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Gibb's free energy

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So, at standard state conditions. Go = Ho - T Sosys. Units on the State ... the system will NOT proceed spontaneously at high temperatures. Predict Spontaneity ... – PowerPoint PPT presentation

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Title: Gibb's free energy


1
Thermodynamics
Will a reaction occur spontaneously?
2
  • Laws of Thermodynamics
  • 1st Law the energy in the universe is constant.
  • 2nd Law for a spontaneous process, there will
    be an increase in entropy.
  • 3rd Law the entropy of a perfect crystal at 0 K
    is zero.

3
If ?Suniverse is then reaction is
spontaneous ?Suniv ?Ssurr ?Ssys ?Ssurr
-?H/T for an exothermic process for an
endothermic process ?Ssys ( for a system
becoming more random) Ex (s) ?(l) or (l)
?(g) or less ? more
gaseous particles
4
?Suniv ?Ssurr ?Ssys ?Suniv - ?G /
T ?Ssurr -?H/T -?G / T -?H / T ?Ssys So,
at standard state conditions ?Go ?Ho - T
?Sosys
5
Units on the State Functions
6
Predict Spontaneity ?G ?H - T ?Ssys If ?H is
(-) and ?S is () ?G will be (-) at all
temperatures system will proceed spontaneously
at any temperature
7
Predict Spontaneity ?G ?H - T ?Ssys If ?H is
() and ?S is (-) ?G () at all temperatures
the system will NOT proceed spontaneously at
any temperature
8
  • Predict Spontaneity
  • ?G ?H - T ?Ssys
  • If ?H(-) and ? S(-)
  • ? G (-) at low temperatures
  • the system will NOT proceed spontaneously at
    high temperatures

9
  • Predict Spontaneity
  • ?G ?H - T ?Ssys
  • If ?H() and ? S()
  • ? G (-) at high temperatures
  • the system will NOT proceed spontaneously at low
    temperatures

10
Summary of Spontaneity ?G ? H - T? S ?H
?S ?G Spont. - -
yes - no -
- ? - at low T
? - at high T
11
  • ?G 0 for a system at equilibrium
  • Such as normal melting or boiling
  • Since, ?Go ? Ho - T? So
  • At equilibrium T ?Ho/ ?So
  • A system will proceed spontaneously
  • if ?Go is (-)
  • See example 16.5 in book

12
State Functions follow Hess Law ?GO
?n?GO(p) - ?n?GO(r) ?SO Sn ?So (p) - Sn ?So
(r) ?Ho Sn ?Ho (p) - Sn ?Ho (r)
13
Dependance of Free energy on Pressure
  • As a reaction proceeds the free energy of the
    system changes until equilibrium is established
  • ?G ?Go RT ln Q
  • (at equilibrium ?G 0 and Q K)
  • Therefore ?Go - RT ln K
  • if ?Go 0 then (K 1) if ?Go is then
    (Klt1) if ?G is - (Kgt1)

14
  • Since, ?Go - RT ln K
  • And ?Go ? Ho - T? So
  • Then, ? Ho - T? So - RT ln K
  • Or, ln K -? Ho/RT ? So / R

15
  • ln K -? Ho/R (1/T) ? So / R
  • y m x
    b
  • A plot ln K vs. 1/T
  • gives a line with slope -? Ho/R
  • ln K
    y-int ? So/R
  • 1/T (K-1)

16
  • The most work that can be obtained from a system
    is ?G
  • (energy is lost from any system so all real
    systems are irreversible)
  • Maximum work obtained from any system
  • w ?G
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