Title: Chemistry 181
1Chemistry 18-1
- The Nature of Chemical Equilibrium
2Equilibrium Overview
- At the beginning of a reaction, the
concentrations of the reactants are at a maximum,
and the concentrations of the products are at
zero - As the reaction progresses, the concs of the
reactants increase, decrease, while the concs
of the products increase, decrease - DECREASE, INCREASE
- If the reaction is reversible, EQUILIBRIUM is
established when the rates of the forward and
reverse reactions become equal
3Equilibrium Constant
- Once equilibrium is established, the
concentrations of the reactants and products will
remain constant - Therefore, the RATIO of the concentrations should
also remain constant! - Ex) nA mB ? xC yD
- The equilibrium expression for this rxn is Keq
Cx Dy An Bm
4Comparing Keq and Rate Laws
- Keq involves K as the whole expression
- (K something)
- Rate Laws involve k as part of the expression
- (R k something)
- Keq deals with BOTH products AND reactants
- Rate Laws deal with __________ only!
- REACTANTS
5Equilibrium Constant, cont.
- The numerical value of Keq for a particular
reaction depends on temperature and must be
experimentally determined - If Keq is approx. equal to 1, then at equilibrium
there must be approx. equal concentrations of
reactants and products present
6Equilibrium Constant, cont.
- If Keq is very small (much less than 1), then the
concentration of the products at equilibrium must
be much greater, smaller than the concentration
of reactants - Therefore, the forward, reverse reaction is
favored - SMALLER, REVERSE
- Similarly, if Keq is very large (much greater
than 1), then the concentration of the products
at equilibrium must be much greater than the
concentration of reactants - Therefore, the forward reaction is favored
7Practice ?p559 6
- Write the equilibrium expression for the
following reaction4HCl(g) O2(g) ? 2Cl2(g)
2H2O(g) - Answer Keq Cl22 H2O2 HCl4 O2
8More Practice ?p559 8
- Calculate the equilibrium constant (Keq) for the
reaction H2(g) I2(g) ? 2HI(g)if, at 425oC,
H2 1.83x10-3 M, I2 3.13x10-3 M, and HI
1.77x10-2 M. - Answer Keq HI2 54.7 H2 I2
9Chemistry 18-2
10LeChateliers Principle (Review)
- If a system at equilibrium is subjected to a
stress, the system will shift to reduce the
stress. - Effect of pressure changes?
- Pressure is only a concern for reactions
involving gases! - Effect of temperature changes?
- The direction of shift depends on whether the
reaction is endothermic or exothermic!
11LeChateliers Principle Review Problem ?
- 556 kJ CaCO3(s)?CaO(s) CO2(g)
- Which way will the system shift to reduce the
following disturbances? - Increase temp
- Decrease pressure
- Add CaO
- Remove CO2
12LeChateliers Principle, cont.
- Effects of concentration changes
- Changing the concentration does not change the
equilibrium constant, Keq! (Why not??) - Because the system will always shift to
reestablish equilibrium! - Pure solids and pure liquids are always defined
to have a concentration of 1, so they do not
affect the equilibrium constant! - This is only a concern for problems involving
solubility (Section 18-4)
13Rxns that Go To Completion
- Not all chemical reactions result in
equilibrium!!! - Under what conditions will the forward reaction
go to completion? - (This means that reactants are fully converted to
products, and the reverse reaction does not
occur!)
14Rxns that Go To Completion, cont.
- Conditions favoring a complete reaction
- 1) Formation of a gas
- A gas will escape from the reaction. According
to LeChateliers Principle, removal of a product
(the gas) will cause the reaction to shift to the
_______, and so - RIGHT, and so THE REACTION RUNS AWAY!
15Rxns that Go To Completion, cont.
- 2) Formation of a precipitate
- A precipitate is soluble, insoluble.
Therefore - INSOLUBLE. It cannot break apart to reform the
reactants and the reverse reaction cannot occur!
- 3) Formation of a slightly ionized product
- If the product only ionizes minimally (like
liquid water), then - Very little of the reactants reform, and the
reverse reaction essentially does not occur!
16Common Ion Effect
- Suppose we have a saturated solution of sodium
chloride in equilibrium - NaCl(s) ? Na1(aq) Cl-1(aq)
- Now suppose we add some hydrochloric acid to the
salt system - HCl(g) H2O(l) ? H3O 1(aq) Cl-1(aq)
- (Recall, how do we know the HCl will fully
dissociate in water?) - HCl is a STRONG ACID!
17Common Ion Effect, cont.
- According to LeChateliers Principle, how will
the NaCl equilibrium adjust to compensate for the
addition of HCl? NaCl(s) ? Na1(aq) Cl-1(aq) - Answer Because of the added Cl-1 ion, the
system will shift to the _______, causing more
NaCl to _______! - LEFT, PRECIPITATE
- This phenomenon is known as the common ion effect
(where a common ion causes precipitation to
occur).
18An Application of the Common Ion Effect (18-3)
- Buffers solutions that can resist changes in
pH. - Formed from a weak acid and its salt (or, from a
weak base and its salt). - Ex) acetic acid and sodium acetate
- HC2H3O2 H2O ? H3O1 C2H3O2-1
- NaC2H3O2 ? Na1 C2H3O2-1
- This buffer system only works because both the
acid (HC2H3O2) and its conjugate base (which
is?) are present in large amounts.
19Buffers (Common Ion Effect), cont.
- Recall, conjugates come from whose definition of
acids and bases?? - BRONSTED-LOWRY! ACID p donor, BASE p
acceptor - So, what is the conjugate base of
HC2H3O2? HC2H3O2 H2O ? H3O1 C2H3O2-1 - CONJUGATE BASE C2H3O2-1
- Why is it necessary to include the salt
(NaC2H3O2) in the buffer system? - Because a weak acid only dissociates slightly, so
the concentration of the conjugate base would be
very small without the salt (which dissociates
fully).
20Buffers (Common Ion Effect), cont.
- What would happen if an ACID (like HCl) was added
to this buffer system? HC2H3O2 H2O ? H3O1
C2H3O2-1 - Equilibrium will shift to the right, left.
- LEFT
- This converts the added acid to a much weaker
acid (acetic). - The pH of the system changes only a little, and
we say that the pH has been buffered.
21Buffers (Common Ion Effect), cont.
- What would happen if a BASE (like KOH) was added
to this buffer system? HC2H3O2 H2O ? H3O1
C2H3O2-1 - HINT What would the added K1 ion do to the
system? What about the added OH-1 ion? - K1 reacts with C2H3O2-1, OH-1 reacts with H3O1
- This is why we need a good quantity of conjugate
base present! - So, equilibrium will shift to the right, left.
- RIGHT
- This converts the added base to a much weaker
base (the conjugate). - Again, the pH of the system has been buffered!
22What good are buffers?
- The blood in your body in naturally buffered to
maintain a neutral pH (between 7.3 and 7.5) - Aspirin is often buffered to prevent sharp
changes to the pH of your stomach acid (between
1.0 and 3.0)