Title: Announcements
1Announcements
- Exam 1 next week, 9/19, 9/20 in testing center.
Covers chapters 1 through 4, with emphasis on
material from lectures through 9/13, from Monk
in the garden, and from lab. Part
multiple-choice, part short answer - emphasis on
problem-solving. No time limit, but must finish
that day so choose a 2-3 hr. time block. Closed
book bring calculator, 2 pencils and BLUE BOOK. - Review sessions next week in lecture and in
lab. Bring your questions! - Problem set 2 answers due Friday, 9/13 at start
of class. Also practice Ch.4 problems
this week (but do not turn in) 1, 7, 16, 27, 31.
- 3. re. printing power point slide files when
in computer room of Brooks, please choose
handout when asked print what and - print 6 slides/page. Do not print 1 slide per
page.
2Problem Set 2 due Friday 9/13 in class - show
all your work.
- The LM and LN alleles at the MN blood group locus
exhibit codominance. Give the expected genotypes
and phenotypes (with their ratios) of progeny
from the following crosses - a) LMLM x LMLN
- b) LMLN x LNLN
- A woman of blood group AB marries a man of blood
group A whose father was group O. What is the
probability that - a) their 2 children will both be group A?
- b) one child will be group B and the other child
group O? - 3. In snapdragons, red flower color (R1) is
incompletely dominant to white (R2) the R1/R2
heterozygotes are pink. A red-flowered
snapdragon is crossed to a white colored one.
Determine the ratios of the flower colors in the
progeny from a cross of an F1 with the red parent.
2 points each question part for 10 points total
3Review of last lecture
- I. Chi-square revisited small deviation from
expected yields small X2 value this correlates
with high probability that deviation is due to
chance and you should NOT reject your hypothesis - II. Pedigree analysis- recessive vs. dominant
traits - - solving pedigree problems
4Solving Pedigree Problems
- Inspect the pedigree
- If trait is dominant, it will not skip
generations nor be passed on to offspring unless
parents have it. - If trait is recessive, it will skip generations
and will exist in carriers. - Form a hypothesis, e.g. autosomal recessive.
- Deduce the genotypes.
- Check that genotypes are consistent with
phenotypes. - Revise hypothesis if necessary, e.g. autosomal
dominant.
5Pedigree Example 2 p. 71, 26
6Outline of Lecture 7
In all crosses discussed so far, one of two
traits for a character has been dominant to the
other. ie. according to Mendels second
postulate of dominance/ recessiveness. Does the
expression of all genes occur in this way? ex.
Are there only two colors of hair for humans with
one clearly dominant to the other? NO
- I. Alleles alter phenotypes in different ways a
variety of symbols are used for alleles - II. Incomplete dominance - where neither allele
is dominant - III. Codominance - both alleles in a
heterozygote are expressed - IV. Multiple alleles of a gene are studied in a
population - V. Lethal alleles - recessive or dominant
- VI. Modification of the 9331 ratio
7I. Alleles - alternate forms of the same gene
- Wild-type allele - allele (form of gene) most
frequently found in nature (normal) specifies
normal phenotype and is usually dominant. - Mutant allele specifies an altered phenotype.
- Mutation creates new alleles.
8 Gene Symbol Conventions
- ebony body color mutation in Drosophila e
- Normal (wildtype) color is gray e
- e/e or / is homozygous wildtype
- e/e is homozygous ebony
- e/e or /e is heterozygous
- Other systems are also used, but symbol usually
reflects the function of the gene, e.g. cdc,
leu-, BRCA1
9II. Incomplete Dominance
- Neither of two alleles is dominant, e.g.
snapdragon flower color - R1 is red
- R2 is white
- Heterozygotes give an intermediate (blended)
phenotype - P1 cross gives pink flowers in F1
- F1 cross gives 121 redpinkwhite in F2
10III. Codominance
- When two alleles of a gene specify two distinct,
detectable gene products - MN blood group in humans LM, LN alleles
- MN locus codes for surface glycoprotein on red
blood cells can detect immunochemically. - LM LM gives M phenotype
- LM LN gives MN phenotype
- LN LN gives N phenotype
- LM LN X LM LN produces 1/4 LM LM, 1/2 LM LN,
1/4 LN LN
11IV. Multiple Alleles ABO Blood Groups
- When 3 or more alleles present (allelic series)
can only be studied in populations. - A and B alleles code for glycoproteins on red
blood cells which can be detected
immunochemically - mix blood sample with type A or type B antibodies
- look for clumping of RBCs
- O allele carries neither antigen
12ABO Blood Groups
A - A antigen only B - B antigen only AB -
Both A and B antigens O - Neither antigen
13ABO Genotypes and Phenotypes
14ABO, continued
- IA and IB are codominant
- Both IA and IB are dominant to IO
- All possible matings shown in Table 4.1
- Applications
- testing compatibility of blood transfusions
- disproving parentage of a child
- forensic science
15Biochemical Basis of ABO
- A and B antigens are on carbohydrate groups bound
to fatty acids (glycolipid) on RBC membrane - The A and B alleles code for enzymes that
differentially process the carbohydrate during
synthesis of the glycolipid - A enzyme adds N-acetylgalactosamine
- B enzyme adds galactose
16Complexity with ABO blood groups The Bombay
Phenotype
17Biochemical Basis of Bombay Phenotype
- h mutation prevents addition of fucose to form H
substance. - A and B enzymes no longer recognize structure,
dont add A and B antigens. - So individual is phenotypically O but can be
genotypically A_, B_ or AB. - H/h acts upstream of A and B in the pathway.
18Bombay Phenotype hh masks the expression of ABO
(Epistasis)
19The Secretor Locus also affects the expression of
the ABO blood type
About 80 of human population have the A and B
antigens present in various body secretions - not
only in blood. Genetics - dominant allele, Se
(Se/Se or Se/se)
In what societal application would the secretor
locus have significance?
Forensic science - ABO blood typing can be
performed on tissue samples other than blood.
20Multiple alleles - a second example
White locus in Drosophila - over 100 alleles may
occupy this locus. This results in an allelic
series of eye colors ranging from pure white, to
light buff to yellowish pink to deep ruby. (Table
4.3 in text)
21V. Lethal Alleles
- Recessive lethal if heterozygote is viable,
homozygous mutants die common, e.g. - Yellow (AY) in mice
- Manx (M) in cats
- Curly wing (Cy) in Drosophila
- Dominant lethal if either heterozygotes or
homozygous mutants die rare, e.g. Huntington
disease
22Mouse coat colors
Agouti x agouti Yellow x yellow Agouti x yellow
All agouti 2/3 yellow, 1/3 agouti 1/2 yellow, 1/2
agouti
23Effect of Dominant Yellow, Recessive Lethal in F2
AY is dominant to A AAY is yellow, but AYAY is
lethal
Results in 21 monohybrid ratio
24VI. Modified Dihybrid Cross First Consider Each
Trait on its Own
Ex. 2 humans heterozygous for albinism and are
blood type AB
25Modified Dihybrid Cross Next Consider Both
Traits Together