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Inverse Trigonometric Functions

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Title: Inverse Trigonometric Functions


1
Inverse Trigonometric Functions
  • 6.1-6.2

2
4.1-4.2 Review
  • Each function has an inverse relation. The
    inverse relation is a function only when the
    original function is
  • 1-1
  • Some functions are important enough that we want
    to study their inverse behavior despite the fact
    that they are not 1-1. We do this by
  • Restricting the domain.

3
4.1-4.2 Review
  • We restrict it to an interval on which it is 1-1,
    then we find the inverse of the restricted
    function.

4
Inverse Sine Function
  • The unique angle y in the interval -p/2, p/2
    such that sin y x is the inverse sine or
    arcsine of x, denoted sin-1 x or arcsin x.

5
Inverse Sine Function
  • So sin-1 x y where y is an angle.
  • Domain of ysin-1 x is
  • -1,1 and the range is
  • -p/2, p/2 .

6
Inverse Sine Function Graph
7
Inverse Sine Example 1
  • Arcsin(1/2) ?
  • What angle has a sin of ½?
  • The range for arcsin puts us in quadrant 1 or 4.
    Sin is positive only in quadrant 1, so that is
    where our answer lies. Use a table that gives the
    sin, cos, tan of 30,60,45 to find this out. 30
    degrees or p/6 has a sine of ½, so the answer is
    p/6 .

8
Inverse Sine Example 2
  • Arcsin(-sqrt(3)/2) ?
  • What angle has a sin of sqrt(3)/2?
  • The range for arcsin puts us in quadrant 1 or 4.
    Sin is negative only in quadrant 4, so that is
    where our answer lies. 60 degrees or p/3 has a
    sine of sqrt(3)/2, so the answer is the p/3 in
    quadrant 4, which is 5p/3.

9
Inverse Sine Example 3
  • Arcsin(p/2) ?
  • What angle has a sin of p/2 ?
  • The domain for arcsin is between 1 and -1, p/2 is
    more than one, so there is no possible answer for
    this.

10
Inverse Cosine Function
  • The unique angle y in the interval 0, p such
    that cos y x is the inverse cosine or arccosine
    of x, denoted cos-1 x or arccos x.

11
Inverse Cosine Function
  • So cos-1 x y where y is an angle.
  • Domain of ycos-1 x is
  • -1,1 and the range is
  • 0, p .

12
Inverse Cosine Function Graph
13
Examples
  • Cos-1(1/2) ?
  • Use a table that gives the sin, cos, tan of
    30,60,45 to find this out.
  • The angle whose cosine is ½ is 60 degrees.
  • Cos-1(1/2) 60 degrees or pi/3

14
Inverse Tangent Function
  • The unique angle y in the interval (-p/2, p/2)
    such that tan y x is the inverse tangent or
    arctangent of x, denoted tan-1 x or arctan x.

15
Inverse Tangent Function
  • So tan-1 x y where y is an angle.
  • Domain of ytan-1 x is
  • (-8, 8) and the range is
  • (-p/2, p/2).

16
Inverse Tangent Function Graph
17
Examples
  • tan-1(1) ?
  • Use a table that gives the sin, cos, tan of
    30,60,45 to find this out.
  • The angle whose tangent is 1 is 45 degrees.
  • tan-1(1) 45 degrees or pi/4

18
Examples
  • Cos-1(1) ?
  • Cos is the x value.
  • X is 1 at 0 radians
  • Or 0 degrees.
  • Cos-1(1) 0

19
Examples
  • Cos-1(-1) ?
  • Cos is the x value.
  • X is -1 at pi radians
  • Or 180 degrees.
  • Cos-1(-1) 180
  • or pi

20
Examples
  • Cos is the x value
  • Sin is the y value
  • Tan is y/x

21
Sin, Cos and Tan
  • We used restricted domains of these functions
    just to get the inverses. The functions
    themselves keep their original domains.

22
Properties for Sin,Cos,Tan and their Inverses
  • Sin-1(sin(x)) x where p/2 x p/2
  • True because x lies in the range for arcsin.
  • If x is not in the range, then you have to
    calculate the sin(x) and then the arcsin of the
    answer.
  • Sin(Sin-1(x)) x where -1 x 1
  • True because x lies in the domain for arcsin.
  • If x is not in arcsins domain, then it is
    unsolvable.

23
Properties for Sin,Cos,Tan and their Inverses
  • cos-1(cos(x)) x where 0 x p
  • True because x is in the range of arccos.
  • If x is not in the range, then you have to
    calculate the cos(x) and then the arccos of the
    answer.
  • cos(cos-1(x)) x where -1 x 1
  • True because x lies in the domain for arccos.
  • If x is not in arccoss domain, then it is
    unsolvable.

24
Properties for Sin,Cos,Tan and their Inverses
  • tan-1(tan(x)) x where p/2 ltxlt p/2
  • True because x is in the range of arctan.
  • If x is not in the range, then you have to
    calculate the tan(x) and then the arctan of the
    answer.
  • tan(tan-1(x)) x where -8 ltxlt 8

25
Inverse Sine Example 4
  • Arcsin(sin(p/9)) ?
  • Since p/9 is in the range for arcsin, then answer
    is p/9.

26
Inverse Sine Example 5
  • Arcsin(sin(5p/6)) ?
  • Since 5p/6 is not in the range for arcsin, we
    need to find the sin(5p/6).
  • Sin(p/6) ½, so sin(5p/6) ½
  • Now find arcsin(1/2).
  • What angle has a sin of ½?
  • p/6 does and this is in arcsins range.
  • p/6 is the answer.

27
Example 6
  • Sin(Sin-1(1.8))
  • 1.8 is outside of arcsins domain.
  • Therefore, the answer does not exist for this
    value.

28
Example 7
  • Sin-1(sin(2p/3))
  • 2p/3 is not in arcsins range, so..
  • Find the sin(2p/3)
  • sin(2p/3) sqrt(3)/2
  • Then find the inverse sin of the result.
  • Arcsin(sqrt(3)/2) p/3.
  • Since sin(p/3) sqrt(3)/2

29
Evaluating Composites of Trigonometric Functions
  • Evaluate the inside first. If the inside is an
    inverse function, then watch the range. If the
    inside is a regular trig function, then use the
    bowtie triangle, drawing the angle in standard
    position, allsintancos, and the unit circle to
    find the value.
  • Use the answer to the inside as the input for the
    outside function. If the outside is an inverse
    function, then watch the range.

30
Evaluating Composites of Trigonometric Functions
  • Find the Arccos(sin(7pi/6)).
  • Sin(7pi/6) sin(210degrees)
  • Sin(30) ½ so by allsintancos
  • Sin(210degrees) -1/2
  • Now we need to find arccos(-1/2).

31
Evaluating Composites of Trigonometric Functions
  • Arccos(-1/2) ? therefore,
  • Cos(?) -1/2
  • The range for arccos is 0,pi, so ? must fit in
    this interval.
  • T must be in quadrant 2 since cosine is negative.
  • The angle must be a multiple of pi/3, since
    cos(pi/3)1/2, so ? is 2pi/3.

32
Find an Algebraic Expression Equivalent to the
Given Expression
  • Create a right triangle with one of the acute
    angles being ?.
  • Set the inside inverse function to theta.
  • Rewrite as the corresponding function.
  • Use this function to set up two of the sides of
    the triangle.
  • Solve for the third side with pythagorean
    theorem.
  • Finally evaluate the outside function at theta
    using the created triangle.

33
Example 1
  • Cos(arctan(x))
  • Arctan(x) ? so tan(?) x
  • Opposite side is x
  • Adjacent side is 1
  • Hyp is sqrt(x2 1)
  • Cos(?) 1/ sqrt(x2 1)
  • sqrt(x2 1)

X
?
1
34
Example 2
  • Cot(arccos(x))
  • Arccos(x) ? so cos(?) x
  • Adjacent side is x
  • Hyp is 1
  • Opposite side is sqrt(1-x2)
  • Cot(?) x/ sqrt(1-x2)
  • 1

Sqrt(1-x2)
?
x
35
Example 3
  • sin(arccos(3x))
  • Arccos(3x) ? so cos(?) 3x
  • Adjacent side is 3x
  • Hyp is 1
  • Opposite side is sqrt(1-9x2)
  • sin(?) sqrt(1-9x2)
  • 1

Sqrt(1-9x2)
?
3x
36
Example 4
  • tan(arccos(1/3))
  • Arccos(1/3) ? so cos(?) 1/3
  • Adjacent side is 1
  • Hyp is 3
  • Opposite side is sqrt(8)
  • tan(?) sqrt(8)/1
  • 3

Sqrt(8)
?
1
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