1'5CIRCULAR MOTION - PowerPoint PPT Presentation

1 / 41
About This Presentation
Title:

1'5CIRCULAR MOTION

Description:

1.5.4 Examples of Horizontal Circular Motion. 1.5.5 Examples of Vertical ... Skidding ... To prevent skidding, it is preferable to have the centripetal ... – PowerPoint PPT presentation

Number of Views:142
Avg rating:3.0/5.0
Slides: 42
Provided by: ssgc2
Category:

less

Transcript and Presenter's Notes

Title: 1'5CIRCULAR MOTION


1
1.5 CIRCULAR MOTION
1.5.1 Describing Circular Motion
1.5.2 Centripetal Acceleration
1.5.3 Centripetal Force
1.5.4 Examples of Horizontal Circular Motion
1.5.5 Examples of Vertical Circular Motion
2
1.5.1 Describing Circular Motion
  • Is the ball undergoing circular motion?
  • Is there a net force acting on the ball? If yes,
    what is the direction of it?

3
  • Angular Displacement
  • The position of a particle in a circular track at
    any time t is specified by its angular
    displacement ?, in , is defined by the equation
  • ? Eq.(1)
  • where is the radius and is the arc
    length.
  • Change the subject of Eq.(1) to s, we get
  • s Eq.(2)

4
  • Angular Velocity
  • The linear speed v of a body moving in a circle
    at an instant refers to its speed along the
    at that instant, i.e.,
  • v Eq.(3)
  • The angular velocity ? of a body moving in a
    circle at an instant is defined as the of its
    anglar displacement at that instant, i.e.,
  • ? Eq.(4)

5
  • Differentiating both sides of Eq.(2) with respect
    to t, we get
  • Then by Eq.(3) and (4), we have
  • Eq.(5)
  • Angular Velocity, Period and Frequency
  • The time T for a circulating body to swept
    through an angle 2? (one revolution) at an
    angular speed of ?, is
  • T Eq.(6)
  • If the number of revolutions made in one second
    is f, the angle, in radian, swept in one second,
    ?, is given by
  • ? Eq.(7)

6
1.5.2 Centripetal Acceleration
  • Magnitude of centripetal acceleration
  • Consider a body describing circular motion moves
    from A to B in a very short time interval ?t as
    shown. Its speed v remains almost the same while
    the direction changes. The change in velocity
    can be found by a vector .
  • a Eq.(8)

7
  • Direction of centripetal acceleration
  • The direction of centripetal acceleration is
    of the circle as it can be seen that if ?t
    is so small, A and B nearly , vector ?v is then
    to vA (or vB), i.e., along . That
    is why this acceleration is given the name
    centripetal acceleration.
  • Conceptual questions
  • Does a body moving uniformly in a circle have
    constant acceleration?
  • Is the centripetal acceleration of a body moving
    non-uniformly in a circle still given by the
    expression a ?2r?

8
Examination questions
  • 2002-IIA-8
  • A particle P is moving in a horizontal circle in
    a clockwise direction as shown (top view). The
    following diagrams show the direction of the
    acceleration a of the particle. Which of them
    is/are possible?
  • (1) (2) (3)
  • A. (1) only
  • B. (3) only
  • C. (1) and (2) only
  • D. (2) and (3) only

9
1.5.3 Centripetal Force
  • Magnitude and direction of centripetal force
  • According to Newtons first law, a body
    undergoing circular motion must be acted on by
    to produce the centripetal
    acceleration. This force should be directed
    and is called the centripetal force, which
    causes the body to deviate from the motion
    which it would naturally follow in the absence of
    the force. The magnitude of centripetal force
    according to Newtons second is
  • F Eq.(9)
  • Example
  • A ball attached to a string being swung round
    in a horizontal circle is kept in its track by
    the . It the ball is swung round faster, a
    force is needed, and if it exceeds the maximum
    tension the string can provide, the ball
    continues to travel along the of the
    circle at that point.

10
  • Agents providing centripetal force
  • Centripetal force is not a new type of
    interaction instead, it is refers to the amount
    of force to substain a circular motion at a
    certain speed.
  • The sources providing the centripetal force are
    different in different situations, two examples
    are given below.
  • A car riding round a bend
  • A bead turning round a smooth track

11
  • Experimental verification of centripetal force
  • The following set up is used to show that F
    m?2r.
  • The of the screw nuts are measured. It is
    the in the string.
  • The length l is measured, where l .
  • The time t for 50 revolutions of the rubber bung
    is measured, so that the period T , and
    the angular speed ? .

12
  • As the rubber bung is whirled round a horizontal
    circle, the string is never horizontal, since the
    always tends to pull the rubber bung .
    An component of the tension is therefore needed
    to balance the , so that
  • The centripetal force acting on the rubber bung
    is provided by the component of the tension in
    the string, therefore, if F m?2r, we have
  • However, since r , we have
  • Eq.(10)

Angular speed and radius
13
Examination questions
  • 2000-IIA-11
  • A student performing a centripetal force
    experiment whirls a rubber bung attached to one
    end of a string which passes through a glass tube
    with smooth openings, and has a weight W hanging
    at its other end. The weight of the rubber bung
    is much smaller than W. The rubber bung is set
    into a horizontal circular motion with angular
    speed ? while the length of the string beyond the
    upper opening of the glass tube is L and this
    portion of the string makes an angle ? with the
    vertical as shown. Which of the following
    statements is/are correct?
  • (1) If L is kept constant, ? will decrease
    with ?.
  • (2) If ? is kept constant, L will increase with
    ?.
  • (3) When W increases, ? will increase.
  • A.  (1) only B.  (2) only C. (3) only
  • D.  (1) and (2) only E. (2) and (3) only

14
  • Centripetal versus centrifugal force
  • Consider a boy B revolving round another boy A at
    a distance r in a circlar path centered at A with
    angular speed ? as shown. According to A, the
    horizontal force acting on B is the
    force acting towards A.
  • According to B, however, A seems to be revolving
    round himself with radius r centered at at
    angular speed. However, is there a
    centripetal force acting on A?
  • In fact, B is frame, and so if he insists
    to apply Newtons laws of motion, a force
    equals the product of the mass of and the
    of the of B. Therefore, there is an
    apparent centripetal force acting on A in Bs
    frame, which is called the force, as it is
    directed of the circle describing by B.

15
  • Simulating gravity in space
  • It has been suggested to build a huge disc in
    space that is revolving about a axis at a
    angular speed ?, such that passengers inside the
    disc are all subjected to the forces supplied
    by the of the floor, which give them the
    of weight, just like those on the
    earth.
  • In doing so, the acceleration should equal the
    , which gives the required angular
    speed,
  • Eq.(11)

16
1.5.4 Examples of Horizontal Circular Motion
  • Conical Pendulum
  • A conical pendulum consists of a bob of mass m
    supported by a string circulating round a
    circle of radius r with a speed v.
  • Horizontal circular motion
  • Vertical equilibrium
  • The tilting angle ? is governed by

17
Examination questions
  • 1990-IIA-6
  • A spring of unstretched length 10.0 cm, has one
    end fixed to the ceiling. A mass is suspended at
    the other end, and the extension so produced is
    3.0 cm. When the mass is set to rotate in a
    horizontal circular path the length of the spring
    is 16.0 cm. The angle between the spring and the
    vertical is
  • A. 15o
  • B. 30o
  • C. 45o
  • D. 60o
  • E. 75o

18
  • 2005-IIA-5
  •   A horizontal elastic cord of natural length a
    is fixed at one end and a small mass m is
    attached to the other end. The mass rotates
    uniformly in a horizontal circle on a smooth
    horizontal surface. When the mass takes time T
    to complete one revolution, the length of the
    cord is 1.5 a. The angular speed of the mass is
    changed such that the length of the cord becomes
    2a. What is the new time for one revolution?
    (Assume that the elastic cord obeys Hookes law.)
  • A. B. C. D.

19
  • Riding round a bend
  • When riding round a bend at speed v, it is the
    at the ground that provides the
    centripetal force.
  • Horizontal circular motion
  • Vertical equilibrium
  • Rotational equilibrium about C.M.
  • The tilting angle ? is therefore governed by
  • Eq.(12)

20
  • Toppling accidents
  • During riding round a bend at a definite speed,
    if the rider makes an inclined angle
  • - smaller than that given by Eq.(12), the rider
    would topple .
  • - greater than that given by Eq.(12), the rider
    would topple .
  • Skidding (slipping) accidents
  • When the riding speed is too high, the
    centripetal force required may the maximum
    friction that can be supplied, i.e. the
    . If
  • the rider will skip for the static
    friction no longer can hold the rider in its
    track.

21
Examination questions
  • 1985-IIA-3
  • A motorcyclist going round a corner on a level
    road leans over at an angle to the horizontal.
    The reason for this is
  • A. to allow his weight to exert a torque about
    the contact point on the ground.
  • B. to increase the frictional force between the
    motorcycle and the road.
  • C. to lower his centre of mass.
  • D. to provide the centripetal force to reduce
    the radius of curvature of his path.
  • E. to reduce the radius of curvature of his
    path.

22
  • Driving round a bend
  • It is the friction between the tyres
    and the ground which provides the centripetal
    force for a car to turn round a bend.
  • Horizontal circular motion
  • Vertical equilibrium
  • Rotational equilibrium about C.M.
  • Eliminating f1 and f2, we get
  • Solving for N1 and N2, we have
  • Eq.(13)

23
  • Toppling accidents
  • According to Eq.(13), N1 becomes negative when
  • in which case the car would topple about the
    wheel.
  • Skidding (slipping) accidents
  • When the driving speed is too high, the
    centripetal force required may the maximum
    friction that can be supplied, i.e. the
    . If
  • the car will skip for the static friction
    no longer can hold the car in its track.

24
  • Rounding a banked bend
  • To prevent skidding, it is preferable to have the
    centripetal force not rely only on the friction
    of the road. This can be achived by
    the road, so as
  • to have the component of the to act
    as the centripetal force.
  • Horizontal circular motion
  • Vertical equilibrium
  • Eliminating the normal reaction N, we get
  • Eq.(14)
  • Note that for a given radius of bend, the angle
    of banking is only correct for speed.

25
Examination questions
  • 1997-IIA-4
  •  
  • The figure shows a car moving round a corner
    with a radius of 8 m on a banked road of
    inclination 20o. At what speed would there be no
    friction acting on the car along OA?
  •  
  • A. 5.0 ms-1
  • B. 5.2 ms-1
  • C. 5.4 ms-1
  • D. 5.6 ms-1
  • E. 5.8 ms-1

26
  • 2000-IIA-8
  •  
  • A car of mass m is moving with speed v on a
    banked road along a circular path of horizontal
    radius r. The angle of inclination of the road
    is ?. If the centripetal force arises entirely
    from a component of the normal reaction N from
    the road, which of the following relations is
    correct?  
  • A. Ncos? mg
  • B. N mgcos?
  • C. v2 gr/sin?
  • D. v2 gr/tan?
  • E. N/sin? mv2/r

27
  • Aircraft turning in flight
  • An aircraft can fly in the sky because of the
    force at angles to the surface of its
    wing. In order to turn,
  • the aircraft has to so that the
    componet of the lift supplies the centripetal
    force.
  • Horizontal circular motion
  • Vertical equilibrium
  • Eliminating L, we get
  • Eq.(15)
  • Note that before turning, L , so immediately
    after banking, the component of L is
    smaller than mg, and the height will be lost,
    unless L is , say, by increasing the during
    turning.

28
Examination questions
  • 1995-IIA-6
  • An aircraft flies along a horizontal circle of
    radius 10 km with a constant speed of 155 ms-1.
    Calculate the angle between its wings and the
    horizontal.
  • A. 11.5o
  • B. 12.0o
  • C. 12.5o
  • D. 13.0o
  • E. 13.5o

29
  • The rotor
  • A rotor found in an amusement park is a rapidly
    spinning upright drum inside which players can
    remain pinned against the wall without falling.

r
  • As the rotor spins, the centripetal force on the
    player is supplied by the by the wall N,
    while the weight is balanced by the
    by the wall.
  • Horizontal circular motion
  • Vertical equilibrium
  • If the coefficient of friction between the wall
    and the players cloth is ?, we must have f (
    mg) ? , i.e., the range of rotating speed of
    the drum is found by

30
  • Centrifuges
  • A centrifuge is a device that separate mattes of
    different in liquids.
  • Test tubes containing the mixtures in the
    centrifuges are rotated at speed in a
  • circle so that matters finally
    moves towards the centre.
  • If the horizontal tube of liquid is rotated, the
    force exerted by the must be greater than
    that by the so that a necessary
    centripetal force is provided. A is
    therefore built up along the liquid.
  • For any part of the liquid the force due to the
    difference supplies exactly the centripetal
    force needed, but if the part is replaced by
    matter of smaller density, the force is too
    so the matter moves .

31
1.5.5 Examples of Vertical Circular Motion
  • Whirling freely with a rod
  • Consider a rod of length r attached to the bob of
    mass m being whirled freely about a smooth joint.
    Assume the speed of the bob at the lowest
    position be vo.
  • Vertical circular motion
  • Conservation of mechanical energy
  • If T gt 0, the rod is in while if T lt 0, the
    rod is in .
  • The angle ?max at which the bob reverses
    direction can be found by putting 0 in the
    energy equation. However, if the speed of the
    bob is high enough, the bob will not reverse its
    direction at all.

32
Examination questions
  • 1996-IIA-7
  • A small object P of mass 0.3 kg is attached to
    one end of a light, rigid rod of length 0.5 m,
    which is free to rotate about the other end O as
    shown. The object is swung to rotate in a
    vertical circle so that it attains a speed of 2 m
    s-1 at its topmost position. What is the force
    exerted on one end of the rod at this instant?
  • A. a compressive force of 0.6 N
  • B. a tensional force of 0.6 N
  • C. a tensional force of 2.4 N
  • D. a tensional force of 5.4 N
  • E. a compressive force of 5.4 N

33
  • Whirling freely with a string
  • Consider a rod of length r attached to the bob of
    mass m being whirled freely about a smooth joint.
    Assume the speed of the bob at the lowest
    position be vo.
  • Unlike a rigid rod, a string would when
    the tension equals zero.
  • Minimum speed at the highest point
  • At the minimum speed the centripetal force is
    entirely supplied by the , i.e.,
  • Tension at the lowest point

34
Examination questions
  • 1993-IIA-8
  • The figure shows a small heavy bob P attached to
    a fixed point A on the ceiling by a light
    inextensible string. The bob is pulled aside
    with the string taut and then released from rest.
    Which of the following descriptions is/are true?
  • (1) When moving towards the lowest point of its
    path, the angular speed of the bob is
    increasing.
  • (2) The centripetal acceleration of the bob is
    constant.
  • (3) When the bob is at the lowest point, the
    tension in the string equals the centripetal
    force.
  • A. (1) only B. (3) only C. (1)
    and (2) only
  • D. (2) and (3) only E. (1), (2) and (3)

35
  • Looping the loop
  • The loop-the-loop motion on a frictionless
    railway is similar to whirling an object freely
    in a vertical plane by a string, with the tension
    in the string is now being replaced by the
  • by the railway.
  • The trajectories of the bead for different values
    of vo are shown below

36
Examination questions
  • 1991-IIA-6
  • The diagram shows a part of the route of a
    roller-coaster in an amusement park. The cart
    descends from H, completes a circular loop A and
    moves to B. If the cart of passengers is to
    complete the central circular track safely, what
    is the minimum velocity of the cart at the bottom
    of the circular track A? (Assume that there is
    no friction between the cart and the track.)
  • A. 10m s-1 B. 20 ms-1 C. 22.4 ms-1
  • D. 24.5 ms-1 E. 30 ms-1

37
  • 1994-IIA-7
  • A student whirls a small bucket of water in a
    vertical circle of radius 0.6 m. For no
    spilling, what is the minimum speed of the bucket
    at the highest point of its path.
  •  
  • A. 2.45 ms-1
  • B. 3.46 ms-1
  • C. 4.08 ms-1
  • D. 4.90 ms-1
  • E. 5.77 ms-1

38
  • 1995-IIA-5
  • A small object of mass 0.05 kg is released form
    rest at the rim of a heavy, smooth semi-spherical
    bowl of radius 10 cm. Find the force acting on
    the object by the bowl when it passes the bottom
    of the bowl.
  • A. 0.5 N B. 1.0 N C. 1.5 N
    D. 2.0 N E. 2.5 N
  • ball bearing at the highest point A of the loop,
    which of the following graphs correctly shows the
    variation of R with h?
  • A. B. C. D.
    E.
  • 1997-IIA-5
  • A ball bearing is released form rest at a height
    h on a smooth track and completes the circular
    loop of the track. If R is the reaction acting
    on the

39
  • 1999-IIA-8
  • A small ball-bearing is projected with velocity
    v from the lowest position P of vertical circular
    track which is not smooth. The ball-bearing
    starts to leave the track at Q. Which of the
    following diagrams best represents all the forces
    on the ball-bearing at Q?
  • A. B. C.
  • D. E.

40
  • 2003-IIA-7
  • A simple pendulum is pulled horizontal and hen
    released from rest with the string taut. Which
    of the following statements about the tension in
    the string is not correct when the pendulum
    reaches its vertical position?
  • A. The tension equals the weight of the pendulum
    bob in magnitude.
  • B. The tension attains its greatest value.
  • C. The tension does not depend on the length of
    the pendulum.
  • D. The tension depends on the mass of the
    pendulum bob.

41
  • 2005-IIA-2
  • The figure shows a pendulum bob swinging between
    positions x and y.
  • Which of the arrows P, Q, R, S represents the
    direction of the resultant force acting on the
    bob when the bob is at position z? (Neglect air
    resistance.)
  • A. P B. Q C. R D. S
Write a Comment
User Comments (0)
About PowerShow.com