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Quantization

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... levels of gray, (e.g. decrease halftone spot size to increase spatial resolution) ... do not violate color knowledge, e.g. sky is blue, fruit colors, skin ... – PowerPoint PPT presentation

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Title: Quantization


1
Quantization
  • If too few levels of gray, (e.g. decrease
    halftone spot size to increase spatial
    resolution), then boundaries between adjacent
    gray levels become apparent. This can happen in
    color halftoning also.
  • See demo at http//www.ctr.columbia.edu/sfchang/c
    ourse/dip/demos/Quat.html

2
Saturation
  • Distance from white point
  • Adding white desaturates but does not change hue
    or perceptual brightness.
  • HSB model is approximate representative of this.
    See PhotoShop

3
Device Independence
  • Calibration to standard space
  • typically CIE XYZ
  • Coordinate transforms through standard space
  • Gamut mapping

4
Device independence
  • Stone et. al. Color Gamut Mapping and the
    Printing of Digital Color Images, ACM
    Transactions on Graphics, 7(4) October 1998, pp.
    249-292.
  • The following slides refer to their techniques.

5
Device to XYZ
  • Sample gamut in device space on 8x8x8 mesh (7x7x7
    343 cubes).
  • Measure (or model) device on mesh.
  • Interpolate with trilinear interpolation
  • for small mesh and reasonable function
    XYZf(device1, device2, device3) this
    approximates interpolating to tangent.

6
XYZ to Device
  • Invert function XYZf(device1, device2, device3)
  • hard to do in general if f is ill behaved
  • At least make f monotonic by throwing out
    distinct points with same XYZ.
  • e.g. CMY device
  • (continued)

7
XYZ to CMY
  • Invert function XYZf(c,m,y)
  • Given XYZx,y,z want to find CMYc,m,y such
    that f(CMY)XYZ
  • Consider X(c,m,y), Y(c,m,y), Z(c,m,y)
  • A continuous function on a closed region has max
    and min on the region boundaries, here the cube
    vertices. Also, if a continuous function has
    opposite signs on two boundary points, it is zero
    somewhere in between.

8
XYZ to CMY
  • Given X0, find c,m,y such that f(c,m,y) X0
  • if ci,mi,yi cj,mj,yj are vertices on a given
    cube, and UX(c,m,y)- X0 has opposite sign on
    them, then it is zero in the cube. Similarly Y,
    Z. If find such vertices for all of X0,Y0,Z0,
    then the found cube contains the desired point.
    (and use interpolation). Doing this recursively
    will find the desired point if there is one.

9
Gamut Mapping
  • Criteria
  • preserve gray axis of original image
  • maximum luminance contrast
  • few colors map outside destination gamut
  • hue, saturation shifts minimized
  • increase, rather than decrease saturation
  • do not violate color knowledge, e.g. sky is blue,
    fruit colors, skin colors

10
Gamut Mapping
  • Special colors and problems
  • Highlights this is a luminance issue so is about
    the gray axis
  • Colors near black locus of these colors in image
    gamut must map into something reasonably similar
    shape else contrast and saturation is wrong

11
Gamut Mapping
  • Special colors and problems
  • Highly saturated colors (far from white point)
    printers often incapable.
  • Colors on the image gamut boundary occupying
    large parts of the image. Should map inside
    target gamut else have to project them all on
    target boundary.

12
Gamuts
CRT
Printer
13
Gamut Mapping
  • First try map black points and fill destination
    gamut.

14
device gamut
image gamut
15
device gamut
translate Bito Bd
image gamut
bs (black shift)
16
device gamut
translate Bito Bd
image gamut
scale by csf
17
device gamut
translate Bito Bd
image gamut
scale by csf
rotate
18
Gamut Mapping
  • Xd Bd csf R (Xi - Bi)
  • Bi image black, Bd destination black
  • R rotation matrix
  • csf contrast scaling factor
  • Xi image color, Xd destination color
  • Problems
  • Image colors near black outside of destination
    are especially bad loss of detail, hue shifts
    due to quantization error, ...

19
Xd Bd csf R (Xi - Bi) bs (Wd - Bd)
shift and scale alongdestination gray
20
Fig 14a, bs0, csf small, image gamut maps
entirelyinto printer gamut, but contrast is low.
Fig 14b, bs0, csf large, more contrast, more
colors inside printer gamut, butalso more
outside.
21
Saturation control
  • Umbrella transformation
  • Rs Gs Bs monitor whitepoint
  • Rn Gn Bn new RGB coordinates such that Rs
    Gs Bs Rn Gn Bnand Rn Gn Bn maps
    inside destination gamut
  • First map R RsG GsB Bs to R RnG GnB Bn
  • Then map into printer coordinates
  • Makes minor hue changes, but relative colors
    preserved. Achromatic remain achromatic.

22
Projective Clipping
  • After all, some colors remain outside printer
    gamut
  • Project these onto the gamut surface
  • Try a perpendicular projection to nearest
    triangular face in printer gamut surface.
  • If none, find a perpendicular projection to the
    nearest edge on the surface
  • If none, use closest vertex

23
Projective Clipping
  • This is the closest point on the surface to the
    given color
  • Result is continuous projection if gamut is
    convex, but not else.
  • Bad want nearby image colors to be nearby in
    destination gamut.

24
Projective Clipping
  • Problems
  • Printer gamuts have worst concavities near black
    point, giving quantization errors.
  • Nearest point projection uses Euclidean distance
    in XYZ space, but that is not perceptually
    uniform.
  • Try CIELAB? SCIELAB?
  • Keep out of gamut distances small at cost of use
    of less than full printer gamut use.
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