Title: Reactions of Alkenes II
1Chapter 9
- Reactions of Alkenes (II)
2Hydrogenation of alkenes
- The addition of H2 to a double bond leads to the
saturated alkane - The most commonly used catalyst is Pd on carbon
(Pd/C)
3Addition of H2 occurs syn
- Both hydrogens (or deuteriums in this case) end
up at the same face of the molecule. - There is a 100 selectivity without exceptions
4The supposed mechanism
- Adsorption leads to more reactive bonds of both
the alkene and the hydrogen gas. - This is the reason of the syn mode of addition
5Rate of hydrogenation
- The more stable the double bond, the slower the
hydrogenation - In other words the more substituted, the slower
the hydrogenation of the double bond proceeds
6Steric effects
- The hydrogen usually reacts at the least hindered
site of the molecule
7Addition of halogens
- Reaction of alkenes with molecular bromine (Br2)
and chlorine (Cl2) give vicinal dihalides - Vicinal means on adjacent (1,2) positions
- The reaction gives selectively anti addition
8Two possible mechanisms
- The reaction proceeds exclusively via the
so-called bromonium ion this explans the
anti-product - Is the product optically active?
9Competition with other nucleophiles
- In the presence of different nucleophiles,
different products are formed, depending on their
nucleophilicity and concentration
10Question
- How many products do you expect for the following
reaction? Explain the answer.
11Several possibilities
- The ratio depends on the relative concentrations
of the nucleophiles
12100 anti addition of H2O
- Bromohydrin formation the mode of addition is
similar (anti) to the reaction with Br2 itself
13Question
- Predict the major product of the following
reaction and explain the answer.
14Problems
- Make problems 9.33 a-e, 9.35
15Addition of H2O revisited
- Oxymercuration of an alkene with Hg(OAc)2,
followed by reduction with NaBH4 leads to
overall addition of H2O
16The mechanism
- The mechanism proceeds via a three-membered ring
mercurinium ion - The stable three membered ring prevents
carbocation rearrangements
17The reduction
- NaBH4 is a hydride (H) donor the hydride
replaces the mercury atom
18Other oygen donors
- Most peroxides and peracids are potential
explosives!! - This is because they easily loose an oxygen atom
19Peracids react with double bonds
mCPBA
- Peracids react with alkenes to form epoxides
(oxiranes) - The most used peracid is m-chloroperbenzoic acid
(mCPBA)
20The stereochemistry is retained
- (E)-alkenes lead to trans-substituted epoxides
and (Z)-alkenes lead to cis-substituted epoxides - The double bond geometry is conserved in the
product
21Ring opening of epoxides
- Epoxides can be opened under basic and acidic
conditions
22Question
- Predict the outcome of the following reactions.
Explain the answer.
23Two different mechanisms
- Why is the oxygen anion (usually a poor leaving
group) in this case a good leaving group?
24Other nucleophiles
- As long as there are no cations involved, other
nucleophiles (such as the azide) will open the
epoxide from the least hindered side
25Addition of HX
- Opening with strong acids proceed via the
cationic intermediate
26Problems
- Make problems 9.31 a-f, 9.37 (de uitgangsstof
moet cis-2-buteen zijn!)
27Figure 9.40
Carbenes
- Carbenes can be generated in two ways
- Carbenes are species containing a carbon atom,
that bears a free electron pair (and only six
electrons)
28Carbenes and alkenes give cyclopropanes
- The carbene lone pair reacts with alkenes to
cyclopropanes - The geometry of the double bond is preserved in
the product the addition is syn
29The mode of addition
HOMO-LUMO interactions change through the
addition process
301,3-Dipolar compounds
- Examples of reagents that contain a 1,3-dipole a
positive and a negative charge in the same
molecule
31A well-known 1,3-dipole is O3
- Ozone reacts very fast (at 78 ÂșC) with alkenes
to form a five-membered ring (the primary
ozonide) - This is a syn addition the double bond geometry
is retained
32The fate of the primary ozonide
- The primary ozonide rearranges almost immediately
to the more stable ozonide - This proceeds via a reverse 1,3-dipolar addition
33Figure 9.65
The fate of the ozonide (I)
- Reductive workup leads to aldehydes and ketones
- Reductive workup Me2S, or PPh3, or Zn
34Figure 9.66
The fate of the ozonide (II)
Oxidative workup (rxn with H2O2) leads to ketones
and carboxylic acids.
35Problems
- Make problem 9.32 e,f, 9.41 and 9.42
36Other oxidation rxns of alkenes
- Alkenes react rapidly with the permanganate ion
(MnO4), but also with OsO4 (osmium tetroxide)
37Hydrolysis leads to diols
- Propose a reasonable mechanism for the hydrolysis
of the cyclic osmate ester
38Examples
- In all cases, the mode of addition is syn
39Problems
40Addition reactions to alkynes
- Alkynes behave very similar to alkenes in all
previous reactions
41Addition of HX to alkynes
- The trend in stability of vinyl cations is
similar to the normal cations - Vinal cations are significantly less stable than
saturated carbocations - What is the hybridization of a vinyl cation?
42A terminal alkyne
- The chloride adds to the more stable secondary
vinyl cation Markovnikov addition
43Other examples
- Explain the outcome of the reaction with
2-chloropropene
44Reaction with Cl2
- Draw a plausible intermediate for these reactions
45Oxymercuration gives ketones
- The oxymercuration follows the same pathway as
with alkenes in the presence of acid, the
product breaks down to give an enol, which
tautomerizes to the ketone
46The keto-enol tautomerization
- Note tautomers are not mesomeric structures,
they are different species, which are (in
principle) in equilibrium with each other
47Hydroboration of alkynes
- Note an (E)-substituted double bond is formed,
resulting from syn-addition
48Hydrolysis leads to aldehydes
- Hydrolysis leads to an enol, which again
tautomerizes to a carbonyl in this case the
anti-Markovnikov mode of addition leads to an
aldehyde.
49Hydrogenation of alkynes (I)
- In the presence of Pd/C and H2-gas, alkanes are
formed
50Formation of (Z)-alkenes
- Hydrogenation in the presence of the Lindlar
catalyst (a poisoned Pd-catalyst), the
hydrogenation stops in the alkene stage - An (Z)-alkene is formed resulting from
syn-addition of H2
51Formation of (E)-alkenes
- In contrast, reduction of the acetylene with Na
in NH3 leads to the (E)-alkene
52The mechanism
53The mechanism (II)
- Na in NH3 is a very strong reductive medium
- It can donate electrons to the triple bond in a
stepwise manner - The radical intermediate equilibrates to the most
stable isomer
54Problems