Title: Chapter 2 : Circumcenter, Orthocenter, incenter, and centroid of triangles
1Chapter 2 Circumcenter, Orthocenter,
incenter, and centroid of triangles
- Outline
- Perpendicular bisector ,
- circumcentre and orthocenter
- Bisectors of angles and the incentre
- Medians and centroid
22.1 Perpendicular bisector, Circumcenter and
orthocenter of a triangle
- Definition 1 The perpendicular bisector
- of a line segment is a line perpendicular
- to the line segment at its midpoint.
CD is a perpendicular bisector of AB if (i)
ACBC (ii) DCA DCB
3In-Class-Activity 1
- (1) If P is a point on the perpendicular
bisector of AB, what is the relationship
between PA and PB? - (2) Make a conjecture from the observation in
(1). Prove the conjecture. -
- (3) What is the converse of the conjecture in
(2). - Can you prove it?
4- Theorem 1 The perpendicular bisectors of the
three sides of a triangle meet at a point - which is equally distant from the vertices
of the triangle. -
-
The point of intersection of the three
perpendicular bisectors of a triangle is called
the circumcenter of the triangle.
5- DG, MH and EF are the perpendicular
bisectors of the sides AB,AC and BC
respectively - DG, MH and EF meet at a point O
- OAOBOC
- O is the circumcenter of triangle ABC.
6Proof of Theorem 1
- Given in ABC that DG, EF and MH are the
perpendicular bisectors of sides AB, BC and CA
respectively. - To prove that
- DG,EF and MH meet at a point O,
- and AOBOCO.
- Plan Let DG and EF meet at a point O. Then show
that OM is perpendicular to AC.
7Proof
- 1.Let DG and EF meet at O
- 2. Connect M and O.
- We show MO is
- perpendicular to side AC
- 3. Connect AO, BO and CO.
- (If they dont meet, then DG//EF, so AB//BC,
impossible) -
8- 4. AOBO, BOCO
- 5. AOCO
- 6. MOMO
- 7. AMCM
- 8.
- 9.
- 10
- (O is on the perpendicular bisects of AB and BC)
- ( By 4 )
- (Same segment )
- ( M is the midpoint )
- (S.S.S)
- (Corresponding angles
- (By 9 and )
9- 11.OM is the perpendicular (Two conditions
satisfied) - bisector of side AC.
- 12. The three perpendicular
- bisector meet at point O.
- 13.O is equally distant from ( by 4)
- vertices A,B and C.
10- Remark 1 ( A method of proving that three lines
meet at a point ) - In order to prove three lines meet at one point,
we can - first name the meet point of two of the lines
- then construct a line through the meet point
- (iii) last prove the constructed line coincides
with the third line.
11- In-Class-Exercise 1
-
- Prove Theorem 1 for obtuse triangles.
-
-
- Draw the figure and give the outline of the
- proof
12- Remark 2 The circumcenter of a triangle is
equally distant from the three vertices. - The circle whose center is the
circumcenter of a triangle and whose radius is
the distance from the circumcenter to a vertex
is called the - circumscribed circle
- of the triangle.
-
13- In-Class-Activity
- Give the definition of parallelograms
- (2) List as many as possible conditions for a
quadrilateral to be a parallelogram. - (3) List any other properties of parallelogram
which are not listed in (2).
14(1) Definition A parallelogram is a quadrilateral
with its opposite sides parallel
ABCD
- (2) Conditions
- The opposite sides equal
- Opposite angles equal
- The diagonals bisect each other
- Two opposite side parallel and equal
- (3)
15- Theorem 2
- The three altitudes of a triangle meet at a
point.
16- Given triangle ABC with altitudes AD, BE
and CF. - To prove that AD, BE and CF meet at a point.
- Plan is to construct another larger triangle
ABC - such that AD, BE and CF are the perpendicular
bisectors - of the sides of ABC. Then apply
Theorem 1.
17- Proof (Brief)
- Construct triangle ABC such that
- AB//AB, AC//AC, BC//BC
- 1. ABCB is a parallelogram.
- 2. BCAB.
- 3. Similarly CAAB.
- 4. CE is the perpendicular bisector of ABC
of side BA. - 5. Similarly BF and AD are perpendicular
bisectors of sides of ABC. - 6. So AD, BF and CE meet at a point (by
Theorem 1)
18- The point of intersection of the three
altitudes of a triangle is called the - orthocenter
- of the triangle.
192.2 Angle bisectors , the incenter of a
triangle
- Angle bisector
- ABD DBC
- In-Class-Exercise 2
- (1) Show that if P is a point on the bisector
of then the distance from P to AB
equals the distance - from P to CB.
- (2) Is the converse of the statement in (1)
also true?
20- Lemma 1 If AD and BE are the bisectors of the
angles - A and B of ABC, then AD and BE
intersect at a point.
Proof Suppose they do not meet. 1. A
B C180 ( Property of triangles) 2.
Then AD// BE. ( Definition of parallel
lines) 3. DAB EBA180 ( interior
angles on same side ) 4.
( AD and BE are bisectors
)
21- 5.This contradicts that
- The contradiction shows that the two angle
bisectors must meet at a point.
Proof by contradiction ( Indirect proof) To
prove a statement by contradiction, we first
assume the statement is false, then deduce
two statements contradicting to each other.
Thus the original statement must be true.
22- Theorem 3 The bisectors of the three angles of
a triangle - meet at a point that is equally distant from the
three side - of the triangle.
The point of intersection of angle bisectors of
a triangle is called the
incenter of the triangle
Read and complete the proof
23- Remark Suppose r is the distance from the
incenter to a side of a triangle. Then there
is a circle whose center is the incenter and
whose radius is r. - This circle tangents to the three sides
- and is called the
- inscribed circle ( or incircle) of the
triangle.
24Example 1 The sum of the distance from any
interior point of an equilateral triangle to the
sides of the triangle is constant.
25- Proof
- 1.
- 2.
- 3. ABACBC (ABC is equilateral )
- 4.
- 5.
( by 1 and 4) - 6.
- is a constant.
26- In-Class-Activity
- (1) State the converse of the conclusion proved
in Example 1. - Is the converse also true?
- Is the conclusion of Example 1 true for points
outside the triangle?
272.3 Medians and centroid of a triangle
- A median of a triangle is a line drawn from any
vertex to the mid-point of the opposite side. - Lemma 2 Any two medians of a triangle meet at a
point.
28- Theorem 3 The three medians of a triangle meet
at a point which is two third of the distance
from each vertex to the mid-point of the opposite
side.
The point of intersection of the three medians of
a triangle is called the
centroid of the triangle
29- Proof (Outline)
- Let two median AD and BE meet at O.
- Show
- If CE and AE meet at O, then
- So O is the same as O
- All medians pass through O.
- Read the proof
30- Example 2 Let line XYZ be parallel to side
BC and pass - through the centroid O of .
- BX, AY and CZ are perpendicular to XYZ.
- Prove AYBXCZ.
31 32Question
- Is the converse of the conclusion in
- Example 2 also true?
- How to prove it?
33- Summary
- The perpendicular bisectors of a triangle meet at
a point---circumcenter, which is equally distant
from the three vertices and is the center of the
circle outscribing the - triangle.
- The three altitudes of a triangle meet at a
point--- orthocenter . - The angle bisectors of a triangle meet at a
point---incenter, which is equally distant from
the three sides and is the center of the circle
inscribed the triangle. - The three medians of a triangle meet at a point
---centroid. Physically, centroid is the center
of mass of the triangle with uniform density.
34Key terms
- Perpendicular bisector
- Angle bisector
-
Altitude -
Median - Circumcenter
-
Orthocenter - Incenter
-
Centroid - Circumscribed circle
- Incircle
35Please submit the solutions of 4
problems in Tutorial 2
next time. THANK YOU
Zhao Dongsheng MME/NIE Tel 67903893 E-mail
dszhao_at_nie.edu.sg