Title: Thermodynamics II
1Thermodynamics II
2Review Sample Problem
- 40.0 g NH4NO3 dissolved in 500. g water in
insulated cup, what is the final temperature of
the solution, given same specific heat as water,
and standard enthalpies of formation - ?Hof NH4NO3(s) -365.6 kJ/F NH4(aq) -132.5 kJ/F
- NO3-(aq) -205.05 kJ/F
- NH4NO3(s) ? NH4(aq) NO3-(aq)
3(No Transcript)
4ENTROPY S
- Measurement of randomness or disorder
- Greater disorder ? larger S
- Second Law of Thermodynamics
- Entropy of universe always increasing
- Nature favors increase in disorder
- For any process ?S SPRODUCTS SREACTANTS
- ?S 0 products favored by entropy
- ?S
- Energy must be expended to give a more ordered
state
5One liter of an ideal gas is allowed to expand to
two liters at constant temperature. What is the
?S of the process? -- of the reverse process?
- For system ?S Rln(Vf/ ?S i)
- In general
- Units of ?S J/K or J/FK
- S is a STATE FUNCTION
- ?S 0 favors spontaneous
- ?S
- S alone does not determine spontaneity
6?So for reactions and phase changes
- So ABSOLUTE ENTROPY of one mole of a substance
at 1.00 atm pressure and T 298 K - Can be calculated and tabulated
- So 0 for a perfect crystal at 0 K
- ?So SSo(products) - SSo(reactants)
- Hesss Law holds for ?So
7Find ?So forCaCO3(s) 2H(aq) ? Ca2(aq)
CO2(g) H2O(l)
8Predict Signs for ?So
- ?So always positive if more gas is produced
- ?So always positive for phase change to state
with more freedom. - ?So usually positive if more moles of products in
solution
9Gibbs Free Energy G H - TS
- G is a state function
- Absolute Go of a substance cant be determined
- ?Go difference in total free energy between
reactants and products in thermodynamic standard
states. - ?Go ?Ho - T ?So at constant T
- Hesss Law works for ?Go
- ?Gof can be tabulated (defined like ?Ho)
10Find ?Go (at 25o) forCaCO3(s) 2H(aq) ?
Ca2(aq) CO2(g) H2O(l)
- From ?Gof
- Or from ?Ho ( -15.17 kJ) and ?So ( 141.7 J/K)
11?Go -RTlnK K ? products/reactants
- ?Go 1 ? spontaneous
- ?Go 0 ? K
- ?Go 0 ? K 1
- Find K (at 25oC) for
- CaCO3(s) 2H(aq) ? Ca2(aq) CO2(g) H2O(l)
- ?Go -57.36 kJ/F
12?G ?Go RTlnQat equilibrium, ?G 0, Q K
13Temperature Dependence of ?Gofor reactions and
phase changes, reactants products at same T
- ?Ho does not depend on temperature ?HoT ?Ho25
- ?So does not depend on temperature ?SoT ?So25
- ?GoT ? ?Go25 ?GoT ?Ho25 T?So25
-
14Temperature Dependence of K
- ?Go ?Ho - T?So -RTlnK
- lnK -?Ho/RT ?So/R vant Hoff
- Plot lnK vs 1/T, straight line
- Slope - ?Ho/R
- Intercept ?So/R
- Given K at two different T
- lnK1 -?Ho/RT1 ?So/R
- lnK2 -?Ho/RT2 ?So/R
- ln(K1/K2) (?Ho/R)(T1 T2)/T1T2
15Find K (at 50oC) forCaCO3(s) 2H(aq) ?
Ca2(aq) CO2(g) H2O(l)?Go -57.36 kJ/F ?Ho
-15.17 kJ/F ?So 141.7J/FK
- Method I, vant Hoff K25 1.1E10
- Method II from ?Go25
16Temperature Dependence of Phase Changeexample
H2O(l) ? H2O(g)
- K P(H2O) in atm
- Plot of lnK vs 1/T see back page
17PHASE CHANGES - generalizations
- To state with more freedom
- ?Ho positive
- ?So positive
- ?Go positive at high T
- ?Go negative at low T
- ?Go 0 at To normal temperature of phase
transition - For vaporization ln(P1/P2) (?Hovap/R)(T1
T2)/T1T2
18N2(g) 3H2(g) ? 2NH3(g)
- Find ?Ho, ?So, ?Go, K at 25oC, and 250oC. Find T
range for spontaneous. Why run at 250oC?