Vectors - PowerPoint PPT Presentation

About This Presentation
Title:

Vectors

Description:

Scalar : Scalar quantity with magnitude only. Example: Temperature,mass ... Resultant vector is vector sum of two vectors ... d1 d2 vector using head-to-tail ... – PowerPoint PPT presentation

Number of Views:174
Avg rating:3.0/5.0
Slides: 20
Provided by: Naq2
Category:

less

Transcript and Presenter's Notes

Title: Vectors


1
Chapter-3
  • Vectors

2

Chapter 3 vectors
  • In physics we have Phys. quantities that can be
    completely described by a number and are known as
    scalars. Temperature and mass are good examples
    of scalars.
  • Other physical quantities require additional
    information about direction and are known as
    vectors. Examples of vectors are displacement,
    velocity, and acceleration.
  • In this chapter we learn the basic mathematical
    language to describe vectors. In particular we
    will learn the following

  • Geometric vector addition and subtraction
    Resolving a
    vector into its components
    The
    notation of a unit vector

    Addition and subtraction vectors by components

    Multiplication of a vector by a scalar

    The scalar (dot) product of two vectors

    The vector (cross) product of two vectors

3
Ch 3-2 Vectors and Scalars
  • Vectors Vector quantity has magnitude and
    direction
  • Vector represented by arrows with length equal to
    vector magnitude and arrow direction giving the
    vector direction
  • Example Displacement Vector
  • Scalar Scalar quantity with magnitude only.
  • Example Temperature,mass

4
Ch 3-3 Adding Vectors Geometrically
  • Vector addition
  • Resultant vector is vector sum of two vectors
  • Head to tail rule vector sum of two vectors a
    and b can be obtained by joining head of a
    vector with the tail of b vector. The sum of
    the two vectors is the vector s joining tail of a
    to head of b
  • sa b b a

5
Ch 3-3 Adding Vectors Geometrically
  • Commutative Law Order of addition of the vectors
    does not matter
  • a b b a
  • Associative Law More than two vectors can be
    grouped in any order for addition
  • (ab)c a (bc)
  • Vector subtraction Vector subtraction is
    obtained by addition of a negative vector

6
Check Point 3-1
  • The magnitude of displacement a and b are 3 m and
    4 m respectively. Considering various orientation
    of a and b, what is
  • i) maximum magnitude for c and ii) the minimum
    possible magnitude?
  • i) c-maxab347

a
b
c-max
ii) c-mina-b3-41
a
-b
c-min
7
Ch 3-4 Components of a Vector
  • Components of a Vector Projection of a vector on
    an axis
  • x-component of vector
  • its projection on x-axis
  • axa cos?
  • y-component of a vector
  • Its projection on y-axis
  • aya sin?
  • Building a vector from its components
  • a ?(ax2ay2) tan ? ay/ax

8
Check Point 3-2
  • In the figure, which of the indicated method for
    combining the x and y components of the vector d
    are propoer to determine that vector?
  • Ans
  • Components must be connected following
    head-to-tail rule.
  • c, d and f configuration

9
Ch 3-5 Unit Vectors
  • Unit vector a vector having a magnitude of 1 and
    pointing in a specific direction
  • In right-handed coordinate system, unit vector i
    along positive x-axis, j along positive y-axis
    and k along positive z-axis.
  • a ax i ay j az k
  • ax , ay and az are scalar components of the
    vector
  • Adding vector by components r ab
  • then rx ax bx ry ay by rz axz bz
  • r rx i ry j rz k

10
Ch 3-6 Adding Vectors by components
  • To add vectors a and b we must
  • 1) Resolve the vectors into their scalar
    components
  • 2) Combine theses scalar components , axis by
    axis, to get the components of the sum vector r
  • 3) Combine the components of r to get the vector
    r
  • r a b
  • aaxi ay j b bxibyj
  • rxax bx ry ay by
  • r rx i ry j

11
Check Point 3-3
  • Ans
  • a) ,
  • b) , -
  • c) Draw d1d2 vector using head-to-tail rule
  • Its components are ,
  • a) In the figure here, what are the signs of the
    x components of d1 and d2?
  • b) What are the signs of the y components of d1
    and d2?
  • c) What are the signs of x and y components of
    d1d2?

12
Ch 3-8 Multiplication of vectors
  • Multiplying a vector by a scalar
  • In multiplying a vector a by a scalar s, we get
    the product vector sa with magnitude sa in the
    direction of a ( positive s) or opposite to
    direction of a ( negative s)

13
Ch 3-8 Multiplication of vectors
  • Multiplying a vector by a vector
  • i) Scalar Product (Dot Product)
  • a.b a(b cos?)b(a cos?)
  • (axiayj).(bxibyj)
  • axbxayby
  • where b cos? is projection of b on a and a
    cos? is projection of a on b

14
Ch 3-8 Multiplication of vectors
  • Since a.b ab cos?
  • Then dot product of two similar unit vectors i or
    j or k is given by
  • i.ij.jk.k1 (?0, cos?1)
  • is a scalar
  • Also dot product of two different unit vectors is
    given by
  • i.jj.kk.i 0 (?90, cos?0).

15
Check Point 3-4
  • Vectors C and D have magnitudes of 3 units and 4
    units, respectively. What is the angle between
    the direction of C and D if C.D equals
  • a) Zero
  • b) 12 units
  • c) -12 units?
  • a) Since a.b ab cos? and a.b0 cos? 0 and ?
    cos-1(0)90?
  • (b) a.b12, cos? 1 and
  • ? cos-1(1)0?
  • (vectors are parallel and in the same
    direction)
  • (c) b) a.b-12, cos? -1 and
  • ? cos-1(-1)180?
  • (vectors are in opposite directions)

16
Ch 3-8 Multiplication of vectors
  • Multiplying a vector by a vector
  • ii) Vector Product (Cross Product)
  • c ax b absin?
  • c (axiayj)x(bxibyj)
  • Direction of c is perpendicular to plane of a
    and b and is given by right hand rule

17
Ch 3-8 Multiplication of vectors
  • Since a x b ab sin ? is a vector
  • Then cross product of two similar unit vectors i
    or j or k is given by
  • ixi jxj kxk 0 (as ?0 so sin ?0).
  • Also cross product of two different unit vectors
    is given by
  • ixjk jxk i kxi j
  • jxi -k kxj -i ixk-j

18
Ch 3-8 Multiplication of vectors
  • If aaxi ayj and bbxibyj
  • Then c axb
  • (axi ayj )x(bxibyj)
  • axi x (bxi byj) ayj (bxibyj)
  • axbx(i x i ) axby(i x j) aybx(jx i )
    ayby(j x j)
  • but ixi0, ixjk jxi-k
  • Then caxb (axby-aybx) k

19
Check Point 3-5
  • Vectors C and D have magnitudes of 3 units and 4
    units, respectively. What is the angle between
    the direction of C and D if magnitude of C x D
    equals
  • a) Zero
  • b) 12 units

a) Since a xb ab sin? and axb0 sin ? 0 and ?
sin-1 (0) 0?, 180? (b) a xb 12, sin ? 1 and
? sin-1(1)90?
Write a Comment
User Comments (0)
About PowerShow.com