Title: 12'6 Binomial Distribution
1Permutation
Notation
2Permutation
When deciding who goes 1st, 2nd, etc., order is
important.
A permutation is an arrangement or listing of
objects in a specific order.
The order of the arrangement is very important!!
The notation for a permutation nPr
n is the total number of
objects
r is the number of objects selected (wanted)
Note if n r then nPr n!
3Permutations
- Simplify each expression.
- a. 12P2
- b. 10P4
- c. At a school science fair, ribbons are given
for first, second, third, and fourth place, There
are 20 exhibits in the fair. How many different
arrangements of four winning exhibits are
possible?
12 11 132
10 9 8 7 5,040
20P4 20 19 18 17 116,280
4Combinations
- A selection of objects in which order is not
important. - Example 8 people pair up to do an assignment.
How many different pairs are there?
5Combinations
- AB AC AD AE AF AG AH
- BA BC BD BE BF BG BH
- CA CB CD CE CF CG CH
- DA DB DC DE DF DG DH
- EA EB EC ED EF EG EH
- FA FB FC FD FE FG FH
- GA GB GC GD GE GF GH
- HA HB HC HD HE HF HG
6Combinations
- The number of r-combinations of a set with n
elements, - where n is a positive integer and
- r is an integer with 0 lt r lt n,
- i.e. the number of combinations of r objects from
n unlike objects is
7Example 1
- How many different ways are there to select two
class representatives from a class of 20
students?
8Binomial Distribution
9Many Experiments can be done with the results of
each trial reduced to 2 outcomes
- Binomial Experiment
- There are n independent trials
- Each trial has only 2 possible outcomes
- Success or failure.
- The probability of success is the same for each
trial. - The probability is p.
- The probability of failure is 1-p
10Finding a Binomial Probability
- For a binomial experiment consisting of n trials,
the probability of exactly K successes is - P(k successes) nCk pk (1-p)n-k
- Where the probability of success on each trial is
p.
11EXAMPLE 1
- At a college, 53 of students receive financial
aid. In a random group of 9 students, what is the
probability that exactly 5 of them receive
financial aid? - p.53 (the prob of success for each trial)
- n9 (diff trials or experiments)
- The prob of getting 5 successes (k5)
- P(k5) 9C5 .535 (1-.53)9-5
- about 26
12EXAMPLE 2
- Draw a bar graph of the binomial distribution for
the class of students in Example 1 and find the
probability that fewer than 3 students in the
class receive financial aid. - Hint Use P(k successes) nCk pk (1-p)n-k
13- P(k0) 9C0 .530 (1-.53)9-0 .001
- P(k1) 9C1 .531 (1-.53)9-1 .011
- P(k2) 9C2 .532 (1-.53)9-2 .05
- P(k3) 9C3 .533 (1-.53)9-3 .13
- P(k4) 9C4 .534 (1-.53)9-4 .23
- P(k5) 9C5 .535 (1-.53)9-5 .26
- P(k6) 9C6 .536 (1-.53)9-6 .19
- P(k7) 9C7 .537 (1-.53)9-7 .09
- P(k8) 9C8 .538 (1-.53)9-8 .03
- P(k9) 9C9 .539 (1-.53)9-9 .003
14(No Transcript)
15- Probability of fewer than 3
- P(0) P(1) P(2)
- .001 .011 .05
- 0.062
16EXAMPLE 4
- A diet company claims that 78
- of people who use their product
- lose weight. To test this hypothesis,
- you randomly choose 9 people
- and ask them to follow the
- diet for 3 months. Of the 9 people,
- only 4 people lose weight. Should
- you reject the claim? Explain your
- reasoning.
- P(k 4) 0.02 which
- is fairly small, so you should reject
- the claim.
17The binomial distribution describes the behavior
of a count variable X if the following conditions
apply 1 The number of observations n is
fixed. 2 Each observation is independent. 3
Each observation represents one of two outcomes
("success" or "failure"). 4 The probability of
"success" p is the same for each outcome. If
these conditions are met, then X has a binomial
distribution with parameters n and p, abbreviated
B(n,p).
18Assignment
- Page 216 math 3 book
- s 1 18
- Read over page 217 (try to figure it out on the
calculatorstill stuck? Well go over). - s 1-3