Title: Equilibria of Weak Acids
1Equilibria ofWeak Acids BasesPart II Ka and
Kb
Based on Brady Senese 5/eChap. 16 Sec 2
2Relationship between Ka and Kb
Review Ka x Kb Kw 1.0 x 10-14
pKa pKb
14.00 Calculations can be (1) to determine
Ka and Kb (2) to make use of Ka and Kb
3Calculations to find Ka and Kb
Pract Exer 7 p.648 The methylammonium ion CH3NH3
has a Ka of 2.3x10-11. What is the Kb for the
base methylamine? Ka x Kb 1.0 x 10-14
Do Pract Exer 8 p.648
Review Write the equilibrium expression for Ka
and Kb in this problem.
4Ka x Kb 1.0x10-14
- If Ka is large, Kb must be small.
- If Ka is small, Kb must be large.
- Ka and Kb are INVERSELY PROPORTIONAL.
- When comparing 2 acids,
- the weaker acid produces
- the stronger conjugate base.
5Stronger acids give weaker conjugate bases.
CONJUGATE BASES
ACIDS
Fig. 16.1 p.649
6- Example 16.5 p.650
- Lactic acid (HC3H5O3), which is present in sour
milk, also gives sauerkraut its tartness. It is
a monoprotic acid. - In a 0.100 M soln of lactic acid, the pH is 2.44
at 25oC. Calc the Ka and pKa for lactic acid at
that temperature.
7- Example 16.6 p.651
- Methylamine, CH3NH2, is a weak base and one of
several substances that give herring brine its
pungent odor. - In 0.100 M CH3NH2 only 6.4 of the base is
ionized. what are Kb and pKb of methylamine? - What does "6.5 ionized" mean?
Do Pract Exer 9, 10, 11 p.652
8Determining the pH Of Aqueous Weak Acid Solutions
- Dominant equilibrium is Ka reaction
- write the net ionic equation
- look up the Ka value for the acid
- set up ICE table
- solve for x
- Calculate pH from the hydronium concentration at
equilibrium
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9- Example 16.7 p.654
- A student planned an experiment that would use
0.10 M propionic acid, HC3H5O2. - Calculate the value of H and the pH for this
soln. - For propionic acid, Ka 1.34x10-5
- Do Pract Exer 12, 13 p.655
10- Example 16.8 p. 655
- A solution of hydrazine, N2H4 has a conc of 0.25
M. what is the pH of the soln, and what is the
percentage ionization of the hydrazine? Hydrazine
has Kb 9.6x10-7 - Do Pract Exer 14, 15, 16 p.655
11- SALT SOLUTIONS
- HCl NaOH H2O NaCl
- We say that HCl has been neutralized by NaOH.
The product mixture is neutral. - HCl NH4OH H2O NH4Cl
- The product mixture is acidic! Why?
- NH4Cl dissociates into NH4 and Cl-
- and NH4 is acidic!
- NH4 H2O NH3 H3O
12- In the same way,
- HC2H3O2 NaOH H2O NaC2H3O2
- The product mixture is not neutral.
- NaC2H3O2 dissociates into Na and C2H3O2- and
acetate is the conjugate base of a weak acid
(acetic acid). - C2H3O2- is a strong base. It will pull a proton
off water - C2H3O2- HOH C2H3O2H OH-
- producing OH- ions.
- THUS SODIUM ACETATE PRODUCES A BASIC SOLUTION!
13Predicting AcidBase Properties Of A Salt
- 1. If neither the cation nor the anion can affect
the pH, the solution should be neutral - 2. If only the cation of the salt is acidic, the
solution will be acidic - 3. If only the anion of the salt is basic, the
solution will be basic - 4. If a salt has a cation that is acidic and an
anion that is basic, the pH of the solution is
determined by the relative strengths of the acid
and base - compare Ka and Kb for the ions
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14Predicting Effects Of Ions On pH
- Most metal cations are neutral or extremely weak
acids - Conjugate acids of weak bases are acidic
- Conjugate bases of weak acids are basic
- Conjugate bases of the strong acids are neutral
(except HSO4- which is still fairly acidic)
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15- 0.1M solutions of the following are acid/ base/
neutral or amphoteric? - HCl
- NaCl
- NaCN
- HCN
- Na2S
- Na3PO4
- NH4Cl
- Acid
- Neutral
- Base
- Acid
- Base
- Base
- acid
Do Example 16.9, Pract Exer 17 18.
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16- At this point, you are expected to recognize
whether a salt will produce an acidic or basic
solution from looking at its formula (see last
slide, and Example 16.9, Pract Exer 17 18).
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