Title: Particle Physics II CP violation Lecture 1
1Particle Physics II CP violationLecture 1
Acknowledgements Slides based on the course from
Wouter Verkerke.
2Outline
- 5 March
- Introduction matter and anti-matter
- P, C and CP symmetries
- K-system
- CP violation
- Oscillations
- Cabibbo-GIM mechanism
- 12 March
- CP violation in the Lagrangian
- CKM matrix
- B-system
- 19 March
- B?J/Psi Ks
- Delta ms
- (26 March No lecture)
- 2 April
- B-experiments BaBar and LHCb
- Measurements at LHCb
3Literature
- Slides based on the course from Wouter Verkerke.
- W.E. Burcham and M. Jobes, Nuclear and Particle
Physics, chapters 11 and 14. - Z. Ligeti, hep-ph/0302031, Introduction to Heavy
Meson Decays and CP Asymmetries - Y. Nir, hep-ph/0109090, CP Violation A New Era
- H. Quinn, hep-ph/0111177, B Physics and CP
Violation
4Motivation What is so interesting about CP
violation?
- Its about differences in matter and anti-matter
- Why would they be different in the first place?
- We see they are different our universe is matter
dominated
5Where and how do we generate the Baryon asymmetry?
- No definitive answer to this question yet!
- In 1967 A. Sacharov formulated a set of general
conditions that any such mechanism has to meet - You need a process that violates the baryon
number B(Baryon number of matter1, of
anti-matter -1) - Both C and CP symmetries should be violated
- Conditions 1) and 2) should occur during a phase
in which there is no thermal equilibrium
- In these lectures we will focus on 2) CP
violation - Apart from cosmological considerations, I will
convince you that there are more interesting
aspects in CP violation
6What is evidence for the existence of anti-matter?
- Energetic photons produced in matter/anti-matter
annihilation - Look at spectrum of photons in universe and look
for spikes - Main problem photons can not travel unlimited
distances in the universe because of interactions
with remaining cosmic background radiation and
gases etc - Conclusion No anti-matter in 20Mpc radius.
- How to look further into space?
- Better Look for anti-Helium nuclei flying
through space - Positrons, anti-protons can occasionally be
produced in various processes, but producing
anti-Helium is way too complicated by regular
means Only viable source of anti-Helium are
fusion processes in anti-stars - Presence/absence of anti-Helium says something
about existence of anti-matter in distant regions
of space - Large rest mass of Helium nuclei allows them to
travel much further through space than photons ?
Conclusions of anti-Helium searches cover much
larger region of space
7The AMS experiment Searching for He
- In essence as small particle physics experiment
in space - AMS-01 brought to space through flight of
Discovery shuttle - Can detect and identify many types of cosmic rays
8Results of the AMS experiment
- Zero anti-helium found, plenty of Helium found
- Rigidity of tracks is measure of particles
momentum - Very high energy Helium nuclei have traveled from
far ? Says something about spatial reach of
experiment - Universe with pockets of anti-matter hypothesis
increasingly unlikely - Future AMS-02 experiment will (launch 2007) will
have much increased range
9Introduction positron discovery by Anderson
- Result discovery of a positively charged
electron-like particle dubbed the positron - Experimental confirmation of existence of
anti-matter!
e (23 MeV)
Outgoing particle (low momentum / hi curvature)
Lead plate to slow down particlein chamber
6mm Pb
Incoming particle (high momentum / low curvature)
e (63 MeV)
10Introduction positron discovery by Anderson
- 4 years later Anderson confirmed this with g ?
ee- in lead plate using g from Thorium carbide
source
11Introduction anti-neutrino Savannah river
- Decisive experiment close to Savannah River
nuclear reactor in South Carolina in 1956 (Nobel
prize 1995) - Idea nuclear reactor provides enormous
anti-neutrino flux from fission O(1013) /cm2/sec - Try to detect inverse beta decay n p ? n e
(Beta decay n ? p e- n)
n e ? p n p n ? n e
Cross over e-
Invert reaction
12Introduction anti-neutrino Savannah river
- How do you detect n p ? n e
- Look for the positron through the reaction
e e- ? g gand detect 2 photons produced
simultaneously. - Savannah river Detector
- Tank with 200 liters of water with 40 kg of CdCl2
dissolved in it. - Surrounded by 110 photomultipliers for photon
detection - Clean signal found ? direct proof of existence of
neutrino - Nobel prize 1995
- ?? n ? p e- not observed
- ????? , Lepton number must be conserved
From inversebeta decay
From detectormaterial
13Introduction - What about the other
anti-particles?
- Dirac equation for every (spin ½) particle there
is an anti-particle - It took a bit longer, but more were
discoveredAnti-proton (1955) and anti-neutron
(1955) using cyclotrons - Reactions with particles and anti-particles
- Q How do you produce anti-particles anyway?
- A In pairs with particles, e.g. g ? e e-
- But this is not the whole story as we will see
later - General rule crossing symmetry
- In any existing reaction you can move a particle
through the arrow while turning it into an
anti-particle - Example e- g ? e- g (Compton scattering) g g
? e e- (Pair creation)
Move e- to right Move g to left(g g)
14Definition and discovery of C,P,CP violation
15Continuous vs discrete symmetries
- Space, time translation orientation symmetries
are all continuous symmetries - Each symmetry operation associated with one ore
more continuous parameter - There are also discrete symmetries
- Charge sign flip (Q ? -Q) C parity
- Spatial sign flip ( x,y,z ? -x,-y,-z) P parity
- Time sign flip (t ? -t) T parity
- Are these discrete symmetries exact symmetries
that are observed by all physics in nature? - Key issue of this course
16Example People believe in symmetry
- Instruction for Abel Tasman, explorer of
Australia (1642) - Since many rich mines and other treasures have
been found in countries north of the equator
between 15o and 40o latitude, there is no doubt
that countries alike exist south of the equator.
- The provinces in Peru and Chili rich of gold and
silver, all positioned south of the equator, are
revealing proofs hereof.
17Three Discrete Symmetries
- Parity, P
- Parity reflects a system through the origin.
Convertsright-handed coordinate systems to
left-handed ones. - Vectors change sign but axial vectors remain
unchanged - x ? -x , p ? -p, but L x ? p ? L
- Charge Conjugation, C
- Charge conjugation turns a particle into its
anti-particle - e ? e- , K - ? K
- Time Reversal, T
- Changes, for example, the direction of motion of
particles - t ? -t
18P-parity experiments
- Before 1956 physicists were convinced that the
laws of nature were left-right symmetric.
Strange? - A gedanken experiment Consider two perfectly
mirror symmetric cars - What would happen if the ignition mechanism uses,
say, 60Co b decay?
Gas pedal
Gas pedal
driver
driver
L and R are fully symmetric, Each nut, bolt,
molecule etc. However the engine is a black box
R
L
Person L gets in, starts, .. 60 km/h
Person R gets in, starts, .. What happens?
19The situation in 1956
- Nothing hints at the existence of any kind of
Parity violating physics - Reminder Parity (x,y,z) ? (-x,-y,-z)
- If universe is parity-symmetric, inverting all
spatial coordinates would not changes laws of
physics - 1956 Lee and Yang publish a paper Question of
Parity Conservation in Weak Interactions/ - Suggestion Weak interaction might violate Parity
symmetry. - Originated from discussions at April HEP
conference in Rochester, NY. Following Yang's
presentation Richard Feynman brought up the
question of non-conservation of parity. - Feynman himself later said, "I thought the idea
(of parity violation) unlikely, but possible, and
a very exciting possibility." Indeed Feynman
later made a fifty dollar bet with a friend that
parity would not be violated.
20Parity symmetry The situation in 1956
- When the paper appeared, physicists were not
immediately prompted into action. The proposition
of parity non-conservation was not unequivocally
denied rather, the possibility appeared so
unlikely that experimental proof did not warrant
immediate attention. - The physicist Freeman Dyson wrote of his reaction
to the paper "A copy of it was sent to me and I
read it. I read it twice. I said, This is very
interesting,' or words to that effect. But I had
not the imagination to say, By golly, if this is
true it opens up a whole new branch of physics.'
And I think other physicists, with very few
exceptions, at that time were as unimaginative as
I."
21Parity symmetry the experiment
- Madame Wu
- Another immigrant was now to play the next major
role, Madame Chien-Shiung Wu. - Arriving at Berkely in 1936 from Shanghai, Wu was
one of the most ardently pursued coeds on
campus. But she was also a hard worker who
abhorred the marked absence of women from the
American scientific establishment. She says, "
... it is shameful that there are so few women
in science... In China there are many, many
women in physics. There is a misconception in
America that women scientists are all dowdy
spinsters. This is the fault of men. In Chinese
society, a woman is valued for what she is, and
men encourage her to accomplishments --- yet she
retains eternally feminine." - Idea from experiment in collaboration with Lee
and Yang Look at spin of decay products of
polarized radioactive nucleus - Production mechanism involves exclusively weak
interaction
22Intermezzo Spin and Parity
- How does the decay of a particle with spin tell
you something about parity? - Gedanken-experiment decay of X ? a b
- Spin 1,1gt ? ½, ½ gt ½, ½gt
- It is important that X is maximally polarized
only then there is a single solution for the spin
of the decay products. If not, e.g. - 1,0gt ? ½, ½gt ½, -½gt
- 1,0gt ? ½, -½gt ½, ½gt
?
23Intermezzo Spin and Parity and Helicity
- We introduce a new quantity Helicity the
projection of the spin on the direction of flight
of a particle
H1 (right-handed)
H-1 (left-handed)
24Intermezzo Spin and Parity and Helicity
- Spin is quantized ? Helicity is quantized
- Possible H values for S1/2 H-1 and H1
- Most particles are linear combination of H1 and
H-1 states - Angular distribution for particles observed in
specific helicity eigenstate
I(q)RH 1 - (v/c) cos q
I(q)LH 1 (v/c) cos q
ConstantIf both helicitiesare producedequally
in decay.If not angulardistribution willnot
be flat
Superpositionof H1 and H-1states
25Note on Helicity
- Note that Helicity is not generally a Lorentz-
invariant observable - Sign of particle momentum p is relative to
observer. - A second observer overtaking the particle from
the lab observer perspective will see the
particle moving in the opposite direction (p
-p) ? It see the opposite Helicity - Exception for massless particles
- You cannot overtake massless particles moving at
speed of light - Helicity for massless particles is
Lorentz-invariant intrinsic property
26A realistic experiment the Wu experiment (1956)
- Observe radioactive decay of Cobalt-60 nuclei
- The process involved 6027Co ? 6028Ni e- ne
- 6027Co is spin-5 and 6028Ni is spin4, both e- and
ne are spin-½ - If you start with fully polarized Co (SZ5) the
experiment is essentially the same (i.e. there is
only one spin solution for the decay) 5,5gt ?
4,4gt ½ ,½gt ½,½gt
S4
27The Wu experiment 1956
- Experimental challenge how do you obtain a
sample of Co(60) where the spins are aligned in
one direction - Wus solution adiabatic demagnitization of
Co(60) in magnetic fields at very low
temperatures (1/100 K!). Extremely challenging
in 1956!
28The Wu experiment 1956
- The surprising result the counting rate is
different - Electrons are preferentially emitted in direction
opposite of 60Co spin! - Careful analysis of results shows that
experimental data is consistent with emission of
left-handed (H-1) electrons only at any angle!!
Backward Counting ratew.r.t unpolarized rate
60Co polarization decreasesas function of time
Forward Counting ratew.r.t unpolarized rate
29The Wu experiment 1956
- Physics conclusion
- Angular distribution of electrons shows that only
pairs of left-handed electrons / right-handed
anti-neutrinos are emitted regardless of the
emission angle - Since right-handed electrons are known to exist
(for electrons H is not Lorentz-invariant
anyway), this means no left-handed
anti-neutrinos are produced in weak decay - Parity is violated in weak processes
- Not just a little bit but 100
- How can you see that 60Co violates parity
symmetry? - If there is parity symmetry there should exist no
measurement that can distinguish our universe
from a parity-flipped universe, but we can!
30Our universe vs a parity-flipped universe
- What happens to helicity in parity-flipped
universe? - Momentum flips sign
- Spin stays the same
- Helicity is product and flips sign
- Conclusion
- Any process that produces right-handed
anti-neutrinos in our universe will produce
left-handed anti-neutrinos in the mirrored
universe. - If left and right-handed neutrinos are not
produced at the same rate the physics in the
mirrored universe is different
Orientation of spin
righthanded H1
Direction of motion
P
lefthanded H-1
Orientation of spin
Direction of motion
31Parity violation in weak decays
- Apply parity operation to 60Co decay
P-Flipped universe
Our universe
RH ne
RH ne
e-
e-
LH ne
LH ne
e-
e-
32Parity violation in weak decays
- Apply parity operation to 60Co decay
P-Flipped universe(LH anti-neutrinos only)
Our universe(RH anti-neutrinos only)
Allowed
Forbidden
Allowed
Forbidden
RH ne
RH ne
e-
e-
LH ne
LH ne
e-
e-
Preferential direction of electronsis forward
Preferential direction of electronsis backward
33So P is violated, whats next?
- Wus experiment was shortly followed by another
clever experiment by L. Lederman Look at decay
p ? m nm - Pion has spin 0, m,nm both have spin ½ ? spin of
decay products must be oppositely aligned ?
Helicity of muon is same as that of neutrino. - Nice feature can also measure polarization of
both neutrino (p decay) and anti-neutrino (p-
decay) - Ledermans result All neutrinos are left-handed
and all anti-neutrinos are right-handed
p
m
nm
34Charge conjugation symmetry
- Introducing C-symmetry
- The C(harge) conjugation is the operation which
exchanges particles and anti-particles (not just
electric charge) - It is a discrete symmetry, just like P, i.e. C2
1 - C symmetry is broken by the weak interaction,
- just like P
OK
p
m
nm(LH)
C
nm(LH)
p-
m-
OK
35The Weak force and C,P parity violation
- What about CP ? CP symmetry?
- CP symmetry is parity conjugation (x,y,z ?
-x,-y,z) - followed by charge conjugation (X ? X)
?
??
??
P
C
CP appears to be preservedin weakinteraction!
?
?
??
??
?
??
CP
36What do we know now?
- C.S. Wu discovered from 60Co decays that the weak
interaction is 100 asymmetric in P-conjugation - We can distinguish our universe from a parity
flipped universe by examining 60Co decays - L. Lederman et al. discovered from p decays that
the weak interaction is 100 asymmetric in
C-conjugation as well, but that CP-symmetry
appears to be preserved - First important ingredient towards understanding
matter/anti-matter asymmetry of the universe
weak force violates matter/anti-matter(C)
symmetry! - C violation is a required ingredient, but not
enough as we will learn later - Next a precision test of CP symmetry
conservation in the weak interaction
37Conserved properties associated with C and P
- C and P are still good symmetries in any reaction
not involving the weak interaction - Can associate a conserved value with them
(Noether Theorem) - Each hadron has a conserved P and C quantum
number - What are the values of the quantum numbers
- Evaluate the eigenvalue of the P and C operators
on each hadronPygt pygt - What values of C and P are possible for hadrons?
- Symmetry operation squared gives unity so
eigenvalue squared must be 1 - Possible C and P values are 1 and -1.
- Meaning of P quantum number
- If P1 then Pygt 1ygt (wave function
symmetric in space)if P-1 then Pygt -1 ygt
(wave function anti-symmetric in space)
38Figuring out P eigenvalues for hadrons
- QFT rules for particle vs. anti-particles
- Parity of particle and anti-particle must be
opposite for fermions (spin-N1/2) - Parity of bosons (spin N) is same for particle
and anti-particle - Definition of convention (i.e. arbitrary choice
in def. of q vs q) - Quarks have positive parity ? Anti-quarks have
negative parity - e- has positive parity as well.
- (Can define other way around Notation different,
physics same) - Parity is a multiplicative quantum number for
composites - For composite AB the parity is P(A)P(B), Thus
- Baryons have P1111, anti-baryons have
P-1-1-1-1 - (Anti-)mesons have P1-1 -1
- Excited states (with orbital angular momentum)
- Get an extra factor (-1) l where l is the
orbital L quantum number - Note that parity formalism is parallel to total
angular momentum JLS formalism, it has an
intrinsic component and an orbital component - NB Photon is spin-1 particle has intrinsic P of
-1
39Parity eigenvalues for selected hadrons
- The p meson
- Quark and anti-quark composite intrinsic P
(1)(-1) -1 - Orbital ground state ? no extra term
- P(p)-1
- The neutron
- Three quark composite intrinsic P (1)(1)(1)
1 - Orbital ground state ? no extra term
- P(n) 1
- The K1(1270)
- Quark anti-quark composite intrinsic P
(1)(-1) -1 - Orbital excitation with L1 ? extra term (-1)1
- P(K1) 1
Meaning Ppgt -1pgt
40Figuring out C eigenvalues for hadrons
- Only particles that are their own anti-particles
are C eigenstates because Cxgt ? xgt cxgt - E.g. p0,h,h,r0,f,w,y and photon
- C eigenvalues of quark-anti-quark pairs is
determined by L and S angular momenta C
(-1)LS - Rule applies to all above mesons
- C eigenvalue of photon is -1
- Since photon is carrier of EM force, which
obviously changes sign under C conjugation - Example of C conservation
- Process p0 ? g g C1(p0 has spin 0) ?
(-1)(-1) - Process p0 ? g g g does not occur (and would
violate C conservation)
41Introduction to K0 physics
- Now focusing on another little mystery in the
domain of strange mesons what precisely is a
K0 meson? - Quark contents K0 ?sd,?K0 ?ds
- First what is the effect of C and P conjugation
on the K0/K0-bar particles? - PK0gt -1K0gt (because ?qq pair)
- PK0gt -1K0gt (because ?qq pair)
- CK0gt K0gt (because K0 is anti-particle of K0
ls0) - CK0gt K0gt (because K0 is anti-particle of K0
ls0) - Knowing this we can evaluate the effect of CP on
the K0 - CPK0gt -1K0gt
- CPK0gt -1 K0gt
42What are the K0 CP Eigenstates
- Thus K0 and K0 are not CP eigenstates,
- Somewhat strange since they decay through weak
interaction which appears to conserve CP! - Nevertheless it is possible to construct CP
eigenstates as linear combinations - Remember QM You can always construct wave
functions as linear combinations of the solutions
of any operator (like the Hamiltonian) - K1gt 1/?2(K0gt - K0gt)
- K2gt 1/?2(K0gt K0gt)
- Proof is exercise for today
- Does it make sense to look at linear combinations
of K0gt and K0gt? - I.e does K1gt represent a real particle?
43K0/K0 oscillations
- Well it might, because it turns out that the weak
interaction can turn a K0 particle into a K0
particle! - Weird? Yes! Impossible? No!
- In can be done using two consecutive weak
interactions - Important implication for nature of K0 particle
- Q If a K0 can turn into a K0 at any moment, how
do you know what particle youre dealing with? - A You dont. Any particle in the lab is always a
linear combination of the two ? It makes as much
sense to talk about K1 and K2 eigenstates as it
does to talk about K0 and K0 eigenstates
Weak force
Weak force
K0
(X)
K0
S1
S0
S-1
DS-1
DS-1
44So what is the K0 really?
- The K0 meson is something you can only describe
with quantum mechanics - It is a linear combination of two particles!
- You can either see it as a combination of K0gt
and ?K0gt,eigenvalues of Strangeness (1 vs 1)
and undefined CP - Or you can see it as a combination of K1gt and
K2gt,eigenvalues of CP (1, -1), with undefined
strangeness - Both representations are equivalent.
- Kaons are typically produced in strong
interactions in a strangeness eigenstate (K0 or
?K0) - Kaons decay through the weak interaction as
eigenstates of CP (K1 or K2) - Since K1 and K2 dont have definite S, S is not
conserved in weak decays as we already know - If you believe a particle must have a single well
defined lifetime, then K1 and K2 are the real
particles
45So what is the K0 really?
- Graphical analogy Any object with two
components can be decomposed in more than one way
Anti-K0
K2
Kgt
K0
K1
46Decays of neutral kaons
- Neutral kaons is the lightest strange particle ?
it must decay through the weak interaction - If weak force conserves CP then
- decay products of K1 can only be a CP1 state,
i.e.K1gt (CP1) ? p p (CP
(-1)(-1)(-1)l0 1) - decay products of K2 can only be a CP-1 state,
i.e.K2gt (CP-1) ? p p p (CP
(-1)(-1)(-1)(-1)l0 -1) - You can use neutral kaons to precisely test that
the weak force preserves CP (or not) - If you (somehow) have a pure CP-1 K2 state and
you observe it decaying into 2 pions (with CP1)
then you know that the weak decay violates CP
( S(K)0 ? L(pp)0 )
47Designing a CP violation experiment
- How do you obtain a pure beam of K2 particles?
- It turns out that you can do that through clever
use of kinematics - Exploit that decay of K into two pions is much
faster than decay of K into three pions - Related to fact that energy of pions are large in
2-body decay - t1 0.89 x 10-10 sec
- t2 5.2 x 10-8 sec (600 times larger!)
- Beam of neutral Kaons automatically becomes beam
of K2gt as all K1gt decay very early on
K1 decay early (into pp)
Pure K2 beam after a while!(all decaying into
ppp) !
Initial K0 beam
48The Cronin Fitch experiment
Essential idea Look for (CP violating) K2 ? pp
decays 20 meters away from K0 production point
Decay of K2 into 3 pions
Incoming K2 beam
If you detect two of the three pionsof a K2 ?
ppp decay they will generallynot point along the
beam line
49The Cronin Fitch experiment
Essential idea Look for K2 ? pp decays20 meters
away from K0 production point
Decay pions
Incoming K2 beam
If K2 decays into two pions instead ofthree both
the reconstructed directionshould be exactly
along the beamline(conservation of momentum in
K2 ? pp decay)
50The Cronin Fitch experiment
Essential idea Look for K2 ? pp decays20 meters
away from K0 production point
Decay pions
K2 ? pp decays(CP Violation!)
Incoming K2 beam
K2 ? ppp decays
Result an excess of events at Q0 degrees!
- CP violation, because K2 (CP-1) changed into K1
(CP1)
Note scale 99.99 of K ?ppp decaysare left of
plot boundary
51Cronin Fitch Discovery of CP violation
- Conclusion weak decay violates CP (as well as C
and P) - But effect is tiny! (0.05)
- Maximal (100) violation of P symmetry easily
follows from absence of right-handed neutrino,
but how would you construct a physics law that
violates a symmetry just a tiny little bit? - Results also provides us withconvention-free
definition ofmatter vs anti-matter. - If there is no CP violation, the K2 decaysin
equal amounts to p e- ne (a) p- e ne (b) - Just like CPV introduces K2 ? pp decays, it also
introduces a slight asymmetry in the above
decays (b) happens more often than (a) - Positive charge is the charged carried by the
lepton preferentially produced in the decay of
the long-lived neutral K meson
52Kaons K0,?K0, K1, K2, KS, KL,
- The kaons are produced in mass eigenstates
- K0gt ?sd
- ?K0gt ?ds
- The CP eigenstates are
- CP1 K1gt 1/?2 (K0gt - ?K0gt)
- CP -1 K2gt 1/?2 (K0gt ?K0gt)
- The kaons decay as short-lived or long-lived
kaons - KSgt predominantly CP1
- KLgt predominantly CP -1
-
- ?- (2.236 0.007) x 10-3
- e (2.232 0.007) x 10-3
53What do we know now?
- C and P are both violated by the weak interaction
because neutrinos can only be produced in a
single helicity state (LH neutrinos and RH
anti-neutrinos) - Results from Wu and Lederman experiments
- You can associate a P quantum number to all
hadrons and a C quantum number to all hadrons
that are their own anti-particle - These C and P quantum numbers are conserved in
any reaction not involving the weak interaction - The K0 meson is a special particle that really
exists as a combination of two particle the K0 /
K0 combination or the K1 / K2 combination at your
choice - The Cronin and Fitch experiment shows that in
addition to C and P violation the product CP is
also violated, but only a tiny little bit - Origin of CP violation sofar unknown ? Topic of
future section
54Schematic picture of selected weak decays
- K0 ? K0 transition
- Note 1 Two W bosons required (DS2 transition)
- Note 2 many vertices, but still lowest order
process
?s
?d
W
u
u
K0
K0
W
s
d
55Strangeness violation in W mediated decays
- In 1963 N. Cabibbo made the first step to
formally incorporate strangeness violation in W
mediated decays - For the leptons, transitions only occur within a
generation - For quarks the amount of strangeness violation
can be neatly described in terms of a rotation,
where qc13.1o
Weakforcetransitions
u
Idea weak interaction couples to different
eigenstates than strong interactionweak
eigenstates can be writtenas rotation of
strongeigenstates
W
d d?cosqc s?sinqc
56Cabibbos theory successfully correlated many
decay rates
- Cabibbos theory successfully correlated many
decay rates by counting the number of cosqc and
sinqc terms in their decay diagram
57Cabibbos theory successfully correlated many
decay rates
- There was however one major exception which
Cabibbo could not describe K0 ? m m- - Observed rate much lower than expected from
Cabibbos ratecorrelations (expected rate ?
g8sin2qccos2qc)
d
?s
cosqc
sinqc
u
W
W
nm
m
m-
58The Cabibbo-GIM mechanism
- Solution to K0 decay problem in 1970 by Glashow,
Iliopoulos and Maiani ? postulate existence of
4th quark - Two up-type quarks decay into rotated
down-type states - Appealing symmetry between generations
u
c
W
W
dcos(qc)dsin(qc)s
s-sin(qc)dcos(qc)s
59The Cabibbo-GIM mechanism
- Cabibbo-GIM mechanism introduces clean formalism
for quark flavour violations in the weak
interactionThe weak interaction (W boson)
couples to a rotated set of down-type
states - Tiny problem at time of introduction there was
no evidence for a 4th quark - Fourth charm quark discovered in 1974 ?
Vindication of Cabbibo/GIM mechanism
Leptonsectorunmixed
Quark section mixed throughrotation of weak
w.r.t. strong eigenstates by qc
60The Cabibbo-GIM mechanism
- How does it solve the K0 ? mm- problem?
- Second decay amplitude added that is almost
identical to original one, but has relative minus
sign ? Almost fully destructive interference - Cancellation not perfect because u, c mass
different
d
?s
?s
d
-sinqc
cosqc
cosqc
sinqc
c
u
nm
nm
m
m-
m
m-
61From 2 to 3 generations
- 2 generations d0.97 d 0.22 s (?c13o)
- 3 generations d0.97 d 0.22 s 0.003 b
- NB probabilities have to add up to 1
0.9720.2220.00321 - ? Unitarity !
62What do we know about the CKM matrix?
- Magnitudes of elements have been measured over
time - Result of a large number of measurements and
calculations
Magnitude of elements shown only, no information
of phase
63How do you measure those numbers?
- Magnitudes are typically determined from ratio of
decay rates - Example 1 Measurement of Vud
- Compare decay rates of neutrondecay and muon
decay - Ratio proportional to Vud2
- Vud 0.9735 0.0008
- Vud of order 1
64Outline
- 5 March
- Introduction matter and anti-matter
- P, C and CP symmetries
- K-system
- CP violation
- Oscillations
- Cabibbo-GIM mechanism
- 12 March
- CP violation in the Lagrangian
- CKM matrix
- B-system
- 19 March
- B?J/Psi Ks
- Delta ms
- (26 March No lecture)
- 2 April
- B-experiments BaBar and LHCb
- Measurements at LHCb