Title: Monther Dwaikat
168402 Structural Design of Buildings II61420
Design of Steel Structures62323 Architectural
Structures II
Design of Beam-Columns
- Monther Dwaikat
- Assistant Professor
- Department of Building Engineering
- An-Najah National University
2Beam-Column - Outline
- Beam-Columns
- Moment Amplification Analysis
- Second Order Analysis
- Compact Sections for Beam-Columns
- Braced and Unbraced Frames
- Analysis/Design of Braced Frames
- Analysis/Design of Unbraced Frames
- Design of Bracing Elements
3Design for Flexure LRFD Spec.
- Commonly Used Sections
- I shaped members (singly- and doubly-symmetric)
- Square and Rectangular or round HSS
4Beam-Columns
5Beam-Columns
6Beam-Columns
7Beam-Columns
8Beam-Columns
9Beam-Columns
10Beam-Columns
- Likely failure modes due to combined bending and
axial forces - Bending and Tension usually fail by yielding
- Bending (uniaxial) and compression Failure by
buckling in the plane of bending, without torsion - Bending (strong axis) and compression Failure
by LTB - Bending (biaxial) and compression (torsionally
stiff section) Failure by buckling in one of the
principal directions. - Bending (biaxial) and compression (thin-walled
section) failure by combined twisting and
bending - Bending (biaxial) torsion compression
failure by combined twisting and bending
11Beam-Columns
- Structural elements subjected to combined
flexural moments and axial loads are called
beam-columns - The case of beam-columns usually appears in
structural frames - The code requires that the sum of the load
effects be smaller than the resistance of the
elements - Thus a column beam interaction can be written as
- This means that a column subjected to axial load
and moment will be able to carry less axial load
than if no moment would exist.
12Beam-Columns
- AISC code makes a distinct difference between
lightly and heavily axial loaded columns
AISC Equation
AISC Equation
13Beam-Columns
- Definitions
- Pu factored axial compression load
- Pn nominal compressive strength
- Mux factored bending moment in the x-axis,
including second-order effects - Mnx nominal moment strength in the x-axis
- Muy same as Mux except for the y-axis
- Mny same as Mnx except for the y-axis
- ?c Strength reduction factor for compression
members 0.90 - ?b Strength reduction factor for flexural
members 0.90
14Beam-Columns
- The increase in slope for lightly axial-loaded
columns represents the less effect of axial load
compared to the heavily axial-loaded columns
Unsafe Element
Pu/fcPn
Safe Element
0.2
Mu/fbMn
These are design charts that are a bit
conservative than behaviour envelopes
15Moment Amplification
- When a large axial load exists, the axial load
produces moments due to any element deformation. - The final moment M is the sum of the original
moment and the moment due to the axial load. The
moment is therefore said to be amplified. - As the moment depends on the load and the
original moment, the problem is nonlinear and
thus it is called second-order problem.
16Moment Amplification
- Second-order Moments, Pud and Pu?
-
Moment amplification in column braced against
sidesway Mu Mnt Pud
Moment amplification in unbraced column Mu Mlt
Pu?
17Moment Amplification
- Using first principles we can prove that the
final moment Mmax is amplified from M0 as
- The amplification factor B can be
Where
18Second Order Analysis
19Second Order Analysis
20Second Order Analysis
21Second Order Analysis
22Second Order Analysis
23Second Order Analysis
24Second Order Analysis
25Compact Sections for Beam-Columns
- The axial load affects the ratio for compactness.
When the check for compactness for the web is
performed while the web is subjected to axial
load the following ratios shall be
Flange limit is similar to beams
26Braced and Unbraced Frames
- Two components of amplification moments can be
observed in unbraced frames - Moment due to member deflection (similar to
braced frames) - Moment due to sidesway of the structure
Unbraced Frames
Member deflection
Member sidesway
27Unbraced and Braced Frames
- In braced frames amplification moments can only
happens due to member deflection
Braced Frames
Sidesway bracing system
Member deflection
28Unbraced and Braced Frames
- The AISC code approximate the effect by using two
amplification factors B1 and B2
AISC Equation
AISC Equation
- Where
- B1 amplification factor for the moment occurring
in braced member - B2 amplification factor for the moment occurring
from sidesway - Mnt and Pnt is the maximum moment and axial force
assuming no sidesway - Mlt and Plt is the maximum moment and axial force
due to sidesway - Pr is the required axial strength
29Unbraced and Braced Frames
- Braced frames are those frames prevented from
sidesway. - In this case the moment amplification equation
can be simplified to
AISC Equation
- KL/r for the axis of bending considered
- K 1.0
30Unbraced and Braced Frames
- The coefficient Cm is used to represent the
effect of end moments on the maximum deflection
along the element (only for braced frames)
- When there is transverse loading on the beam
either of the following case applies
31Unbraced and Braced Frames
- AISC requires stability bracing to have
- Specific strength to resist the lateral load
- Specific axial stiffness to limit the lateral
deformation.
Braced Frames
Unbraced Frames
- Where Pu is the sum of factored axial load in the
braced story - Pbr is bracing strength and bbr is braced or
unbraced frame stiffness (f 0.75)
32Unbraced and Braced Frames
- Unbraced frames can observe loading sidesway
- In this case the moment amplification equation
can be simplified to
BMD
AISC Equation
33Unbraced and Braced Frames
- A minimum lateral load in each combination shall
be added so that the shear in each story is given
by
34Analysis of Unbraced Frames
is the sum of factored axial loads on all columns
in floor
is the drift due to the unfactored horizontal
forces
is the story height
story shear produced by unfactored horizontal
forces
is the drift index (is generally between 1/500 to
1/200)
is the sum of Euler buckling loads of all columns
in floor
is the factored axial load in the column
RM
can be conservatively taken as 0.85
35Ex. 5.1- Beam-Columns in Braced Frames
- A 3.6-m W12x96 is subjected to bending and
compressive loads in a braced frame. It is bent
in single curvature with equal and opposite end
moments and is not loaded transversely. Use Grade
50 steel. Is the section satisfactory if Pu
3200 kN and first-order moment Mntx 240 kN.m - Step I From Section Property Table
- W12x96 (A 18190 mm2, Ix 347x106 mm4, Lp
3.33 m, Lr 14.25 m, Zx 2409 mm3, Sx 2147
mm3)
36Ex. 5.1- Beam-Columns in Braced Frames
- Step II Compute amplified moment
- - For a braced frame let K 1.0
- KxLx KyLy (1.0)(3.6) 3.6 m
- - From Column Chapter ?cPn 4831 kN
- Pu/?cPn 3200/4831 0.662 gt 0.2 ? Use eqn.
- - There is no lateral translation of the frame
Mlt 0 - ? Mux B1Mntx
-
- Cm 0.6 0.4(M1/M2) 0.6 0.4(-240/240)
1.0 - Pe1 ?2EIx/(KxLx)2 ?2(200)(347x106)/(3600)2
52851 kN
37Ex. 5.1- Beam-Columns in Braced Frames
Mux (1.073)(240) 257.5 kN.m Step III
Compute moment capacity Since Lb 3.6 m
Lp lt Lblt Lr
38Ex. 5.1- Beam-Columns in Braced Frames
Step IV Check combined effect
? Section is satisfactory
39Ex. 5.2- Analysis of Beam-Column
- Check the adequacy of an ASTM A992 W14x90 column
subjected to an axial force of 2200 kN and a
second order bending moment of 400 kN.m. The
column is 4.2 m long, is bending about the strong
axis. Assume - ky 1.0
- Lateral unbraced length of the compression flange
is 4.2 m.
40Ex. 5.2- Analysis of Beam-Column
- Step I Compute the capacities of the beam-column
- ?cPn 4577 kN ?Mnx 790 kN.m
- ?Mny 380 kN.m
- Step II Check combined effect
OK
41Design of Beam-Columns
- Trial-and-error procedure
- Select trial section
- Check appropriate interaction formula.
- Repeat until section is satisfactory
42Design of Unbraced Frames
- Design can be performed using the following
procedure - Use a procedure similar to that of braced frames
- To start the design assume B1 1.0 and compute
B2 by assuming the ratio - Compute Mu and perform same procedure used for
braced frames
43Ex. 5.3- Analysis-External Column
- Check the exterior column of an unbraced frame
shown in the figure for the following load
combination. All columns are 3.8 m long and all
beams are 9 m long. Assume A992 steel.
W24x76
W14x90
For this frame
W24x76
44Ex. 5.3- Analysis-External Column
- Step I Calculate Kx and Ky
-
- Effective length, Ky ,
- assumed braced frame
W24x76
W14x90
W24x76
45Ex. 5.3- Analysis-External Column
- Step II Calculate ?Pn and p
46Ex. 5.3- Analysis-External Column
- Step III Determine second-order moments-No
translation, Mnt
Due to lack of information, assume Cm 1.0
47Ex. 5.3- Analysis-External Column
- Step IV Determine second-order moments -
Translation, Mlt. - Dont know all columns in story, thus assume the
frame will have a deflection limit - For this frame
-
- Thus,
48Ex. 5.3- Analysis-External Column
- Step V Second-order moment
- Step VI Check combined effect
OK
- Thus, the W14x90, Fy 344 MPa will work for this
loading case. - Now it should be checked for any other load case,
such as 1.2D1.6L
49Ex. 5.4 Design-Beam Column
- Select a W shape of A992 steel for the
beam-column of the following figure. This member
is part of a braced frame and is subjected to the
service-load axial force and bending moments
shown (the end shears are not shown). Bending is
about the strong axis, and Kx Ky 1.0. Lateral
support is provided only at the ends. Assume that
B1 1.0.
PD 240 kN
PL 650 kN
MD 24.4 kN.m
ML 66.4 kN.m
4.8 m
MD 24.4 kN.m
ML 66.4 kN.m
50Ex. 5.4 Design-Beam Column
- Step I Compute the factored axial load and
bending moments - Pu 1.2PD 1.6PL 1.2(240) 1.6(650) 1328
kN. - Mntx 1.2MD 1.6ML 1.2(24.4) 1.6(66.4)
135.5 kN.m. - B1 1.0 ? Mux B1Mntx 1.0(135.5) 135.5
kN.m - Step II compute ?Mnx, ?Pn
- The effective length for compression and the
unbraced length for bending are the same KL
Lb 4.8 m. - The bending is uniform over the unbraced length ,
so Cb1.0 - Try a W10X60 with ?Pn 2369 kN and ?Mnx 344
kN.m
51Ex. 5.4 Design-Beam Column
- Step III Check interaction equation
-
-
- Step IV Make sure that this is the lightest
possible section. - ? Try W12x58 with ?Pn 2247 kN and ?Mnx
386 kN.m - ? Use a W12 x 58 section
OK
52Design of Base Plates
- We are looking for design of concentrically
loaded columns. These base plates are connected
using anchor bolts to concrete or masonry
footings - The column load shall spread over a large area of
the bearing surface underneath the base plate
AISC Manual Part 16, J8
53Design of Base Plates
- The design approach presented here combines three
design approaches for light, heavy loaded, small
and large concentrically loaded base plates
Area of Plate is computed such that
n
m
B
0.8 bf
where
If plate covers the area of the footing
0.95d
N
If plate covers part of the area of the footing
- The dimensions of the plate are computed such
that m and n are approximately equal.
A1 area of base plate
A2 area of footing
fc compressive strength of concrete used for
footing
54Design of Base Plates
Thickness of plate
However ? may be conservatively taken as 1
55Ex. 5.5 Design of Base Plate
- For the column base shown in the figure, design a
base plate if the factored load on the column is
10000 kN. Assume 3 m x 3 m concrete footing with
concrete strength of 20 MPa.
N
0.95d
W14x211
0.8bf
B
56Ex. 4.7- Design of Base Plate
- Step I Plate dimensions
- Assume thus
- Assume m n
- N 729.8 mm say N 730 mm
- B 671.8 mm say B 680 mm
57Ex. 4.7- Design of Base Plate
58Ex. 4.7- Design of Base Plate
- Selecting the largest cantilever length
- use 730 mm x 670 mm x 80 mm Plate
59Eccentrically Loaded Columns
- For eccentrically loaded columns
- Compute dimensions such that stress (q) is less
than concrete compressive strength. - Compute thickness so that the ultimate moment on
the plate equals the full plastic moment
multiplied by ?, where ? 0.9. -
- no tension e eccentricity
- Mu ultimate moment per (mm) width on the
plate