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Thermodynamics II

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Thermodynamics II. Review Sample Problem. 40.0 g NH4NO3 ... Plot of lnK vs 1/T see back page. PHASE CHANGES - generalizations. To state with more freedom ... – PowerPoint PPT presentation

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Title: Thermodynamics II


1
Thermodynamics II
2
Review Sample Problem
  • 40.0 g NH4NO3 dissolved in 500. g water in
    insulated cup, what is the final temperature of
    the solution, given same specific heat as water,
    and standard enthalpies of formation
  • ?Hof NH4NO3(s) -365.6 kJ/F NH4(aq) -132.5 kJ/F
  • NO3-(aq) -205.05 kJ/F
  • NH4NO3(s) ? NH4(aq) NO3-(aq)

3
(No Transcript)
4
ENTROPY S
  • Measurement of randomness or disorder
  • Greater disorder ? larger S
  • Second Law of Thermodynamics
  • Entropy of universe always increasing
  • Nature favors increase in disorder
  • For any process ?S SPRODUCTS SREACTANTS
  • ?S 0 products favored by entropy
  • ?S
  • Energy must be expended to give a more ordered
    state

5
One liter of an ideal gas is allowed to expand to
two liters at constant temperature. What is the
?S of the process? -- of the reverse process?
  • For system ?S Rln(Vf/ ?S i)
  • In general
  • Units of ?S J/K or J/FK
  • S is a STATE FUNCTION
  • ?S 0 favors spontaneous
  • ?S
  • S alone does not determine spontaneity

6
?So for reactions and phase changes
  • So ABSOLUTE ENTROPY of one mole of a substance
    at 1.00 atm pressure and T 298 K
  • Can be calculated and tabulated
  • So 0 for a perfect crystal at 0 K
  • ?So SSo(products) - SSo(reactants)
  • Hesss Law holds for ?So

7
Find ?So forCaCO3(s) 2H(aq) ? Ca2(aq)
CO2(g) H2O(l)
8
Predict Signs for ?So
  • ?So always positive if more gas is produced
  • ?So always positive for phase change to state
    with more freedom.
  • ?So usually positive if more moles of products in
    solution

9
Gibbs Free Energy G H - TS
  • G is a state function
  • Absolute Go of a substance cant be determined
  • ?Go difference in total free energy between
    reactants and products in thermodynamic standard
    states.
  • ?Go ?Ho - T ?So at constant T
  • Hesss Law works for ?Go
  • ?Gof can be tabulated (defined like ?Ho)

10
Find ?Go (at 25o) forCaCO3(s) 2H(aq) ?
Ca2(aq) CO2(g) H2O(l)
  • From ?Gof
  • Or from ?Ho ( -15.17 kJ) and ?So ( 141.7 J/K)

11
?Go -RTlnK K ? products/reactants
  • ?Go 1 ? spontaneous
  • ?Go 0 ? K
  • ?Go 0 ? K 1
  • Find K (at 25oC) for
  • CaCO3(s) 2H(aq) ? Ca2(aq) CO2(g) H2O(l)
  • ?Go -57.36 kJ/F

12
?G ?Go RTlnQat equilibrium, ?G 0, Q K
13
Temperature Dependence of ?Gofor reactions and
phase changes, reactants products at same T
  • ?Ho does not depend on temperature ?HoT ?Ho25
  • ?So does not depend on temperature ?SoT ?So25
  • ?GoT ? ?Go25 ?GoT ?Ho25 T?So25

14
Temperature Dependence of K
  • ?Go ?Ho - T?So -RTlnK
  • lnK -?Ho/RT ?So/R vant Hoff
  • Plot lnK vs 1/T, straight line
  • Slope - ?Ho/R
  • Intercept ?So/R
  • Given K at two different T
  • lnK1 -?Ho/RT1 ?So/R
  • lnK2 -?Ho/RT2 ?So/R
  • ln(K1/K2) (?Ho/R)(T1 T2)/T1T2

15
Find K (at 50oC) forCaCO3(s) 2H(aq) ?
Ca2(aq) CO2(g) H2O(l)?Go -57.36 kJ/F ?Ho
-15.17 kJ/F ?So 141.7J/FK
  • Method I, vant Hoff K25 1.1E10
  • Method II from ?Go25

16
Temperature Dependence of Phase Changeexample
H2O(l) ? H2O(g)
  • K P(H2O) in atm
  • Plot of lnK vs 1/T see back page

17
PHASE CHANGES - generalizations
  • To state with more freedom
  • ?Ho positive
  • ?So positive
  • ?Go positive at high T
  • ?Go negative at low T
  • ?Go 0 at To normal temperature of phase
    transition
  • For vaporization ln(P1/P2) (?Hovap/R)(T1
    T2)/T1T2

18
N2(g) 3H2(g) ? 2NH3(g)
  • Find ?Ho, ?So, ?Go, K at 25oC, and 250oC. Find T
    range for spontaneous. Why run at 250oC?
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