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Chapter 8 Internal Forced convection

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Do not used forced convection if nature convection is adequate ... to use nature convection to help forced convection ... Forced convection- internal flow ... – PowerPoint PPT presentation

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Title: Chapter 8 Internal Forced convection


1
Chapter 8 Internal Forced convection
  • 8.1 Introduction
  • The laminar turbulent flows in channels
  • The developing fully developed regions
  • The heat transfer rate under two boundary
    conditions
  • - Constant heat flux
  • - Constant surface temperature
  • Method to select a cooling fan

2
The laminar turbulent in ducts
  • The critical Reynolds number
  • Similar to the case of external flow, the
    flow in a duct can be laminar or turbulent. The
    critical Reynolds number is
  • Dh is called hydraulic diameter which is
    defined as 4A/P, P is the wetted perimeter A is
    the cross-sectional area of the duct, and ? is
    the kinematic viscosity of the coolant.
  • For a duct of rectangular cross-sectional
    area

3
  • The developing and fully developed regions
  • The flow in a duct can be divided into two
    regions
  • Near the inlet of the duct, the boundary
    layer starts developing from both sides of the
    channel increases along the flow direction. At
    the point x where the two boundaries meet at the
    center and they cannot increase anymore. From the
    inlet to the meeting point is called developing
    region. Down stream of the developing region is
    called developed or fully developed region.
  • - For laminar flow, the thermal boundary
    layer developing length is
  • and the velocity boundary developing
    length is
  • - For turbulent flow the developing length
    for both thermal and velocity
  • boundary layers is

4
  • The Nussult number and heat transfer coefficient
  • At any location in the duct, the Nussult
    number heat flux can be expressed
  • h convection heat transfer coefficient
  • Tsx Local surface temperature of the duct
  • Tmx local mean fluid temperature
  • It was found experimentally as well as
    theoretically that, for a given channel, the
    convection heat transfer coefficient is constant
    in the developed region. Near the inlet, where
    the boundary layer thickness increases from zero
    to half height of the duct. Both the temperature
    gradient and the heat transfer coefficient are
    very large at the leading edge and decrease along
    the flow direction and then meet the constant
    values in the developed region, as shown in
    figure above and values of heat transfer
    coefficients for various forms of channels are
    shown in Table 8-3
  • The channel surface temperature is,

5
8-3 the Nusselt correlation equations
  • Nusselt number correlation equations for laminar
    flow

6
8-3 the Nusselt correlation equations
  • Nusselt number for turbulent flow and the
    transitional region

  • (for Re is
    greater than 2300)
  • The average bulk mean temperature is used to get
    the properties of the coolant.
  • The total heat transfer rate
  • The distribution of the surface temperature of
    the duct depends on the boundary conditions.

7
8-4 Internal forced convection with constant heat
flux
  • The distribution of surface and bulk mean fluid
    temperatures
  • The distribution of buck mean
  • fluid temperature is linear

8
8-4 Internal forced convection with constant heat
flux
  • The variation of Tsx is also linear in the fully
    developed region
  • The rate of heat transfer is equal to the rate of
    heat absorbed by the coolant
  • The maximum surface temperature

9
8-5 Internal convection heat transfer--Constant
surface temperature
  • The energy balance on a elemental control volume
    (Ts is larger than Tm)
  • Integrating from the entrance (x 0),
    where the inlet fluid mean temperature is Tmi, to
    any point x along the duct, where the mean fluid
    temperature is equal to Tmx
  • The fluid temperature at any point x is

10
8-5 constant surface temperature
  • The maximum fluid temperature is at x L or the
    outlet fluid temperature
  • The heat transfer rate
  • logarithmic mean temperature difference

11
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12
Cooling of a hollow PCB
  • Given Hollow PCB 12cm x 18cm, total heat
    dissipation 40W
  • Tmi 20oC, air volume flow
    rate at inlet section 0.72litre/s
  • channel cross-sectional area
    0.3cm x12cm
  • Find (a) Tmo, (b) Tsmax
  • Solution
  • - Assumptions
  • 1, Pressure at 1 atm.
  • 2. Smooth inner surface
  • 3. Steady state operation
  • - the inlet condition

12cm
13
Cooling of a hollow PCB
14
Cooling of a constant surface temperature hollow
PCB
  • Given Board 12cm x 20cm, flow rate
    0.72x10-3m3/s, channel 0.3cm x 12cm, Tmi 20oC,
    Ts 60oC
  • Find Tmo , Heat dissipation rate
  • Solution Assumptions 1. Steady state
    operation

  • 2. Air behaves as ideal gas

  • 3. pressure is equal to 1 atm.

  • 4. Assume Tmo to be 50oC

15



16
Method to select a cooling fan
  • Characteristic curves
  • - The static pressure developed by a given
    fan depends on its rpm and the flow rate of the
    fluid which it propels. The fan curve is usually
    provided by the manufacturers.
  • - The system curve is the total pressure
    loss verses flow rate or velocity of
  • a given flow system
  • - The intersection of the two curves is the
    operation point of the fan

P1
p2
17
Installation considerations
  • Inlet or outlet of the duct
  • - Preferred position is at the inlet
    positive pressure
  • inside the cabinet to prevent air
    infiltration into the
  • box from cracks or other openings and the
    air is
  • denser and cooler at the position of the
    fan.
  • - Heat generated by the motor is forced into
    the system. The inlet air temperature is higher.
  • Do not used forced convection if nature
    convection is adequate
  • Critical electronics should be mounted near the
    inlet where the coolant
  • temperature is lower
  • Air velocity should be less than 7m/s, otherwise
    noise will be too large.
  • Arrange the system to use nature convection to
    help forced convection
  • Series operation helps to increase the pressure
    head and parallel operation helps to increase the
    flow rate.
  • Arrange the openings on the side surfaces, not on
    the top surface
  • The maximum air temperature at the exit port
    should be less than 70oC
  • Make a good arrangement of the boards for small
    flow resistance
  • Consider the effect of air pressure change due to
    altitude effect

18
  • Parallel double the flow rate
  • Series double the pressure difference

19
  • Heat transfer coefficient
  • The actual average heat transfer coefficient is
    larger than the following
  • developed value. For a given inlet coolant
    temperature, the surface
  • temperature is smaller. Then the device
    temperature mounted on the surface is
  • Smaller than that calculated by following
    developed h value.

h
x x
20
  • The following pages will not be taught

21
8-5 Internal convection heat transfer--Constant
surface temperature
  • The energy balance on a elemental control volume
    (Ts is larger than Tm)
  • Integrating from the entrance (x 0),
    where the inlet fluid mean temperature is Tmi, to
    any point x along the duct, where the mean fluid
    temperature is equal to Tmx
  • The fluid temperature at any point x is

22
Forced convection- internal flow
  • The mean film temperature, if one of the
    temperature is unknown, assume one.
  • Properties of the coolant
  • Calculate the Reynolds number
  • - Re 2300, the flow is laminar
  • - Re 2300, treat the flow as turbulent
  • Select the Nusselt correlation equation
  • - The boundary conditions constant
    surface or constant surface heat flux
  • - Flow conditions laminar or turbulent
    flow
  • Calculate the Nusselt number and heat transfer
    coefficient
  • Calculate the heat transfer rate or the unknown
    temperature or both or the area
  • Compare the assumed temperature and the
    calculated one. If the different is large,
    re-assume a temperature and repeat the process.

23
The pressure loss in a flow system
  • The total pressure in a flow system is
    represented by
  • Pressure loss can be written in terms of loss
    of velocity head
  • pressure loss
  • k is called loss factor and it is
    dimensionless. Its value depends on the type of
    obstructions
  • Type of obstruction k
  • Inlet loss 0.5
  • outlet loss 1.0
  • channel
  • L length of the channel and Dh is the
    hydraulic diameter
  • f friction factor For fully developed
    flow is shown in Table 8 1

24
8-2 The velocity and temperature fields in a duct
  • The mass flow rate
  • um is the average velocity in the duct.
  • The bulk mean fluid temperature
  • The energy transport rate of the fluid in
    the duct
  • Tm is the average or mean temperature in the
    duct

25
Example Hollow PCB- continue
  • Find the system or pressure loss curve of example
    .
  • u (m/s)
  • 0 0
  • 0.5 0.246
  • 1.0 0.94
  • 1.5 2.07
  • 2.0 3.65

26
Example 15-13 continue
  • Plot the system curve
    The characteristic of the fan
  • Superimpose the two curves

  • For u 2m/s, the rpm of the fan
    is selected

rpm
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