Title: CTC 475 Review
1CTC 475 Review
- Cost Estimates
- Job Quotes (distributing overhead)
- Rate per Direct Labor Hour
- Percentage of Direct Labor Cost
- Percentage of Prime (LaborMatl) Cost
- Present Economy Problems
- No capital investment
- Long-term costs are same
- Alternatives have identical results
2CTC 475
- Interest and Single Sums of Money
3Objectives
- Know the difference between simple and compound
interest - Know how to find the future worth of a single sum
- Know how to find the present worth of a single
sum - Know how to solve for i or n
4 Time Value of Money
- Value of a given sum of money depends on when the
money is received
5Which would you prefer?
6Which Would you Prefer?
7Money Has a Time Value
- Money at different time intervals is worth
different amounts - Time (or year at which cash flow occurs) must be
taken into account
8Simple vs Compound Interest
- If 1,000 is deposited in a bank account, how
much is the account worth after 5 years, if the
bank pays - 3 per year ---simple interest?
- 3 per year ---compound interest?
9Simple vs Compound Interest
10Simple Interest Equation
- Simpleevery year you earn 3 (30) on the
original 1000 deposited in the account at year 0 - FnP(1in)
- Where
- FFuture amount at year n
- PPresent amount deposited at year 0
- iinterest rate
11Compound Interest Equation
- Compoundevery year you earn 3 on whatever is in
the account at the end of the previous year - FnP(1i)n
- Where
- FFuture amount at year n
- PPresent amount deposited at year 0
- iinterest rate
12Example-Simple vs Compound
- An individual borrows 1,000. The principal
plus interest is to be repaid after 2 years. An
interest rate of 7 per year is agreed on. How
much should be repaid using simple and compound
interest? - Simple FP(1in)1000(1.072)1,140
- Compound FP(1i)n1000(1.07)21,144.90
13Simple or Compound?
- In practice, banks usually pay compound interest
- Unless otherwise stated assume compound interest
is used
14Factor Form
- Previous slide shows equation form for compound
interest - The factor form is a shortcut used to find
answers faster from tables in the book
15Factor Form
- FP(F/Pi,n)
- Find the future worth (F) given the present
worth (P) at interest rate (i) at number of
interest periods (n) - Future worthPresent worth factor
- Note that the factor(1i)n
16Example of Find F given P problem-Equation vs
Factor
- An individual borrows 1,000 at 6 per year
compounded annually. If the loan is to be repaid
after 5 years, how much will be owed? - Equation
- FP(1i)n1000(1.06)51,338.20
- Factor
- F P(F/P6,5)1000(1.3382)1,338.20
- Note that the factor comes from Appendix C,
Table C-9, from your book. Also note that the
factor (1.06)5 1.3382
17Find P given F
- Can rewrite FP(1i)n equation to find P given
F - Equation Form PF/(1i)n F(1i)-n
- OR
- Factor Form PF(P/Fi,n)
18Example of Find P given F problem-Equation vs
Factor
- What single sum of money does an investor need
to put away today to have 10,000 5 years from
now if the investor can earn 6 per year
compounded yearly? - Equation
- PF(1i)-n10,000(1.06)-5 7,473
- Factor
- PF(P/Fi,n)1000(0.7473)7,473
- Note that the factor comes from appendix C out
of your book. Also note that the factor
(1.06)-5 0.7473. Also note that the F/P factor
is the reciprocal of the P/F factor
19Example of Find P given F
- If you wish to accumulate 2,000 in a savings
account in 2 years and the account pays interest
at a rate of 6 per year compounded annually, how
much must be deposited today? - F2,000
- P?
- i6 per year compounded yearly
- n2 years
- Answer 1,780
20Relationship between P and F
- F occurs n periods after P
- P occurs n periods before F
21Find i given P/F/n
- Can rewrite FP(1i)n equation and solve for i
- 15 years ago a textbook costs 25.00. Today it
costs 50.00. What is the inflation rate per year
compounded yearly? - Answer 4.73
22Find n given P/F/i
- Can rewrite FP(1i)n equation and solve for n
- How long (to the nearest year) does it take to
double your money at 7 per year compounded
yearly? - Answer 10 years
23Solve for NMethod 1-Solve directly
- FP(1i)n
- 2DD(1.07) n
- 21.07 n
- log 2 nlog(1.07)
- n10.2 years
24Solve for nMethod 2-Trial Error
25Solve for NMethod 3-Use factors in back of book
- F/P2
- _at_ n10 F/P1.9727
- _at_ n11 F/P2.1049
- To the nearest year n10
- Interpolate to get n10.2
26Series of single sum cash flows
- How much must be deposited at year 0 to
withdraw the following cash amounts? (i2 per
year compounded yearly)
27Cash Flow Series (Present Worth)
- P(at year 0)
- 1000(P/F2,1)
- 3000(P/F2,2)
- 2000(P/F2,3)
- 3000(P/F2,4)
28Series of single sum cash flows
- How much would an account be worth if the
following cash flows were deposited? (i2 per
year compounded yearly)
29Cash Flow Series (Future worth)
- F(at year 4)
- 1000(F/P2,3)
- 3000(F/P2,2)
- 2000(F/P2,1)
- 3000(F/P2,0)
30Next lecture