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The 'Golden Age' of Greek mathematics ended by the close of the third century. ... interests to theological debates (a consequence of the spread of Christianity) ... – PowerPoint PPT presentation

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Title: Diophantus:


1
Diophantus
Chapter 5
  • The Curtain Closes on
  • Greek Mathematics
  • Robert Owens Angi Purdon

2
Brief Historical Background
  • Ptolemy VII banished all scholars and scientists
    that had not proven their fidelity to
    themAlexandrias loss was the remainder of the
    Mediterraneans gain.

3
Brief Historical Background
  • The Golden Age of Greek mathematics ended by
    the close of the third century. By the fourth
    century scholars began to turn their interests to
    theological debates (a consequence of the spread
    of Christianity).

4
Brief Historical Background
  • It is interesting to note that although Greek and
    Roman cultures existed simultaneously, no Roman
    mathematicians of note are mentioned in
    historical documents. This is perhaps in part
    due to the widespread Roman contempt for theory
    (illustrated by Cicero). The Romans did,
    however, call on the Greeks for mathematical help
    when they needed it.

Cicero The Greeks held the geometer in the
highest honor accordingly, nothing made more
brilliant progress among them than mathematics.
But we have established as the limits of this art
its usefulness in measuring and counting.
5
Diophantus (in some texts Diophantos)
  • As with most of ancient Greek mathematicians,
    little is known about him personally, what little
    we know is that he lived in Alexandria around the
    middle of the third century AD, and was most
    likely a Hellenized Babylonian.
  • The remainder of the details of his life we learn
    from a famous epitaphic problem
  • God granted him to be a boy for the sixth part
    of his life, and adding a twelfth part to this,
    He clothed his cheeks with down He lit him the
    light of wedlock after a seventh part, and five
    years after his marriage He granted him a son.
    Alas! late-born wretched child after attaining
    the measure of half his father's life, chill Fate
    took him. After consoling his grief by this
    science of numbers for four years he ended his
    life
  • Setting this problem up as
  • 1/6x 1/12x 1/7x 5 1/2x 4 x This
    implies x 84,
  • Personal details can be ascertained from this
    answer.

6
Diophantus Contributions to Mathematics
  • We know of three mathematical works written by
    him On Polygonal Numbers (only a small portion
    still exists), Porisms (which remains lost), and
    the most influential, Arithmetica.
  • Algebra progressed through three stages
  • Rhetorical, in which the solution of an
    equation is
  • written in prose from (without symbols or
  • abbreviations),
  • Syncopated, in which symbols are incorporated
    for the
  • more commonly occurring operations and
    quantities, and Symbolic, where solutions are
    expressed in a
  • mathematical shorthand composed primarily of
  • symbols.
  • Diophantus is largely responsible for the
    syncopation of algebra, and the extensive
    exploration of indeterminate algebraic problems.

7
Syncopation of Algebra
  • Diophantus syncopated algebra by developing
    symbols for the following expressions an
    unknown, powers, equality, subtraction,
    reciprocals and constants.
  • V is designated for an unknown value (x)
  • D is designated for an unknown squared (x2)
  • k is designated for an unknown cubed (x3)
  • DD is a unknown square-square or 4th power
    (x4)
  • Dk is a unknown square-cube or 5th power (x5)
  • kk is a unknown cube-cube or 6th power (x6)
  • y is designated for subtraction (-)
  • i is designated for equality ()
  • c is designated for reciprocals of powers
  • M is designated for a constant

8
Syncopation of Algebra
  • Coefficients were ordinary numerals following
    power symbol.
  • An example of a term used would be something
    like
  • kle k35 35x3
  • Since there was no symbol for addition, all
    negative terms were placed together after a
    single subtractive symbol
  • k1V8 y D 5 M2
  • would be equivalent to
  • X3 5x2 8x 2

9
Diophantine Equations
  • The expression Diophantine equations is used
    for any equation in one or more unknown that is
    to be solved for the explicit value of the
    unknown(s).
  • Diophantus was not the first to solve this type
    of equation, but is given the honor of this
    naming because of his great ability with this
    type of problem (demonstrated in the Arithmetica.
  • It is fair, however, to say that Diophantus was a
    pioneer in many aspects of number theory, and we
    are all the richer for his developments in this
    area.
  • One interesting thing of note, is that although
    rational numbers were considered relevant
    solutions to problems, negative numbers were not.
    Diophantus described a problem such as 2x 17
    7 as absurd.

10
The Arithmetica
  • Originally, 13 books only 6 have been preserved.
  • Diophantus most famous work.
  • There are approximately 190 assorted problems,
    like the Rhind papyrus.

11
Problems from Arithmetica
  • Book II, Problem 8. Divide a given square
    number, say 16 into the sum of two squares.
  • Let one of the required squares be x2.
  • This implies that 16- x2 would yield another
    perfect square.
  • Diophantus selected a particular instance of a
    perfect square to set this equal to, one that was
    particularly useful in eliminating the constant
    terms (2x-4)2
  • Setting these terms equal to each other, we
    have
  • 16 - x2 (2x-4)2 which simplifies to 5x2 16x
  • Thus x 16/5.
  • Hence, the two squares would be
  • (16/5)2 or 256/25
  • and 16-256/25, or 144/25

12
Problems from Arithmetica
  • Book III, Problem 17. Find two numbers such that
    their product added to either one or to their sum
    gives a square.
  • Let the required numbers be x and 4x-1.
  • (These numbers are chosen so that they satisfy
    one condition directly, as shown below).
  • x(4x-1) x 4x2 (2x)2
  • Adding the product to their sum and also to 4x-1
    must yield a square.
  • Using the identity a2 b2 (a b)(a b), we
    set a2 4x2 4x 1, and b2 4x2 3x 1, so
    a2 b2 will equal x.
  • x is then separated into 2 factors 4x (we will
    call (a b)) and ¼ (we will call (a-b))
  • solving this system, we reach a ½(4x ¼) and b
    ½(4x- ¼)
  • plugging these values into either a2 or b2
    equation above, we attain x to be 65/224, so the
    other number is 36/224.

13
Problem from Lilavati
  • Say quickly, mathematician, what is the
    multiplier by which 221 being multiplied, and 65
    added to the product, the sum divided by 195
    becomes exhausted leaves no remainder?
  • This can be expressed as 221y 65 195x,
    rewritten 195x 221y 65
  • Using Euclids algorithm to find the gcd of 195
    and 221
  • 221 195 1 26
  • 195 26 7 13
  • 26 13 2
  • So 13 is the greatest common divisor of 195 and
    221. Since it also divides 65, a solution
    exists.
  • Finding a linear combination, we work backwards
  • 13 195 726
  • 13 195 7(221-195)
  • 13 8 195 (-7)221
  • Multiplying the equation through by 5, we see
    that
  • 65 40 195 (-35)221
  • hence, one (there are many) solution to this
    problem is x 40, y 35.

14
Hypatia
  • First woman mathematician of historical
  • note.
  • Lived 370-415.
  • Daughter of Theon learned mathematics,
  • medicine and philosophy from him.
  • Wrote a commentary on Arithmetica, also on
    Apollonius Conic Sections.
  • Lectured at the Museum, attracted many important
    listeners.
  • Christian leaders felt threatened by her
    heretical teachings
  • One day, returning from teaching, she was
    ambushed, cut using the shells of oysters, then
    dismembered, her remains burnt.
  • Considered the last of the great Greek
    Mathematicians.

15
Homework Problems
  • 5.3.3. Book I, Problem 27. Find two number such
    that their sum and product are given numbers say
    their sum is 20 and their product is 96. Hint
    Call the numbers 10 x and 10 x. Then one
    condition is already satisfied.
  • 5.3.7. Book II, Problem 22. Find two number
    such that the square of either number added to
    the sum of both gives a square. Hint If the
    numbers are taken to be x and x1, then one
    condition is satisfied.
  • 5.3.13. Which of the following diophantine
    equations cannot be solved?
  • a) 6x 51y 22
  • b) 33x 14y 115
  • c) 14x 35y 93
  • 5.3.15. Determine all solutions in the positive
    integers of the following diophantine equations.
  • a) 18x 5y 48
  • b) 123x 57y 30
  • c) 123x 360y 99
  • Homework is due Monday, November 10 and worth a
    quiz grade.

16
Sources Utilized
  • Burton, David M., The History of Mathematics, An
    Introduction, p 203-226, McGraw-Hill, New York,
    NY, 2003.
  • Eves, Howard, An Introduction to the History of
    Mathematics, p 179-182, Saunders College
    Publishing, Orlando, FL, 1990.
  • Eves, Howard, Great Moments in Mathematics, p
    117-120, The Mathematical Association of America,
    1980.
  • Eves, Howard, In Mathematical Circles, p 59-62,
    Prindle, Weber Schmidt, Inc., Boston, 1969.
  • Grattan-Guinness, Ivor, The Norton History of the
    Mathematicl Sciences The Rainbow of Mathematics,
    p. 80-82, W.W. Norton Company, New York, 1997.
  • http//www-gap.dcs.st-and.ac.uk/history/Mathemati
    cians/Diophantus.html
  • http//www-gap.dcs.st-and.ac.uk/history/Quotation
    s/Diophantus.html
  • http//www.lib.virginia.edu/science/parshall/dioph
    ant.html
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