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Section 5'7 Applications of Quadratic Equations

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The result will be the same as the square of the Hypotenuse. Pythagorean Theorem. 42 ... The hypotenuse of a right triangle is 3 inches longer than the longer leg. ... – PowerPoint PPT presentation

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Title: Section 5'7 Applications of Quadratic Equations


1
Section 5.7Applications of Quadratic Equations
2
Area Example
w
48
l w 2
  • The length of a room is 2 meters more than the
    width. The area of the floor is 48 square
    meters. Find the length and width of the room.

Can w -8?
Thus w 6
And l w 2 l 8
3
Complicated Example
  • The length of each side of a square is increased
    by 4 inches.
  • The sum of the areas of the original square and
    the larger square is 106 square inches.
  • What is the length of a side of the original
    square?

4
The length of each side of a square is increased
by 4 inches.
x 4
x
Area x2
Area (x4)2
x2 8x 16
The sum of the areas of the original square and
the larger square is 106 square inches.
x2 x2 8x 16 106
5
Algebra
  • x2 x2 8x 16 106
  • 2x2 8x - 90 0
  • 2(x2 4x - 45) 0
  • 2(x 9)(x - 5) 0
  • x -9, 5
  • Reject -9
  • so x 5 and x 4 9

So the original square measures 5inches on a side.
6
Consecutive Integers
  • 1
  • 2
  • 3
  • 4
  • 5
  • x
  • x 1
  • x 2
  • x 3
  • x 4

7
Consecutive Even Integers
  • 0
  • 2
  • 4
  • 6
  • 8
  • x
  • x 2
  • x 4
  • x 6
  • x 8

8
Consecutive Odd Integers
  • 1
  • 3
  • 5
  • 7
  • 9
  • x
  • x 2
  • x 4
  • x 6
  • x 8

9
Product of Consecutive Even
  • The product of two consecutive even integers is 4
    more than two times their sum. Find the integers.

x(x2)

4
2(x(x2))
x-2, 4
x2 2x 42(2x2))
-2, 0 is one pair
x2 2x 4 4x 4
x2 - 2x - 8 0
4, 6 is the other
(x 2)(x - 4) 0
10
Consecutive Odd
  • Find three consecutive odd integers such that the
    product of the smallest and the largest is 16
    more than the middle integer.

x(x4)

16
(x 2)
x2 4x 16 x 2
x x 2 x 4
3 5 7
x2 3x - 18 0
(x 6)(x - 3) 0
x - 6, 3
11
Pythagorean Theorem
In a right triangle, the side opposite the right
angle is called the hypotenuse.
A triangle with a 90º angle is called a right
triangle.
The other two sides are called legs.
The small square indicates a 90º angle.
12
Pythagorean Theorem
  • If you square the legs of a right triangle and
    then add...
  • The result will be the same as the square of the
    Hypotenuse.

c
c
a2 b2 c2
a
3
32 42 c2
9 16 c2
b
4
25 c2
5 c
13
Pythagorean Theorem
52
32
9 16 25
42
14
Right Triangle Example
c
x 3
a
x - 3
  • The hypotenuse of a right triangle is 3 inches
    longer than the longer leg.
  • The shorter leg is 3 inches shorter than the
    longer leg.
  • Find the lengths of the sides of the triangle.

b
x
a2 b2 c2
(x - 3)2 x2 (x 3)2
15
Right Triangle Example
x 3
x 3 15
x - 3 9
x - 3
(x - 3)2 x2 (x 3)2
x
x 12
x2 - 3x - 3x 9 x2 x2 3x 3x 9
x2 - 12x 0
9 inches 12 inches 15 inches
x(x - 12) 0
x 0, 12
Reject x 0
16
What is the difference?
  • (x 3)(x 2) 0

x-3, 2
  • (x 3)(x - 2) 24

x2 x 6 24
x2 x 30 0
x-6, 5
(x 6)(x 5) 0
17
Right Triangle Problem
c
15
a
x - 3
  • The hypotenuse of a right triangle is 15 inches
    long.
  • The shorter leg is 3 inches shorter than the
    longer leg.
  • Find the perimeter of the triangle.

b
x
a2 b2 c2
(x - 3)2 x2 (15)2
Now for a bunch of algebra.
18
(x - 3)2 x2 (15)2
(x - 3)2 (x - 3)(x - 3)
x2 - 3x - 3x 9
x2 - 6x 9 x2 225
x2 - 6x 9
2x2 - 6x 9 - 225 0
2x2 - 6x - 216 0
2(x2 - 3x - 108) 0
2(x - 12)(x 9) 0
x 12, -9
Now back to the problem.
19
Right Triangle Problem
c
15
a
x - 3
9
  • The hypotenuse of a right triangle is 15 inches
    long.
  • The shorter leg is 3 inches shorter than the
    longer leg.
  • Find the perimeter of the triangle.

12
x
b
a2 b2 c2
(x - 3)2 x2 (15)2
x 12, -9
Perimeter 91215
Perimeter 36
Reject -9
20
Consecutive Evens
  • The product of two consecutive even integers is
    168. Find the integers.

x(x2)

168
x2 2x 168
x2 2x - 168 0
-14, -12 is one pair
(x - 12)(x 14) 0
12, 14 is the other
x-14, 12
21
Homework Section 5.7
  • 1-31 odd
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