MC 302 Graph Theory Thursday, 102804 - PowerPoint PPT Presentation

1 / 10
About This Presentation
Title:

MC 302 Graph Theory Thursday, 102804

Description:

... more vertices is 1-connected IFF there is at least one ... Corollary: A graph G is 2-connected IFF every pair of vertices, u, v, are contained in a cycle. ... – PowerPoint PPT presentation

Number of Views:31
Avg rating:3.0/5.0
Slides: 11
Provided by: Mathematic53
Category:
Tags: graph | iff | theory | thursday

less

Transcript and Presenter's Notes

Title: MC 302 Graph Theory Thursday, 102804


1
MC 302 Graph TheoryThursday, 10/28/04
  • Today (Questions?)
  • Go over rest of Worksheet 7
  • k-connected and k-edge-connected graphs
  • Whitneys Theorem
  • Mengers Theorem
  • Application k-connected networks
  • Todays reading exercises
  • Reading still 4.3, Exercise 13
  • Also read Bondy Murty Section 3.3, Exercise
    3.3.1
  • Link from class web site, or
  • Direct link http//www.ecp6.jussieu.fr/pageperso/
    bondy/books/gtwa/gtwa.html
  • Reminders
  • HW 4 due Monday at 5 PM
  • Dont forget to VOTE on Tuesday!

2
k-Connected and k-edge-Connected Graphs
  • For a connected graph G, we now have that ?(G) is
    the minimum of vertices whose removal
    disconnects or trivializes G, and likewise ?(G)
    for edges.
  • We say a graph G is k-connected if ?(G) ? k.
  • We say a graph G is k-edge-connected if ?(G) ?
    k.
  • Since ?(G) ? ?(G), we have if ?(G) ? k, then also
    ?(G) ? k. So a k-connected graph is always
    k-edge-connected, but not necessarily vice versa.
  • We will focus primarily of vertex-connectivity.
  • Which are 1-connected, 2-connected, 3-connected
  • Trees, cycles, Q2, Q3, Kn, Kp,q

3
k-Connected Graphs
  • Alternative Definition A (simple) graph is
    k-connected if at least k vertices must be
    deleted to disconnect or trivialize it.
  • A 1-connected graph is the same as a connected
    graph.
  • A 2-connected graph is a connected graph with no
    cut vertices.
  • Note that a 2-connected graph is also
    1-connected.
  • In general if k gt m and G is k-connected, then
    its also m-connected (but not necessarily vice
    versa).
  • The highest k for which a graph G is k-connected
    is ?(G).
  • The higher k is, the more reliable a network
    based on this graph will be.

4
Generalizing the Unique Path Property Whitneys
Theorem
  • We know A graph with 2 or more vertices is
    1-connected IFF there is at least one path
    between each pair of distinct vertices.
  • Whitneys Theorem A graph with 3 or more
    vertices is 2-connected IFF there are at least
    two internally disjoint paths between each pair
    of vertices.

5
More on Whitneys Theorem
  • Corollary A graph G is 2-connected IFF every
    pair of vertices, u, v, are contained in a cycle.
  • Verify above Corollary and Theorem for graphs on
    previous slides.
  • Generalized Whitneys Theorem A simple graph is
    k-connected IFF there are at least k internally
    vertex-disjoint paths between each pair of
    vertices.

6
Mengers Theorem
  • A result related to Whitneys Theorem
  • Mengers Theorem. Let u and v be distinct
    nonadjacent vertices in G. Then the maximum
    number of internally disjoint paths from u to v
    equals the minimum number of vertices in a set
    that separates u from v.
  • This is also related to the Max-Flow Min-Cut
    Theorem in Chap. 10 which is about maximimizing
    flow in a directed network with a source and
    sink

7
Application K-connected networks (BM Section
3.3)
  • Reliable networks need to be connected, but
    k-connected for k gt 1 is even better.
  • For every n, there is a graph on n vertices that
    is 1-connected what is it?
  • For every n, is there a graph on n vertices that
    is 2-connected?
  • What about k-connected?

8
k-Connected graphs on n vertices.
  • Since ?(G) ? ?(G), it follows that a k-connected
    graph on n vertices has at least edges.
  • Can we always find a graph G with n vertices that
    is k-connected?
  • YES result of Harary, 1962. There is a such a
    graph, named Hk,n

9
Constructing Hk,n for k even
  • Start with a cycle on n vertices
  • Add extra edges to make it k-connected.
  • Case 1. k even, k 2r. (See BM for other
    cases).
  • Start with n vertices, 0, 1 , , n-1.
  • For each vertex i, add edges to r preceding and r
    following vertices.
  • Then

10
Theorem for k even
  • Theorem. For k 2r even, Hk,n is k-connected.
  • Proof
  • Let V be any set of vertices with V lt 2r, and
    let i and j be distinct vertices in G V .
  • Look at the two sections S1 i, i1, , j, and
    S2 j, j1, , i.
  • At least one of these sets, say S1, contains
    fewer than r vertices of V
  • This implies there is a path in S1 from i to j
  • Therefore V does not disconnect Hk,n.
Write a Comment
User Comments (0)
About PowerShow.com