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Lecture 2: Analysis of Adaptation

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e.g. Eyesight vs. Giraffe's neck. Adaptations. When analyzing adaptation we need to remember: ... Show that a trait has been shaped by NS. Determine the agent ... – PowerPoint PPT presentation

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Title: Lecture 2: Analysis of Adaptation


1
Lecture 2 Analysis of Adaptation
  • Adaptation a feature that, because it increases
    fitness, has been shaped by NS
  • In other words
  • NS genetic variation adaptation
  • Adaptations are not always obvious
  • e.g. Eyesight vs. Giraffes neck

2
Adaptations
  • When analyzing adaptation we need to remember
  • Not all features of a population are adaptive
  • Not all adaptations are perfect

3
Analysis of Adaptation
  • We need to
  • Show that a trait has been shaped by NS
  • Determine the agent of selection

4
4 Ways to Identify an Adaptation
  • COMPLEXITY
  • Complex structures are usually adaptive
  • e.g. ampullae of Lorenzini
  • Variants of complex structures may not be
    adaptive (e.g. Hb)

5
2) Engineering
  • Does the trait fit efficient model predicted by
    engineering?
  • e.g. Fish shapes
  • Fits aerodynamic prediction
  • Form fits function

6
3) Convergence
  • Correlational Evidence Convergent Evolution

7
  • Patterns of convergence are studied using the
    COMPARATIVE METHOD
  • Variation in character should correlate with
    selective pressures of ecological context
  • Problem similarity can mean similar adaptive
    response or close relationship
  • Need traits that arise independently in
    different phylogenies

8
  • Eliminate the effect of common ancestry
    therefore ecology is the determining factor
  • Thus need correct phylogeny

Conclusion biparental care adaptive response
9
Experiments
  • 4) Experimental manipulation
  • Manipulate a trait and see if affects fitness
  • e.g. Swallows tails
  • e.g. Bower birds
  • e.g. Zonosemata flies

10
Zonosemata
  • Dark banded wings, waving behaviour
  • Main predator jumping spiders
  • Does wing colouration or waving reduce predation?
    (mimicry?)

11
  • 5 test flies
  • Untreated Zonosemata, sham surgery, housefly
    wings, housefly with Zonosemata wings, housefly
  • Against jumping spider and other predator
  • Needed to have both markings waving to repel
    jumping spider (no surgery effect)
  • No effect on any other predators
  • Mimic jumping spiders to avoid jumping spider
    predation

12
Cepea nemoralis
  • Snails vary in colour
  • of bands (polymorphism)
  • Morphotype varies with habitat
  • Why?
  • Engineering thermoregn depends on darkness
  • Experimental camouflage thrush predation

13
Examples
  1. Evolution of sex
  2. Sexual selection
  3. Evolution of sex ratio

14
Evolution of Sex
  • Sex is costly so why is it so common?
  • Asexual reproduction is only found in patches on
    the phylogenetic tree
  • Asexual species have higher rates of extinction
    than sexual species

15
Model Asexual variant
  • e.g. Given each female has 2 offspring, no
    difference in survival

Asexual 100 females Sexual 100 females (100 males) Frequency p(female) 0.33
200 females 100 females (100 males) p(female) 0.5
400 females 100 females (100 males) p(female) 0.67
16
Sexual vs. Asexual
  • Sexual females lose ½ genes in each generation
    to survive to repro females must be fit but their
    mate may be less fit
  • Sexual female has ½ fitness of asexual
  • Plus, costs of finding a mate, STDs etc.
  • Given this disadvantage, there must be a benefit
    in sexual reproduction

17
Models Assumptions Violated
  • 1. Reproductive mode does not affect number of
    offspring
  • Parental care/Nuptial gifts (fairly rare)
  • 2. Reproductive mode does not affect survival of
    offspring

18
Group Selectionist Argumentsex accelerates rate
of evolution
  • Increases a groups ability to respond to
    changing environment
  • Asexual populations have a higher extinction rate
  • Given 2 loci with 2 alleles (Aa Bb)
  • p(A) gtgtgt p(a)
  • p(B) gtgtgt p(b)
  • (A B are fixed)
  • a b interact to increase fitness

19
How get aabb in one individual?
  • Asexual AABB ? aabb only by mutation
  • get AaBB and AABb but
  • p(AABB ? aabb) ? 0
  • Sexual recombination
  • AaBB x AABb
  • Gives AABB AaBB AABb AaBb
  • AaBb x AaBb aabb
  • Mutant genotype can arise quickly and prevent
    extinction

20
Mutation rate is important
  • Mutation rate slow
  • Sexual ? Asexual
  • No advantage to sex
  • Mutation rate fast
  • Sexual gt Asexual

Thus, sexual popns can outcompete asexual
popns Sex is still disadvantageous to the
individual
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