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ELE1110A Tutorial Notes

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Keep in mind that the capacitor voltage is always continuous so that V(0 )=V(0 ... The energy initially stored in the capacitor and inductor is released to the ... – PowerPoint PPT presentation

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Title: ELE1110A Tutorial Notes


1
ELE1110A Tutorial Notes
  • Second-Order Circuits
  • by Tian Feng

2
1.Typical Examples of Second-order Circuits
  • Typical examples of second-order circuits
    includes
  • (a) Series RLC circuit, (b) Parallel RLC circuit,
    (c) RL circuit, (d) RC circuit

3
2. How to get v(0), i(0), dv(0)/dt, di(0)/dt,
v(8), i(8)
  • Main points that should be take care of
  • We must carefully handle the polarity of voltage
    v (t) across the capacitor and the direction of
    the current i (t) through the inductor.
  • Keep in mind that v and i are defined strictly
    according to the passive sign convention. One
    should carefully observe how these are defined
    and apply them accordingly.
  • Keep in mind that the capacitor voltage is always
    continuous so that V(0)V(0-) where t 0-
    denotes the time just before the switching event,
    and t 0 is the time after the switching event
    and the inductor current is always continuous so
    that i(0)i(0-)

4
Classwork 1
  • Determine (a) i(0) and v(0)(b) di(0)/dt
    and dv(0)/dt (c) i(8) and v(8).

5
3. The Source-free Series RCL Circuit
  • A source-free series RCL circuit occurs when
    its dc source is suddenly disconnected. The
    energy initially stored in the capacitor and
    inductor is released to the resistor. A
    source-free RCL circuit is typically constructed
    as depicted in Fig. 3, comprising only three
    elements R, C and L.

The final equation is
The initial conditions are v(0)v(0-)v0,
i(0)i(0-)i0, and
Therefore the final solution is
Where s1 and s2 are solutions of
Where A1 and A2 are to be determined.
6
Discussions
7
Conclusions
  • The behavior is characterized by the idea of
    damping, which is the gradual loss of the initial
    stored energy. The damping is due to the presence
    of the resistance R. If R 0, we have an LC
    circuit with as the oscillation frequency that is
    lossless.
  • Oscillatory response is possible due to the
    presence of the two types of storage elements.
    Having both L and C allows the flow of energy
    back and forth between the two elements. The
    damped oscillation exhibited by the underdamped
    response is known as ringing.
  • The waveforms of the responses differ. The
    critical damped response decays faster than the
    overdamped response.

8
4. The Source-free Parallel RCL Circuit
The equations are
where
and A1 and A2 are to be determined.
9
Discussions
  • Overdamped case(agt?0)
  • Critically damped case (a?0)
  • Underdamped case (alt?0)

10
5. Step Response of a Series RCL Circuit
The final equation is
1)vn is the natural (or transient) response and
dependent on time. And has been discussed
before, for three different cases. 2) vf is the
forced (or steady-state) response, independent of
time. Because the voltages drop across the
inductor and resistor will be zero after
switching for long time.
11
Classwork 2
  • For the circuit in following figure, find v(t)
    and i(t) for tgt0. Consider the cases R5ohm,
    R4ohm and R1ohm.

12
6. Step Response of a Parallel RCL Circuit
For the above circuit, the equations
1)in is the natural (or transient) response and
dependent on time. And in has been discussed
before, for three different cases. 2) if is the
forced (or steady-state) response, independent of
time Because the currents through the
capacitor and resistor will be zero after
switching for long time.
13
Classwork 3
In the circuit, find i(t) and iR(t) for tgt0
14
7. General Second-Order Circuits
  • We first determine the initial conditions x(0)
    and dx(0)/dt and the final value of x(8).
  • We find the natural response xn(t) by switching
    off independent sources and applying KCL and KVL
    and let icCdVc./dt, VLLdiL/dt. Once a
    second-order differential equation is obtained,
    we can find the standard solutions for xn(t) by
    examining a and ?0.
  • We obtain the forced (steady-state) response as
  • The total response is the sum of the natural
    response and forced response

15
Classwork 4
  • Determine v and i for tgt0 in the circuit.
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