Chapter 6: Gene Expression: Translation - PowerPoint PPT Presentation

1 / 37
About This Presentation
Title:

Chapter 6: Gene Expression: Translation

Description:

What are the building blocks of proteins, and what type of covalent bond holds ... What does it mean that the code is 'comma free' and 'nonoverlapping' ... – PowerPoint PPT presentation

Number of Views:40
Avg rating:3.0/5.0
Slides: 38
Provided by: laura437
Category:

less

Transcript and Presenter's Notes

Title: Chapter 6: Gene Expression: Translation


1
Chapter 6 Gene Expression Translation
  • Linnea Fletcher Ph.D.
  • BIOL 2316

2
Ribosomal subunits are made of protein and rRNA
Three-dimensional structure of the 30S ribosomal
subunit.
3
  • What are the building blocks of proteins, and
    what type of covalent bond holds them together in
    the polypeptide chain?
  • How many different types of amino acids are used
    to build proteins?
  • What structural elements do all amino acids
    share, and in what way do they differ?
  • About how long are polypeptide chains?

4
You should be able to draw this picture!
5
There are four groups of amino acids based
on chemical and physical Characteristics What
are the characteristics of an acidic amino acid?
Nonpolar and neutral?
6
Covalent bond holding amino acids together
7
  • Describe the 4 levels of protein structure and
    the forces holding these structures together.
  • What type of amino acids become buried to the
    interior of proteins, and why?
  • Do all proteins have quaternary structure?
  • What determines what secondary, tertiary, and
    quaternary structures that proteins assume inside
    the cell?

8
What are the bonds that form the primary,
secondary, teritary, And quatenary structures in
proteins?
For example, for secondary structure, it is
primarily the hydrogen bonding between peptide
bonds that form the repeating structure you
see in beta-pleated sheets and alpha-helices
9
  • Explain why Francis Crick predicted that the
    genetic code was a triplet message, and how he
    and others found experimental support for this
    idea.
  • Describe the in vitro translation experiments of
    Nirenberg Khorana that deciphered many of the
    genetic codons.
  • What advantages did the ribosome-binding assays
    of Nirenberg Leder have in deciphering the
    genetic code?

10
Review Crick and his colleagues experiments with
T4 phage
Figure 6.5 Reversion of a deletion frameshift
mutation by a nearby addition mutation. (a)
Hypothetical segment of normal DNA, mRNA
transcript, and polypeptide in the wild type. (b)
Effect of a deletion mutation on the amino-acid
sequence of a polypeptide. The reading frame is
disrupted. (c) Reversion
11
Figure 6.6 Hypothetical example showing how three
nearby mutations restore the reading frame,
giving normal or near-normal function. The
mutations are shown here at the level of the
mRNA.
12
  • Characteristics of the CODE
  • To what extent is the genetic code universal?
  • What does it mean that the code is comma free
    and nonoverlapping?
  • How many codons are there in the genetic code
    that code for amino acids?
  • What does it mean that the code is degenerate?
  • What are the start and stop signals?
  • Explain the Wobble Hypothesis

13
Using this table, you should be able to translate
mRNAs
Figure 6.7 The genetic code. Of the 64 codons, 61
specify one of the 20 amino acids. The other 3
codons are chain-terminating codons and do not
specify any amino acid. AUG, one of the 61 codons
that specify an amino acid, is used in the
initiation of protein synthesis.
14
Amino acids that occur more frequently in
proteins have the higher number of codons (e.g.
Thr occurs more frequently than His)
Figure 6.8 Example of base-pairing wobble. Two
different leucine codons (CUC, CUU) can be read
by the same leucine tRNA molecule, contrary to
regular base-pairing rules.
15
(No Transcript)
16
Describe how aminoacyl-tRNA synthetases produce
charged tRNAs
Figure 6.9 Charging of a tRNA molecule by
aminoacyl-tRNA synthetase to produce an
aminoacyl-tRNA (charged tRNA).
PowerPoint Layered Art
17
Figure 6.9 Charging of a tRNA molecule by
aminoacyl-tRNA synthetase to produce an
aminoacyl-tRNA (charged tRNA).
PowerPoint Layered Art
18
PowerPoint Layered Art
19
(No Transcript)
20
  • Describe the actions of the molecules of
    translation in prokaryotes during these stages of
    translation initiation, elongation,
    termination.
  • What types of molecules make up the structure of
    a ribosome?
  • What signals initiation and termination?
  • What are the steps of ribosome assembly during
    initiation?
  • Compare the initiation step for prokaryotes and
    eukaryotes in what ways are they the same and
    in what ways are they different? For example how
    does the 5 CAP and the poly A tail play a role
    in initiation in the eukaryote?
  • (I suggest you make a table of the 3 stages that
    indicates the similarities and differences
    between prokaryotes and eukaryotes)

21
Figure 6.11 Initiation of protein synthesis in
prokaryotes. A 30S ribosomal subunit, complexed
with initiation factors and GTP, binds to mRNA
and fMet-tRNA to form a 30S initiation complex.
Next, the 50S ribosomal subunit binds, forming a
70S initiation complex. During this event, the
initiation factors are released and GTP hydrolyzed
22
  • What are the 3 steps of elongation during
    translation in prokaryotes?
  • Know detail, such as
  • What are the three sites of the large subunit of
    the ribosome positioned at the mRNA? (A, P and
    Eknow this!)
  • In what direction do the tRNA and mRNA travel
    along these sites during elongation?
  • What happens during the translocation step?
  • What becomes of the freed tRNA once peptidyl
    transferase has removed its amino acid?
  • What creates a polysome in a prokaryote?

23
This is found only in a prokaryote!
Figure 6.12 Sequences involved in the binding of
ribosomes to the mRNA in the initiation of
protein synthesis in prokaryotes. (a) Nucleotide
sequence at the end of E. coli 16S rRNA. (b)
Example of how the end of 16S rRNA can base pair
with the nucleotide sequence upstream from the
AUG initiation codon
24
Again, only in a prokaryote
Figure 6.13 Elongation stage of translation in
prokaryotes.
PowerPoint Layered Art
25
Prokaryotes
PowerPoint Layered Art
26
PowerPoint Layered Art
27
PowerPoint Layered Art
28
PowerPoint Layered Art
29
Enzyme is composed of RNA
30
In a prokaryote, translation can start BEFORE
transcription has finished! This cannot occur
with eukaryotic mRNAs that are made in the
nucleus and then transport out to be translated.
31
Figure 6.16 Termination of translation. The
ribosome recognizes a chain termination codon
(UAG) with the aid of release factors. A release
factor reads the stop codon, initiating a series
of specific termination events leading to the
release of the completed polypeptide.
PowerPoint Layered Art
32
PowerPoint Layered Art
33
PowerPoint Layered Art
34
  • What signals the termination of translation?
  • Describe the structure and action of release
    factors during termination.
  • BOTTOM LINE BE ABLE to DIAGRAM TRANSLATION and
    KNOW the difference between prokaryotes and
    eukaryotes!

35
  • In a eukaryote, what tags a protein for secretion
    or localization to an organelle?

36
(No Transcript)
37
Problem 6.21 A segment of a polypeptide chain is
Arg-Gly-Ser-Phe-Val-Asp-Arg it is encoded by the
following segment of DNA. Which strand is the
template strand? Label each strand with its
correct polarity (5 and 3)?
Problem 6.29 In the recessive condition in humans
known as sickle-cell anemia, the beta globin
polypeptide of Hb is found to be abnormal.
Explain how the difference in the DNA gives rise
to the difference in the mRNA and the resulting
protein. Compared the abnormal protein to the
normal Hb and explain why this difference causes
the sicklingeffect.
Write a Comment
User Comments (0)
About PowerShow.com