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Physics 212 Lecture 8, Slide 1

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Physics 212 Lecture 8, Slide 2. Music. Who is the Artist? Ray Charles. Solomon Burke. Henry Butler. Johnny Adams. Otis Redding ' ... – PowerPoint PPT presentation

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Title: Physics 212 Lecture 8, Slide 1


1
Physics 212 Lecture 8
2
Music
  • Who is the Artist?
  • Ray Charles
  • Solomon Burke
  • Henry Butler
  • Johnny Adams
  • Otis Redding

3
I like this format a lot better than last year,
but I would still like to be doing more
quantitative questions in lecture since those are
the harder ones.
Even though i feel like i am learning, i also
feel that if i were to take a test on this
material i would not do well.
I liked the format of PHYS211 last semester
better I was able to learn the material better
in lecture than at home on my laptop, especially
when I'm pressed for time and have to rush it.
I would like more quantitative examples.
Try to explain concepts as well as do problems.
I think this lecture system is much better than
last semester, 211.
I think overall the experience has been great
because I learn more. However, I do seem to be
spending quite alot of time on the prelectures
and preflights in my attempt to understand
everything fully.
I like the enthusiasm in lecture now, but I
dislike how figuring out how to do the actual
calculations of the concepts is essentially
placed on us. We maybe do one example calculation
a week I would love to see more. We don't need
the whole hour on conceptual stuff. That can be
read up on, it's harder to learn calculating
stuff on your own.
I think this set up is very good and helpful. I
wasn't happy about the extra work at first, but
they definitely make the lectures more beneficial
since I already have some ideas about the
material heading in. I would continue to do more
problems in class.
4
(No Transcript)
5
Things you identified as difficult
  • Wire up capacitors in different ways in a
    circuit - What is Q, V, C, E etc. -
    Comparing cases, when is V the same, when Q the
    same, etc. - How do I know what changes from one
    case to the next ?
  • Dielectrics - Does it take work to stick some
    into a capacitor?

6
Simple Capacitor Circuit
V
C
7
Dielectrics
By adding a dielectric you are just making a new
capacitor with larger capacitance (factor of k)
8
Parallel Capacitor Circuit
C2
C1
V
Key point V is the same for both capacitors
Key Point Qtotal Q1 Q2 VC1 VC2 V(C1
C2)
Ctotal C1 C2
9
Series Capacitor Circuit
V
Key point Q is the same for both capacitors
Key point Q VCtotal V1C1 V2C2
Also V V1 V2
10
Preflight 1
Which has lowest total capacitance
C
C
C
C
C
1/Ctotal 1/C 1/C
2/C
Ctotal 2C
Ctotal C/2
Ctotal C
11
Preflight 4
Which has lowest total capacitance
C
C
C
C
C
Ctotal C
Ctotal Cleft Cright
Same
12
Preflight 7
CD
Ctotal
  • Which of the following is NOT true
  • V0 V1
  • Ctotal gt C1
  • V2 V3
  • Q2 Q3
  • V1 V2 V3

13
Preflight 7
14
Energy in a Capacitor
In pre-lecture 7 we calculated the work done to
move charge Q from one plate to another
Q
C
V
U 1/2QV
-Q
This is potential energy waiting to be used
(big bang)
15
Energy in a Capacitor with dielectric
Its simple just use the new capacitance C1 kC0
Case 1 If Q is constant (not attached to
battery) then V changes
C0
Q
Q
C1kC0
V0
V1
16
Energy in a Capacitor with dielectric
Case 2 If V is constant (cap attached to
battery) then Q changes
17
Preflight 10
For dielectric, there's field created that is
opposing the field by the conductors, so the
field is smaller, which means the voltage is
smaller as well since V Ed.
18
Preflight 12
For dielectric, there's field created that is
opposing the field by the conductors, so the
field is smaller, which means the voltage is
smaller as well since V Ed.
19
Preflight 15
CD
20
Calculation
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Qf, the final charge on the capacitor?

V
fx0
Q
21
Calculation
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Qf, the final charge on the capacitor?

V
fx0
Q
  • Strategic Analysis
  • Calculate new capacitance C
  • Apply definition of capacitance to determine Q

(A) Vleft lt Vright (B) Vleft Vright
(C) Vleft gt Vright
The conducting plate is an equipotential !!
22
Calculation
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Qf, the final charge on the capacitor?

V
fx0
Q
  • Can consider capacitor to be two capacitances,
    C1 and C2

In general. For parallel plate capacitor C
e0A/d
23
Calculation
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Qf, the final charge on the capacitor?

V
fx0
C2
Q
C1

C1 (1-f)C0
In general. For parallel plate capacitor filled
with dielectric C ke0A/d
24
Calculation
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Qf, the final charge on the capacitor?

V
fx0
C2
C
Q
C1

C1 (1-f)C0
C2 kfC0
C parallel combination of C1 and C2 C C1
C2
25
Calculation
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Qf, the final charge on the capacitor?

V
fx0
C2
C
Q
C1

C1 (1-f)C0
C2 kfC0
C C0 (f(k-1) 1)
What is Q?
Q increases linearly from Q0 to kQ0
26
Calculation
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Qf, the final charge on the capacitor?

V
fx0
C2
C
Q
C1

C1 (1-f)C0
C2 kfC0
C C0 (f(k-1) 1)
U ½ QV Q increased V remained same
27
Different Problem
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V
    and then battery is disconnected.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Vf, the final voltage on the capacitor?

Q0
C0
V
V
x0
fx0
Q
(A) Vf lt V (B) Vf V (C) Vf
gt V
Q stays same no way to add or subtract
We know C (property of capacitor)
28
Different Problem
  • An air-gap capacitor, having capacitance C0 and
    width x0 is connected to a battery of voltage V
    and then battery is disconnected.
  • A dielectric (k) of width fx0 is inserted into
    the gap as shown.
  • What is Vf, the final voltage on the capacitor?

Q0
C0
V
V
x0
fx0
Vf Q/C V / (f(k-1) 1)
How did energy stored in capacitor change when
dielectric inserted?
  • U increased (B) U stayed same (C) U
    decreased

U ½ QV Q remained same V decreased
29
Extra 1
30
Extra 2
31
Extra 3
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