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Chapter 7: Recurrence Relations

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Initial conditions for the sequence a0, a1,... are explicitly given values for a finite number ... subject to the initial condition S0 = 1 by. iteration. ... – PowerPoint PPT presentation

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Title: Chapter 7: Recurrence Relations


1
Chapter 7 Recurrence Relations
  • Discrete Mathematics
  • ???

2
Recurrence Relation
  • A recurrence relation for the sequence a0,
  • a1,is an equation that relates an to certain
  • of its predecessors a0, a1,, an-1.
  • Initial conditions for the sequence a0, a1,
  • are explicitly given values for a finite number
  • of the terms of the sequence.

3
Example 7.1.1
  • The Fibonacci sequence is defined by the
  • recurrence relation
  • and initial conditions

4
Example 7.1.2
  • A person invests 1,000 at 12 percent
  • interest compounded annually. If An
  • represents the amount at the end of n years,
  • find a recurrence relation and initial
  • conditions that define the sequence An.

5
Solving Recurrence Relations
  • To solve a recurrence relation involving the
  • sequence a0, a1, is to find an explicit
  • formula for the general term an.
  • There are two methods of solving recurrence
  • relations
  • Iteration
  • Linear homogeneous recurrence relations with
    constant coefficients.

6
Solving Recurrence Relations by Iteration
  • To solve a recurrence relation involving the
  • sequence a0, a1, by iteration, we use the
  • recurrence relation to write the nth term an
  • In terms of certain of its predecessors
  • an-1,,a0.
  • We then successively use the recurrence
  • relation to replace each of an-1, by certain
  • of their predecessors.

7
Example 7.2.1
  • Solving the recurrence relation
  • subject to the initial condition
  • by iteration.

8
Example 7.2.2
  • Solving the recurrence relation Sn 2Sn-1
  • subject to the initial condition S0 1 by
  • iteration.

9
Definition 7.2.6
  • A linear homogeneous recurrence relation of order
  • k with constant coefficients is a recurrence
    relation
  • of the form
  • Notice that a linear homogeneous recurrence
  • relation of order k with constant coefficients,
  • together with the k initial conditions
  • uniquely defines a sequence a0, a1,.

10
Theorem 7.2.11
  • Let be a
    second-order,
  • linear homogeneous recurrent relation with
  • constant coefficients.
  • If S and T are solutions of
  • then U bS dT is also a solution of

11
Example
  • Solving recurrence relation
  • and initial conditions

12
Example 7.2.13
  • Find an explicit formula for the Fibonacci
  • sequence.

13
Theorem 7.2.14
  • Let be a
    second-order,
  • linear homogeneous recurrent relation with
  • constant coefficients and initial conditions
  • a0 C0, a1 C1.
  • If both roots of
  • are equal to r, then there exist constants b
  • and d such that

14
Example 7.2.15
  • Solve the recurrence relation
  • subject to the initial conditions
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