Title: Chapter 8 Internal Forced convection
1Chapter 8 Internal Forced convection
- 8.1 Introduction
- The laminar turbulent flows in channels
- The developing fully developed regions
- The heat transfer rate under two boundary
conditions - - Constant heat flux
- - Constant surface temperature
- Method to select a cooling fan
2The laminar turbulent in ducts
- The critical Reynolds number
- Similar to the case of external flow, the
flow in a duct can be laminar or turbulent. The
critical Reynolds number is - Dh is called hydraulic diameter which is
defined as 4A/P, P is the wetted perimeter A is
the cross-sectional area of the duct, and ? is
the kinematic viscosity of the coolant. - For a duct of rectangular cross-sectional
area -
3- The developing and fully developed regions
- The flow in a duct can be divided into two
regions - Near the inlet of the duct, the boundary
layer starts developing from both sides of the
channel increases along the flow direction. At
the point x where the two boundaries meet at the
center and they cannot increase anymore. From the
inlet to the meeting point is called developing
region. Down stream of the developing region is
called developed or fully developed region. - - For laminar flow, the thermal boundary
layer developing length is - and the velocity boundary developing
length is - - For turbulent flow the developing length
for both thermal and velocity - boundary layers is
4- The Nussult number and heat transfer coefficient
- At any location in the duct, the Nussult
number heat flux can be expressed - h convection heat transfer coefficient
- Tsx Local surface temperature of the duct
- Tmx local mean fluid temperature
- It was found experimentally as well as
theoretically that, for a given channel, the
convection heat transfer coefficient is constant
in the developed region. Near the inlet, where
the boundary layer thickness increases from zero
to half height of the duct. Both the temperature
gradient and the heat transfer coefficient are
very large at the leading edge and decrease along
the flow direction and then meet the constant
values in the developed region, as shown in
figure above and values of heat transfer
coefficients for various forms of channels are
shown in Table 8-3 - The channel surface temperature is,
-
58-3 the Nusselt correlation equations
- Nusselt number correlation equations for laminar
flow
68-3 the Nusselt correlation equations
- Nusselt number for turbulent flow and the
transitional region -
(for Re is
greater than 2300) - The average bulk mean temperature is used to get
the properties of the coolant. -
- The total heat transfer rate
- The distribution of the surface temperature of
the duct depends on the boundary conditions.
78-4 Internal forced convection with constant heat
flux
- The distribution of surface and bulk mean fluid
temperatures - The distribution of buck mean
- fluid temperature is linear
88-4 Internal forced convection with constant heat
flux
- The variation of Tsx is also linear in the fully
developed region - The rate of heat transfer is equal to the rate of
heat absorbed by the coolant - The maximum surface temperature
9 8-5 Internal convection heat transfer--Constant
surface temperature
- The energy balance on a elemental control volume
(Ts is larger than Tm) - Integrating from the entrance (x 0),
where the inlet fluid mean temperature is Tmi, to
any point x along the duct, where the mean fluid
temperature is equal to Tmx - The fluid temperature at any point x is
108-5 constant surface temperature
- The maximum fluid temperature is at x L or the
outlet fluid temperature - The heat transfer rate
- logarithmic mean temperature difference
11(No Transcript)
12 Cooling of a hollow PCB
- Given Hollow PCB 12cm x 18cm, total heat
dissipation 40W - Tmi 20oC, air volume flow
rate at inlet section 0.72litre/s - channel cross-sectional area
0.3cm x12cm - Find (a) Tmo, (b) Tsmax
- Solution
- - Assumptions
- 1, Pressure at 1 atm.
- 2. Smooth inner surface
- 3. Steady state operation
- - the inlet condition
12cm
13Cooling of a hollow PCB
14Cooling of a constant surface temperature hollow
PCB
- Given Board 12cm x 20cm, flow rate
0.72x10-3m3/s, channel 0.3cm x 12cm, Tmi 20oC,
Ts 60oC - Find Tmo , Heat dissipation rate
- Solution Assumptions 1. Steady state
operation -
2. Air behaves as ideal gas -
3. pressure is equal to 1 atm. -
4. Assume Tmo to be 50oC
15 16Method to select a cooling fan
- Characteristic curves
- - The static pressure developed by a given
fan depends on its rpm and the flow rate of the
fluid which it propels. The fan curve is usually
provided by the manufacturers. - - The system curve is the total pressure
loss verses flow rate or velocity of - a given flow system
- - The intersection of the two curves is the
operation point of the fan
P1
p2
17Installation considerations
- Inlet or outlet of the duct
- - Preferred position is at the inlet
positive pressure - inside the cabinet to prevent air
infiltration into the - box from cracks or other openings and the
air is - denser and cooler at the position of the
fan. - - Heat generated by the motor is forced into
the system. The inlet air temperature is higher. - Do not used forced convection if nature
convection is adequate - Critical electronics should be mounted near the
inlet where the coolant - temperature is lower
- Air velocity should be less than 7m/s, otherwise
noise will be too large. - Arrange the system to use nature convection to
help forced convection - Series operation helps to increase the pressure
head and parallel operation helps to increase the
flow rate. - Arrange the openings on the side surfaces, not on
the top surface - The maximum air temperature at the exit port
should be less than 70oC - Make a good arrangement of the boards for small
flow resistance - Consider the effect of air pressure change due to
altitude effect
18- Parallel double the flow rate
- Series double the pressure difference
-
19- Heat transfer coefficient
- The actual average heat transfer coefficient is
larger than the following - developed value. For a given inlet coolant
temperature, the surface - temperature is smaller. Then the device
temperature mounted on the surface is - Smaller than that calculated by following
developed h value.
h
x x
20- The following pages will not be taught
21 8-5 Internal convection heat transfer--Constant
surface temperature
- The energy balance on a elemental control volume
(Ts is larger than Tm) - Integrating from the entrance (x 0),
where the inlet fluid mean temperature is Tmi, to
any point x along the duct, where the mean fluid
temperature is equal to Tmx - The fluid temperature at any point x is
22 Forced convection- internal flow
- The mean film temperature, if one of the
temperature is unknown, assume one. - Properties of the coolant
- Calculate the Reynolds number
- - Re 2300, the flow is laminar
- - Re 2300, treat the flow as turbulent
- Select the Nusselt correlation equation
- - The boundary conditions constant
surface or constant surface heat flux - - Flow conditions laminar or turbulent
flow - Calculate the Nusselt number and heat transfer
coefficient - Calculate the heat transfer rate or the unknown
temperature or both or the area - Compare the assumed temperature and the
calculated one. If the different is large,
re-assume a temperature and repeat the process.
23The pressure loss in a flow system
- The total pressure in a flow system is
represented by - Pressure loss can be written in terms of loss
of velocity head - pressure loss
- k is called loss factor and it is
dimensionless. Its value depends on the type of
obstructions - Type of obstruction k
- Inlet loss 0.5
- outlet loss 1.0
- channel
- L length of the channel and Dh is the
hydraulic diameter - f friction factor For fully developed
flow is shown in Table 8 1
-
248-2 The velocity and temperature fields in a duct
- The mass flow rate
- um is the average velocity in the duct.
- The bulk mean fluid temperature
- The energy transport rate of the fluid in
the duct - Tm is the average or mean temperature in the
duct
25Example Hollow PCB- continue
- Find the system or pressure loss curve of example
. - u (m/s)
- 0 0
- 0.5 0.246
- 1.0 0.94
- 1.5 2.07
- 2.0 3.65
26Example 15-13 continue
- Plot the system curve
The characteristic of the fan - Superimpose the two curves
-
For u 2m/s, the rpm of the fan
is selected
rpm