (P11 P22) / 2 ? mgt (p - q) V11
2pq V12 (if equil)
AGV
11Genetic Value
12Genetic Value
The contribution of the genotype to the
expression of a characteristic
13Genetic Value
The contribution of the genotype to the
expression of a characteristic
Scenario V11 V12 (complete dominance)
14Genetic Value
The contribution of the genotype to the
expression of a characteristic
Scenario V11 V12 (complete
dominance) Performance is equal. P11 P12
15Phenotype
P11
Represent Ps
P22
A2A2
A1A2
A1A1
16Genetic Value
Two components for a single locus
17Genetic Value
Two components for a single locus 1) value of
individual alleles (B1 vs. B2 -- additive or
breeding value)
18Genetic Value
Two components for a single locus 1) value of
individual alleles (B1 vs. B2 -- additive or
breeding value) 2) value of the allele
combination in each individual (dominance value)
19ANIMAL
GENETIC VALUE
BREEDING VALUE
OWN PERFORMANCE
PROGENY
20ANIMAL
GENETIC VALUE
BREEDING VALUE
OWN PERFORMANCE
Parents can only pass on individual genes, not
combinations.
PROGENY
21To assess the value of an animal as a parent, we
evaluate the value of the genes it will
transmit.
22To assess the value of an animal as a parent, we
evaluate the value of the genes it will
transmit. Breeding Value (Additive Genetic
Value)
23To assess the value of an animal as a parent, we
evaluate the value of the genes it will
transmit. Breeding Value (Additive Genetic
Value) Transmitting Ability 1/2 BV
24To assess the value of an animal as a parent, we
evaluate the value of the genes it will
transmit. Breeding Value (Additive Genetic
Value) Transmitting Ability 1/2 BV -- average
value of gametes produced by an individual
25To assess the value of an animal as a parent, we
evaluate the value of the genes it will
transmit. Breeding Value (Additive Genetic
Value) Transmitting Ability 1/2 BV -- average
value of gametes produced by an
individual EBV -- Estimated Breeding ValueETA --
Estimated Transmitting Ability
26Questions 0.1 for being here 0.05 for every
right answer 0.25 total
Where did I get my undergraduate degree?
Where did I get my Ph.D.?
Where did I teach before Cornell?
27Answers
Where did I get my undergraduate degree? Cornell
University
Where did I get my Ph.D.? Iowa State University
Where did I teach before Cornell? UC Davis
28Example Breeding values
29Measured Phenotypes
Genotype Phenotype B1B1 P11 100 B1B2 P12
90 B2B2 P22 60
From previous lecture
30Example f(B1) p 2/3 f(B2) q 1/3 (at
equilibrium) ? 91.1 units
31Example f(B1) p 2/3 f(B2) q 1/3 (at
equilibrium) ? 91.1 units What is the mean of
progeny from a B1B1 male if mated at random to
the population?
32In the females
f(B1 B1) 4/9 f(B1 B2) 4/9 f(B2 B2) 1/9
Randomly mate these to B1 B1 male.
33Example B1B1 B1B2 B2B2 B1B1 B1B1
B1B2 B2B2
freq
male female
34Example B1B1 B1B2 B2B2 B1B1 B1B1 4/9
1 -- -- B1B2 B2B2
freq
male female
35Example B1B1 B1B2 B2B2 B1B1 B1B1 4/9
1 -- -- B1B2 4/9 1/2 1/2 -- B2B2
freq
male female
36Example B1B1 B1B2 B2B2 B1B1 B1B1 4/9
1 -- -- B1B2 4/9 1/2 1/2 --
B2B2 1/9 -- 1 --
freq
male female
37Example B1B1 B1B2 B2B2 B1B1 B1B1 4/9
1 -- -- B1B2 4/9 1/2 1/2 --
B2B2 1/9 -- 1 -- f(B1B1) 4/9 2/9
2/3 f(B1B2) 2/9 1/9 1/3
freq
male female
38Means of progeny of B1B1 male, (((((((B1B2 and
B2B2 males (not in equilibrium when looking at
progeny) ?11 f(B1B1) P11 f(B1B2) P12 f(B2B2)
P22 2/3 (100) 1/3 (90) 96.6
39Means of progeny of B1B1, B1B2 and B2B2
males ?11 f(B1B1) P11 f(B1B2) P12 f(B2B2)
P22 2/3 (100) 1/3 (90) 96.6 ?12
88.33 ?22 80.00
Calculated following same process used for the B1
B1 male but with B1 B2 and B2 B2 males.
40Difference in Means ?11 - ?12 96.66 - 88.33
8.33 ?12 - ?22 88.33 - 80.00 8.33
41Difference in Means ?11 - ?12 96.66 - 88.33
8.33 ?12 - ?22 88.33 - 80.00
8.33 parent B2B2 gt B1B2 gt B1B1
B1
B1
42Difference in Means ?11 - ?12 96.66 - 88.33
8.33 ?12 - ?22 88.33 - 80.00
8.33 parent B2B2 gt B1B2 gt B1B1
B1
B1
?22 ?12 ?11
43Difference in Means ?11 - ?12 96.66 - 88.33
8.33 ?12 - ?22 88.33 - 80.00
8.33 parent B2B2 gt B1B2 gt B1B1 8.3
8.3
B1
B1
?22 ?12 ?11
?
?
-- This implies value to the B1 allele. --
44For a single locus TA progeny mean minus
population mean
45For a single locus TA progeny mean minus
population mean Genotype ETA BV 2
ETA B1B1 ?11 - ? 96.66 - 91.11
5.55 11.10 B1B2 ?12 - ? 88.33 - 91.11
-3.78 -5.56 B2B2 ?12 - ?
46For a single locus TA progeny mean minus
population mean Genotype ETA BV 2
ETA B1B1 ?11 - ? 96.66 - 91.11
5.55 11.10 B1B2 ?12 - ? 88.33 - 91.11
-3.78 -5.56 B2B2 ?12 - ?
47For a single locus TA progeny mean minus
population mean Genotype ETA BV 2
ETA B1B1 ?11 - ? 96.66 - 91.11
5.55 11.10 B1B2 ?12 - ? 88.33 - 91.11
-2.78 -5.56 B2B2 ?12 - ?
48For a single locus TA progeny mean minus
population mean Genotype ETA BV 2
ETA B1B1 ?11 - ? 96.66 - 91.11
5.55 11.10 B1B2 ?12 - ? 88.33 - 91.11
-2.78 -5.56 B2B2 ?12 - ? 80.00 - 91.11
-11.11 -22.22
49For a single locus TA progeny mean minus
population mean Genotype ETA BV 2
ETA B1B1 ?11 - ? 96.66 - 91.11
5.55 11.10 B1B2 ?12 - ? 16.66 88.33 -
91.11 -2.78 -5.56 B2B2 ?12 - ?
16.66 80.00 - 91.11 -11.11 -22.22
50More Formulas
? average effect of a gene substitution
51More Formulas
? average effect of a gene substitution V11
V12 (q - p) 16.66
52More Formulas
? average effect of a gene substitution V11
V12 (q - p) 16.66 -- the difference in BVs
of individuals who differ in genotype by one
B1 allele
53More Formulas
? average effect of a gene substitution V11
V12 (q - p) 16.66 -- the difference in BVs
of individuals who differ in genotype by one
B1 allele
BV11 2 q ? BV12 (q- p) ? BV22 -2 p ?
54Phenotype
Represent BVs
Represent Ps
A2A2
A1A2
A1A1
55Basic Model Pij mgt Vij
56Basic Model Pij mgt Vij Pij mgt Vij
(AGV - AGV)
57Basic Model Pij mgt Vij Pij mgt Vij
(AGV - AGV) (mgt AGV) (Vij - AGV)
58Basic Model Pij mgt Vij Pij mgt Vij
(AGV - AGV) (mgt AGV) (Vij - AGV)
? (Vij - AGV)
59Basic Model Pij mgt Vij Pij mgt Vij
(AGV - AGV) (mgt AGV) (Vij - AGV)
? (Vij - AGV) Vij - AGV BVij Dij (Dij
value of combination)
60Basic Model Pij mgt Vij Pij mgt Vij
(AGV - AGV) (mgt AGV) (Vij - AGV)
? (Vij - AGV) Vij - AGV BVij Dij Pij
? BVij Dij (for a single locus)
61Phenotype
Represent BVs
Represent Ps
A2A2
A1A2
A1A1
62Basic Model, Single Locus
Estimating Dominance effect for an animal Dij
Pij - ? - BVij
63Basic Model, Single Locus
Own performance Pij ? BVij Dij
Progenys performance Pij ? BVij Dij
64Have a good break!