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Industrial Operations 233

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A = Annuity (payments of equal amount) 0 1 2 . n-1 n. P A A A A A. Fn ... Above formulas are only valid for compound interest and with Fn and P (no annuities) ... – PowerPoint PPT presentation

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Title: Industrial Operations 233


1
Industrial Operations 233
  • Investment Analysis

2
Time value of Money
  • Time Line
  • P present value
  • Fn Future value
  • A Annuity (payments of equal amount)

Fn
P A A A A A

0 1 2 ... n-1 n
3
Basic Formulas
  • Fn P(1i)n
  • P Fn/(1I)n
  • n Log(Fn/P)/Log(1i)
  • i (Fn/P)1/n - 1
  • Above formulas are only valid for compound
    interest and with Fn and P (no annuities)

4
Some examples
  • (1) Find P of 10,000, 18 years hence, if the
    interest rate is 10 per annum compounded (i)
    half-yearly, (ii) quarterly, and (iii) monthly.
  • Solution
  • (i) n 36 i 0.05 p Fn/(1i)n
  • P 10000/(1.05)36 1726.57
  • (ii) n 72 i 0.025 Therefore P 1689.98
  • (iii) n 216 i 0.0083 P 1677.30

5
Examples Contd.
  • (2) At 10 per annum converted quarterly, how
    long will it take for 750 to increase to 1000.
  • Solution
  • i 0.10 P 750 Fn 1000 n ?
  • n Log(Fn/P)/Log(1i)
  • n Log(1.333)/Log(1.025) n 11.64 quarters
  • ie. 2.9 years, or 3 years.

6
Examples Contd.
  • (3) 500 has to be turned into 1200 in 7 years.
    What must be the annual interest rate compounded
    quarterly?
  • Solution
  • P 500 F28 1200 n 28 i ??
  • i (Fn/P)1/n - 1 i (1200/500)1/28 - 1
    0.0317
  • ie. 3.17 per quarter ie. 3.17 x 4 12.68 per
    year compounded quarterly.

7
Time equivalence of money
  • An important concept
  • eg. 100 today is equivalent to 110 one year
    from now at i 10
  • All the amounts above are equivalent
  • The basis for project comparisons
  • Comparisons have to be at the same point in time


100 110 121 133.1 146.4
8
Interest rates
  • Simple - ie. not compounding
  • eg. 10 per annum
  • Compound - any rate which is compounded
  • Nominal
  • the advertised interest rate by banks financial
    institutions
  • eg. 10 per annum compounded quarterly
  • Effective - the real int rate per period

9
Effective Interest rate
  • Two types
  • effective per period effective per annum
  • eg. Nominal, i 10 per annum comp quarterly
  • effective per quarter (period) 10/4 2.5
  • What is the effective rate per annum?


0 1 2 3 4
quarters
year
0 1
1 F?
I 10 p. a. comp quart
10
Effective Rate
  • For quarters
  • F 1(1.1/4)4 1.0254 1.1038 .. (1)
  • For years
  • F 1 (1i)1 1I .(2)
  • Therefore, 1.1038 1i i 0.1038
  • ie. 10.38 per annum effective (or, ie 10.38)
  • From (1) (2)
  • (1r/k)k (1ie) where, r nominal rate, k
    no of compoundings per annum
  • Therefore, ie (1r/k)k - 1 ..(3)

11
Examples
  • (1) r 8.5 p.a. comp monthly. Find the
    effective rates.
  • Effective rate per month 8.5/12 0.70833 per
    month
  • Effective rate per annum, ie (1r/k)k - 1
  • ie (1 .085/12)12 -1 0.08839 ie. 8.839
    p.a. effective
  • (2) Bank A offers 9.5 interest credited half
    yearly. Bank B offers 9.25 interest comp daily.
    Where should we put our money?

12
Examples Contd.
  • Approach 1 Find effective interest rate
  • Bank A ie (1.095/2)2 -1 0.09725, ie. 9.725
  • Bank B ie (1.0925/365)365 -1 0.0969, ie.
    9.69
  • Bank A gives higher effective interest
  • Approach 2 Invest 100 for one year
  • Bank A F 100(1 0.095/2)2 109.725
  • Bank B F 100(1 0.0925/365)365 109.69
  • Money grows faster in Bank A

13
A Complete Example
  • I wish to save 5000 for a boat, which I intend
    to buy 2 years from now
  • (a) How much should I invest today if int rate is
    8 p.a. comp quarterly?
  • Solution F 5000 n8 quarters i0.02 P?
  • P5000/(1.02)8 4267.45
  • (b) 6 months after my investment rate drops to 6
    p.a. quarterly. How much will I be short of 5000
    at the end of 2 years?


0 2 4 6 8
i.02 i.015
14
Complete Example Contd.
  • Solution P4267.45 i.02 for the first 2
    quarters and .015 for the remaining 6 quarters
    F?
  • F4267.45(1.02)2(1.015)6 4854.72
  • Shortfall 5000 - 4854.72 145.28
  • (c) How much longer would it take to reach 5000
  • Solution P4854.72 F5000 i0.015 per quar
    n?
  • n Log(Fn/P)/Log(1i) Log(5000/4854.72)/Log(1.0
    15)
  • n 1.98 quarters

15
Tutorial
  • (1) Describe the concept of time equivalence of
    money. Why it is so important.
  • (2) How long will it take for a sum of money to
    double itself if the interest rate is 12 p.a.
    comp monthly?
  • (3) A loan of 10000 is obtained at 10 p.a. comp
    quarterly. After 2 years a partial repayment of
    6000 is to be made, with the balance a further 2
    years later. How much is the balance?
  • (4) Bill borrowed 3750 at 6 p.a. comp
    quarterly, and settled his debt by a payment of
    4500. When was the payment made?
  • (5) Max borrows 10000 at 12 p.a. converted
    quarterly. He is to repay 2000 at the end of
    each of the first 4 years, with a final payment
    at the end of 5 years. What is the size of the
    final payment?
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